Pearson Product Moment Coefficient Correlation (Pearson r).pptx
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The document discusses calculating Pearson's correlation coefficient (r) between midterm and final exam scores of students. It provides steps to compute r using an online calculator. For 10 students, r = 0.949, p = 0.000, indicating a significant relationship. For 12 students, r = 0.467, p = 0.126, not significant. The null hypothesis of no relationship is rejected for the first group but accepted for the second.
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The time required for a citizen to complete the 2000 U.S. Census "long" form is normally distributed with a mean of 40 minutes and a standard deviation of 10 minutes. What proportion of the citizens will require less than one hour?
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Assume that X is normally distributed with a mean μ= $64. Given that P(X ≥$75) = 0.2981, we can calculate that the standard deviation of X is approximately
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If arrivals follow a Poisson distribution with mean 1.2 arrivals per minute, find the 75th percentile of waiting times (i.e., 75 percent below).
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1 60 60
2 75 100
3 70 80
4 72 68
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6 83 97
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8 65 90
a. Construct a scatter plot of the data, using exam 1 score as the X variable. Does the relationship look linear?
b. Assuming a linear relationship exists between scores on the two exams, compute the value for Pearson r.
c. How well does the relationship account for the scores on exam 2?
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When the null hypothesis has been rejected for a specific a value, any of the following five possibilities can exist.
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Pearson Product Moment Coefficient Correlation (Pearson r).pptx
- 2. Pearson Product Moment Coefficient Correlation Is an index of relationship between two variables. The independent variable can be represented by x while the dependent variable can be represented by y.
- 3. Pearson Product Moment Coefficient Correlation Formula
- 4. The following are the midterm and final examination scores of the 10 students in Mathematics. Compute for (r). Midterm(x) Finals(y) 75 80 70 75 65 65 90 95 85 90 85 85 80 90 70 75 65 70 90 90
- 5. Statement of the Problem Is there a significant relationship on the midterm and final examination scores among the 10 students in Mathematics? Hypothesis There is no significant relationship on the midterm and final examination scores among the 10 students in Mathematics.
- 6. Level of Significance 0.05 level of significance
- 7. Steps in computing for (r) 1. Open a new browser. 2. Search this website. https://www.socscistatistics.com/
- 8. 2. Search this website. https://www.socscistatistics.com/ 3. Click “Calculators”
- 9. 4. Once this screen will appear, scroll down and look for pearson coefficient correlation calculator and click it.
- 10. 4. Once this screen will appear, click “Take me to the calculator!” box
- 11. 5. Once this screen will appear, Encode your data
- 12. 6. Recheck if the encoded data were correct and click “Calculate R” box.
- 14. 7. On the lower screen will appear like this. Get the r value. Then click “Click here to calculate p-value.
- 15. 7. Once this screen will appear , Encode the r value or score and the N.
- 16. 7. Once this screen will appear , Encode the r value or score and the N. Then click “Calculate” box.
- 17. 7. Once this screen will appear , Encode the r value or score and the N.
- 18. The computed r-value of 0.9493 or 0.949 (P- value:0.0000) is lower than the critical p-value 0.05 level of significance. This means that there is significant relationship on the midterm and finals examination scores among 10 students in Mathematics. Thus, the null hypothesis is rejected. Computed (r) P-value Decision 0.949 0.000 Significant
- 19. Performance Task
- 20. The following are the midterm and final examination scores of the 12 students in Mathematics. Compute for (r). Midterm(x) Finals(y) 20 25 30 35 10 25 15 25 20 20 10 20 18 22 14 20 15 20 20 15 18 30 15 10
- 21. Statement of the Problem Is there a significant relationship on the midterm and final examination scores among the 12 students in Mathematics? Hypothesis There is no significant relationship on the midterm and final examination scores among the 12 students in Mathematics.
- 24. The computed r-value of 0.4666 or 0.467 (P- value:0.1262) is higher than the p-critical value of 0.05 level of significance. This means that there no significant relationship on the midterm and finals examination scores among 12 students in Mathematics. Thus, the null hypothesis is accepted. Computed (r) P-value Decision 0.4666 0.1262 Not Significant
- 25. Outputs Format
- 26. Statement of the Problem Is there a significant relationship on the midterm and final examination scores among the 10 students in Mathematics? Hypothesis There is no significant relationship on the midterm and final examination scores among the 10 students in Mathematics.
- 27. The computed r-value of 0.9493 or 0.949 (P- value:0.0000) is lower than the critical p-value 0.05 level of significance. This means that there is significant relationship on the midterm and finals examination scores among 10 students in Mathematics. Thus, the null hypothesis is rejected. Computed (r) Computed P-value Decision 0.9493 0.0000 Significant Test Correlation Table
- 28. Screenshots for computed r-value
- 29. Screenshot of computed p-value