Learning Target:
b. Find the surface area of cube,
prism, pyramid, cylinder, cone,
and sphere.
a. Derive a formula for finding the
surface area of cube, prism, pyramid,
cylinder, cone and sphere; and
How do I find
out how much
gift-wrap I need
to buy for this
box?
You need to get
the surface area
of the box.
 is the total area of
the surface of a three-
dimensional object.
Ana wraps her gift for Elsa. The
measure of the edge of the cube is 10
inches. She does not have extra
paper, so she does not overlap any of
the edges. How much paper was used
to cover Ana’s gift?
Formula:
Cube
SA =
6s2
=
6
x 10
in
2
= 6 x 100
in2
= 600 in2
Compute the SURFACE AREA
of a CUBE.
SA = 6s2
SA = 216
2
SA = 384
2
A Christmas ball has a radius of 11
cm. If its surface area is to be
filled up with glitters, how much
area will be covered with glitters?
Formula:
Sphere
SA = 4ꙥr2
= 4ꙥx 11 cm2
= 4ꙥ x 121 cm2
= 1519.76 cm2
= 4 x 3.14 x 121 cm2
Compute the SURFACE AREA of
a SPHERE.
SA = 4ꙥr2
SA = 452.16
2
SA = 803.84
2
Mark has a pool filled with water. The
pool is 10 m long, 8 m wide, and 4 m
deep. Find the surface area of the
pool.
Formula:
Rectangular
Prism
SA = 2LW + 2LH +
2WH
= 2(10 x 8) + 2(10 x 4) +
2 (8 x 4)
= 2 (80) + 2 (40) + 2
(32)
= 304 m2
= 160 + 80 + 64
Compute the SURFACE AREA of a
RECTANGULAR PRISM.
SA = 2LW + 2LH +
2WH
SA = 150
2
SA = 170
2
Our cylindrical tank has a radius
of 5 ft and height of 10 ft. How
much paint is needed to paint its
surface?
Formula:
Cylinder
SA = 2ꙥr2 +
2ꙥrh
= 2(3.14 x 52) + 2(3.14 x 5 x
10)
= 2(3.14 x 25) + 2(3.14 x 50)
= 2(78.5) + 2(157)
= 157 + 314
= 471 ft2
Compute the SURFACE AREA of a
Cylinder.
SA = 2ꙥr2 + 2ꙥrh
SA = 94.2
2
SA = 301.44
2
A cone has a radius of 3 cm,
height of 4 cm and the slant
measures 5 cm. Find the total
surface area of the cone.
Formula:
Cone
SA = ꙥr2 + ꙥrs
= 3.14 x 32 + 3.14 x 3 x 5
= 3.14 x 9 + 3.14 x 15)
= 28.26 + 47.1
= 75.36 cm2
Compute the SURFACE AREA of a CONE.
SA = ꙥr2 + ꙥrs
SA = 136.8
2
SA = 50.24
2
10
cm
8
m

Math 6 - Surface Area of Space Figures.ppsx

  • 2.
    Learning Target: b. Findthe surface area of cube, prism, pyramid, cylinder, cone, and sphere. a. Derive a formula for finding the surface area of cube, prism, pyramid, cylinder, cone and sphere; and
  • 3.
    How do Ifind out how much gift-wrap I need to buy for this box? You need to get the surface area of the box.
  • 4.
     is thetotal area of the surface of a three- dimensional object.
  • 5.
    Ana wraps hergift for Elsa. The measure of the edge of the cube is 10 inches. She does not have extra paper, so she does not overlap any of the edges. How much paper was used to cover Ana’s gift? Formula: Cube SA = 6s2 = 6 x 10 in 2 = 6 x 100 in2 = 600 in2
  • 6.
    Compute the SURFACEAREA of a CUBE. SA = 6s2 SA = 216 2 SA = 384 2
  • 7.
    A Christmas ballhas a radius of 11 cm. If its surface area is to be filled up with glitters, how much area will be covered with glitters? Formula: Sphere SA = 4ꙥr2 = 4ꙥx 11 cm2 = 4ꙥ x 121 cm2 = 1519.76 cm2 = 4 x 3.14 x 121 cm2
  • 8.
    Compute the SURFACEAREA of a SPHERE. SA = 4ꙥr2 SA = 452.16 2 SA = 803.84 2
  • 9.
    Mark has apool filled with water. The pool is 10 m long, 8 m wide, and 4 m deep. Find the surface area of the pool. Formula: Rectangular Prism SA = 2LW + 2LH + 2WH = 2(10 x 8) + 2(10 x 4) + 2 (8 x 4) = 2 (80) + 2 (40) + 2 (32) = 304 m2 = 160 + 80 + 64
  • 10.
    Compute the SURFACEAREA of a RECTANGULAR PRISM. SA = 2LW + 2LH + 2WH SA = 150 2 SA = 170 2
  • 11.
    Our cylindrical tankhas a radius of 5 ft and height of 10 ft. How much paint is needed to paint its surface? Formula: Cylinder SA = 2ꙥr2 + 2ꙥrh = 2(3.14 x 52) + 2(3.14 x 5 x 10) = 2(3.14 x 25) + 2(3.14 x 50) = 2(78.5) + 2(157) = 157 + 314 = 471 ft2
  • 12.
    Compute the SURFACEAREA of a Cylinder. SA = 2ꙥr2 + 2ꙥrh SA = 94.2 2 SA = 301.44 2
  • 13.
    A cone hasa radius of 3 cm, height of 4 cm and the slant measures 5 cm. Find the total surface area of the cone. Formula: Cone SA = ꙥr2 + ꙥrs = 3.14 x 32 + 3.14 x 3 x 5 = 3.14 x 9 + 3.14 x 15) = 28.26 + 47.1 = 75.36 cm2
  • 14.
    Compute the SURFACEAREA of a CONE. SA = ꙥr2 + ꙥrs SA = 136.8 2 SA = 50.24 2 10 cm 8 m