This document discusses linked lists and their implementation as an alternative to arrays for representing list abstract data types (ADTs). It covers the basic operations of linked lists like insertion, deletion, finding elements, and printing the list. Variations of linked lists like circular and doubly linked lists are also introduced. The key benefits of linked lists over arrays are their dynamic size and efficient insertion/deletion operations. Linked lists provide a modular way to implement common ADTs through encapsulation of data and operations.
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2. Linked Lists / Slide 2
Outline
Abstract Data Type (ADT)
List ADT
List ADT with Array Implementation
Linked lists
Basic operations of linked lists
Insert, find, delete, print, etc.
Variations of linked lists
Circular linked lists
Doubly linked lists
3. Linked Lists / Slide 3
Abstract Data Type (ADT)
Data type
a set of objects + a set of operations
Example: integer
set of whole numbers
operations: +, -, x, /
Can this be generalized?
(e.g. procedures generalize the notion of an
operator)
Yes!
Abstract data type
high-level abstractions (managing complexity
through abstraction)
Encapsulation
4. Linked Lists / Slide 4
Encapsulation
Operation on the ADT can only be done by calling the
appropriate function
no mention of how the set of operations is
implemented
The definition of the type and all operations on that
type can be localized to one section of the program
If we wish to change the implementation of an ADT
we know where to look
by revising one small section we can be sure that
there is no subtlety elsewhere that will cause errors
We can treat the ADT as a primitive type: we have no
concern with the underlying implementation
ADT → C++: class
method → C++: member function
5. Linked Lists / Slide 5
ADT…
Examples
the set ADT
A set of elements
Operations: union, intersection, size and complement
the queue ADT
A set of sequences of elements
Operations: create empty queue, insert, examine, delete,
and destroy queue
Two ADT’s are different if they have the same
underlying model but different operations
E.g. a different set ADT with only the union and
find operations
The appropriateness of an implementation
depends very much on the operations to be
performed
6. Linked Lists / Slide 6
Pros and Cons
Implementation of the ADT is separate from its use
Modular: one module for one ADT
Easier to debug
Easier for several people to work simultaneously
Code for the ADT can be reused in different
applications
Information hiding
A logical unit to do a specific job
implementation details can be changed without affecting user
programs
Allow rapid prototying
Prototype with simple ADT implementations, then tune them
later when necessary
Loss of efficiency
7. Linked Lists / Slide 7
The List ADT
A sequence of zero or more elements
A1, A2, A3, … AN
N: length of the list
A1: first element
AN: last element
Ai: position i
If N=0, then empty list
Linearly ordered
Ai precedes Ai+1
Ai follows Ai-1
8. Linked Lists / Slide 8
Operations
printList: print the list
makeEmpty: create an empty list
find: locate the position of an object in a list
list: 34,12, 52, 16, 12
find(52) → 3
insert: insert an object to a list
insert(x,3) → 34, 12, 52, x, 16, 12
remove: delete an element from the list
remove(52) → 34, 12, x, 16, 12
findKth: retrieve the element at a certain
position
9. Linked Lists / Slide 9
Implementation of an ADT
Choose a data structure to represent the
ADT
E.g. arrays, records, etc.
Each operation associated with the ADT is
implemented by one or more subroutines
Two standard implementations for the list ADT
Array-based
Linked list
10. Linked Lists / Slide 10
Array Implementation
Elements are stored in contiguous array
positions
11. Linked Lists / Slide 11
Array Implementation...
Requires an estimate of the maximum size of
the list
waste space
printList and find: linear
findKth: constant
insert and delete: slow
e.g. insert at position 0 (making a new element)
requires first pushing the entire array down one spot to
make room
e.g. delete at position 0
requires shifting all the elements in the list up one
On average, half of the lists needs to be moved for
either operation
12. Linked Lists / Slide 12
Pointer Implementation (Linked List)
Ensure that the list is not stored contiguously
use a linked list
a series of structures that are not necessarily adjacent
in memory
Each node contains the element and a pointer to a
structure containing its successor
the last cell’s next link points to NULL
Compared to the array implementation,
the pointer implementation uses only as much space as is needed
for the elements currently on the list
but requires space for the pointers in each cell
13. Linked Lists / Slide 13
Linked Lists
A linked list is a series of connected nodes
Each node contains at least
A piece of data (any type)
Pointer to the next node in the list
Head: pointer to the first node
The last node points to NULL
A ∅
Head
B C
A
data pointer
node
14. Linked Lists / Slide 14
A Simple Linked List Class
We use two classes: Node and List
Declare Node class for the nodes
data: double-type data in this example
next: a pointer to the next node in the list
class Node {
public:
double data; // data
Node* next; // pointer to next
};
15. Linked Lists / Slide 15
A Simple Linked List Class
Declare List, which contains
head: a pointer to the first node in the list.
Since the list is empty initially, head is set to NULL
Operations on List
class List {
public:
List(void) { head = NULL; } // constructor
~List(void); // destructor
bool IsEmpty() { return head == NULL; }
Node* InsertNode(int index, double x);
int FindNode(double x);
int DeleteNode(double x);
void DisplayList(void);
private:
Node* head;
};
16. Linked Lists / Slide 16
A Simple Linked List Class
Operations of List
IsEmpty: determine whether or not the list is
empty
InsertNode: insert a new node at a particular
position
FindNode: find a node with a given value
DeleteNode: delete a node with a given value
DisplayList: print all the nodes in the list
17. Linked Lists / Slide 17
Inserting a new node
Node* InsertNode(int index, double x)
Insert a node with data equal to x after the index’th elements.
(i.e., when index = 0, insert the node as the first element;
when index = 1, insert the node after the first element, and so on)
If the insertion is successful, return the inserted node.
Otherwise, return NULL.
(If index is < 0 or > length of the list, the insertion will fail.)
Steps
1. Locate index’th element
2. Allocate memory for the new node
3. Point the new node to its successor
4. Point the new node’s predecessor to the new node
newNode
index’th
element
18. Linked Lists / Slide 18
Inserting a new node
Possible cases of InsertNode
1. Insert into an empty list
2. Insert in front
3. Insert at back
4. Insert in middle
But, in fact, only need to handle two cases
Insert as the first node (Case 1 and Case 2)
Insert in the middle or at the end of the list (Case 3 and
Case 4)
19. Linked Lists / Slide 19
Inserting a new node
Node* List::InsertNode(int index, double x) {
if (index < 0) return NULL;
int currIndex = 1;
Node* currNode = head;
while (currNode && index > currIndex) {
currNode = currNode->next;
currIndex++;
}
if (index > 0 && currNode == NULL) return NULL;
Node* newNode = new Node;
newNode->data = x;
if (index == 0) {
newNode->next = head;
head = newNode;
}
else {
newNode->next = currNode->next;
currNode->next = newNode;
}
return newNode;
}
Try to locate
index’th node. If it
doesn’t exist,
return NULL.
20. Linked Lists / Slide 20
Inserting a new node
Node* List::InsertNode(int index, double x) {
if (index < 0) return NULL;
int currIndex = 1;
Node* currNode = head;
while (currNode && index > currIndex) {
currNode = currNode->next;
currIndex++;
}
if (index > 0 && currNode == NULL) return NULL;
Node* newNode = new Node;
newNode->data = x;
if (index == 0) {
newNode->next = head;
head = newNode;
}
else {
newNode->next = currNode->next;
currNode->next = newNode;
}
return newNode;
}
Create a new node
21. Linked Lists / Slide 21
Inserting a new node
Node* List::InsertNode(int index, double x) {
if (index < 0) return NULL;
int currIndex = 1;
Node* currNode = head;
while (currNode && index > currIndex) {
currNode = currNode->next;
currIndex++;
}
if (index > 0 && currNode == NULL) return NULL;
Node* newNode = new Node;
newNode->data = x;
if (index == 0) {
newNode->next = head;
head = newNode;
}
else {
newNode->next = currNode->next;
currNode->next = newNode;
}
return newNode;
}
Insert as first element
head
newNode
22. Linked Lists / Slide 22
Inserting a new node
Node* List::InsertNode(int index, double x) {
if (index < 0) return NULL;
int currIndex = 1;
Node* currNode = head;
while (currNode && index > currIndex) {
currNode = currNode->next;
currIndex++;
}
if (index > 0 && currNode == NULL) return NULL;
Node* newNode = new Node;
newNode->data = x;
if (index == 0) {
newNode->next = head;
head = newNode;
}
else {
newNode->next = currNode->next;
currNode->next = newNode;
}
return newNode;
}
Insert after currNode
newNode
currNode
23. Linked Lists / Slide 23
Finding a node
int FindNode(double x)
Search for a node with the value equal to x in the list.
If such a node is found, return its position. Otherwise, return
0.
int List::FindNode(double x) {
Node* currNode = head;
int currIndex = 1;
while (currNode && currNode->data != x) {
currNode = currNode->next;
currIndex++;
}
if (currNode) return currIndex;
return 0;
}
24. Linked Lists / Slide 24
Deleting a node
int DeleteNode(double x)
Delete a node with the value equal to x from the list.
If such a node is found, return its position. Otherwise, return
0.
Steps
Find the desirable node (similar to FindNode)
Release the memory occupied by the found node
Set the pointer of the predecessor of the found node to the
successor of the found node
Like InsertNode, there are two special cases
Delete first node
Delete the node in middle or at the end of the list
25. Linked Lists / Slide 25
Deleting a node
int List::DeleteNode(double x) {
Node* prevNode = NULL;
Node* currNode = head;
int currIndex = 1;
while (currNode && currNode->data != x) {
prevNode = currNode;
currNode = currNode->next;
currIndex++;
}
if (currNode) {
if (prevNode) {
prevNode->next = currNode->next;
delete currNode;
}
else {
head = currNode->next;
delete currNode;
}
return currIndex;
}
return 0;
}
Try to find the node with
its value equal to x
26. Linked Lists / Slide 26
Deleting a node
int List::DeleteNode(double x) {
Node* prevNode = NULL;
Node* currNode = head;
int currIndex = 1;
while (currNode && currNode->data != x) {
prevNode = currNode;
currNode = currNode->next;
currIndex++;
}
if (currNode) {
if (prevNode) {
prevNode->next = currNode->next;
delete currNode;
}
else {
head = currNode->next;
delete currNode;
}
return currIndex;
}
return 0;
}
currNodeprevNode
27. Linked Lists / Slide 27
Deleting a node
int List::DeleteNode(double x) {
Node* prevNode = NULL;
Node* currNode = head;
int currIndex = 1;
while (currNode && currNode->data != x) {
prevNode = currNode;
currNode = currNode->next;
currIndex++;
}
if (currNode) {
if (prevNode) {
prevNode->next = currNode->next;
delete currNode;
}
else {
head = currNode->next;
delete currNode;
}
return currIndex;
}
return 0;
}
currNodehead
28. Linked Lists / Slide 28
Printing all the elements
void DisplayList(void)
Print the data of all the elements
Print the number of the nodes in the list
void List::DisplayList()
{
int num = 0;
Node* currNode = head;
while (currNode != NULL){
cout << currNode->data << endl;
currNode = currNode->next;
num++;
}
cout << "Number of nodes in the list: " << num << endl;
}
29. Linked Lists / Slide 29
Destroying the list
~List(void)
Use the destructor to release all the memory used by the list.
Step through the list and delete each node one by one.
List::~List(void) {
Node* currNode = head, *nextNode = NULL;
while (currNode != NULL)
{
nextNode = currNode->next;
// destroy the current node
delete currNode;
currNode = nextNode;
}
}
30. Linked Lists / Slide 30
Using List
int main(void)
{
List list;
list.InsertNode(0, 7.0); // successful
list.InsertNode(1, 5.0); // successful
list.InsertNode(-1, 5.0); // unsuccessful
list.InsertNode(0, 6.0); // successful
list.InsertNode(8, 4.0); // unsuccessful
// print all the elements
list.DisplayList();
if(list.FindNode(5.0) > 0) cout << "5.0 found" << endl;
else cout << "5.0 not found" << endl;
if(list.FindNode(4.5) > 0) cout << "4.5 found" << endl;
else cout << "4.5 not found" << endl;
list.DeleteNode(7.0);
list.DisplayList();
return 0;
}
6
7
5
Number of nodes in the list: 3
5.0 found
4.5 not found
6
5
Number of nodes in the list: 2
result
31. Linked Lists / Slide 31
Variations of Linked Lists
Circular linked lists
The last node points to the first node of the list
How do we know when we have finished traversing
the list? (Tip: check if the pointer of the current
node is equal to the head.)
A
Head
B C
32. Linked Lists / Slide 32
Variations of Linked Lists
Doubly linked lists
Each node points to not only successor but the
predecessor
There are two NULL: at the first and last nodes in
the list
Advantage: given a node, it is easy to visit its
predecessor. Convenient to traverse lists backwards
A
Head
B∅ C ∅
33. Linked Lists / Slide 33
Array versus Linked Lists
Linked lists are more complex to code and manage
than arrays, but they have some distinct advantages.
Dynamic: a linked list can easily grow and shrink in size.
We don’t need to know how many nodes will be in the list. They
are created in memory as needed.
In contrast, the size of a C++ array is fixed at compilation time.
Easy and fast insertions and deletions
To insert or delete an element in an array, we need to copy to
temporary variables to make room for new elements or close the
gap caused by deleted elements.
With a linked list, no need to move other nodes. Only need to
reset some pointers.
34. Linked Lists / Slide 34
Example: The Polynomial ADT
An ADT for single-variable polynomials
Array implementation
∑=
=
N
i
i
i xaxf
0
)(
35. Linked Lists / Slide 35
The Polynomial ADT…
Acceptable if most of the coefficients Aj are
nonzero, undesirable if this is not the case
E.g. multiply
most of the time is spent multiplying zeros and stepping
through nonexistent parts of the input polynomials
Implementation using a singly linked list
Each term is contained in one cell, and the cells
are sorted in decreasing order of exponents
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1510)(
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