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V SIVAHAR / LEVEL 1 / MT 101 1
PHASE DIAGRAMS
Alloy:
An alloy is a metallic material consisting of
two or more elements. The principal
element is generally a metal the other
elements can be metallic or non-metallic
elements.
e.g. Steel (Fe + C)
V SIVAHAR / LEVEL 1 / MT 101 2
PHASE DIAGRAMS
Alloys can be formed in three different
ways.
1. Interstitial Solid Solution (ISS)
2. Substitutional Solid Solution (SSS)
3. Intermediate Compounds
V SIVAHAR / LEVEL 1 / MT 101 3
PHASE DIAGRAMS
Interstitial Solid Solution e.g. C in Fe
Solvent atoms
(Fe)
Solute atoms
(C)
V SIVAHAR / LEVEL 1 / MT 101 4
PHASE DIAGRAMS
Substitutional Solid Solution e.g. Zn in Cu
Solvent atoms
(Cu)
Solute atoms
(Zn)
V SIVAHAR / LEVEL 1 / MT 101 5
PHASE DIAGRAMS
Intermediate Compound e.g. Fe3C
•Intermediate compounds have fixed compositions.
•Find the weight percentage of carbon in Fe3C. (Ans : 6.67%)
•If both the elements are metals it is known as an Intermetallic
Compound. E.g. CuAl2
V SIVAHAR / LEVEL 1 / MT 101 6
PHASE DIAGRAMS
Phase
A state in which a material can exist. E.g.
water can exist in solid (ice), liquid (water)
and gaseous (steam) phases.
• Existence of particular phase depends on
temperature and pressure.
• The factors temperature and pressure are
known as the variables.
V SIVAHAR / LEVEL 1 / MT 101 7
PHASE DIAGRAMS
• In an alloy, composition becomes the third
variable.
PHASE DIAGRAM
Phase diagram is a graphical representation
of the phases present in a material system
under different conditions.
V SIVAHAR / LEVEL 1 / MT 101 8
PHASE DIAGRAM – PURE WATER
V SIVAHAR / LEVEL 1 / MT 101 9
PHASE DIAGRAM – PURE IRON
1539 0C
1394 0C
910 0C
P atm
T0C
α – IRON (BCC)
γ – IRON (FCC)
δ – IRON (BCC)
LIQUID
VAPOR
V SIVAHAR / LEVEL 1 / MT 101 10
BINARY ALLOY PHASE
DIAGRAMS
• Alloys containing two elements are known
as binary alloys. E.g.: Steel (Fe + C)
• Binary alloy phase diagrams are obtained
for Temperature and Composition while
maintaining the pressure constant –
usually 1 atm
V SIVAHAR / LEVEL 1 / MT 101 11
BINARY ALLOY PHASE
DIAGRAMS
• Binary alloy phase diagrams are
considered under 3 different categories:
1. Complete solubility in solid state
2. Complete insolubility in solid state
3. Partial solubility in solid state
V SIVAHAR / LEVEL 1 / MT 101 12
Complete solubility
Line 1
T 0C
TB
LIQUID liquidus
L + α solidus
TA
α
100A 50A 0A
0B 50B 100B
V SIVAHAR / LEVEL 1 / MT 101 13
Complete solubility
• Microstructural changes along line 1
LIQUID α
V SIVAHAR / LEVEL 1 / MT 101 14
Complete insolubility
1 2 3
T 0C
TB
LIQUID
TA
L + A L + B
TE
E
A + B
100A 50A 0A
0B 50B 100B
V SIVAHAR / LEVEL 1 / MT 101 15
Complete insolubility
• At point E along line 2
LIQUID A + B
Such a transformation is known as eutectic
transformation. E is known as the eutectic point
and TE is known as eutectic temperature.
V SIVAHAR / LEVEL 1 / MT 101 16
Complete insolubility
LINE 2
LIQUID B
A
V SIVAHAR / LEVEL 1 / MT 101 17
Complete insolubility
LINE 1
B
A
LIQUID
V SIVAHAR / LEVEL 1 / MT 101 18
Complete insolubility
LINE 3
B
A
LIQUID
V SIVAHAR / LEVEL 1 / MT 101 19
Partial solubility
1 2 3 4 5 6 7
T 0C
TB
LIQUID
TA
L + α L + β
TE
α β
E α + β
100A 50A 0A
0B 50B 100B
V SIVAHAR / LEVEL 1 / MT 101 20
Partial solubility
LINE 4
LIQUID β
α
V SIVAHAR / LEVEL 1 / MT 101 21
Partial solubility
LINE 3
β
α
LIQUID
V SIVAHAR / LEVEL 1 / MT 101 22
Partial solubility
LINE 5
β
α
LIQUID
V SIVAHAR / LEVEL 1 / MT 101 23
Partial solubility
LIQUID α
LINE 1
V SIVAHAR / LEVEL 1 / MT 101 24
Partial solubility
LIQUID β
LINE 7
V SIVAHAR / LEVEL 1 / MT 101 25
Partial solubility
LINE 2
LIQUID α α β
V SIVAHAR / LEVEL 1 / MT 101 26
Partial solubility
LIQUID β
LINE 6
β α
V SIVAHAR / LEVEL 1 / MT 101 27
Lever rule
• Lever rule is used to find the proportions of
the phases present in a two-phase region
30B 45B 65B
Liquid
L+α
α
70A 55A 35A
X Y
T
V SIVAHAR / LEVEL 1 / MT 101 28
Lever rule
• Find the relative proportions of liquid and α phases
at the temperature T for an alloy of 55%A + 45%B
 
1
Y
%
X
L% 


 
%
43
%
35
15
100
%
%
57
%
35
20
100
L%







 
35
%
100
15
α%
20
L%
Y
X
%
100
X
α%
Y
L%
1
equation
From





 
2
100%
%
L% 


V SIVAHAR / LEVEL 1 / MT 101 29
Lever rule
• What are the compositions of the liquid and α
phases at this temperature?
Answer:
• Liquid phase – 70A+30B
• α phase – 35A+65B
V SIVAHAR / LEVEL 1 / MT 101 30
MECHANICAL PROPERTIES
• Reaction of materials to the action of external
stresses is indicated as mechanical properties
A
F
]
[
2
Pa
m
N
A
F
Stress 

V SIVAHAR / LEVEL 1 / MT 101 31
MECHANICAL PROPERTIES
• Application of a stress causes a material to
deform. A stress as shown below elongates
the material. Elongation (or contraction), when
expressed per unit length is known as strain.
l0 e 0
l
e
Strain 

V SIVAHAR / LEVEL 1 / MT 101 32
MECHANICAL PROPERTIES
(Uniaxial) Tensile Stress
(Uniaxial) Compressive Stress
V SIVAHAR / LEVEL 1 / MT 101 33
MECHANICAL PROPERTIES
• Mechanical properties of a material is studied by
performing tensile test. Tensile test employs a
specimen as shown below.
l0
do
lo – Gauge length do – Initial diameter
Ao – Initial area 4
2
d
Ao 

V SIVAHAR / LEVEL 1 / MT 101 34
MECHANICAL PROPERTIES
• The specimen will be subjected to a
progressively increasing tensile force until it
fractures.
V SIVAHAR / LEVEL 1 / MT 101 35
MECHANICAL PROPERTIES
• From the test, Force-Extension curve is
obtained.
e
F
V SIVAHAR / LEVEL 1 / MT 101 36
MECHANICAL PROPERTIES
• Force-Extension curve is then converted
to a Stress-Strain [σ-ε] diagram.
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 37
MECHANICAL PROPERTIES
• Form of Stress-Strain [σ-ε] diagram of Cu, Al etc.
ε
σ
UTS
YS
FS
UTS – Ultimate Tensile Strength
YS – Yield Stress
FS – Fracture Stress
V SIVAHAR / LEVEL 1 / MT 101 38
MECHANICAL PROPERTIES
• Form of Stress-Strain [σ-ε] diagram of steel
ε
σ
UTS
UYS
LYS
FS
UTS – Ultimate Tensile Strength
UYS – Upper Yield Stress
LYS – Lower Yield Stress
FS – Fracture Stress
V SIVAHAR / LEVEL 1 / MT 101 39
Stress-Strain Diagram Steel
V SIVAHAR / LEVEL 1 / MT 101 40
MECHANICAL PROPERTIES
• Form of Stress-Strain [σ-ε] diagram for glass,
diamond, cast iron, ceramics etc.
ε
σ
FS
FS – Fracture Stress
V SIVAHAR / LEVEL 1 / MT 101 41
MECHANICAL PROPERTIES
• Form of Stress-Strain [σ-ε] diagram for a plastic
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 42
MECHANICAL PROPERTIES
• Form of Stress-Strain [σ-ε] diagram for rubber
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 43
ELASTICITY
• All materials show temporary deformation
to a certain extent
• Such a deformation is known as elastic
deformation
• Property of possessing elastic deformation
is known as elasticity
• Elasticity of most of the materials gives a
straight line in the σ-ε diagram – known as
linear elastic materials
V SIVAHAR / LEVEL 1 / MT 101 44
ELASTICITY
• For linear elastic materials
• E is known as Elastic modulus or Young’s
modulus
• E of steel is 2 x 1011Pa
Eε
σ
;
ε
σ 

ε
σ
V SIVAHAR / LEVEL 1 / MT 101 45
ELASTICITY
• Elasticity of some other materials does not
give a straight line in the σ-ε diagram –
known as non-linear elastic materials -
rubber
• Elasticity in materials is due to the
stretching of atomic bonds.
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 46
PLASTICITY
• The deformation becomes permanent
beyond a certain stress level in metals
• It known as plastic deformation and the
property is known as plasticity
• Plastic deformation begins at the yield
stress.
• Plastic deformation facilitates solid-state
fabrication in metals
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 47
PLASTICITY
• Plastic deformation in metals occurs due to
a phenomenon known as slip [relative
displacement of atomic planes]
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 48
PLASTICITY
• Slip is favored by the movement of
dislocations
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 49
PLASTICITY
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 50
PLASTICITY
• Movement of dislocations and slip occurs
on close packed planes in close packed
directions
• In FCC metals slip takes place on (111)
plane in [110] direction
• In BCC metals slip takes place on (110)
plane in [111] direction
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 51
PLASTICITY
ε
σ
Atoms are packed more closer in (111) of FCC
Slip occurs more favorably in FCC structures
(110) BCC (111) FCC
V SIVAHAR / LEVEL 1 / MT 101 52
ε
σ
DUCTILE &BRITTLE MATERIALS
• Ductile materials – materials that exhibit
plastic deformation – most metals are
ductile
• Brittle materials – materials that do not
have plasticity – glass, cast iron
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 53
DUCTILITY
• Ability of a metal to undergo plastic
deformation is defined as ductility
• Plastic strain at fracture εpf is a
measure of ductility
ε
σ
εpf
V SIVAHAR / LEVEL 1 / MT 101 54
DUCTILITY
• Ductility of copper is greater than that of
steel
ε
σ
V SIVAHAR / LEVEL 1 / MT 101 55
DUCTILITY
• Ductility can also be measured by
I. Percentage elongation
II. Percentage reduction in area
%
100


o
o
f
l
l
l
%
100


o
f
o
A
A
A
V SIVAHAR / LEVEL 1 / MT 101 56
DUCTILITY
• Example
• Why ductility of copper is greater than that
of steel at room temperature?
Note:
• Brittleness is the property that is opposite
to ductility
V SIVAHAR / LEVEL 1 / MT 101 57
STRENGTH
• Ability of a material to withstand the
applied stresses without failure is defined
as strength
[Maximum stress that can be applied on a
material]
• Strength of a brittle material is given by
it’s fracture stress
ε
σ
FS
V SIVAHAR / LEVEL 1 / MT 101 58
STRENGTH
• Yield stress is considered as the strength
for a ductile material
• UTS is not considered, since significant
plastic deformation takes place before
UTS is reached
V SIVAHAR / LEVEL 1 / MT 101 59
STRENGTH
ε
σ
UTS
YS
FS
Strength of steel 227MPa
V SIVAHAR / LEVEL 1 / MT 101 60
PROOF STRESS
• Proof stress is defined as the stress
required to cause a certain amount of
plastic strain.
• E.g. : 0.1% Proof stress is the stress at a
plastic strain of 0.1% or 0.001
• Following diagram demonstrates the
method to find 0.1% Proof Stress
V SIVAHAR / LEVEL 1 / MT 101 61
PROOF STRESS
ε
σ
0.001
0.1% PROOF STRESS
V SIVAHAR / LEVEL 1 / MT 101 62
WORK HARDENING
• Stress required for plastic deformation
increase continuously up to the UTS. This
phenomenon is known as work hardening.
• Work hardening increases the strength
and hardness while decreasing the
ductility and toughness.
• Effect of work hardening on strength is
demonstrated by a tensile test as follows
V SIVAHAR / LEVEL 1 / MT 101 63
WORK HARDENING
ε
σ
SPECIMEN UNLOADED
B
P
P
F
O
YS2
YS1
Test stopped at B
and the specimen
is unloaded
It is then reloaded
The new σ-ε
diagram is PBF
This shows that
the strength has
increased from
YS1 to YS2
V SIVAHAR / LEVEL 1 / MT 101 64
WORK HARDENING
Mechanism:
• During plastic deformation dislocations not
only move but also multiply.
• Increased number of dislocations
increases dislocation interactions within
themselves as well as with external factors
such as grain boundaries
V SIVAHAR / LEVEL 1 / MT 101 65
WORK HARDENING
Mechanism [contd…]:
• This increases the resistance for the
movement of dislocations in the
metal.
• As a result stress required for plastic
deformation continue to increase
V SIVAHAR / LEVEL 1 / MT 101 66
NECKING
• At the UTS a localized deformation begins
in the specimen
• This localized deformation is called
necking
V SIVAHAR / LEVEL 1 / MT 101 67
NECKING
• The area of cross-section continue to
decrease at the neck as the test continues
• Fracture occurs at the neck
• Fracture surfaces give cup & cone
appearance
V SIVAHAR / LEVEL 1 / MT 101 68
TOUGHNESS
• Work done during the deformation of a
material is stored in the form of strain
energy
• Strain energy absorbed by a material up
to fracture is defined as toughness
• Toughness can also be defined as the
work done at fracture
V SIVAHAR / LEVEL 1 / MT 101 69
TOUGHNESS
• Area under the σ-ε diagram is a measure
of toughness [cross hatched area]
ε
σ
σ
ε
V SIVAHAR / LEVEL 1 / MT 101 70
TOUGHNESS
• The above σ-ε diagrams show that
ductile materials have greater
toughness than brittle materials
• Toughness can also be measured by
performing Impact Test
V SIVAHAR / LEVEL 1 / MT 101 71
IMPACT TEST
• Impact test employs a notched specimen
as shown
IMPACT LOAD
[applied by a swinging pendulum]
V SIVAHAR / LEVEL 1 / MT 101 72
IMPACT TEST
M 1
2
SPECIMEN
PIVOT
PENDULUM
h
H
V SIVAHAR / LEVEL 1 / MT 101 73
IMPACT TEST
• Energy of pendulum
– At position ‘1’ = MgH + 0
– At position ‘2’ = Mgh + 0
• Energy change = Mg(H-h)
• This is the toughness of the material used
V SIVAHAR / LEVEL 1 / MT 101 74
DUCTILE-BRITTLE TRANSITION
• Whether a material is ductile or brittle
depends on the temperature
• Ductile materials show brittle behavior as
the temperature is lowered
• This is known as ductile-brittle transition
• Ductile-brittle transition behavior of
materials is studied by performing impact
test over a range of temperatures
V SIVAHAR / LEVEL 1 / MT 101 75
DUCTILE-BRITTLE TRANSITION
TEMPERATURE 0C
STEEL [BCC] ENERGY
DBTT
0
DUCTILE
BRITTLE
V SIVAHAR / LEVEL 1 / MT 101 76
DUCTILE-BRITTLE TRANSITION
TEMPERATURE 0C
COPPER [FCC] ENERGY
0
DUCTILE
BRITTLE
V SIVAHAR / LEVEL 1 / MT 101 77
DUCTILE-BRITTLE TRANSITION
• In BCC metals like steel, a sudden change
in behavior is observed over a narrow
range of temperature.
• Ductile-Brittle Transition Temperature
(DBTT) is the middle value of this
temperature range
• In FCC metals like copper the change is
gradual
V SIVAHAR / LEVEL 1 / MT 101 78
HARDNESS
• Hardness of metals [and some other
materials] is defined as the resistance
for indentation
• Hardness of metals is measured by
indentation test
• Hardness of brittle materials is defined as
resistance to scratching
• Brittle material hardness is measured
using Moh’s scale
V SIVAHAR / LEVEL 1 / MT 101 79
HARDNESS OF METALS
• In the indentation test the metal is subject
to indentation with a hard indenter as
shown. Depth of indentation is the
measure of hardness
F
INDENTER
HARD SOFT
V SIVAHAR / LEVEL 1 / MT 101 80
HARDNESS OF METALS
• Hardness units differ depending on the
type of indenter used and the load
applied
1. Brinell (HB)
 10mm diameter steel / WC ball indenter
 Any load ‘P’ can be applied
 Diameter ‘d’ of the indentation is measured
in place of the depth
V SIVAHAR / LEVEL 1 / MT 101 81
HARDNESS OF METALS
 
2
2
2
d
D
D
D
P
HB




P
INDENTER
d
D = 10mm
V SIVAHAR / LEVEL 1 / MT 101 82
2. Vickers (HV)
 Pyramid shaped indenter made of diamond
is used
 Any load ‘P’ can be applied
 Diagonal lengths d1 and d2 of the diamond-
shape indentation are measured
 Average d = (d1+d2)/2 is used in the
calculation
HARDNESS OF METALS
V SIVAHAR / LEVEL 1 / MT 101 83
HARDNESS OF METALS
2
2
854
.
1
2
136
sin
2
d
P
d
P
HV


d2
P
INDENTER
d1
θ = 1360
V SIVAHAR / LEVEL 1 / MT 101 84
HARDNESS OF METALS
3. Rockwell
1. Rockwell A, C & D – these 3 units use cone
shaped indenter made of diamond
 HRA – 60 kg
 HRD – 100 kg
 HRC – 150 kg
V SIVAHAR / LEVEL 1 / MT 101 85
HARDNESS OF METALS
2. Rockwell B, F & G – these 3 units use 1/16”
diameter (1.5mm approx.) ball made of steel
/ WC
 HRF – 60 kg
 HRB – 100 kg
 HRG – 150 kg
3. Rockwell E – uses 1/8” diameter (3mm
approximately) ball
 100 kg - HRE
V SIVAHAR / LEVEL 1 / MT 101 86
HARDNESS OF OTHER
MATERIALS
Hardness of brittle materials like
ceramics is measured using Moh’s
scale. In this scale 10 hardness
numbers are given to ten standard
materials. Hardness of the given
material is given relative to the hardness
numbers of these materials.
V SIVAHAR / LEVEL 1 / MT 101 87
MOH’S SCALE
1. Talc
2. Gypsum
3. Calcite
4. Fluorite
5. Apatite
6. Orthoclase
7. Quartz
8. Topaz
9. Corundum
10.Diamond

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Lecture Presentation (2).ppt

  • 1. V SIVAHAR / LEVEL 1 / MT 101 1 PHASE DIAGRAMS Alloy: An alloy is a metallic material consisting of two or more elements. The principal element is generally a metal the other elements can be metallic or non-metallic elements. e.g. Steel (Fe + C)
  • 2. V SIVAHAR / LEVEL 1 / MT 101 2 PHASE DIAGRAMS Alloys can be formed in three different ways. 1. Interstitial Solid Solution (ISS) 2. Substitutional Solid Solution (SSS) 3. Intermediate Compounds
  • 3. V SIVAHAR / LEVEL 1 / MT 101 3 PHASE DIAGRAMS Interstitial Solid Solution e.g. C in Fe Solvent atoms (Fe) Solute atoms (C)
  • 4. V SIVAHAR / LEVEL 1 / MT 101 4 PHASE DIAGRAMS Substitutional Solid Solution e.g. Zn in Cu Solvent atoms (Cu) Solute atoms (Zn)
  • 5. V SIVAHAR / LEVEL 1 / MT 101 5 PHASE DIAGRAMS Intermediate Compound e.g. Fe3C •Intermediate compounds have fixed compositions. •Find the weight percentage of carbon in Fe3C. (Ans : 6.67%) •If both the elements are metals it is known as an Intermetallic Compound. E.g. CuAl2
  • 6. V SIVAHAR / LEVEL 1 / MT 101 6 PHASE DIAGRAMS Phase A state in which a material can exist. E.g. water can exist in solid (ice), liquid (water) and gaseous (steam) phases. • Existence of particular phase depends on temperature and pressure. • The factors temperature and pressure are known as the variables.
  • 7. V SIVAHAR / LEVEL 1 / MT 101 7 PHASE DIAGRAMS • In an alloy, composition becomes the third variable. PHASE DIAGRAM Phase diagram is a graphical representation of the phases present in a material system under different conditions.
  • 8. V SIVAHAR / LEVEL 1 / MT 101 8 PHASE DIAGRAM – PURE WATER
  • 9. V SIVAHAR / LEVEL 1 / MT 101 9 PHASE DIAGRAM – PURE IRON 1539 0C 1394 0C 910 0C P atm T0C α – IRON (BCC) γ – IRON (FCC) δ – IRON (BCC) LIQUID VAPOR
  • 10. V SIVAHAR / LEVEL 1 / MT 101 10 BINARY ALLOY PHASE DIAGRAMS • Alloys containing two elements are known as binary alloys. E.g.: Steel (Fe + C) • Binary alloy phase diagrams are obtained for Temperature and Composition while maintaining the pressure constant – usually 1 atm
  • 11. V SIVAHAR / LEVEL 1 / MT 101 11 BINARY ALLOY PHASE DIAGRAMS • Binary alloy phase diagrams are considered under 3 different categories: 1. Complete solubility in solid state 2. Complete insolubility in solid state 3. Partial solubility in solid state
  • 12. V SIVAHAR / LEVEL 1 / MT 101 12 Complete solubility Line 1 T 0C TB LIQUID liquidus L + α solidus TA α 100A 50A 0A 0B 50B 100B
  • 13. V SIVAHAR / LEVEL 1 / MT 101 13 Complete solubility • Microstructural changes along line 1 LIQUID α
  • 14. V SIVAHAR / LEVEL 1 / MT 101 14 Complete insolubility 1 2 3 T 0C TB LIQUID TA L + A L + B TE E A + B 100A 50A 0A 0B 50B 100B
  • 15. V SIVAHAR / LEVEL 1 / MT 101 15 Complete insolubility • At point E along line 2 LIQUID A + B Such a transformation is known as eutectic transformation. E is known as the eutectic point and TE is known as eutectic temperature.
  • 16. V SIVAHAR / LEVEL 1 / MT 101 16 Complete insolubility LINE 2 LIQUID B A
  • 17. V SIVAHAR / LEVEL 1 / MT 101 17 Complete insolubility LINE 1 B A LIQUID
  • 18. V SIVAHAR / LEVEL 1 / MT 101 18 Complete insolubility LINE 3 B A LIQUID
  • 19. V SIVAHAR / LEVEL 1 / MT 101 19 Partial solubility 1 2 3 4 5 6 7 T 0C TB LIQUID TA L + α L + β TE α β E α + β 100A 50A 0A 0B 50B 100B
  • 20. V SIVAHAR / LEVEL 1 / MT 101 20 Partial solubility LINE 4 LIQUID β α
  • 21. V SIVAHAR / LEVEL 1 / MT 101 21 Partial solubility LINE 3 β α LIQUID
  • 22. V SIVAHAR / LEVEL 1 / MT 101 22 Partial solubility LINE 5 β α LIQUID
  • 23. V SIVAHAR / LEVEL 1 / MT 101 23 Partial solubility LIQUID α LINE 1
  • 24. V SIVAHAR / LEVEL 1 / MT 101 24 Partial solubility LIQUID β LINE 7
  • 25. V SIVAHAR / LEVEL 1 / MT 101 25 Partial solubility LINE 2 LIQUID α α β
  • 26. V SIVAHAR / LEVEL 1 / MT 101 26 Partial solubility LIQUID β LINE 6 β α
  • 27. V SIVAHAR / LEVEL 1 / MT 101 27 Lever rule • Lever rule is used to find the proportions of the phases present in a two-phase region 30B 45B 65B Liquid L+α α 70A 55A 35A X Y T
  • 28. V SIVAHAR / LEVEL 1 / MT 101 28 Lever rule • Find the relative proportions of liquid and α phases at the temperature T for an alloy of 55%A + 45%B   1 Y % X L%      % 43 % 35 15 100 % % 57 % 35 20 100 L%          35 % 100 15 α% 20 L% Y X % 100 X α% Y L% 1 equation From        2 100% % L%   
  • 29. V SIVAHAR / LEVEL 1 / MT 101 29 Lever rule • What are the compositions of the liquid and α phases at this temperature? Answer: • Liquid phase – 70A+30B • α phase – 35A+65B
  • 30. V SIVAHAR / LEVEL 1 / MT 101 30 MECHANICAL PROPERTIES • Reaction of materials to the action of external stresses is indicated as mechanical properties A F ] [ 2 Pa m N A F Stress  
  • 31. V SIVAHAR / LEVEL 1 / MT 101 31 MECHANICAL PROPERTIES • Application of a stress causes a material to deform. A stress as shown below elongates the material. Elongation (or contraction), when expressed per unit length is known as strain. l0 e 0 l e Strain  
  • 32. V SIVAHAR / LEVEL 1 / MT 101 32 MECHANICAL PROPERTIES (Uniaxial) Tensile Stress (Uniaxial) Compressive Stress
  • 33. V SIVAHAR / LEVEL 1 / MT 101 33 MECHANICAL PROPERTIES • Mechanical properties of a material is studied by performing tensile test. Tensile test employs a specimen as shown below. l0 do lo – Gauge length do – Initial diameter Ao – Initial area 4 2 d Ao  
  • 34. V SIVAHAR / LEVEL 1 / MT 101 34 MECHANICAL PROPERTIES • The specimen will be subjected to a progressively increasing tensile force until it fractures.
  • 35. V SIVAHAR / LEVEL 1 / MT 101 35 MECHANICAL PROPERTIES • From the test, Force-Extension curve is obtained. e F
  • 36. V SIVAHAR / LEVEL 1 / MT 101 36 MECHANICAL PROPERTIES • Force-Extension curve is then converted to a Stress-Strain [σ-ε] diagram. ε σ
  • 37. V SIVAHAR / LEVEL 1 / MT 101 37 MECHANICAL PROPERTIES • Form of Stress-Strain [σ-ε] diagram of Cu, Al etc. ε σ UTS YS FS UTS – Ultimate Tensile Strength YS – Yield Stress FS – Fracture Stress
  • 38. V SIVAHAR / LEVEL 1 / MT 101 38 MECHANICAL PROPERTIES • Form of Stress-Strain [σ-ε] diagram of steel ε σ UTS UYS LYS FS UTS – Ultimate Tensile Strength UYS – Upper Yield Stress LYS – Lower Yield Stress FS – Fracture Stress
  • 39. V SIVAHAR / LEVEL 1 / MT 101 39 Stress-Strain Diagram Steel
  • 40. V SIVAHAR / LEVEL 1 / MT 101 40 MECHANICAL PROPERTIES • Form of Stress-Strain [σ-ε] diagram for glass, diamond, cast iron, ceramics etc. ε σ FS FS – Fracture Stress
  • 41. V SIVAHAR / LEVEL 1 / MT 101 41 MECHANICAL PROPERTIES • Form of Stress-Strain [σ-ε] diagram for a plastic ε σ
  • 42. V SIVAHAR / LEVEL 1 / MT 101 42 MECHANICAL PROPERTIES • Form of Stress-Strain [σ-ε] diagram for rubber ε σ
  • 43. V SIVAHAR / LEVEL 1 / MT 101 43 ELASTICITY • All materials show temporary deformation to a certain extent • Such a deformation is known as elastic deformation • Property of possessing elastic deformation is known as elasticity • Elasticity of most of the materials gives a straight line in the σ-ε diagram – known as linear elastic materials
  • 44. V SIVAHAR / LEVEL 1 / MT 101 44 ELASTICITY • For linear elastic materials • E is known as Elastic modulus or Young’s modulus • E of steel is 2 x 1011Pa Eε σ ; ε σ   ε σ
  • 45. V SIVAHAR / LEVEL 1 / MT 101 45 ELASTICITY • Elasticity of some other materials does not give a straight line in the σ-ε diagram – known as non-linear elastic materials - rubber • Elasticity in materials is due to the stretching of atomic bonds. ε σ
  • 46. V SIVAHAR / LEVEL 1 / MT 101 46 PLASTICITY • The deformation becomes permanent beyond a certain stress level in metals • It known as plastic deformation and the property is known as plasticity • Plastic deformation begins at the yield stress. • Plastic deformation facilitates solid-state fabrication in metals ε σ
  • 47. V SIVAHAR / LEVEL 1 / MT 101 47 PLASTICITY • Plastic deformation in metals occurs due to a phenomenon known as slip [relative displacement of atomic planes] ε σ
  • 48. V SIVAHAR / LEVEL 1 / MT 101 48 PLASTICITY • Slip is favored by the movement of dislocations ε σ
  • 49. V SIVAHAR / LEVEL 1 / MT 101 49 PLASTICITY ε σ
  • 50. V SIVAHAR / LEVEL 1 / MT 101 50 PLASTICITY • Movement of dislocations and slip occurs on close packed planes in close packed directions • In FCC metals slip takes place on (111) plane in [110] direction • In BCC metals slip takes place on (110) plane in [111] direction ε σ
  • 51. V SIVAHAR / LEVEL 1 / MT 101 51 PLASTICITY ε σ Atoms are packed more closer in (111) of FCC Slip occurs more favorably in FCC structures (110) BCC (111) FCC
  • 52. V SIVAHAR / LEVEL 1 / MT 101 52 ε σ DUCTILE &BRITTLE MATERIALS • Ductile materials – materials that exhibit plastic deformation – most metals are ductile • Brittle materials – materials that do not have plasticity – glass, cast iron ε σ
  • 53. V SIVAHAR / LEVEL 1 / MT 101 53 DUCTILITY • Ability of a metal to undergo plastic deformation is defined as ductility • Plastic strain at fracture εpf is a measure of ductility ε σ εpf
  • 54. V SIVAHAR / LEVEL 1 / MT 101 54 DUCTILITY • Ductility of copper is greater than that of steel ε σ
  • 55. V SIVAHAR / LEVEL 1 / MT 101 55 DUCTILITY • Ductility can also be measured by I. Percentage elongation II. Percentage reduction in area % 100   o o f l l l % 100   o f o A A A
  • 56. V SIVAHAR / LEVEL 1 / MT 101 56 DUCTILITY • Example • Why ductility of copper is greater than that of steel at room temperature? Note: • Brittleness is the property that is opposite to ductility
  • 57. V SIVAHAR / LEVEL 1 / MT 101 57 STRENGTH • Ability of a material to withstand the applied stresses without failure is defined as strength [Maximum stress that can be applied on a material] • Strength of a brittle material is given by it’s fracture stress ε σ FS
  • 58. V SIVAHAR / LEVEL 1 / MT 101 58 STRENGTH • Yield stress is considered as the strength for a ductile material • UTS is not considered, since significant plastic deformation takes place before UTS is reached
  • 59. V SIVAHAR / LEVEL 1 / MT 101 59 STRENGTH ε σ UTS YS FS Strength of steel 227MPa
  • 60. V SIVAHAR / LEVEL 1 / MT 101 60 PROOF STRESS • Proof stress is defined as the stress required to cause a certain amount of plastic strain. • E.g. : 0.1% Proof stress is the stress at a plastic strain of 0.1% or 0.001 • Following diagram demonstrates the method to find 0.1% Proof Stress
  • 61. V SIVAHAR / LEVEL 1 / MT 101 61 PROOF STRESS ε σ 0.001 0.1% PROOF STRESS
  • 62. V SIVAHAR / LEVEL 1 / MT 101 62 WORK HARDENING • Stress required for plastic deformation increase continuously up to the UTS. This phenomenon is known as work hardening. • Work hardening increases the strength and hardness while decreasing the ductility and toughness. • Effect of work hardening on strength is demonstrated by a tensile test as follows
  • 63. V SIVAHAR / LEVEL 1 / MT 101 63 WORK HARDENING ε σ SPECIMEN UNLOADED B P P F O YS2 YS1 Test stopped at B and the specimen is unloaded It is then reloaded The new σ-ε diagram is PBF This shows that the strength has increased from YS1 to YS2
  • 64. V SIVAHAR / LEVEL 1 / MT 101 64 WORK HARDENING Mechanism: • During plastic deformation dislocations not only move but also multiply. • Increased number of dislocations increases dislocation interactions within themselves as well as with external factors such as grain boundaries
  • 65. V SIVAHAR / LEVEL 1 / MT 101 65 WORK HARDENING Mechanism [contd…]: • This increases the resistance for the movement of dislocations in the metal. • As a result stress required for plastic deformation continue to increase
  • 66. V SIVAHAR / LEVEL 1 / MT 101 66 NECKING • At the UTS a localized deformation begins in the specimen • This localized deformation is called necking
  • 67. V SIVAHAR / LEVEL 1 / MT 101 67 NECKING • The area of cross-section continue to decrease at the neck as the test continues • Fracture occurs at the neck • Fracture surfaces give cup & cone appearance
  • 68. V SIVAHAR / LEVEL 1 / MT 101 68 TOUGHNESS • Work done during the deformation of a material is stored in the form of strain energy • Strain energy absorbed by a material up to fracture is defined as toughness • Toughness can also be defined as the work done at fracture
  • 69. V SIVAHAR / LEVEL 1 / MT 101 69 TOUGHNESS • Area under the σ-ε diagram is a measure of toughness [cross hatched area] ε σ σ ε
  • 70. V SIVAHAR / LEVEL 1 / MT 101 70 TOUGHNESS • The above σ-ε diagrams show that ductile materials have greater toughness than brittle materials • Toughness can also be measured by performing Impact Test
  • 71. V SIVAHAR / LEVEL 1 / MT 101 71 IMPACT TEST • Impact test employs a notched specimen as shown IMPACT LOAD [applied by a swinging pendulum]
  • 72. V SIVAHAR / LEVEL 1 / MT 101 72 IMPACT TEST M 1 2 SPECIMEN PIVOT PENDULUM h H
  • 73. V SIVAHAR / LEVEL 1 / MT 101 73 IMPACT TEST • Energy of pendulum – At position ‘1’ = MgH + 0 – At position ‘2’ = Mgh + 0 • Energy change = Mg(H-h) • This is the toughness of the material used
  • 74. V SIVAHAR / LEVEL 1 / MT 101 74 DUCTILE-BRITTLE TRANSITION • Whether a material is ductile or brittle depends on the temperature • Ductile materials show brittle behavior as the temperature is lowered • This is known as ductile-brittle transition • Ductile-brittle transition behavior of materials is studied by performing impact test over a range of temperatures
  • 75. V SIVAHAR / LEVEL 1 / MT 101 75 DUCTILE-BRITTLE TRANSITION TEMPERATURE 0C STEEL [BCC] ENERGY DBTT 0 DUCTILE BRITTLE
  • 76. V SIVAHAR / LEVEL 1 / MT 101 76 DUCTILE-BRITTLE TRANSITION TEMPERATURE 0C COPPER [FCC] ENERGY 0 DUCTILE BRITTLE
  • 77. V SIVAHAR / LEVEL 1 / MT 101 77 DUCTILE-BRITTLE TRANSITION • In BCC metals like steel, a sudden change in behavior is observed over a narrow range of temperature. • Ductile-Brittle Transition Temperature (DBTT) is the middle value of this temperature range • In FCC metals like copper the change is gradual
  • 78. V SIVAHAR / LEVEL 1 / MT 101 78 HARDNESS • Hardness of metals [and some other materials] is defined as the resistance for indentation • Hardness of metals is measured by indentation test • Hardness of brittle materials is defined as resistance to scratching • Brittle material hardness is measured using Moh’s scale
  • 79. V SIVAHAR / LEVEL 1 / MT 101 79 HARDNESS OF METALS • In the indentation test the metal is subject to indentation with a hard indenter as shown. Depth of indentation is the measure of hardness F INDENTER HARD SOFT
  • 80. V SIVAHAR / LEVEL 1 / MT 101 80 HARDNESS OF METALS • Hardness units differ depending on the type of indenter used and the load applied 1. Brinell (HB)  10mm diameter steel / WC ball indenter  Any load ‘P’ can be applied  Diameter ‘d’ of the indentation is measured in place of the depth
  • 81. V SIVAHAR / LEVEL 1 / MT 101 81 HARDNESS OF METALS   2 2 2 d D D D P HB     P INDENTER d D = 10mm
  • 82. V SIVAHAR / LEVEL 1 / MT 101 82 2. Vickers (HV)  Pyramid shaped indenter made of diamond is used  Any load ‘P’ can be applied  Diagonal lengths d1 and d2 of the diamond- shape indentation are measured  Average d = (d1+d2)/2 is used in the calculation HARDNESS OF METALS
  • 83. V SIVAHAR / LEVEL 1 / MT 101 83 HARDNESS OF METALS 2 2 854 . 1 2 136 sin 2 d P d P HV   d2 P INDENTER d1 θ = 1360
  • 84. V SIVAHAR / LEVEL 1 / MT 101 84 HARDNESS OF METALS 3. Rockwell 1. Rockwell A, C & D – these 3 units use cone shaped indenter made of diamond  HRA – 60 kg  HRD – 100 kg  HRC – 150 kg
  • 85. V SIVAHAR / LEVEL 1 / MT 101 85 HARDNESS OF METALS 2. Rockwell B, F & G – these 3 units use 1/16” diameter (1.5mm approx.) ball made of steel / WC  HRF – 60 kg  HRB – 100 kg  HRG – 150 kg 3. Rockwell E – uses 1/8” diameter (3mm approximately) ball  100 kg - HRE
  • 86. V SIVAHAR / LEVEL 1 / MT 101 86 HARDNESS OF OTHER MATERIALS Hardness of brittle materials like ceramics is measured using Moh’s scale. In this scale 10 hardness numbers are given to ten standard materials. Hardness of the given material is given relative to the hardness numbers of these materials.
  • 87. V SIVAHAR / LEVEL 1 / MT 101 87 MOH’S SCALE 1. Talc 2. Gypsum 3. Calcite 4. Fluorite 5. Apatite 6. Orthoclase 7. Quartz 8. Topaz 9. Corundum 10.Diamond