Mathematical description of Legendre Functions.
Presentation at Undergraduate in Science (math, physics, engineering) level.
Please send any comments or suggestions to improve to solo.hermelin@gmail.com.
More presentations can be found on my website at http://www.solohermelin.com.
Gamma Function mathematics and history.
Please send comments and suggestions for improvements to solo.hermelin@gmail.com. Thanks.
More presentations on different subjects can be found on my website at http://www.solohermelin.com.
Mathematical description of Legendre Functions.
Presentation at Undergraduate in Science (math, physics, engineering) level.
Please send any comments or suggestions to improve to solo.hermelin@gmail.com.
More presentations can be found on my website at http://www.solohermelin.com.
Gamma Function mathematics and history.
Please send comments and suggestions for improvements to solo.hermelin@gmail.com. Thanks.
More presentations on different subjects can be found on my website at http://www.solohermelin.com.
The purpose of this work is to formulate and investigate a boundary integral method for the solution of the internal waves/Rayleigh-Taylor problem. This problem describes the evolution of the interface between two immiscible, inviscid, incompressible, irrotational fluids of different density in three dimensions. The motion of the interface and fluids is driven by the action of a gravity force, surface tension at the interface, elastic bending and/or a prescribed far-field pressure gradient. The interface is a generalized vortex sheet, and dipole density is interpreted as the (unnormalized) vortex sheet strength. Presence of the surface tension or elastic bending effects introduces high order derivatives into the evolution equations. This makes the considered problem stiff and the application of the standard explicit time-integration methods suffers strong time-step stability constraints.
The proposed numerical method employs a special interface parameterization that enables the use of an efficient implicit time-integration method via a small-scale decomposition. This approach allows one to capture the nonlinear growth of normal modes for the case of Rayleigh-Taylor instability with the heavier fluid on top.
Validation of the results is done by comparison of numeric solution to the analytic solution of the linearized problem for a short time. We check the energy and the interface mean height preservation. The developed model and numerical method can be efficiently applied to study the motion of internal waves for doubly periodic interfacial flows with surface tension and elastic bending stress at the interface.
Singularities in the one control problem. S.I.S.S.A., Trieste August 16, 2007.Igor Moiseev
Singularities in the one control problem. S.I.S.S.A., Trieste August 16, 2007.
The geometry of strokes arises in the control problems of Reeds–Shepp car, Dubins’ car, modeling of vision and some others. The main problem is to characterize the shortest paths and minimal distances on the plane, equipped with the structure of geometry of strokes.
This problem is formulated as an optimal control problem in 3-space with 2 dimensional control and a quadratic integral cost. Here is studied the symmetries of the sub-Riemannian structure, extremals of the optimal control problem, the Maxwell stratum, conjugate points and boundary value problem for the corresponding Hamiltonian system.
NITheP UKZN Seminar: Prof. Alexander Gorokhov (Samara State University, Russi...Rene Kotze
NITheP UKZN Seminar: Prof. Alexander Gorokhov (Samara State University, Russia)
TITLE: Dynamical Groups, Coherent States and Some of their Applications in Quantum Optics and Molecular Spectroscopy
21st Mediterranean Conference on Control and Automation
The present paper is a survey on linear multivariable systems equivalences. We attempt a review of the most significant types of system equivalence having as a starting point matrix transformations preserving certain types of their spectral structure. From a system theoretic point of view, the need for a variety of forms of polynomial matrix equivalences, arises from the fact that different types of spectral invariants give rise to different types of dynamics of the underlying linear system. A historical perspective of the key results and their contributors is also given.
Mathematics (from Greek μάθημα máthēma, “knowledge, study, learning”) is the study of topics such as quantity (numbers), structure, space, and change. There is a range of views among mathematicians and philosophers as to the exact scope and definition of mathematics
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Palestine last event orientationfvgnh .pptxRaedMohamed3
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Instructions for Submissions thorugh G- Classroom.pptxJheel Barad
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Synthetic Fiber Construction in lab .pptxPavel ( NSTU)
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdfTechSoup
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
2. 5.1 Expected Value of a function of R.Vs
• If g(x,y) is function of two r.v.s X and Y , then the expected value
of g is:
• Note that the expected value of a jam of functions is equal to the
sum of the expected values of the functions:
4. 5.1.1 Joint Moments about the origin:
4
Notes:
1. mn0= E[ Xn
] are the moments of X, m0k are the moments of Y.
2. The sum n+k is called the order of the moments.
Thus, m02 ,m20 m11 are called second order moments of X and Y.
3. m10 = E[X] and m01 = E[Y] are the expected values of X and Y,
respectively, and are the coordinators of the "center of gravity" of
the function fXY(x,y).
5. 5.1.1 Joint Moments about the origin:
Correlation: The second-order moment m11 = E[XY] is called the
correlation of X and Y. In fact, it is a very important statistic and
denoted by RXY.
- If RXY = E[X] E[Y] ,then X and Y are said to be uncorrelated.
- If X and Y are independent ,then fXY(x,y) = fX(x) fY(y) and
6. 5.1.1 Joint Moments about the origin:
• Therefore, if X and Y are independent they are⇒
uncorrelated.
• However, if X and Y are uncorrelated, it is not necessary
that they are independent.
• If RXY = 0 then X and Y are called orthogonal.
6
7.
8. 5.1.2 Joint Central Moments:
• Covariance: The second order joint moment u11 is called the
covariance of X and Y and denoted by CXY
8
10. 5.1.2 Joint Central Moments:
10
• The normalized second-order moment ρ
is known as the correlation coefficient of X and Y.
11.
12. 5.2 Joint characteristic Functions:
12
Where w1and w2 are real numbers.
- By setting w1= 0 or w2 = 0, we obtain the marginal
characteristic function.
The joint characteristic function of two r.v.s X and Y is defined
by
13. Joint moments are obtained as :
13
Joint moments mnk can be found from the joint characteristic
function as follows:
14.
15. 5.3 Jointly Gaussian Random Variables
• Two random variables are jointly Gaussian if their joint
density function is of the form (sometimes called bivariate
Gaussian)
15
17. 17
Jointly Gaussian Random Variables
• The locus of constant values of fXY(x,y) will be an ellipse.
• This is equivalent to saying that the line of intersection formed by
slicing the function fXY(x,y) with a plane parallel to the xy plane is an
ellipse.
18. 18
Jointly Gaussian Random Variables
Where fX(x) and fY(y) are the marginal density functions of X and Y.
,0 ( , ) ( ) ( )X Y X Yf x y f x f yρ = ⇒ =
jointly gaussian & uncorr. indep.⇒
19. • Consider r.v.s Y1 and Y2 related to arbitrary r.v.s X and Y by the
coordinate relation
19
Jointly Gaussian Random Variables
1 cos sinY X Yθ θ= +
2 sin cosY X Yθ θ= − +
1 2, 1 1 2 2[( )( )]Y YC E Y Y Y Y= − −
[{( )cos ( )sin }{ ( )sin ( )cos }]E X X Y Y X X Y Yθ θ θ θ= − + − − − + −
20. 20
Jointly Gaussian Random Variables
2 2 2 2
( )sin cos [cos sin ]Y X XYCσ σ θ θ θ θ= − + −
2 2 2 21 1
( )sin 2 cos2 ( )sin 2 cos2
2 2
Y X XY Y X X YCσ σ θ θ σ σ θ ρσ σ θ= − + = − +
1 2
1
, 2 2
21
0 tan
2
X Y
Y Y
X Y
C
ρσ σ
θ
σ σ
−
= ⇒ = −
• From correlation coefficient.,
• If we require Y1 and Y2 to be uncorrelated, we must have CY1Y2=0.
by equating the above equation to zero we get.,
21. N Random variables
21
• N random variables are jointly Gaussian if their joint density
function is of the form (sometimes called multivariate
Gaussian)
23. 23
Jointly Gaussian Random Variables
Uncorrelated Gaussian random variables are also statistically
independent.
Other properties of Gaussian r.v.s include:
• Gaussian r.v.s are completely defined through their 1st- and 2nd-
order moments, i.e., their means, variances, and covariance's.
• Random variables produced by a linear transformation of jointly
Gaussian r.v.s are also Gaussian.
• The conditional density functions defined over jointly Gaussian r.v.s
is also Gaussian.
There fore we conclude that any uncorrelated Gaussian
random variables are also statistically independent.
It results that a coordinate rotation through an angle
24. Transformations of Multiple Random Variables
24
One function
1 2( , )Y g X X=
1 2, 1 2( , )X Xf x x
1 2
1 2
1 2 , 1 2 1 2
( , )
( ) [ ( , ) ] ( , )Y X X
g x x y
F y P g X X y f x x dx dx
≤
= ≤ = ∫∫
( )
( ) Y
Y
dF y
f y
dy
=
25. 25
1 2positive r.v.'s &X X
2
1 2
1
, 1 2 1 20 0
2
( ) [ ] ( , )
yx
Y X X
X
F y P y f x x dx dx
X
∞
= ≤ = ∫ ∫ 0y >
Transformations of Multiple Random Variables
1 22 , 2 2 20
( )
( ) ( , )Y
Y X X
dF y
f y x f yx x dx
dy
∞
= = ∫ 0y >
Example 1: find the density function for 1
2
X
Y
X
=
26. Transformations of Multiple Random Variables
• Multiple functions
Yi= Ti (X1, X2, X3…………XN)., i =1,2,3……….N
26
1 1 1 2
1 2
2 2 1 2
( , )
( , )
( , )
Y T X X
T X X
Y T X X
= =
1
1 1 1 21
1 2 1
2 2 1 2
( , )
( , )
( , )
x T y y
T y y
x T y y
−
−
−
= =
1 2 1 2, 1 2 , 1 2( , ) ( , )Y Y X Xf y y f x x J=
1 1
1 1
1 2
1 1
2 2
1 2
T T
y y
J
T T
y y
− −
− −
∂ ∂
∂ ∂
=
∂ ∂
∂ ∂
jacobian
27. Transformations of Multiple Random Variables
27
1 2
1 2
1 2 1 2
,
, 1 2
( , )
( , )
X X
Y Y
dy by cy ay
f
ad bc ad bcf y y
ad bc
− − +
− −=
−
1
1 1 1 2 11
1 2 1
2 22 1 2
( , ) 1
( , )
( , )
x T y y yd b
T y y
x c a yad bcT y y
−
−
−
−
= = = −−
1 1
1 1
1 2
1 1
2 2
1 2
1
T T
y y
J
ad bcT T
y y
− −
− −
∂ ∂
∂ ∂
= =
−∂ ∂
∂ ∂
1 1 1 2 1 2 1
1 2
2 2 1 2 1 2 2
( , )
( , )
( , )
Y T X X aX bX Xa b
T X X
Y T X X cX dX c d X
+
= = = = +
Example :
28. 28
Linear Transformations of Gaussian Random Variables
1 1 11 12
21 222 2
Y X a a
Y A AX X
a aY X
= = = =
[ ] [ ] [ ]E Y E AX AE X= =
[( )( ) ] [ ( )( ) ]T T T
YC E Y Y Y Y E A X X X X A= − − = − −
[( )( ) ]T T T
XAE X X X X A AC A= − − = 1 1 1T
Y XC A C A− − − −
⇒ =
1
1 2
1
( ) ( )
2
, 1 2 1/2/2
1
( , )
(2 )
T
Xx X C x X
X X N
X
f x x e
Cπ
−
− − −
=
1 2, 1 2( , ) ?Y Yf y y =
2
det( ) det( ) det( )Y XC A C=
29. 29
5.5 Linear Transformations of
Gaussian Random Variables
1 1 11
( ) ( )
2
1/2/2
1
(2 ) det( )
T
XA y X C A y X
N
X
e
C Aπ
− − −
− − −
=
1 2 1 2
1
, 1 2 ,
1
( , ) ( )
det( )
Y Y X Xf y y f A y
A
−
=
1 1 1 1 1
( ) ( ) ( ) ( )T T T
X XA y X C A y X y Y A C A y Y− − − − − −
− − = − −
1
( ) ( )T
Yy Y C y Y−
= − −
1
1 2
1
( ) ( )
2
, 1 2 1/2/2
1
( , )
(2 )
T
Yy Y C y Y
Y Y N
Y
f y y e
Cπ
−
− − −
⇒ =
1/2 1/2
det( )X YC A C=
(gaussian)
30. 30
5.5 Linear Transformations of
Gaussian Random Variables
1
1 2
1
( ) ( )
2
, 1 2 1/2
1
( , )
(2 )
T
Yy Y C y Y
Y Y
Y
f y y e
Cπ
−
− − −
⇒ =
Ex 5.5-1: 1 1 1
2 2 2
1 2
3 4
Y X X
A
Y X X
−
= =
1
2
[ ] 0
[ ] 0
E X
E X
=
4 3
3 9
XC
=
1 1
2 2
[ ] [ ] 0
[ ] [ ] 0
E Y E X
A
E Y E X
= =
1 2 4 3 1 3 28 66
3 4 3 9 2 4 66 252
T
Y XC AC A
− −
= = = − −
1 2
1 2
66
0.786
28 252
YY
Y Y
C
ρ
σ σ
−
= = = −