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CC GPS
Geometry
 Learning Objective
#34:
 Identify the steps to
the factoring process
for two terms, three
terms, and four terms
Practice Problems set 1:
(x2 – 25)
(x2 + 7x + 10)
(x3 + 7x + 2x + 14)
(x2 – 1)
(x2 – 6x + 9)
(5x4 – 15x3 + 10x2)
SOLUTIONS
(example of students response):
 (x2 – 25)
2 terms
Look for difference of 2
perfect squares
Solution is 2 binomials,
one +, one –
Square Root of the first
term in position 1,
Square Root of the
second term in position
2 for both binomials
(x + 5)(x – 5)
 (x2 – 1)
2 terms
Look for difference of 2
perfect squares
Solution is 2
binomials, one +, one –
Square Root of the first
term in position
1, Square Root of the
second term in position
2 for both binomials
(x + 1)(x – 1)
SOLUTIONS con’t
(example of students response):
 (x2 + 7x + 10)
3 terms
Identify a,b, & c from
ax2 + bx + c
Create diamond with
a •c in the North
position and b in the
South position
Find two numbers, East &
West positions, that
multiply to the North and
combine (add/subtract) to
the South
 (x + 2)(x + 5)
 (x2 – 6x + 9)
3 terms
Identify a,b, & c from
ax2 + bx + c
Create diamond with
a •c in the North
position and b in the
South position
Find two numbers, East &
West positions, that
multiply to the North and
combine (add/subtract) to
the South
 (x – 3)(x – 3)
SOLUTIONS con’t
(example of students response):
 (x3 + 7x + 2x + 14)
4 terms
Group like binomials
Find GCF for both sets
Identify matching “left
overs” for one binomial
and GCF’s for second
binomial
(x2 + 2)(x + 7)
 (5x4 – 15x3 + 10x2)
4 terms – in this case, it’s
necessary to separate
the middle term into two
terms
Group like binomials
Find GCF for both sets
Identify matching “left
overs” for one binomial
and GCF’s for second
binomial
(5x3 – 5x2)(x – 2)

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Kadieng oll mod 3 blog posting

  • 1. CC GPS Geometry  Learning Objective #34:  Identify the steps to the factoring process for two terms, three terms, and four terms
  • 2. Practice Problems set 1: (x2 – 25) (x2 + 7x + 10) (x3 + 7x + 2x + 14) (x2 – 1) (x2 – 6x + 9) (5x4 – 15x3 + 10x2)
  • 3. SOLUTIONS (example of students response):  (x2 – 25) 2 terms Look for difference of 2 perfect squares Solution is 2 binomials, one +, one – Square Root of the first term in position 1, Square Root of the second term in position 2 for both binomials (x + 5)(x – 5)  (x2 – 1) 2 terms Look for difference of 2 perfect squares Solution is 2 binomials, one +, one – Square Root of the first term in position 1, Square Root of the second term in position 2 for both binomials (x + 1)(x – 1)
  • 4. SOLUTIONS con’t (example of students response):  (x2 + 7x + 10) 3 terms Identify a,b, & c from ax2 + bx + c Create diamond with a •c in the North position and b in the South position Find two numbers, East & West positions, that multiply to the North and combine (add/subtract) to the South  (x + 2)(x + 5)  (x2 – 6x + 9) 3 terms Identify a,b, & c from ax2 + bx + c Create diamond with a •c in the North position and b in the South position Find two numbers, East & West positions, that multiply to the North and combine (add/subtract) to the South  (x – 3)(x – 3)
  • 5. SOLUTIONS con’t (example of students response):  (x3 + 7x + 2x + 14) 4 terms Group like binomials Find GCF for both sets Identify matching “left overs” for one binomial and GCF’s for second binomial (x2 + 2)(x + 7)  (5x4 – 15x3 + 10x2) 4 terms – in this case, it’s necessary to separate the middle term into two terms Group like binomials Find GCF for both sets Identify matching “left overs” for one binomial and GCF’s for second binomial (5x3 – 5x2)(x – 2)