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JEE Maths B2A (Basic to Advance)
in Tamil
Based on NCERT syllabus
Polynomial
• An expression of the form f(x) = a0xn+ a1xn-1 + a2xn-2 + ………… an-1x + an,
where n is a non negative integer and a0, a1, a2,…………… an are real
numbers and a0 ≠ 0 is called a polynomial.
• Remainder Theorem
+ If a polynomial p(x) is divided by a binomial x-a, the remainder obtained is
p(a).
+ Example: Find the remainder for p(x)=x3-4x2-7x+10 when divided with x-2.
• Factor theorem
+ If f(a)=0 for a polynomial then (x-a) is a factor of the polynomial f(x).
f(x)=(x-a) Q(x) + f(a)
Let’s JEE………
• Let P(x)=a2x2+ax-6 is divisible by (x-1) then possible value of a are:
Let’s JEE………
• If a polynomial p(x) has remainder 3 and 5 when divided by x-1 and x-2 respectively, find the
remainder when p(x) is divided by (x-1)(x-2)
Let’s JEE………
• If x5-5qx+4r is divisible by (x-2)(x-2). Find the value of q and r.
Practijeee…..
• If x-a is a factor of x3-a2x+x+2, then find the value of ‘a’.
• When a polynomial is divided by (x-2) and (x-3), remainders are 3 and 2 respectively. What is the
remainder when the same polynomial is divided by (x-2)(x-3)?
• The remainder when polynomial p(x) of degree 5 is divided by x+1 and x-1 is 1 and 2 respectively. Find
the remainder when p(x) is divided by x2-1.
• If p(x) = ax7+bx5+cx3+3 and p(7) = 2, p(-7) =?
Episode 4 – Intervals
Loading…..

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JEE Mathematics B2A in Tamil | Season 0, Episode 3 | Fundamentals of Mathematics | Polynomial

  • 1. JEE Maths B2A (Basic to Advance) in Tamil Based on NCERT syllabus
  • 2. Polynomial • An expression of the form f(x) = a0xn+ a1xn-1 + a2xn-2 + ………… an-1x + an, where n is a non negative integer and a0, a1, a2,…………… an are real numbers and a0 ≠ 0 is called a polynomial. • Remainder Theorem + If a polynomial p(x) is divided by a binomial x-a, the remainder obtained is p(a). + Example: Find the remainder for p(x)=x3-4x2-7x+10 when divided with x-2. • Factor theorem + If f(a)=0 for a polynomial then (x-a) is a factor of the polynomial f(x). f(x)=(x-a) Q(x) + f(a)
  • 3. Let’s JEE……… • Let P(x)=a2x2+ax-6 is divisible by (x-1) then possible value of a are:
  • 4. Let’s JEE……… • If a polynomial p(x) has remainder 3 and 5 when divided by x-1 and x-2 respectively, find the remainder when p(x) is divided by (x-1)(x-2)
  • 5. Let’s JEE……… • If x5-5qx+4r is divisible by (x-2)(x-2). Find the value of q and r.
  • 6. Practijeee….. • If x-a is a factor of x3-a2x+x+2, then find the value of ‘a’. • When a polynomial is divided by (x-2) and (x-3), remainders are 3 and 2 respectively. What is the remainder when the same polynomial is divided by (x-2)(x-3)? • The remainder when polynomial p(x) of degree 5 is divided by x+1 and x-1 is 1 and 2 respectively. Find the remainder when p(x) is divided by x2-1. • If p(x) = ax7+bx5+cx3+3 and p(7) = 2, p(-7) =?
  • 7. Episode 4 – Intervals Loading…..