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Block 2
Elur Niahc
What is to be learned?
• How to integrate composite functions
y = (7x + 2)5
let y= u5
where u = 7x + 2
dy
/du = 5u4 du
/dx = 7
dy
/du
du
/dx
dy
/dx =
dy
/dx
= 5u4
7
=5(7x + 2)4
7
Add 1 to
power
Chain Rule
y = (7x + 2)5
let y= u5
where u = 7x + 2
dy
/du = 5u4 du
/dx = 7
dy
/du
du
/dx
dy
/dx =
dy
/dx
= 5u4
7
Chain Rule
=5(7x + 2)4
7
÷ 5
Add 1 to
power
y = (7x + 2)5
let y= u5
where u = 7x + 2
dy
/du = 5u4 du
/dx = 7
dy
/du
du
/dx
dy
/dx =
dy
/dx
= 5u4
7
=5(7x + 2)4
7
÷ 5
÷ 7
Add 1 to
power
Chain Rule
∫ (ax + b)n
= (ax + b)n+1
(n+1)a
Elur Niahc∫ (ax + b)n
∫ (5x + 7)3
dx
dx
= (5x + 7)4
(4)5
= (5x + 7)4
20
+ c
∫ (9x + 3)6
dx
= (9x + 3)7
(7)9
= (9x + 3)7
63
+ c
∫ (5 – 4x)7
dx
= (5 – 4x)8
(8)-4
= (5 – 4x)8
32
+ c-
∫ 4(5 – 3x)5
dx
= 4(5 – 3x)6
(6)-3
= 4(5 – 3x)6
-18
+ c
= 2(5 – 3x)6
9
+ c-
∫ (ax + b)n
= (ax + b)n+1
(n+1)a
Elur Niahc
∫ (ax + b)n
∫ (3x + 8)6
dx
dx
= (3x + 8)7
(7)3
= (3x + 8)7
21
+ c
Integration 2
+ c
∫ 3(5 – 6x)8
dx
= 3(5 – 6x)9
(9)-6
= 3(5 – 6x)8
-54
+ c
Key Question
= - (5 – 6x)8
18
+ c

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Integration 2 elur niahc

  • 2. What is to be learned? • How to integrate composite functions
  • 3. y = (7x + 2)5 let y= u5 where u = 7x + 2 dy /du = 5u4 du /dx = 7 dy /du du /dx dy /dx = dy /dx = 5u4 7 =5(7x + 2)4 7 Add 1 to power Chain Rule
  • 4. y = (7x + 2)5 let y= u5 where u = 7x + 2 dy /du = 5u4 du /dx = 7 dy /du du /dx dy /dx = dy /dx = 5u4 7 Chain Rule =5(7x + 2)4 7 ÷ 5 Add 1 to power
  • 5. y = (7x + 2)5 let y= u5 where u = 7x + 2 dy /du = 5u4 du /dx = 7 dy /du du /dx dy /dx = dy /dx = 5u4 7 =5(7x + 2)4 7 ÷ 5 ÷ 7 Add 1 to power Chain Rule
  • 6. ∫ (ax + b)n = (ax + b)n+1 (n+1)a Elur Niahc∫ (ax + b)n ∫ (5x + 7)3 dx dx = (5x + 7)4 (4)5 = (5x + 7)4 20 + c
  • 7. ∫ (9x + 3)6 dx = (9x + 3)7 (7)9 = (9x + 3)7 63 + c ∫ (5 – 4x)7 dx = (5 – 4x)8 (8)-4 = (5 – 4x)8 32 + c-
  • 8. ∫ 4(5 – 3x)5 dx = 4(5 – 3x)6 (6)-3 = 4(5 – 3x)6 -18 + c = 2(5 – 3x)6 9 + c-
  • 9. ∫ (ax + b)n = (ax + b)n+1 (n+1)a Elur Niahc ∫ (ax + b)n ∫ (3x + 8)6 dx dx = (3x + 8)7 (7)3 = (3x + 8)7 21 + c Integration 2 + c
  • 10. ∫ 3(5 – 6x)8 dx = 3(5 – 6x)9 (9)-6 = 3(5 – 6x)8 -54 + c Key Question = - (5 – 6x)8 18 + c