Fatigue Failure Theories
Prepared by
Aliyi Umer ( Mechanical Design)
Center for Research and Development
Defence University, College of Engineering
Bishoftu, Ethiopia
aliyiumer@yahoo.com 1
Fatigue Failure
• Occurs when stresses are changing throughout the life
of a part.
• starts with a crack that propagates until a catastrophic
failure occurs.
• This usually begins at a manufacturing defect or
stress concentration that is subjected to tensile
stresses for part of its load cycle.
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Fatigue-Failure Models
• Stress-Life - cyclic stresses are kept below
fatigue strength or endurance limit. Most
widely used.
• Strain-Life - complicated not often used.
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3
-20000
-10000
0
10000
20000
30000
40000
0 2 4 6 8 10
AppliedStress-psi
Load Cycles
Fatigue Stresses
σa
σ
σa
σm
σm
Fully Reversed Repeated Fluctuating
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Fully Reversed Failure Criteria
• Most data comes from R. R. Moore rotating-
beam test.
• Highly polished specimen of 0.3 inches in
diameter is subjected to pure bending stresses
that are alternated by rotating the specimen.
• Rotation is at 1725 rpm.
• Takes 1/2 day to reach 106
cycles.
aliyiumer@yahoo.com 5
10000
100000
1.0E+3 10.0E+3 100.0E+3 1.0E+6 10.0E+6 100.0E+6
FatigueStrength-Sf
Cycles to Failure - N
S-N Curve for Steel with Sut = 100 ksi
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Endurance Limit and Fatigue
Strength
• Endurance Limit of a Material (Se’) - stress
below which fatigue failure does not occur
regardless of the number of stress cycles.
• ____________________Strength of a Material
(Sf’) -stress below which fatigue failure does
not occur for a specified number of stress
cycles.
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10000
100000
1.00E+03 1.00E+04 1.00E+05 1.00E+06 1.00E+07 1.00E+08 1.00E+09
FatigueStrength-psi
Cycles to Failure
Typical S-N Curve for Non-FerrousMetals
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Estimating Se’ or Sf’
• For ____________:
Se’= 0.5Sut for Sut<200 ksi (1400 MPa)
Se’= 100 ksi (700 MPa)
for Sut>200 ksi (1400 MPa)
• For ______________:
Se’= 0.4Sut for Sut<60 ksi (400 MPa)
Se’= 24 ksi (160 MPa)
for Sut>60 ksi (400 MPa)
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Estimating Se’ or Sf’ cont’d
• For __________________:
Sf’@5E8= 0.4Sutfor Sut<48 ksi (330 MPa)
Sf’@5E8= 19 ksi (130 MPa)
for Sut>330 ksi (330 MPa)
• For _____________________:
Se’= 0.4Sutfor Sut<40 ksi (280 MPa)
Se’= 14 ksi (100 MPa)
for Sut>40 ksi (280 MPa)
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Correction Factors to Endurance
Limit and Fatigue Strength
• Se = CloadCsizeCsurfCtempCreliabSe’
• Sf = CloadCsizeCsurfCtempCreliab Sf’
• Se -corrected endurance limit for a part
• Sf -corrected fatigue strength for a part
• Cload - load factor
• Csize - size factor
• Csurf- surface factor
• Ctemp - temperature factor
• Creliab- reliability factor
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Stress Concentration
• Kf = 1+q(Kt + 1)
• Kt - geometric stress concentration factor
• Kf - ___________________________
• q - notch sensitivity factor
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Fluctuating Stresses
Modified-Goodman Diagram
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Failure Lines for Fluctuating Stress
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“Augmented” Modified-Goodman
Diagram
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Stress Concentration
• Apply Kfto the ______________ components of
stress.
• For __________ materials apply Kt to the mean
components of stress.
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Stress Concentration - cont’d
• If Kf|σmaxnom
| < Sythen: Kfm = Kf
• If Kf|σmaxnom
| > Sythen:
Kfm = (Sy - Kfσanom
)/ |σmnom
|
• If Kf|σmaxnom
- σminnom
| < 2Sythen: Kfm = 0
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Factor of Safety for Fluctuating Stress - Case
1
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Factor of Safety for Fluctuating Stress - Case 2
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Factor of Safety for Fluctuating Stress - Case 3
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Factor of Safety for Fluctuating Stress - Case 3
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Factor of Safety for Fluctuating Stress -
Case 4
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Factor of Safety for Fluctuating Stress - Case 4
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Fluctuating Stresses
Multiaxial Stresses in Fatigue
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Fully Reversed Simple Multiaxial
Stresses
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Fluctuating Simple Multiaxial Stresses
• Von Mises Method
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General Approach to High Cycle
Fatigue Design
• Generate Modified Goodman Diagram
• Calculate alternating and mean components of stress
at areas of concern on the part. Include appropriate
stress concentration factors.
• Convert alternating and mean applied stresses to
alternating and mean Von Mises Stresses.
• Plot these stresses on the Modified Goodman
Diagram and find the factor of safety.
aliyiumer@yahoo.com 28

Fatigue failure lecture notes

  • 1.
    Fatigue Failure Theories Preparedby Aliyi Umer ( Mechanical Design) Center for Research and Development Defence University, College of Engineering Bishoftu, Ethiopia aliyiumer@yahoo.com 1
  • 2.
    Fatigue Failure • Occurswhen stresses are changing throughout the life of a part. • starts with a crack that propagates until a catastrophic failure occurs. • This usually begins at a manufacturing defect or stress concentration that is subjected to tensile stresses for part of its load cycle. aliyiumer@yahoo.com 2
  • 3.
    Fatigue-Failure Models • Stress-Life- cyclic stresses are kept below fatigue strength or endurance limit. Most widely used. • Strain-Life - complicated not often used. aliyiumer@yahoo.com 3
  • 4.
    -20000 -10000 0 10000 20000 30000 40000 0 2 46 8 10 AppliedStress-psi Load Cycles Fatigue Stresses σa σ σa σm σm Fully Reversed Repeated Fluctuating aliyiumer@yahoo.com 4
  • 5.
    Fully Reversed FailureCriteria • Most data comes from R. R. Moore rotating- beam test. • Highly polished specimen of 0.3 inches in diameter is subjected to pure bending stresses that are alternated by rotating the specimen. • Rotation is at 1725 rpm. • Takes 1/2 day to reach 106 cycles. aliyiumer@yahoo.com 5
  • 6.
    10000 100000 1.0E+3 10.0E+3 100.0E+31.0E+6 10.0E+6 100.0E+6 FatigueStrength-Sf Cycles to Failure - N S-N Curve for Steel with Sut = 100 ksi aliyiumer@yahoo.com 6
  • 7.
    Endurance Limit andFatigue Strength • Endurance Limit of a Material (Se’) - stress below which fatigue failure does not occur regardless of the number of stress cycles. • ____________________Strength of a Material (Sf’) -stress below which fatigue failure does not occur for a specified number of stress cycles. aliyiumer@yahoo.com 7
  • 8.
    10000 100000 1.00E+03 1.00E+04 1.00E+051.00E+06 1.00E+07 1.00E+08 1.00E+09 FatigueStrength-psi Cycles to Failure Typical S-N Curve for Non-FerrousMetals aliyiumer@yahoo.com 8
  • 9.
    Estimating Se’ orSf’ • For ____________: Se’= 0.5Sut for Sut<200 ksi (1400 MPa) Se’= 100 ksi (700 MPa) for Sut>200 ksi (1400 MPa) • For ______________: Se’= 0.4Sut for Sut<60 ksi (400 MPa) Se’= 24 ksi (160 MPa) for Sut>60 ksi (400 MPa) aliyiumer@yahoo.com 9
  • 10.
    Estimating Se’ orSf’ cont’d • For __________________: Sf’@5E8= 0.4Sutfor Sut<48 ksi (330 MPa) Sf’@5E8= 19 ksi (130 MPa) for Sut>330 ksi (330 MPa) • For _____________________: Se’= 0.4Sutfor Sut<40 ksi (280 MPa) Se’= 14 ksi (100 MPa) for Sut>40 ksi (280 MPa) aliyiumer@yahoo.com 10
  • 11.
    Correction Factors toEndurance Limit and Fatigue Strength • Se = CloadCsizeCsurfCtempCreliabSe’ • Sf = CloadCsizeCsurfCtempCreliab Sf’ • Se -corrected endurance limit for a part • Sf -corrected fatigue strength for a part • Cload - load factor • Csize - size factor • Csurf- surface factor • Ctemp - temperature factor • Creliab- reliability factor aliyiumer@yahoo.com 11
  • 12.
    Stress Concentration • Kf= 1+q(Kt + 1) • Kt - geometric stress concentration factor • Kf - ___________________________ • q - notch sensitivity factor aliyiumer@yahoo.com 12
  • 13.
  • 14.
  • 15.
    Failure Lines forFluctuating Stress aliyiumer@yahoo.com 15
  • 16.
  • 17.
    Stress Concentration • ApplyKfto the ______________ components of stress. • For __________ materials apply Kt to the mean components of stress. aliyiumer@yahoo.com 17
  • 18.
    Stress Concentration -cont’d • If Kf|σmaxnom | < Sythen: Kfm = Kf • If Kf|σmaxnom | > Sythen: Kfm = (Sy - Kfσanom )/ |σmnom | • If Kf|σmaxnom - σminnom | < 2Sythen: Kfm = 0 aliyiumer@yahoo.com 18
  • 19.
    Factor of Safetyfor Fluctuating Stress - Case 1 aliyiumer@yahoo.com 19
  • 20.
    Factor of Safetyfor Fluctuating Stress - Case 2 aliyiumer@yahoo.com 20
  • 21.
    Factor of Safetyfor Fluctuating Stress - Case 3 aliyiumer@yahoo.com 21
  • 22.
    Factor of Safetyfor Fluctuating Stress - Case 3 aliyiumer@yahoo.com 22
  • 23.
    Factor of Safetyfor Fluctuating Stress - Case 4 aliyiumer@yahoo.com 23
  • 24.
    Factor of Safetyfor Fluctuating Stress - Case 4 aliyiumer@yahoo.com 24
  • 25.
    Fluctuating Stresses Multiaxial Stressesin Fatigue aliyiumer@yahoo.com 25
  • 26.
    Fully Reversed SimpleMultiaxial Stresses aliyiumer@yahoo.com 26
  • 27.
    Fluctuating Simple MultiaxialStresses • Von Mises Method aliyiumer@yahoo.com 27
  • 28.
    General Approach toHigh Cycle Fatigue Design • Generate Modified Goodman Diagram • Calculate alternating and mean components of stress at areas of concern on the part. Include appropriate stress concentration factors. • Convert alternating and mean applied stresses to alternating and mean Von Mises Stresses. • Plot these stresses on the Modified Goodman Diagram and find the factor of safety. aliyiumer@yahoo.com 28