This document discusses the distance formula and its applications. It contains: 1) An explanation of using the distance formula which involves finding the difference between corresponding x and y coordinates and plugging them into the Pythagorean theorem. 2) An activity and quiz involving using the distance formula to find the distance between various coordinate points on a graph. 3) An assignment to graph points, use the distance formula to find distances, and research the midpoint formula.

1. DISTANCE FORMULA

2. Plot these coordinates on
our Cartesian plane.
(3,2)
(8,7)
(8,2)

8. RIGHT TRIANGLE

9. AC is
plotted on
the x- axis.

10. Find the difference of the two
coordinates in x axis.
x2-x1
x2=8
x1=3
=8 – 3
=5

11. AC is
plotted on
the x- axis.
BC is plotted on the y-axis

12. Find the difference of the two
coordinates in x axis.
y2-y1
y2=7
y1=2
=7 – 2
=5

13. PYTHAGOREAN
THEOREM

15. DISTANCE FORMULA

16. SUBSTITUTION METHOD

17. ACTIVITY #1
• Graph and show that the following
coordinates forms an isosceles
triangle by using the distance
formula.
S (-1,4)
C (0,1)
B (2,5)

23. QUIZ#6
Get ½ crosswise sheet of pad paper and
answer the following.
Find the distance between the given
points.
1. (0,9) and (0,13)
2. (4,5) and (-3,5)
3. (8,1) and (8,-2)
4. (1,0) and (5,2)
5. (5,-4) and (1,-1)

24. ASSIGNMENT
A. Graph and Find the distance using
distance formula.
I (-4,6)
V (2,5)
Y (-1,6)
S (5, 10)
B. Make a research on midpoint and
give at least 2 examples.