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INEQUALITIES OF COMBINED FUNCTIONS HOMEWORK
QUESTION # 1 Observe the following graph. State the intervals where: F(x)>g(x) and g(x)>f(x)
SOLUTION # 1 f(x)>g(x) when x<0, 0<x<1 and g(x)>f(x) when x>1
QUESTION # 2 Using Graphing Technology (Ti-83, GraphCalc, Online Graphing calculator.) Graph the function f(x) and g(x) on the same set of axes. State where f(x)>g(x) and where g(x)>f(x) by looking at the graph. 𝑓𝑥=𝑥−2, 𝑔𝑥=(𝑥−2)4  
SOLUTION # 2 F(x)>g(x) on the interval (2,3) and g(x)>f(x) (-∞,2) and (3,∞)
QUESTION # 3 Solve question # 2 using a different method learned in class. Only state where f(x)>g(x)
SOLUTION # 3 𝑓𝑥>𝑔(𝑥) 𝑓𝑥−𝑔𝑥>0 𝑥−2𝑥4−8𝑥3+24𝑥62−32𝑥+16>0 𝑥−2−𝑥4+8𝑥3−24𝑥2+32𝑥−16>0 −𝑥4+8𝑥3−24𝑥2+33𝑥−18>0   Synthetic division (𝑥−3)(−𝑥3+5𝑥−9𝑥+6)   (𝑥−2)(𝑥−3)(−𝑥2+3𝑥−3)   ∴ f(x)>g(x) on the interval (2,3) Cant be factored 𝑥=2, 𝑥=3  
QUESTION # 4 Claire builds and sells birdhouses. Claire makes n birdhouses in a given week and sells them for 45-n dollars per birdhouse. Her weekly costs include a fixed cost of $280 plus $8 per birdhouse made. Assume that Claire sells all of the birdhouses that she makes.  A)    Write an equation to represent her total weekly cost. B)    Write an equation to represent her total weekly revenue.  C)    Write an inequality to express the condition for which Claire will make a profit. D)    How many birdhouses should Claire build each week in order to make a profit.
SOLUTION # 4 C(n)=(280+8n) R(n)=(45-n)n R(n)>C(n) 45−𝑛𝑛>280+8 45𝑛−𝑛2−8𝑛−280>0 −𝑛2+37𝑛−280>0 𝑛=37±372−4(−1)(−280)2(1) 𝑛=37±2492 𝑛=26,  𝑥=11 ∴11≤n≤26  
QUESTION # 5 Suppose that the developer (refer to page 450 for full question), found a way to reduce their variable cost to $58 000 per house What would the new cost equation be? How would this effect the minimum and maximum  number of houses the developer could build.
SOLUTION # 6 C(n)=0.058x+8 It increase the maximum and decreases the minimum

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Homework

  • 1. INEQUALITIES OF COMBINED FUNCTIONS HOMEWORK
  • 2. QUESTION # 1 Observe the following graph. State the intervals where: F(x)>g(x) and g(x)>f(x)
  • 3. SOLUTION # 1 f(x)>g(x) when x<0, 0<x<1 and g(x)>f(x) when x>1
  • 4. QUESTION # 2 Using Graphing Technology (Ti-83, GraphCalc, Online Graphing calculator.) Graph the function f(x) and g(x) on the same set of axes. State where f(x)>g(x) and where g(x)>f(x) by looking at the graph. 𝑓𝑥=𝑥−2, 𝑔𝑥=(𝑥−2)4  
  • 5. SOLUTION # 2 F(x)>g(x) on the interval (2,3) and g(x)>f(x) (-∞,2) and (3,∞)
  • 6. QUESTION # 3 Solve question # 2 using a different method learned in class. Only state where f(x)>g(x)
  • 7. SOLUTION # 3 𝑓𝑥>𝑔(𝑥) 𝑓𝑥−𝑔𝑥>0 𝑥−2𝑥4−8𝑥3+24𝑥62−32𝑥+16>0 𝑥−2−𝑥4+8𝑥3−24𝑥2+32𝑥−16>0 −𝑥4+8𝑥3−24𝑥2+33𝑥−18>0   Synthetic division (𝑥−3)(−𝑥3+5𝑥−9𝑥+6)   (𝑥−2)(𝑥−3)(−𝑥2+3𝑥−3)   ∴ f(x)>g(x) on the interval (2,3) Cant be factored 𝑥=2, 𝑥=3  
  • 8. QUESTION # 4 Claire builds and sells birdhouses. Claire makes n birdhouses in a given week and sells them for 45-n dollars per birdhouse. Her weekly costs include a fixed cost of $280 plus $8 per birdhouse made. Assume that Claire sells all of the birdhouses that she makes. A)    Write an equation to represent her total weekly cost. B)    Write an equation to represent her total weekly revenue. C)    Write an inequality to express the condition for which Claire will make a profit. D)    How many birdhouses should Claire build each week in order to make a profit.
  • 9. SOLUTION # 4 C(n)=(280+8n) R(n)=(45-n)n R(n)>C(n) 45−𝑛𝑛>280+8 45𝑛−𝑛2−8𝑛−280>0 −𝑛2+37𝑛−280>0 𝑛=37±372−4(−1)(−280)2(1) 𝑛=37±2492 𝑛=26,  𝑥=11 ∴11≤n≤26  
  • 10. QUESTION # 5 Suppose that the developer (refer to page 450 for full question), found a way to reduce their variable cost to $58 000 per house What would the new cost equation be? How would this effect the minimum and maximum number of houses the developer could build.
  • 11. SOLUTION # 6 C(n)=0.058x+8 It increase the maximum and decreases the minimum