WAVES
What is a wave?
For example: -
⚫ Consider the sound of the horn; this sound reaches our ear
because of sound waves.
⚫ There is transfer of energy from one point to another with
the help of particles in the medium.
⚫ These particles don’t move they just move around their mean
position, but the energy is getting transferred from one
particle to another and it keeps on transferring till it
reaches the destination.
A wave is a disturbance that propagates through
space, that carries energy without the net movement
of particles.
Types of Waves
⚫ Mechanical waves
⚫ Electromagnetic waves
⚫ Matter waves
⚫ Mechanical waves: -
⚫ The mechanical waves are governed by all the Newton’s laws of
motion.
⚫ Medium is needed for propagation of the wave.
⚫ For Example: - Water Waves, Sound Waves
Transverse Waves
⚫The transverse waves are those in which direction of
disturbance or displacement in the medium is
perpendicular to that of the propagation of wave.
⚫The direction in which a wave propagates is
perpendicular to the direction of disturbance.
Longitudinal Waves
⚫ Longitudinal means something related to length.
⚫ In longitudinal waves direction of disturbance or displacement in the
medium is along the propagation of the wave.
⚫ For example: - Sound waves. Particles and wave moving along the
horizontal direction. So both are in the same direction.
⚫ In a Longitudinal wave there are regions where particles are very close to
each other. These regions are known as compressions.
⚫ In some regions the particles are far apart. Those regions are known as
rarefactions.
λ
It represents the phase change per unit path.
WAVE NUMBER
It is the number of waves present in unit distance of a medium.
Relation between Time
period and Frequency
Displacement relation for a plane progressive wave
y(x, t) = a sin (kx + ωt + φ )
(Positive x-axis)
(Negative x-axis)
Relation between wave velocity, frequency
and wavelength of a wave
Equation for a standing wave
 Here, amplitude of the wave is 2A sin kx
The position of antinodes will be at points where,
sin kx = ± 1
i.e. kx = sin-1 (1)
i.e. kx = ( n +
1
2
) π , where n = 0,1,2,3……
(Since, ( n +
1
2
) π multiples of π will give maximum values of sin function.
i.e. 1)
2π
λ
x = ( n +
1
2
) π Now, bringing
2π
λ
to the RHS and taking ½ outside
the bracket, we get:
x = ( n +
1
2
) π .
λ
2π
Or x = ( 2n + 1)
λ
4
Or x =
λ
4
,
3λ
4
,
5λ
4
,………
These positions of maximum amplitudes are called antinodes. Clearly, the
separation between two consecutive nodes is
λ
2
.
The position of nodes will be at points where,
sin kx = 0 or kx = nπ, where n = 0,1,2…..
On solving we get x = n
𝝀
𝟐
or x = 0,
λ
2
,λ,
3λ
2
, ……….
These positions of zero amplitudes are called nodes.
Standing waves in a String
Consider a string clamped to rigid supports at its ends. If the wire be plucked in the
middle, transverse waves will travel along it and gets reflected from the ends. These
identical waves travelling in opposite directions give rise to stationary waves.
The string vibrates in segments or loops with certain natural frequencies. These
special patterns are called normal modes.
Equation of a standing wave,
y = 2A sin kx cos ωt, where 2A sin kx is the amplitude of the wave.
At nodes, amplitude is zero.
i.e. 2A sin kx = 0
Or sin kx = 0
Now, at x = L
sin kL = 0
Or kL = sin-1 0
kL = nπ
= 2π × L = nπ.
Length L is related to wavelength,
Or L =
𝑛𝜆
2
or wavelength of stationary wave is given by,
λ =
𝟐𝑳
𝒏
λ
L
Normal modes of string with fixed ends
• For n = 3  L =
3𝜆
2
and ν3 =3 ×
𝐯
𝟐𝑳
== ν=3 ν1
This frequency is called third Harmonic or second overtone and so
on.
The corresponding frequency is given by, ν =
𝐯
λ
ν =
𝐯
λ
=
𝒏𝐯
𝟐𝑳
• For n = 1, ν1 =
𝐯
𝟐𝑳
also L =
𝝀
𝟐
The lowest possible natural frequency of a system is called its fundamental
mode(note) or the first harmonic. For the stretched string fixed at either
end it is given by , ν1 =
𝒗
𝟐𝑳
corresponding to n = 1
• For n = 2  L = λ and ν2 =2 ×
𝐯
𝟐𝑳
== ν=2 ν1
This frequency is called second harmonic or first overtone.
Equation of a standing wave,
y = 2A sin kx cos ωt, where
2A sin kx is the amplitude of the
wave.
The position of nodes will be at points where,
sin kx = 0 or kx = nπ, where n = 0,1,2…..
On solving we get x = n
𝝀
𝟐
or x = 0,
λ
2
,λ,
3λ
2
, ……….
These positions of zero amplitudes are called nodes.
The positions of nodes in a closed organ pipe
The position of antinodes will be at points where,
sin kx = ± 1
i.e. kx = sin-1 (1)
i.e. kx = ( n +
1
2
) π , where n = 0,1,2,3……
2π
λ
x = ( n +
1
2
) π Now, bringing
2π
λ
to the RHS, we get:
x = ( n +
1
2
) π .
λ
2π
Now, x = L = ( n +
𝟏
𝟐
)
𝝀
𝟐
,where n = 0, 1,2,3….
Or x =
λ
4
,
3λ
4
,
5λ
4
,………
These positions of maximum amplitudes are called antinodes.
The corresponding frequency is given by, ν =
𝐯
λ
So, ν3 = 3 ν1
ν3
ν1
Or third harmonic, for n = 1
Fundamental frequency
L = ( n +
𝟏
𝟐
)
𝝀
𝟐
𝑺𝒐, At n=0
In an organ pipe closed at one end, it is found that the
higher frequencies are odd harmonics.
ν5
So, ν5 = 5 ν1
Similarly for n = 2, the corresponding frequency is fifth
harmonic or second overtone and so on.
λ
ν3
ν5
Normal Modes of vibration of an open organ pipe
(i) First mode of vibration:
L = λ/2 or λ = 2L
Frequency of vibration,
ν1 = v /2L ---- Fundamental note or first harmonic
(ii) Second mode of vibration:
L = λ
Frequency,
ν2 = v / L = 2 ν1 -----First overtone or second harmonic
Similarly,
ν3 = 3 ν1 ---2nd overtone / 3rd harmonic
ν4 = 4 ν1
ν5 = 5 ν1
---3nd overtone / 4th harmonic
---4nd overtone / 5th harmonic
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx
cbse_class 11_lesson 13_oscillations and waves (1).pptx

cbse_class 11_lesson 13_oscillations and waves (1).pptx

  • 1.
  • 2.
    What is awave? For example: - ⚫ Consider the sound of the horn; this sound reaches our ear because of sound waves. ⚫ There is transfer of energy from one point to another with the help of particles in the medium. ⚫ These particles don’t move they just move around their mean position, but the energy is getting transferred from one particle to another and it keeps on transferring till it reaches the destination. A wave is a disturbance that propagates through space, that carries energy without the net movement of particles.
  • 3.
    Types of Waves ⚫Mechanical waves ⚫ Electromagnetic waves ⚫ Matter waves ⚫ Mechanical waves: - ⚫ The mechanical waves are governed by all the Newton’s laws of motion. ⚫ Medium is needed for propagation of the wave. ⚫ For Example: - Water Waves, Sound Waves
  • 4.
    Transverse Waves ⚫The transversewaves are those in which direction of disturbance or displacement in the medium is perpendicular to that of the propagation of wave. ⚫The direction in which a wave propagates is perpendicular to the direction of disturbance.
  • 5.
    Longitudinal Waves ⚫ Longitudinalmeans something related to length. ⚫ In longitudinal waves direction of disturbance or displacement in the medium is along the propagation of the wave. ⚫ For example: - Sound waves. Particles and wave moving along the horizontal direction. So both are in the same direction. ⚫ In a Longitudinal wave there are regions where particles are very close to each other. These regions are known as compressions. ⚫ In some regions the particles are far apart. Those regions are known as rarefactions.
  • 8.
  • 11.
    It represents thephase change per unit path. WAVE NUMBER It is the number of waves present in unit distance of a medium.
  • 14.
  • 15.
    Displacement relation fora plane progressive wave
  • 16.
    y(x, t) =a sin (kx + ωt + φ ) (Positive x-axis) (Negative x-axis)
  • 28.
    Relation between wavevelocity, frequency and wavelength of a wave
  • 32.
    Equation for astanding wave  Here, amplitude of the wave is 2A sin kx
  • 33.
    The position ofantinodes will be at points where, sin kx = ± 1 i.e. kx = sin-1 (1) i.e. kx = ( n + 1 2 ) π , where n = 0,1,2,3…… (Since, ( n + 1 2 ) π multiples of π will give maximum values of sin function. i.e. 1) 2π λ x = ( n + 1 2 ) π Now, bringing 2π λ to the RHS and taking ½ outside the bracket, we get: x = ( n + 1 2 ) π . λ 2π Or x = ( 2n + 1) λ 4 Or x = λ 4 , 3λ 4 , 5λ 4 ,……… These positions of maximum amplitudes are called antinodes. Clearly, the separation between two consecutive nodes is λ 2 .
  • 34.
    The position ofnodes will be at points where, sin kx = 0 or kx = nπ, where n = 0,1,2….. On solving we get x = n 𝝀 𝟐 or x = 0, λ 2 ,λ, 3λ 2 , ………. These positions of zero amplitudes are called nodes.
  • 35.
    Standing waves ina String Consider a string clamped to rigid supports at its ends. If the wire be plucked in the middle, transverse waves will travel along it and gets reflected from the ends. These identical waves travelling in opposite directions give rise to stationary waves. The string vibrates in segments or loops with certain natural frequencies. These special patterns are called normal modes. Equation of a standing wave, y = 2A sin kx cos ωt, where 2A sin kx is the amplitude of the wave.
  • 36.
    At nodes, amplitudeis zero. i.e. 2A sin kx = 0 Or sin kx = 0 Now, at x = L sin kL = 0 Or kL = sin-1 0 kL = nπ = 2π × L = nπ. Length L is related to wavelength, Or L = 𝑛𝜆 2 or wavelength of stationary wave is given by, λ = 𝟐𝑳 𝒏 λ L Normal modes of string with fixed ends
  • 37.
    • For n= 3  L = 3𝜆 2 and ν3 =3 × 𝐯 𝟐𝑳 == ν=3 ν1 This frequency is called third Harmonic or second overtone and so on. The corresponding frequency is given by, ν = 𝐯 λ ν = 𝐯 λ = 𝒏𝐯 𝟐𝑳 • For n = 1, ν1 = 𝐯 𝟐𝑳 also L = 𝝀 𝟐 The lowest possible natural frequency of a system is called its fundamental mode(note) or the first harmonic. For the stretched string fixed at either end it is given by , ν1 = 𝒗 𝟐𝑳 corresponding to n = 1 • For n = 2  L = λ and ν2 =2 × 𝐯 𝟐𝑳 == ν=2 ν1 This frequency is called second harmonic or first overtone.
  • 42.
    Equation of astanding wave, y = 2A sin kx cos ωt, where 2A sin kx is the amplitude of the wave.
  • 43.
    The position ofnodes will be at points where, sin kx = 0 or kx = nπ, where n = 0,1,2….. On solving we get x = n 𝝀 𝟐 or x = 0, λ 2 ,λ, 3λ 2 , ………. These positions of zero amplitudes are called nodes. The positions of nodes in a closed organ pipe
  • 44.
    The position ofantinodes will be at points where, sin kx = ± 1 i.e. kx = sin-1 (1) i.e. kx = ( n + 1 2 ) π , where n = 0,1,2,3…… 2π λ x = ( n + 1 2 ) π Now, bringing 2π λ to the RHS, we get: x = ( n + 1 2 ) π . λ 2π Now, x = L = ( n + 𝟏 𝟐 ) 𝝀 𝟐 ,where n = 0, 1,2,3…. Or x = λ 4 , 3λ 4 , 5λ 4 ,……… These positions of maximum amplitudes are called antinodes. The corresponding frequency is given by, ν = 𝐯 λ
  • 45.
    So, ν3 =3 ν1 ν3 ν1 Or third harmonic, for n = 1 Fundamental frequency L = ( n + 𝟏 𝟐 ) 𝝀 𝟐 𝑺𝒐, At n=0
  • 46.
    In an organpipe closed at one end, it is found that the higher frequencies are odd harmonics. ν5 So, ν5 = 5 ν1 Similarly for n = 2, the corresponding frequency is fifth harmonic or second overtone and so on.
  • 47.
  • 48.
    Normal Modes ofvibration of an open organ pipe (i) First mode of vibration: L = λ/2 or λ = 2L Frequency of vibration, ν1 = v /2L ---- Fundamental note or first harmonic (ii) Second mode of vibration: L = λ Frequency, ν2 = v / L = 2 ν1 -----First overtone or second harmonic Similarly, ν3 = 3 ν1 ---2nd overtone / 3rd harmonic ν4 = 4 ν1 ν5 = 5 ν1 ---3nd overtone / 4th harmonic ---4nd overtone / 5th harmonic