This document contains calculations for resistances and voltages in an integrated circuit. It uses formulas to calculate the total resistance in series and parallel combinations. It then applies the voltage divider principle to determine voltages across specific resistances when a 10V source is applied. The calculations show the voltages across R1, R3, R4, and R5 are 5.15V, 4.85V, 1.58V, and 3.27V respectively.

1. Fredrick Kendrick [Type here] ET1410
Calculated Values
Integrated Circuit (IC)
RAB = R1*R2 / R1 + R2 = 1.0kΩ*2.2kΩ / 3.2kΩ = 688Ω
R4 + R5 = 330Ω + 680Ω = 1010Ω = 1.01 kΩ
RBC = R3(R4 + R5) / R3 + R4 + R5 = 1.8kΩ*1.01kΩ / 2.81kΩ = 647Ω
The resistance from A to B is in series with the resistance from B to C, so the total
circuit resistance is:
RT = RAB + RBC = 688Ω + 647Ω = 1335Ω
Use the voltage-divider principle to calculate the voltages:
VAB = RAB / RT
VS = 688Ω / 1335Ω
10V = 5.15V
________________
VBC = RBC / RT
VS = 647Ω / 1335Ω
10V = 4.85V

2. Fredrick Kendrick [Type here] ET1410
_________________
VR1 = VR2 = VAB = 5.15V
VR3 = VBC = 4.85V
_________________
VR4 = R4 / R4 + R5
VBC = 330Ω / 1010Ω
4.85v = 1.58v
__________________
VRS = R5 / R4 + R5
VBC = 680Ω / 1010Ω
4.85V = 3.27
Work taken off the board of Instructor Don Heller’s ET1410 Integrated Circuits Class
here at ITT Technical Indianapolis. March 2015