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Hydraulics
Hydraulics
An area of engineering
science that deals with
liquid flow and pressure
Hydraulic Fluids
 Liquid pumped through a hydraulic system
 Petroleum-based or synthetic oil
 Serve four major functions:
1. Power transmission
2. Lubrication of moving parts
3. Sealing of spaces between moving parts
4. Heat removal
 Relatively Incompressible!
Two Types or Conditions of
Hydraulic Systems
Hydrostatic
Hydrodynamic
Hydrostatics -
a “No Flow” Scenario
 “Static” means “stationary” or “non flowing” in
a hydraulic system
 Hydraulic systems are considered static when
there is no flow
 Pascal’s Law (for hydrostatics):
 a pressure applied to a confined hydrostatic fluid
is transmitted with equal intensity throughout the
fluid
 Same pressure all throughout!
Hydrodynamics –
a “Flow” scenario
 “Dynamic” means “moving” or “flowing” in a
hydraulic system
 Hydraulic systems are considered dynamic
when there is flow
 Pascal’s Law does not apply!
 Pressure does not have equal intensity in a
flowing dynamic system
 Pressure drops along the length of a hydraulic line
in flowing systems
Flow and Pressure
 Flow, Q
 volume flow rate
 amount of fluid moving through system per
unit time
 Pressure, P
 force per unit area of fluid moving through
a system
Area
Force
Pressure 
A
F
P 
Mechanical Advantage
 Ideal mechanical advantage (IMA)
 Assumes no frictional losses
 Calculated as ratio of output force to input force
 Actual mechanical advantage (AMA)
 always less than ideal
 difficult to calculate
F
F
input
output
IMA 
Application of Pascal’s Law in
a Simple Hydrostatic System
How much force must you exert on piston A to lift a load on piston
B of 500 lbs? What is the ideal mechanical advantage of this
system?
Problem Solving
Step 1: Determine the pressure in
the system using information about
piston B
Known Unknown
A = 500 in2 P=?
F = 500 lb
Equation No algebra needed
Substitution & Solution
STEP 2: Use the pressure
calculated in STEP 1 and information
about piston A to calculate force
Known Unknown
A = 1.0 in2 F=?
Equation and algebra:
Substitution & Solution
1psi
in
lb
1
500in
500lb
P 2
2



(A)
A
F
(A)P 
A
F
P  PA
F 
2
in
lb
1
psi
1
P 

  1.0lb
1.0in
in
lb
1
PA
F 2
2









A
F
P 
Problem Solving
Step 3: Determine the ideal mechanical advantage (IMA) of
the system using information from STEPS 1 & 2
Known Unknown
F(input) = 1 lb IMA=?
F(output) = 500 lb
Equation No algebra needed
Substitution & Solution
500
1.0lb
500lb
IMA 

F(input)
F(output)
IMA 
A Hydraulic System
Tank/Reservoir
 Storage device which is open and not
pressurized
Filter
Pumps
 Positive displacement
pump (Gear Pump): a
specific amount of fluid
passes through the pump
for each rotation
 Centrifugal pump (Vane
Pump): no specific
amount of fluid flow per
rotation; flow depends on
speed of blades
Accumulators
 Storage device which is closed and is
under pressure
Valves
 Check Valve  Directional Control
Linear Actuators
Use hydraulic power to move linearly
Single Acting Double Acting
Rotary Actuators
Use hydraulic power to rotate
Single-Vane Double-Vane
Applications
 Robotics
 Oil systems in vehicles (e.g. brakes)
 Presses
 Heavy equipment
 Wood splitter
 Aircraft control systems
The Hydraulic Trainer
Motor
Pump
Return line
from reservoir
Pressure line
Pressure Regulator
In-line
Pressure
Gauge
Flow Control Valve
Check Valve
Actuators
Directional Control Valve
Inline-Tee
Return line
Connections
Supply line
Connections

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Basics of Hydraulic Systems.ppt

  • 2. Hydraulics An area of engineering science that deals with liquid flow and pressure
  • 3. Hydraulic Fluids  Liquid pumped through a hydraulic system  Petroleum-based or synthetic oil  Serve four major functions: 1. Power transmission 2. Lubrication of moving parts 3. Sealing of spaces between moving parts 4. Heat removal  Relatively Incompressible!
  • 4. Two Types or Conditions of Hydraulic Systems Hydrostatic Hydrodynamic
  • 5. Hydrostatics - a “No Flow” Scenario  “Static” means “stationary” or “non flowing” in a hydraulic system  Hydraulic systems are considered static when there is no flow  Pascal’s Law (for hydrostatics):  a pressure applied to a confined hydrostatic fluid is transmitted with equal intensity throughout the fluid  Same pressure all throughout!
  • 6. Hydrodynamics – a “Flow” scenario  “Dynamic” means “moving” or “flowing” in a hydraulic system  Hydraulic systems are considered dynamic when there is flow  Pascal’s Law does not apply!  Pressure does not have equal intensity in a flowing dynamic system  Pressure drops along the length of a hydraulic line in flowing systems
  • 7. Flow and Pressure  Flow, Q  volume flow rate  amount of fluid moving through system per unit time  Pressure, P  force per unit area of fluid moving through a system Area Force Pressure  A F P 
  • 8. Mechanical Advantage  Ideal mechanical advantage (IMA)  Assumes no frictional losses  Calculated as ratio of output force to input force  Actual mechanical advantage (AMA)  always less than ideal  difficult to calculate F F input output IMA 
  • 9. Application of Pascal’s Law in a Simple Hydrostatic System How much force must you exert on piston A to lift a load on piston B of 500 lbs? What is the ideal mechanical advantage of this system?
  • 10. Problem Solving Step 1: Determine the pressure in the system using information about piston B Known Unknown A = 500 in2 P=? F = 500 lb Equation No algebra needed Substitution & Solution STEP 2: Use the pressure calculated in STEP 1 and information about piston A to calculate force Known Unknown A = 1.0 in2 F=? Equation and algebra: Substitution & Solution 1psi in lb 1 500in 500lb P 2 2    (A) A F (A)P  A F P  PA F  2 in lb 1 psi 1 P     1.0lb 1.0in in lb 1 PA F 2 2          A F P 
  • 11. Problem Solving Step 3: Determine the ideal mechanical advantage (IMA) of the system using information from STEPS 1 & 2 Known Unknown F(input) = 1 lb IMA=? F(output) = 500 lb Equation No algebra needed Substitution & Solution 500 1.0lb 500lb IMA   F(input) F(output) IMA 
  • 13. Tank/Reservoir  Storage device which is open and not pressurized Filter
  • 14. Pumps  Positive displacement pump (Gear Pump): a specific amount of fluid passes through the pump for each rotation  Centrifugal pump (Vane Pump): no specific amount of fluid flow per rotation; flow depends on speed of blades
  • 15. Accumulators  Storage device which is closed and is under pressure
  • 16. Valves  Check Valve  Directional Control
  • 17. Linear Actuators Use hydraulic power to move linearly Single Acting Double Acting
  • 18. Rotary Actuators Use hydraulic power to rotate Single-Vane Double-Vane
  • 19. Applications  Robotics  Oil systems in vehicles (e.g. brakes)  Presses  Heavy equipment  Wood splitter  Aircraft control systems
  • 20. The Hydraulic Trainer Motor Pump Return line from reservoir Pressure line Pressure Regulator In-line Pressure Gauge Flow Control Valve Check Valve Actuators Directional Control Valve Inline-Tee Return line Connections Supply line Connections

Editor's Notes

  1. Used in many applications in industry!
  2. Use syringes to demonstrate the basic concept of hydraulic flow
  3. Four major functions: Power transmission: Pumps apply pressure to hydraulic fluids, which causes the fluid to move (since they can’t be compressed). This movement causes components connected to the hydraulic system to move. Thus, power is transmitted. Lubrication of moving parts: Hydraulic systems provide their own lubrication! Sealing of spaces between moving parts: Hydraulic pressure between moving parts (e.g. piston) makes a seal between those parts. Heat removal: Hydraulic fluids move passed hot components and then carry that heat away via conduction mechanisms.
  4. Four major functions: Power transmission: Pumps apply pressure to hydraulic fluids, which causes the fluid to move (since they can’t be compressed). This movement causes components connected to the hydraulic system to move. Thus, power is transmitted. Lubrication of moving parts: Hydraulic systems provide their own lubrication! Sealing of spaces between moving parts: Hydraulic pressure between moving parts (e.g. piston) makes a seal between those parts. Heat removal: Hydraulic fluids move passed hot components and then carry that heat away via conduction mechanisms.