An Hfr strain that is met+pro+bio+his+ was mated with an F- strain t.pdf

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An Hfr strain that is met+pro+bio+his+ was mated with an F- strain that was met-pro-bio-his-. Mating was interrupted and the percentage of cells with each phenotype was determined by replica plating the cells on minimal media plates that lacked met, pro, bio or his. The data shown in Figure 1 were obtained. During conjugation, cells gain genes in the order they occur in the donor cell chromosome. Genes that are near the origin of transfer will be transferred first. Use the graph to help you construct a map of the four genes. (Figure 2) Drag the genes onto the map in the proper order. Minutes 10 12 15 20 Percentage Percentage Percentage Percentage of cells with of cells with of cells with of cells with bio his met pro phenotype phenotype phenotype phenotype 7 0 0 2 25 15 3 20 40 28 42 17 35 25 Solution Answer: Origin - met+ - his+ - pro+ - bio+ Explanation: As we know that during conjugation, cells gain genes in the order they occur in the donor cell chromosome. Genes that are near the origin of transfer will be transferred first. From the graph it is clear that met+ gene transfer first and goes on increasing its percentage as time passes. so it is present closest to the origin. Then his+ gene shows more percentage transfer than pro+ gene and atlast bio+ gene transfers..

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genetic linkage and gene mapping

Mahammed Faizan

1a- What are three ways that bacteria can exchange genetic information? How are these similar and how are they different? How can they be used to map bacterial genomes? b) Explain how genes in phages are mapped. (This is different from the above question) Solution Ques-1: What are three ways that bacteria can exchange genetic information? How are these similar and how are they different? How can they be used to map bacterial genomes? Answer: Horizontal gene transfer (HGT) or lateral gene transfer is the transfer of genes between two organisms that are phylogenetically unrelated but can readily exchange genes by conjugation or transduction or transformation. HGT commonly occurs in prokaryotes and it plays a key role in their evolution. HGT accelerates evolution. Horizontal gene transfer: 1. conjugation, 2. transformation; 3. transduction Similarities & differences: Horizontal gene transfer is the transfer of genomes by between bacteria by the routes that does not involve parent-offspring transmission. Conjugation, transduction and transformation are the three mechanism of horizontal gene transfer. In the above case, it has clearly illustrated that the conditions, which can successfully prevents transduction and abolish transfer of chromosomal DNA from one bacterial cell to another by generalized transduction with P22 bacteriophage. Initially recipient cell- surface receptors are important for the attachment of the bacteriophage (P22) and finally spikes of phage enable bacterial membrane to lyse finally incorporate phage genome into the bacterial cell for integration. Therefore, for efficient transduction, presence of recipient cell- surface receptors is essential in the culture otherwise, bacteria exert resistant effects to the phages. Transformation type of gene transfer occurs between bacteria. The genes released by dead bacteria can be transferred to the live bacteria, and get integrated into its genome, which results in genetic recombination of the host. Transduction is also involving the genetic material transfer, but this needs bacteriophage as media. The bacteriophage infects the bacteria in lytic cycle and releases the new virions, the capsids of some of these virions carry the bacterial DNA fragments into the new host bacteria, followed by genetic recombination of the host bacteria. Conjugation: It is the transfer of genetic material from cell to cell by means of direct contact or a bridge like structure. Bacterial conjugation needs the conjugation tube for genome transfer, both transduction and transformation does not need this. Mapping the genome -mechanisms F factor is mainly pertaining to a class of conjugate plasmids, which meticulously originated to control sexual functions in prokaryotes via fertility inhibition. The origin of F-factor is mainly with most common functional segments such as gene traJ, Ori, OriC. The structure of this F factor contains OriT for origin of transfer and acts as a starting point for gene transmission.

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Morphogens, induction and cytoplasmic determinants

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Figure 3: Ventral view of the female and male abdomen Virgin females: Difference between a virgin and a mated female fruit fly. Virgin (left): pale in colour, black spot in abdomen (meconium) and often bloated. Mated (right): more pigmented, no meconium. (Source: Twitter) Crosses: For this lab we are observing and crossing the F 1 offspring. The parents and some individuals from the offspring will show the phenotypic traits for the mutations, some will show the wildtype phenotype. The parental cross and F 1 are showed below: Dihybrid cross 1: P l = apterous (vestigial wings showed) x sepia Dihybrid cross 2 : P l = wildtype x white Cross 1: sepia male x apterous virgin female 9 Cross 2: white virgin female 9 x wildtype male So, what is your observed ratio? To determine the proportion each class represents of the total number of offspring, divide \# observed/total offspring: Proportion of wildtype 171/220 = 0.78 , which can also be shown as 78% (multiply by 100 ) Proportion of apterous 49/220 = 0.22 , which can also be shown as 22% To calculate the observed ratio in the offspring among the phenotypic classes: 1. Write the classes with the corresponding numbers as a ratio: 171 wildtype: 49 apterous. 2. Simplify the ratio by dividing each number by the smallest number in the ratio. So, 171/49 = 3.5 and 49/49 = 1 . So, the simplified ratio is 3.5 wildtype: 1 apterous. This is obviously close to a 3:1 ratio, but is it close enough to support your hypothesis? This is the point at which you would do your Chi-Square calculations. Review questions (5 pts) 1) What is the Parental cross genotype and phenotype? What would you expect for the genotype and phenotype about the F 1 and F 2 ? 2) What are the expected rations for a monohybrid and for a dihybrid cross? .

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Functionally important traits in animals tend to vary little from one individual to the next within populations, possible because individuals that deviate too much from the mean die sooner or leave fewer offspring in the long run. If so, does variance in a trait rise after it becomes less functionally important? Billet et al. (2012) investigated this question with the semicircular canals (SC) of the inner ear of the three-toed sloth (Bradypus variegatus). Sloths move very slowly and infrequently, and the authors suggested that this behavior reduces the functional demands on the SC, which usually provide information on angular head movement to the brain. Indeed, the motion signal from the SC to the brain may be very weak in sloths as compared to faster-moving animals. The following numbers are measurements of the length to the width of the anterior semicircular canals in seven sloths. Assume that this represents a random sample. 1.52, 1.06, 0.93, 1.38, 1.47, 1.20, 1.16 a. In related, faster-moving animals, the standard deviation of the ratio of the length to the width of the anterior semicircular canals is known to be 0.09. What is the estimate of the standard deviation of this measurement in three toed sloths? b. Based on these data, what is the most plausible range of values for the population standard deviation in the three-toed sloth? Does this range include the known value of the standard deviation in related, faster-moving species? c. What additional assumption is required for your answer in (b)? What do you know about how sensitive the confidence interval calculation is when the assumption is not met? Solution.

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Find the values of the trigonometric functions of t from the given information. tan(t) = - 8/15, cos(t) > 0 sin(t) = cos(t) = CSC (t) = sec(t) = cot(t) = Solution Here w ehave tan(t) = 8/15 and we know tan() = Perpendicular/Base so we have Perpendicular = 8 and Base = 15 , now we can calculate Hypotenuse from these values hynpotenuse2 = perpendicular2 + base2 hypotenuse2 = 8*8+15*15 hypotenuse2 = 289 (64+225) hypotenuse = 17 (sqaure root of 289) Now we will get the value of other functions sin(t) = Perpendicular/Hynpotenuse sint(t) = 8/17 cost(t)= Base/Hynpotenuse cost(t) = 15/17 csc(t) = Hynpotenuse/Perpendicular csc(t) = 17/8 sec(t) = Hynpotenuse/Base sec(t) = 17/15 cot(t) = Base/Perpendicular cot(t0 = 15/8.

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Explain how the skeletal system is more than just bones/bone tissue. (2 marks) Solution Skeletal system = The body is supported within or around by ahard framework called skeleton skeleton system does not consists bones or bone tissues IT is made from number of bones , joints ,tendons . ligaments ,diaphysis, Epiphysis , Human skeleton is of 2 types 1] Axial skeleton = Consists of 80 bones consists of skull, vertebral column , thoracic cage Skull- formed by 28 bones verte. column- consists of 33 small ring like vertebrae called vertebae thoracic cage= consists of 12 pairs of ribs & sternum 2] Appendicular skeleton = consists of 126 bones consists of bones of girdle & limbs Joints = A place where 2 or more bones articulated to one another called as joints Diaphysis= Shaft of long bone containing a canal filled with yellow bone marrow Ligaments = fibrous connective tissue that connects bone to bone Osteoblast= Are principle bone building cells Peristomeum= Dense fibrous membrane covering the surface of bones except joints Tendons = Are tough inelastic tissue that attaches muscles to bones.

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Digitization introduces quantization errors that cannot be removed by repeaters. Solution . Yes, Digitization introduces quantization errors that cannot be removed by repeaters Quantization error introduces by quantization in the analog to digital conversion in telecommunication systems and signal processing. It is a rounding error among the analog input voltage to the analog to digital and the output digitized value.

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Design, implement, test(In Java ) a doubly linked list ADT, using DLLNode objects as the nodes. In addition to our standard list operations, your class should provide for backward iteration through the list. To support this operation, it should export a resetBack method and get a getPrevious method.To facilitate this, you may want to include an instance variable last that always references the last element on the list. DLLNODE.java public class DLLNode extends LLNode { private DLLNode back; public DLLNode(T info) { super(info); back = null; } public void setBack(DLLNode back) // Sets back link of this DLLNode. { this.back = back; } public DLLNode getBack() // Returns back link of this DLLNode. { return back; } } LLNODE.java public class LLNode { private LLNode link; private T info; public LLNode(T info) { this.info = info; link = null; } public void setInfo(T info) // Sets info of this LLNode. { this.info = info; } public T getInfo() // Returns info of this LLONode. { return info; } public void setLink(LLNode link) // Sets link of this LLNode. { this.link = link; } public LLNode getLink() // Returns link of this LLNode. { return link; } } This list can be an unsorted list. My professor suggested to reference off the RefUnsortedList ADT and modifying it to be a doubly linked list.you need to create resetBack and getPrevious methods which means you will need another variable to keep track of where you are in the backward iteration. It is not correct to use currentPos to keep track of the backward iteration, so make another variable (reference) for this, maybe call it currentBackPos. RefUnsortedList.java public class RefUnsortedList implements ListInterface { protected int numElements; // number of elements in this list protected LLNode currentPos; // current position for iteration // set by find method protected boolean found; // true if element found, else false protected LLNode location; // node containing element, if found protected LLNode previous; // node preceeding location protected LLNode list; // first node on the list public RefUnsortedList() { numElements = 0; list = null; currentPos = null; } public void add(T element) // Adds element to this list. { LLNode newNode = new LLNode(element); newNode.setLink(list); list = newNode; numElements++; } protected void find(T target) // Searches list for an occurence of an element e such that // e.equals(target). If successful, sets instance variables // found to true, location to node containing e, and previous // to the node that links to location. If not successful, sets // found to false. { location = list; found = false; while (location != null) { if (location.getInfo().equals(target)) // if they match { found = true; return; } else { previous = location; location = location.getLink(); } } } public int size() // Returns the number of elements on this list. { return numElements; } public boolean contains (T element) // Returns true if this list contains an element e such that // e.equals(el.

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Describe how caregivers can promote maximum independence among people with functional impairments. Give two examples and explain your reasoning. Solution Caregivers should assist the areas in which the patient is unable to do things for himself or herself. Medical care delivery should focus on patient’s mental, social, and spiritual needs and preferences.The main Human factors like caring, compassion,patient dignity, latitude to govern one’s affairs, and privacy are some important daily practices that should be taken care of by caregivers..

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A uniform plane wave propagates in the y direction in air with its electric field oriented in the z direction. At t = 0, the electric field of the wave has a maximum value of 100 milliVolts/m at a position y = 1 m and an adjacent value of -100 milliVolts/m at a position of y = 2.25 m. Write down the expression for the instantaneous electric field intensity E^rightarrow(y, t). Include the proper dimensional units. Sketch E^rightarrow(y) at t = 0 and t = 12.5 ns in three dimensional (3-D axis) diagram. Add the instantaneous magnetic field H^rightarrow(y) at t = 0 and t = 12.5 ns to your sketches. Sketch E^rightarrow (t) at y = 0 and y = 12.5 m. An observer measures E^rightarrow(t) at y = 12.5 m, starting at t = 0. Find the first time instant at which the observer measures a maximum electric field intensity. Solution Instantaneous electric energy and electric power dissipation in dispersive media Wonseok Shin,1 Aaswath Raman,2 and Shanhui Fan1,* 1 Department of Electrical Engineering, Stanford University, Stanford, California 94305, USA 2 Department of Applied Physics, Stanford University, Stanford, California 94305, USA *Corresponding author: shanhui@stanford.edu Received November 14, 2011; revised December 26, 2011; accepted December 27, 2011; posted January 5, 2012 (Doc. ID 158103); published April 24, 2012 We derive the instantaneous densities of electric energy and electric power dissipation in lossless and lossy dispersive media for a time-harmonic electric field. The instantaneous quantities are decomposed into DC and AC components, some of which are shown to be independent of the dispersion of dielectric constants. The AC component of the instantaneous energy density can be used to visualize propagation of electromagnetic waves through complex 3D structures. © 2012 Optical Society of America OCIS codes: 260.2110, 260.2030, 260.3910. 1. INTRODUCTION Understanding the forms of the densities of energy and power dissipation in dispersive media has been a topic of interest for decades [1–4] and has found renewed interest recently due to the development of metamaterials [5–11]. When electric dispersion is concerned [12], a dispersive medium is characterized by a frequency-dependent dielectric constant 0 i 00. Assuming a time-harmonic electric field (E-field) Et E0eit , it is well-known that in a lossless dispersive medium, where 00 0, the time average of the electric energy density is [3] ue 1 4 d d jE0j 2. (1) The time average of the electric energy density is known also in a lossy dispersive medium, where 00 > 0, provided that the medium is a Lorentz medium, i.e., described by a Lorentz pole [2,6,8,13]. In addition, the time average of the electric power dissipation density in a lossy dispersive medium is [3] qe 1 2 00 jE0j 2; (2) which holds for any lossy dispersive medium including the Lorentz medium. Most of the previous works on electric energy and power dissipation have focused on the time- averaged quantities [Eq. (1) and Eq. (2)]. The.

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5) look up the following health-based peer-reviewed journal article that displays a frequency distribution or histogram in the results section González-Villalpando, C., Dávila-Cervantes, C. A., Zamora-Macorra, M., Trejo-Valdivia, B., & González-Villalpando, M. E. (2014). Risk factors associated to diabetes in Mexican population and phenotype of the individuals who will convert to diabetes. salud pública de méxico, 56(4), 317-322. a) Describe the characteristics of the grouped data in this journal article. b) What additional ways can the group data may be displayed for publication? What is the rationale for selecting these alternative methods? Method of Display Rationale Method of Display Rationale Solution The given quation deals with the study of the research paper results. a. The grouped data shown in the result of the paper is, the number of people, male and female in the converter and non-converter heads on various variables, such as mother,father,brother,their weight and many other variables.The studied variables are all quantitative variables. b. The grouped data can be displayed using, i. pie chart representation, since in this type of represenatation one can at a glance get an overall idea about the reatio or percentage of the people under each head. ii. frequency polygon, since it would also give a crude idea about the relationship between the variable under study and the frequency of the variable under each head. iii. ogive representation, since it would additionally give a trend of the variables under study, and help to estimate or predict the variable value at any point under study. iv. boxplot representation, since it would give an idea about the median of the variables under study and also give an idea about the presence of any possible outliers and also the quartiles. and many more such echniques can be applied depending on the requirement of the research needs..

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will left-wing terror increase, remain the same, or decrease in the next 5 years? Explain the basis for your opinion. Solution Terrorism is the premeditated use or threat to use violence by individuals or sub national groups to obtain a political or social objective through the intimidation of a large audience beyond that of the immediate victims. Left wing extremism often has developed from working -class movements seeking in theory to eliminate, not preserve, class distinctions. Communism evolved from left wing extremism. The threat from left wing extremists did not die with the collapse of the Soviet Union, however. Domestic groups and state -sponsored cells and individuals have continued their espionage activities and the planning of terrorist actions against the U.S. government. Many believe that leftist extremism in the United States was at its peak during the 1960s and 1970s and that right wing extremism then became the major threat. Leftist extremists were responsible for three -fourths of the officially designated acts of terrorism in America in the 1980s. Leftist extremists also pose an espionage threat to U.S. interest. The threat to the United States government from leftist extremists has decreased considerably in the past decade, but it has not disappeared. There are individuals and organizations within the United States who maintain the same ideology that resulted in the growth of left wing terrorism in this country in the 1970s and 1980s. On the basis on my opinion, Left wing extremism continues, indeed, to be a potential threat to U.S. government agencies. The challenge in responding to this threat is to ensure that the rights of individuals to form and express their own beliefs are balanced with the need to provide security and protection against terrorism and espionage that may be committed by the most extreme members of these movements. Leftist extremism presents two threats. We thing that first threat is terrorism. Left wing terrorists have been responsible for bombings, assassinations, robberies, and planned attacks on infrastructure targets. The second threat is their potential support of espionage conducted against the United States by supporting countries such as Cuba. Although the United States has not experienced any major leftist terrorist movements or actions in recent years, these groups continue to be active in other parts of world. Of the 40 terrorist groups listed in the U.S. Department of State\'s 1998 report, 16 were Islamic or Palestinian extremist groups and 16 were Marxist Leninist organizations. But today there is no equivalent threat from left-wing extremists. Small bands of masked protestors periodically indulge in a bout of window smashing or throw rocks at the police, but bombings, bank robberies and gunfights with law enforcement are the province of fringe right-wing extremist groups..

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What is the time difference in myelinated vs. unmyelinated axons? Solution The gap junctions found at regular intervals in the myelin sheath are called as Nodes of Ranveir. Myelin sheath does not allow the exchange of ions through it and exchange of ions occurs at Nodes of Ranveir only. Myelin sheath helps in the faster conduction of impulses through the axons by saltatory conduction (impulses jump from one node to another). Thus, the impulses are conducted faster in myelinated neurons (glial cells insulate the neurons with myelin sheath) than non-myelinated neurons. In non myelinated neurons, the ions move through the axon length, so the conduction is slower..

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whats is the hostory of mathematics? Solution It deals with the investigation into the origin of discoveries in mathematics and an investigation into the mathematical methods and notation of the past. Primarily, there were two main civilizations associated with the development of mathematics, they were (i) Babylonians (ii) Indus valley Ancient mathematics has reached the modern world largely through the work of Greeks in the classical period, building on the Babylonian tradition. A leading figure among the early Greek mathematicians is Pythagoras who deveoped the famous pythagorus theorem. Indian mathematics emerged in the indian subcontinent until the end of eightienth century.A later landmark in Indian mathematics was the development of the series expansions for trigonometric functions (sine, cosine, andarc tangent) by mathematicians of the Kerala school in the 15th century CE. Their remarkable work, completed two centuries before the invention of calculus in Europe, provided what is now considered the first example of a power series (apart from geometric series). From ancient times through the Middle Ages, bursts of mathematical creativity were often followed by centuries of stagnation. Beginning in Renaissance Italy in the 16th century, new mathematical developments, interacting with new scientific discoveries, were made at an increasing pace that continues through the present day..

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what is spiled identity as in disability? Are all aspects of spoiled identity are inevitable? Solution Within a society, certain people are normal and few of them are so different from others. The abnormal identity of an individual from others might be due to the social situations, the race, the gender and physical deformities. This leads to a social stigma on the person who is abnormal. The person who is experiencing stigma has been said to be having a spoiled identity..

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Wendy and Peter want to buy property together. Wendy will be contributing $70,000.00 of the $100,000.00 purchase price, while Peter will be contributing $30,000.00. Wendy has two brothers, John and Michael, whom she loves very much and she really wants them to inherit her share of the property after her death. Tenants in Common can own unequal percentages of the property, allowing the co-owners to take into account varying levels of contribution. Upon the death of a tenant in common, the share owned by the decedent passes through his or her estate to the beneficiaries determined by will, if applicable, or by intestate succession (without a will). Joint Tenants must own equal percentages, regardless of contribution. Upon the death of a joint tenant, the share owned by the decedent goes to the surviving joint tenant. Assume that Wendy and Peter assume ownership in the property as tenants in common. What would happen to Wendy’s share in the property if Wendy died before Peter? Peter would acquire her ownership interest, taking sole title to the entire property. Wendy’s share would go to her estate, to be distributed via her will or via intestate succession. Wendy’s share would go directly to John and Michael, because your siblings always get your property upon death. Wendy’s share would go to her parents. Assume that Wendy and Peter assume ownership in the property as joint tenants. What would happen to Wendy’s share in the property if Wendy died before Peter? Peter would acquire her ownership interest, taking sole title to the entire property. Wendy’s share would go to her estate, to be distributed via her will or via intestate succession. Wendy\'s share would go directly to John and Michael, because your siblings also get your property upon death. d. Wendy\'s share would go to her parents. Assume that Wendy and Peter assume ownership in the property as tenants in common. What is the percentage of ownership interest that each is most likely to have in the property? Wendy would own 70% and Peter would own 30%. Wendy would own 30% and Peter would own 70%. Wendy would own 100%. Wendy would own 50% and Peter would own 50%.a. Peter would acquire her ownership interest, taking sole title to the entire property.b. Wendy’s share would go to her estate, to be distributed via her will or via intestate succession.c. Wendy’s share would go directly to John and Michael, because your siblings always get your property upon death.d. Wendy’s share would go to her parents. Solution Assume that Wendy and Peter assume ownership in the property as tenants in common. What would happen to Wendy’s share in the property if Wendy died before Peter? Wendy’s share would go to her estate, to be distributed via her will or via intestate succession. Assume that Wendy and Peter assume ownership in the property as tenants in common. What is the percentage of ownership interest that each is most likely to have in the property? Wendy would own 70% and Peter would own 30%.b. Wend.

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