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Find the values of the trigonometric functions of t from the given information. tan(t) = - 8/15,
cos(t) > 0 sin(t) = cos(t) = CSC (t) = sec(t) = cot(t) =
Solution
Here w ehave tan(t) = 8/15
and we know tan() = Perpendicular/Base
so we have Perpendicular = 8 and Base = 15 , now we can calculate Hypotenuse from these
values
hynpotenuse2 = perpendicular2 + base2
hypotenuse2 = 8*8+15*15
hypotenuse2 = 289 (64+225)
hypotenuse = 17 (sqaure root of 289)
Now we will get the value of other functions
sin(t) = Perpendicular/Hynpotenuse
sint(t) = 8/17
cost(t)= Base/Hynpotenuse
cost(t) = 15/17
csc(t) = Hynpotenuse/Perpendicular
csc(t) = 17/8
sec(t) = Hynpotenuse/Base
sec(t) = 17/15
cot(t) = Base/Perpendicular
cot(t0 = 15/8

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Find the values of the trigonometric functions of t from the given in.pdf

  • 1. Find the values of the trigonometric functions of t from the given information. tan(t) = - 8/15, cos(t) > 0 sin(t) = cos(t) = CSC (t) = sec(t) = cot(t) = Solution Here w ehave tan(t) = 8/15 and we know tan() = Perpendicular/Base so we have Perpendicular = 8 and Base = 15 , now we can calculate Hypotenuse from these values hynpotenuse2 = perpendicular2 + base2 hypotenuse2 = 8*8+15*15 hypotenuse2 = 289 (64+225) hypotenuse = 17 (sqaure root of 289) Now we will get the value of other functions sin(t) = Perpendicular/Hynpotenuse sint(t) = 8/17 cost(t)= Base/Hynpotenuse cost(t) = 15/17 csc(t) = Hynpotenuse/Perpendicular csc(t) = 17/8 sec(t) = Hynpotenuse/Base sec(t) = 17/15 cot(t) = Base/Perpendicular cot(t0 = 15/8