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Reaction Reagents Added Groups Regioselectivity Stereoselectivity
Hydrohalogenations
HBr -H -Br Markovnikov Mixed
HBr, ROOR -H -Br Anti-Markovnikov Mixed
Halogenation Br2 -Br -Br N/A Anti
Halohydrin Formation Br2, H2O (or ROH) -Br -OH (or OR) "Markovnikov" Anti
Acid Catalyzed Hydration H2SO4, H2O -H -OH Markovnikov Mixed
Oxymercuration-Demercuration
1) Hg(Oac)2, H2O
-H -OH Markovnikov Anti
2) NaBH4
Hydroboration-Oxidation
1) BH3·THF, H2O
-H -OH Anti-Markovnikov Syn
2) H2O2, NaOH
Hydroxlyation KMnO4 or OsO4 -OH -OH N/A Syn
Epoxidation mCPBA (RCO3H) Epoxide Ring N/A Syn
Hydrogenation H2, Ni/Pt/Pd cat. -H -H N/A Syn
ContinuePrevious
For each transformation shown, propose an acceptable reaction mechanism. Be sure to use
proper arrow pushing, and include all lone pairs and formal charges.
A)
C) D)
B)
BA C D
Check Your Answers
1
NextBack
For each transformation shown, propose an acceptable reaction mechanism. Be sure to use
proper arrow pushing, and include all lone pairs and formal charges.
A)
C) D)
B)
BA C D
Check Your Answers
2
NextBack
Predict the product in each of following reactions.
A)
C) D)
B)
B DCA
Check Your Answers
3
NextBack
For each transformation shown, propose an acceptable reaction mechanism. Be sure to use
proper arrow pushing, and include all lone pairs and formal charges.
A)
C)
D)
For additional practice, determine if the products shown are chiral and if so, propose a
separate mechanism for the formation of its enantiomer.
B)
BA C D
Check Your Answers
4
NextBack
For each transformation shown, propose an acceptable reaction mechanism. Be sure to use
proper arrow pushing, and include all lone pairs and formal charges.
A) B)
C) D)
(±)
(±)
(±)(±)
BA C D
Check Your Answers
5
NextBack
Predict the major product(s) in each of the following reactions.
A)
B)
C)
E)
F)
D)
BA C D
Check Your Answers
E F
6
NextBack
D)
For each transformation shown, propose an acceptable reaction mechanism accounting for the
products shown. Be sure to use proper arrow pushing, and include all lone pairs and formal
charges.
Acid-Catalyzed Hydration
A)
B)
C)
BA C D
Check Your Answers
7
NextBack
Acid-Catalyzed Hydration
A)
B)
C)
D)
E)
F)
Predict the major product in each of the following reactions.
BA C D
Check Your Answers
E F
8
NextBack
Complete the mechanism pathway for the oxymercuration of propene by filling in the missing
arrows, lone pairs, and formal charges.
The reductive demercuration step involves a more complex mechanism pathway in which the acetomercury
group is displaced by a borohydride hydrogen. (You do not need to show this)
Oxymercuration-Demercuration
Check Answer
This reaction can be used to achieve “Markovnikov” additions of H2O
to an alkene without the possibility of rearrangements.
Explain why this is.
9
NextBack
Oxymercuration-Demercuration
A)
B)
C)
D)
Predict the major product in each of the following reactions.
BA C D
Check Your Answers
10
NextBack
Hydroboration-Oxidation of an alkene is a 2 step process as shown in the reaction above. Fill in
the missing intermediate compounds for the hydroboration portion of this reaction below. Use
arrows to account for the formation of the intermediates.
Hydroboration-Oxidation
Speculate as to why the successive intermediates become increasingly more regioselective for
the anti-markovnikov orientation.
Check Answer
11
NextBack
Hydroboration-Oxidation
Predict the major product in each of the following reactions.
A)
B)
D)
C)
E)
BA C D
Check Your Answers
E
12
NextBack
A)
B)
Predict the major product in each of the following reactions.
C)
D)
BA C D
Check Your Answers
13
NextBack
For each transformation shown, propose an acceptable chemical mechanism. Be sure to use
proper arrow pushing, and include all lone pairs and formal charges.
A)
B)
C)
D)
BA C D
Check Your Answers
14
NextBack
A)
B)
Predict the major product in each of the following reactions.
C)
D)
BA C D
Check Your Answers
15
NextBack
A)
B)
C)
Predict the major product in each of the following reactions.
D)
E)
F)
BA C D
Check Your Answers
E F
16
NextBack
Predict the major product in each of the following reactions.
BA C E
Check Your Answers
D
17
NextBack
Predict the major product in each of the following reactions.
BA C D
Check Your Answers
E F
18
NextBack
Predict the reagent(s) needed to accomplish the following transformations.
BA C D
Check Your Answers
E
19
NextBack
End of Exercises
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The next slides contain only the answers. There
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Hydrohalogenation of Alkenes (I)
Exercise A
For each transformation make sure your mechanism correctly accounts for the Markovnikov
addition of HX.
Return to
Question
Hydrohalogenation of Alkenes (I)
(Exercise B)
For each transformation make sure your mechanism correctly accounts for the Markovnikov
addition of HX.
Return to
Question
Hydrohalogenation of Alkenes (I)
(Exercise C)
For each transformation make sure your mechanism correctly accounts for the Markovnikov
addition of HX.
Return to
Question
Hydrohalogenation of Alkenes (I)
Exercise DFor each transformation make sure your mechanism correctly accounts for the Markovnikov
addition of HX.
Return to
Question
Hydrohalogenation of Alkenes (II)
(Exercise A)
Each of the following mechanisms first involves homolytic cleavage of a peroxide and the
subsequent creation of a bromine radical:
Return to
Question
Hydrohalogenation of Alkenes (II)
(Exercise B)
Each of the following mechanisms first involves homolytic cleavage of a peroxide and the
subsequent creation of a bromine radical:
Return to
Question
Hydrohalogenation of Alkenes (II)
(Exercise C)
Each of the following mechanisms first involves homolytic cleavage of a peroxide and the
subsequent creation of a bromine radical:
Return to
Question
Hydrohalogenation of Alkenes (II)
(Exercise D)
Each of the following mechanisms first involves homolytic cleavage of a peroxide and the
subsequent creation of a bromine radical:
Return to
Question
Hydrohalogenation of Alkenes (III)
(Exercise A)
Return to
Question
Hydrohalogenation of Alkenes (III)
(Exercise B)
Return to
Question
Hydrohalogenation of Alkenes (III)
(Exercise C)
Return to
Question
Hydrohalogenation of Alkenes (III)
(Exercise D)
Return to
Question
Reactions Involving Halonium Ion Intermediates (I)
(Exercise A)
Return to
Question
Reactions Involving Halonium Ion Intermediates (I)
(Exercise B)
Return to
Question
Reactions Involving Halonium Ion Intermediates (I)
(Exercise C)
Return to
Question
Reactions Involving Halonium Ion Intermediates (I)
(Exercise D)
Return to
Question
Reactions Involving Halonium Ion Intermediates (II)
(Exercise A)
Return to
Question
Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents
are typically present in large excess compared to reagents. In terms of probability, what would be the more
likely base, the solvent (H2O) or a reagent (Br-)?
When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors
in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj.
base of a strong acid)?
Reactions Involving Halonium Ion Intermediates (II)
(Exercise B)
Return to
Question
Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents
are typically present in large excess compared to reagents. In terms of probability, what would be the more
likely base, the solvent (H2O) or a reagent (Br-)?
When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors
in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj.
base of a strong acid)?
Reactions Involving Halonium Ion Intermediates (II)
(Exercise C)
Return to
Question
Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents
are typically present in large excess compared to reagents. In terms of probability, what would be the more
likely base, the solvent (H2O) or a reagent (Br-)?
When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors
in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj.
base of a strong acid)?
Reactions Involving Halonium Ion Intermediates (II)
(Exercise D)
Return to
Question
Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents
are typically present in large excess compared to reagents. In terms of probability, what would be the more
likely base, the solvent (H2O) or a reagent (Br-)?
When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors
in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj.
base of a strong acid)?
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
Return to
Question
A)
Reactions Involving Halonium Ion Intermediates (III)
(Exercise A)
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
Return to
Question
B)
Reactions Involving Halonium Ion Intermediates (III)
(Exercise A)
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
Return to
Question
C)
Reactions Involving Halonium Ion Intermediates (III)
(Exercise C)
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
Return to
Question
D)
Reactions Involving Halonium Ion Intermediates (III)
(Exercise D)
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
E)
Return to
Question
Reactions Involving Halonium Ion Intermediates (III)
(Exercise E)
Be mindful of the creation of chiral products and when this is the case, indicate so by either
drawing out both enantiomers or indicating the presence of the enantiomer.
Return to
Question
F)
Reactions Involving Halonium Ion Intermediates (III)
(Exercise F)
The first step installs two leaving groups (the halogens) and the second step involves E2
between the base and each alkyl halide (two individual eliminations for each Cl).
Additions of H2O to Alkenes (I)
(Exercise A)
Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a
proton be added to the alkene in such a way that the resulting carbocation is in the more stable
location?”
Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with
its regeneration
Acid-Catalyzed Hydration
Return to
Question
Additions of H2O to Alkenes (I)
(Exercise B)
Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a
proton be added to the alkene in such a way that the resulting carbocation is in the more stable
location?”
Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with
its regeneration
Acid-Catalyzed Hydration
Return to
Question
Additions of H2O to Alkenes (I)
(Exercise C)
Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a
proton be added to the alkene in such a way that the resulting carbocation is in the more stable
location?”
Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with
its regeneration
Acid-Catalyzed Hydration
Return to
Question
Additions of H2O to Alkenes (I)
(Exercise D)
Each if the three products involves a rearrangement of the carbocation intermediate. The answer
below shows the rearrangement steps using green arrows for clarity.
Acid-Catalyzed Hydration
Return to
Question
Additions of H2O to Alkenes (II)
(Exercise A)
Acid-Catalyzed Hydration
Return to
Question
A)
Additions of H2O to Alkenes (II)
(Exercise B)
Acid-Catalyzed Hydration
Return to
Question
B)
Additions of H2O to Alkenes (II)
(Exercise C)
Acid-Catalyzed Hydration
Return to
Question
C)
Additions of H2O to Alkenes (II)
(Exercise D)
Acid-Catalyzed Hydration
Return to
Question
D)
Additions of H2O to Alkenes (II)
(Exercise E)
Acid-Catalyzed Hydration
Return to
Question
E)
Additions of H2O to Alkenes (II)
(Exercise F)
Acid-Catalyzed Hydration
Return to
Question
F)
(Ring Expansion Product)
Additions of H2O to Alkenes (III)
Oxymercuration-Demercuration
Rearrangements are not observed because no carbocation is ever
generated in the mechanism and therefore no carbocation shifts can occur.
The carbons in this case only develop partial charges and the water attacks
the more substituted location (similar to bromonium ion) that results in
the final markovnikov orientation.
Return to
Question
Additions of H2O to Alkenes (IV)
(Exercise A)
Oxymercuration-Demercuration
Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism
when appropriate.
Return to
Question
A)
Additions of H2O to Alkenes (IV)
(Exercise B)
Oxymercuration-Demercuration
Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism
when appropriate.
Return to
Question
B)
Additions of H2O to Alkenes (IV)
(Exercise C)
Oxymercuration-Demercuration
Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism
when appropriate.
Return to
Question
C)
Additions of H2O to Alkenes (IV)
(Exercise D)
Oxymercuration-Demercuration
Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism
when appropriate.
Return to
Question
D)
Additions of H2O to Alkenes (V)
Hydroboration-Oxidation
As successive alkyl groups are added, steric bulk increases and increasingly favors a transition
state that minimizes steric forces. The anti-markovnikov orientation is thus preferred; the more
substituted alkene carbon across from the smaller borohydride H.
Return to
Question
Additions of H2O to Alkenes (VI)
(Exercise A)
Hydroboration-Oxidation
Return to
Question
You should consider both regio and stereo selectivity when predicting the
products. Be mindful of any chiral products that are generated.
A)
Additions of H2O to Alkenes (VI)
(Exercise B)
Hydroboration-Oxidation
Return to
Question
You should consider both regio and stereo selectivity when predicting the
products. Be mindful of any chiral products that are generated.
B)
Additions of H2O to Alkenes (VI)
(Exercise C)
Hydroboration-Oxidation
Return to
Question
You should consider both regio and stereo selectivity when predicting the
products. Be mindful of any chiral products that are generated.
C)
Additions of H2O to Alkenes (VI)
(Exercise D)
Hydroboration-Oxidation
Return to
Question
You should consider both regio and stereo selectivity when predicting the
products. Be mindful of any chiral products that are generated.
D)
Additions of H2O to Alkenes (VI)
(Exercise E)
Hydroboration-Oxidation
Return to
Question
You should consider both regio and stereo selectivity when predicting the
products. Be mindful of any chiral products that are generated.
E)
Epoxidation Reactions
(Exercise A)
A)
Return to
Question
Epoxidation Reactions
(Exercise B)
B)
Return to
Question
Epoxidation Reactions
(Exercise C)
C)
Return to
Question
Epoxidation Reactions
(Exercise D)
D)
Return to
Question
Acid/Base Catalyzed Ring Openings of Epoxides (I)
(Exercise A)
Return to
Question
Acid/Base Catalyzed Ring Openings of Epoxides (I)
(Exercise B)
Return to
Question
Acid/Base Catalyzed Ring Openings of Epoxides (I)
(Exercise C)
Return to
Question
Acid/Base Catalyzed Ring Openings of Epoxides (I)
(Exercise D)
Return to
Question
Acid/Base Catalyzed Ring Openings of Epoxides (II)
(Exercise A)
Return to
Question
A)
Acid/Base Catalyzed Ring Openings of Epoxides (II)
(Exercise B)
Return to
Question
B)
Acid/Base Catalyzed Ring Openings of Epoxides (II)
(Exercise C)
Return to
Question
C)
Acid/Base Catalyzed Ring Openings of Epoxides (II)
(Exercise D)
Return to
Question
D)
A)
Oxidative Cleavage via Ozonolysis
(Example A)
Return to
Question
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
Oxidative Cleavage via Ozonolysis
(Example B)
Return to
Question
B)
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
Oxidative Cleavage via Ozonolysis
(Example C)
Return to
Question
C)
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
Oxidative Cleavage via Ozonolysis
(Example D)
Return to
Question
D)
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
Oxidative Cleavage via Ozonolysis
(Example E)
Return to
Question
E)
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
Oxidative Cleavage via Ozonolysis
(Example F)
Return to
Question
*NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be
“reductive” workups for their ability to leave 1° carbons as aldehydes. However there are
other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed
“oxidative” workups.
The terms “reductive” and “oxidative” in this case are relative to each other; both workups
still yield products that are more oxidized than the alkene staring material.
The pi-bonds within the phenyl ring are less reactive (due to aromatic properties) and are
thus resistant to ozonolysis.
Predict the Products (I)
(Exercise A)
Return to
Question
A)
Predict the Products (I)
(Exercise B)
Return to
Question
B)
Predict the Products (I)
(Exercise C)
Return to
Question
C)
Predict the Products (I)
(Exercise D)
Return to
Question
D)
Predict the Products (I)
(Exercise E)
Return to
Question
E)
Predict the Products (II)
(Exercise A)
Return to
Question
A)
Predict the Products (II)
(Exercise B)
Return to
Question
B)
Predict the Products (II)
(Exercise C)
Return to
Question
C)
Predict the Products (II)
(Exercise D)
Return to
Question
D)
Predict the Products (II)
(Exercise E)
Return to
Question
E)
Predict the Products (II)
(Exercise F)
Return to
Question
F)
Predict the Reagents
(Exercise A)
Return to
Question
A)
Predict the Reagents
(Exercise B)
Return to
Question
B)
Predict the Reagents
(Exercise C)
Return to
Question
C)
Predict the Reagents
(Exercise D)
Return to
Question
D)
Predict the Reagents
(Exercise E)
Return to
Question
E)
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Alkene reaction exercises v3.2

  • 1. Prepared by Bill Weigel and Dr. Laurie Starkey [Version 3.2] Begin
  • 2. A fully interactive version of this presentation with functioning navigation buttons can be found here: (Adobe Flash Player is required) https://connect.csupomona.edu/alkenepracticeproblems
  • 3. These exercises are part of research project being conducted at Cal Poly Pomona. We would appreciate your feedback so we can evaluate this current version and continue to improve it. To help us in this endeavor, follow the link that can be found on the last slide to take a short online survey (please spend some time with the problems first). Thank you for your help. Continue
  • 5. Reaction Reagents Added Groups Regioselectivity Stereoselectivity Hydrohalogenations HBr -H -Br Markovnikov Mixed HBr, ROOR -H -Br Anti-Markovnikov Mixed Halogenation Br2 -Br -Br N/A Anti Halohydrin Formation Br2, H2O (or ROH) -Br -OH (or OR) "Markovnikov" Anti Acid Catalyzed Hydration H2SO4, H2O -H -OH Markovnikov Mixed Oxymercuration-Demercuration 1) Hg(Oac)2, H2O -H -OH Markovnikov Anti 2) NaBH4 Hydroboration-Oxidation 1) BH3·THF, H2O -H -OH Anti-Markovnikov Syn 2) H2O2, NaOH Hydroxlyation KMnO4 or OsO4 -OH -OH N/A Syn Epoxidation mCPBA (RCO3H) Epoxide Ring N/A Syn Hydrogenation H2, Ni/Pt/Pd cat. -H -H N/A Syn ContinuePrevious
  • 6. For each transformation shown, propose an acceptable reaction mechanism. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. A) C) D) B) BA C D Check Your Answers 1 NextBack
  • 7. For each transformation shown, propose an acceptable reaction mechanism. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. A) C) D) B) BA C D Check Your Answers 2 NextBack
  • 8. Predict the product in each of following reactions. A) C) D) B) B DCA Check Your Answers 3 NextBack
  • 9. For each transformation shown, propose an acceptable reaction mechanism. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. A) C) D) For additional practice, determine if the products shown are chiral and if so, propose a separate mechanism for the formation of its enantiomer. B) BA C D Check Your Answers 4 NextBack
  • 10. For each transformation shown, propose an acceptable reaction mechanism. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. A) B) C) D) (±) (±) (±)(±) BA C D Check Your Answers 5 NextBack
  • 11. Predict the major product(s) in each of the following reactions. A) B) C) E) F) D) BA C D Check Your Answers E F 6 NextBack
  • 12. D) For each transformation shown, propose an acceptable reaction mechanism accounting for the products shown. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. Acid-Catalyzed Hydration A) B) C) BA C D Check Your Answers 7 NextBack
  • 13. Acid-Catalyzed Hydration A) B) C) D) E) F) Predict the major product in each of the following reactions. BA C D Check Your Answers E F 8 NextBack
  • 14. Complete the mechanism pathway for the oxymercuration of propene by filling in the missing arrows, lone pairs, and formal charges. The reductive demercuration step involves a more complex mechanism pathway in which the acetomercury group is displaced by a borohydride hydrogen. (You do not need to show this) Oxymercuration-Demercuration Check Answer This reaction can be used to achieve “Markovnikov” additions of H2O to an alkene without the possibility of rearrangements. Explain why this is. 9 NextBack
  • 15. Oxymercuration-Demercuration A) B) C) D) Predict the major product in each of the following reactions. BA C D Check Your Answers 10 NextBack
  • 16. Hydroboration-Oxidation of an alkene is a 2 step process as shown in the reaction above. Fill in the missing intermediate compounds for the hydroboration portion of this reaction below. Use arrows to account for the formation of the intermediates. Hydroboration-Oxidation Speculate as to why the successive intermediates become increasingly more regioselective for the anti-markovnikov orientation. Check Answer 11 NextBack
  • 17. Hydroboration-Oxidation Predict the major product in each of the following reactions. A) B) D) C) E) BA C D Check Your Answers E 12 NextBack
  • 18. A) B) Predict the major product in each of the following reactions. C) D) BA C D Check Your Answers 13 NextBack
  • 19. For each transformation shown, propose an acceptable chemical mechanism. Be sure to use proper arrow pushing, and include all lone pairs and formal charges. A) B) C) D) BA C D Check Your Answers 14 NextBack
  • 20. A) B) Predict the major product in each of the following reactions. C) D) BA C D Check Your Answers 15 NextBack
  • 21. A) B) C) Predict the major product in each of the following reactions. D) E) F) BA C D Check Your Answers E F 16 NextBack
  • 22. Predict the major product in each of the following reactions. BA C E Check Your Answers D 17 NextBack
  • 23. Predict the major product in each of the following reactions. BA C D Check Your Answers E F 18 NextBack
  • 24. Predict the reagent(s) needed to accomplish the following transformations. BA C D Check Your Answers E 19 NextBack
  • 25. End of Exercises We would like to evaluate these exercises by seeing how helpful you found them. Please click the link below to take a quick 3 minute survey: Begin Survey 20 Previous
  • 26. The next slides contain only the answers. There are no more questions from this point forward.
  • 27. Hydrohalogenation of Alkenes (I) Exercise A For each transformation make sure your mechanism correctly accounts for the Markovnikov addition of HX. Return to Question
  • 28. Hydrohalogenation of Alkenes (I) (Exercise B) For each transformation make sure your mechanism correctly accounts for the Markovnikov addition of HX. Return to Question
  • 29. Hydrohalogenation of Alkenes (I) (Exercise C) For each transformation make sure your mechanism correctly accounts for the Markovnikov addition of HX. Return to Question
  • 30. Hydrohalogenation of Alkenes (I) Exercise DFor each transformation make sure your mechanism correctly accounts for the Markovnikov addition of HX. Return to Question
  • 31. Hydrohalogenation of Alkenes (II) (Exercise A) Each of the following mechanisms first involves homolytic cleavage of a peroxide and the subsequent creation of a bromine radical: Return to Question
  • 32. Hydrohalogenation of Alkenes (II) (Exercise B) Each of the following mechanisms first involves homolytic cleavage of a peroxide and the subsequent creation of a bromine radical: Return to Question
  • 33. Hydrohalogenation of Alkenes (II) (Exercise C) Each of the following mechanisms first involves homolytic cleavage of a peroxide and the subsequent creation of a bromine radical: Return to Question
  • 34. Hydrohalogenation of Alkenes (II) (Exercise D) Each of the following mechanisms first involves homolytic cleavage of a peroxide and the subsequent creation of a bromine radical: Return to Question
  • 35. Hydrohalogenation of Alkenes (III) (Exercise A) Return to Question
  • 36. Hydrohalogenation of Alkenes (III) (Exercise B) Return to Question
  • 37. Hydrohalogenation of Alkenes (III) (Exercise C) Return to Question
  • 38. Hydrohalogenation of Alkenes (III) (Exercise D) Return to Question
  • 39. Reactions Involving Halonium Ion Intermediates (I) (Exercise A) Return to Question
  • 40. Reactions Involving Halonium Ion Intermediates (I) (Exercise B) Return to Question
  • 41. Reactions Involving Halonium Ion Intermediates (I) (Exercise C) Return to Question
  • 42. Reactions Involving Halonium Ion Intermediates (I) (Exercise D) Return to Question
  • 43. Reactions Involving Halonium Ion Intermediates (II) (Exercise A) Return to Question Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents are typically present in large excess compared to reagents. In terms of probability, what would be the more likely base, the solvent (H2O) or a reagent (Br-)? When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj. base of a strong acid)?
  • 44. Reactions Involving Halonium Ion Intermediates (II) (Exercise B) Return to Question Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents are typically present in large excess compared to reagents. In terms of probability, what would be the more likely base, the solvent (H2O) or a reagent (Br-)? When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj. base of a strong acid)?
  • 45. Reactions Involving Halonium Ion Intermediates (II) (Exercise C) Return to Question Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents are typically present in large excess compared to reagents. In terms of probability, what would be the more likely base, the solvent (H2O) or a reagent (Br-)? When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj. base of a strong acid)?
  • 46. Reactions Involving Halonium Ion Intermediates (II) (Exercise D) Return to Question Bromide and water have lone pairs that in theory can allow either to act as a lewis base. However, solvents are typically present in large excess compared to reagents. In terms of probability, what would be the more likely base, the solvent (H2O) or a reagent (Br-)? When proposing deprotonations, also take into consideration the relative strengths of any proton acceptors in solution. What will be more likely to perform deprotonation, water (a weak base) or bromide (the conj. base of a strong acid)?
  • 47. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. Return to Question A) Reactions Involving Halonium Ion Intermediates (III) (Exercise A)
  • 48. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. Return to Question B) Reactions Involving Halonium Ion Intermediates (III) (Exercise A)
  • 49. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. Return to Question C) Reactions Involving Halonium Ion Intermediates (III) (Exercise C)
  • 50. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. Return to Question D) Reactions Involving Halonium Ion Intermediates (III) (Exercise D)
  • 51. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. E) Return to Question Reactions Involving Halonium Ion Intermediates (III) (Exercise E)
  • 52. Be mindful of the creation of chiral products and when this is the case, indicate so by either drawing out both enantiomers or indicating the presence of the enantiomer. Return to Question F) Reactions Involving Halonium Ion Intermediates (III) (Exercise F) The first step installs two leaving groups (the halogens) and the second step involves E2 between the base and each alkyl halide (two individual eliminations for each Cl).
  • 53. Additions of H2O to Alkenes (I) (Exercise A) Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a proton be added to the alkene in such a way that the resulting carbocation is in the more stable location?” Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with its regeneration Acid-Catalyzed Hydration Return to Question
  • 54. Additions of H2O to Alkenes (I) (Exercise B) Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a proton be added to the alkene in such a way that the resulting carbocation is in the more stable location?” Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with its regeneration Acid-Catalyzed Hydration Return to Question
  • 55. Additions of H2O to Alkenes (I) (Exercise C) Be sure to correctly apply Markovnikov’s Rule in your mechanism. Ask the question “How can a proton be added to the alkene in such a way that the resulting carbocation is in the more stable location?” Note how the acid-catalyzed mechanism begins with the consumption of the acid and ends with its regeneration Acid-Catalyzed Hydration Return to Question
  • 56. Additions of H2O to Alkenes (I) (Exercise D) Each if the three products involves a rearrangement of the carbocation intermediate. The answer below shows the rearrangement steps using green arrows for clarity. Acid-Catalyzed Hydration Return to Question
  • 57. Additions of H2O to Alkenes (II) (Exercise A) Acid-Catalyzed Hydration Return to Question A)
  • 58. Additions of H2O to Alkenes (II) (Exercise B) Acid-Catalyzed Hydration Return to Question B)
  • 59. Additions of H2O to Alkenes (II) (Exercise C) Acid-Catalyzed Hydration Return to Question C)
  • 60. Additions of H2O to Alkenes (II) (Exercise D) Acid-Catalyzed Hydration Return to Question D)
  • 61. Additions of H2O to Alkenes (II) (Exercise E) Acid-Catalyzed Hydration Return to Question E)
  • 62. Additions of H2O to Alkenes (II) (Exercise F) Acid-Catalyzed Hydration Return to Question F) (Ring Expansion Product)
  • 63. Additions of H2O to Alkenes (III) Oxymercuration-Demercuration Rearrangements are not observed because no carbocation is ever generated in the mechanism and therefore no carbocation shifts can occur. The carbons in this case only develop partial charges and the water attacks the more substituted location (similar to bromonium ion) that results in the final markovnikov orientation. Return to Question
  • 64. Additions of H2O to Alkenes (IV) (Exercise A) Oxymercuration-Demercuration Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism when appropriate. Return to Question A)
  • 65. Additions of H2O to Alkenes (IV) (Exercise B) Oxymercuration-Demercuration Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism when appropriate. Return to Question B)
  • 66. Additions of H2O to Alkenes (IV) (Exercise C) Oxymercuration-Demercuration Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism when appropriate. Return to Question C)
  • 67. Additions of H2O to Alkenes (IV) (Exercise D) Oxymercuration-Demercuration Consider both regiochemistry and stereochemistry. Remember to indicate stereoisomerism when appropriate. Return to Question D)
  • 68. Additions of H2O to Alkenes (V) Hydroboration-Oxidation As successive alkyl groups are added, steric bulk increases and increasingly favors a transition state that minimizes steric forces. The anti-markovnikov orientation is thus preferred; the more substituted alkene carbon across from the smaller borohydride H. Return to Question
  • 69. Additions of H2O to Alkenes (VI) (Exercise A) Hydroboration-Oxidation Return to Question You should consider both regio and stereo selectivity when predicting the products. Be mindful of any chiral products that are generated. A)
  • 70. Additions of H2O to Alkenes (VI) (Exercise B) Hydroboration-Oxidation Return to Question You should consider both regio and stereo selectivity when predicting the products. Be mindful of any chiral products that are generated. B)
  • 71. Additions of H2O to Alkenes (VI) (Exercise C) Hydroboration-Oxidation Return to Question You should consider both regio and stereo selectivity when predicting the products. Be mindful of any chiral products that are generated. C)
  • 72. Additions of H2O to Alkenes (VI) (Exercise D) Hydroboration-Oxidation Return to Question You should consider both regio and stereo selectivity when predicting the products. Be mindful of any chiral products that are generated. D)
  • 73. Additions of H2O to Alkenes (VI) (Exercise E) Hydroboration-Oxidation Return to Question You should consider both regio and stereo selectivity when predicting the products. Be mindful of any chiral products that are generated. E)
  • 78. Acid/Base Catalyzed Ring Openings of Epoxides (I) (Exercise A) Return to Question
  • 79. Acid/Base Catalyzed Ring Openings of Epoxides (I) (Exercise B) Return to Question
  • 80. Acid/Base Catalyzed Ring Openings of Epoxides (I) (Exercise C) Return to Question
  • 81. Acid/Base Catalyzed Ring Openings of Epoxides (I) (Exercise D) Return to Question
  • 82. Acid/Base Catalyzed Ring Openings of Epoxides (II) (Exercise A) Return to Question A)
  • 83. Acid/Base Catalyzed Ring Openings of Epoxides (II) (Exercise B) Return to Question B)
  • 84. Acid/Base Catalyzed Ring Openings of Epoxides (II) (Exercise C) Return to Question C)
  • 85. Acid/Base Catalyzed Ring Openings of Epoxides (II) (Exercise D) Return to Question D)
  • 86. A) Oxidative Cleavage via Ozonolysis (Example A) Return to Question *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material.
  • 87. Oxidative Cleavage via Ozonolysis (Example B) Return to Question B) *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material.
  • 88. Oxidative Cleavage via Ozonolysis (Example C) Return to Question C) *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material.
  • 89. Oxidative Cleavage via Ozonolysis (Example D) Return to Question D) *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material.
  • 90. Oxidative Cleavage via Ozonolysis (Example E) Return to Question E) *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material.
  • 91. Oxidative Cleavage via Ozonolysis (Example F) Return to Question *NOTE* The reagents used in the second step of these reactions (Zn and DMS) are said to be “reductive” workups for their ability to leave 1° carbons as aldehydes. However there are other reagents (H2O2) that that convert 1° carbons to carboxylic acids and are thus termed “oxidative” workups. The terms “reductive” and “oxidative” in this case are relative to each other; both workups still yield products that are more oxidized than the alkene staring material. The pi-bonds within the phenyl ring are less reactive (due to aromatic properties) and are thus resistant to ozonolysis.
  • 92. Predict the Products (I) (Exercise A) Return to Question A)
  • 93. Predict the Products (I) (Exercise B) Return to Question B)
  • 94. Predict the Products (I) (Exercise C) Return to Question C)
  • 95. Predict the Products (I) (Exercise D) Return to Question D)
  • 96. Predict the Products (I) (Exercise E) Return to Question E)
  • 97. Predict the Products (II) (Exercise A) Return to Question A)
  • 98. Predict the Products (II) (Exercise B) Return to Question B)
  • 99. Predict the Products (II) (Exercise C) Return to Question C)
  • 100. Predict the Products (II) (Exercise D) Return to Question D)
  • 101. Predict the Products (II) (Exercise E) Return to Question E)
  • 102. Predict the Products (II) (Exercise F) Return to Question F)
  • 103. Predict the Reagents (Exercise A) Return to Question A)
  • 104. Predict the Reagents (Exercise B) Return to Question B)
  • 105. Predict the Reagents (Exercise C) Return to Question C)
  • 106. Predict the Reagents (Exercise D) Return to Question D)
  • 107. Predict the Reagents (Exercise E) Return to Question E)
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Editor's Notes

  1. Change Log V2.0 – Added Survey Links V3.0 – Ungrouped hyperlinks for connect functionality V3.1 – Added extra navigation buttons V3.2 – Fixed continuity errors in 6C, 6F and 14C, -specified stereochemistry for 13C and 13D, -Modified 16F to correctly reflect the phenyl group reactivity -Fixed hyperlinks to correct answers on questions 3A and 3D
  2. A fully interactive version of this presentation with functioning navigation buttons can be found here: https://connect.csupomona.edu/alkenepracticeproblems