The document describes an algorithm to determine if an undirected graph G can be viewed as a perfect left-sided binary tree. It provides BFS and DFS algorithms in pseudocode that take G as input and return true if G is a perfect left-sided binary tree and false otherwise. Both algorithms have a time complexity of O(V+E) where V is the number of vertices and E is the number of edges in G.
A perfect left-sided binary tree is a binary tree where every intern.pdf
1. A perfect left-sided binary tree is a binary tree where every internal node has two children, and
every left child is a leaf. Write an algorithm, based on DFS or BFS, that takes as input an
undirected graph G, and returns whether or not G is (or can be viewed as) a perfect left-sided
binary tree. Analyze the time complexity of your algorithm.
Solution
bfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from start of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
dfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from end of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
2. search(vertex v)
{
visit(v);
for each edge (v,w)
add edge (v,w) to end of L
}
mport java.util.*;
public class BST > implements Iterable
{
public static void main(String[] args)
{
Integer[] a = {1,5,2,7,4};
BST bst = new BST();
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
//testing comparator
//build a mirror BST with a rule: Left > Parent > Right
//code for the comparator at the bottom of the file
bst = new BST(new MyComp1());
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
System.out.println();
for(Integer n : bst) System.out.print(n);
System.out.println();
System.out.println(bst);
//testing restoring a tree from two given traversals
bst.restore(new Integer[] {11,8,6,4,7,10,19,43,31,29,37,49},
new Integer[] {4,6,7,8,10,11,19,29,31,37,43,49});
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
8. {
if(p == null) return -1;
else
return 1 + Math.max( height(p.left), height(p.right));
}
public int countLeaves()
{
return countLeaves(root);
}
private int countLeaves(Node p)
{
if(p == null) return 0;
else
if(p.left == null && p.right == null) return 1;
else
return countLeaves(p.left) + countLeaves(p.right);
}
//This method restores a BST given preorder and inorder traversals
public void restore(T[] pre, T[] in)
{
root = restore(pre, 0, pre.length-1, in, 0, in.length-1);
}
private Node restore(T[] pre, int preL, int preR, T[] in, int inL, int inR)
{
if(preL <= preR)
{
int count = 0;
//find the root in the inorder array
while(pre[preL] != in[inL + count]) count++;
Node tmp = new Node(pre[preL]);
tmp.left = restore(pre, preL+1, preL + count, in, inL, inL +count-1);
tmp.right = restore(pre, preL+count+1, preR, in, inL+count+1, inR);
return tmp;
}
else
return null;
9. }
//The width of a binary tree is the maximum number of elements on one level of the tree.
public int width()
{
int max = 0;
for(int k = 0; k <= height(); k++)
{
int tmp = width(root, k);
if(tmp > max) max = tmp;
}
return max;
}
//rerturns the number of node on a given level
public int width(Node p, int depth)
{
if(p==null) return 0;
else
if(depth == 0) return 1;
else
return width(p.left, depth-1) + width(p.right, depth-1);
}
//The diameter of a tree is the number of nodes
//on the longest path between two leaves in the tree.
public int diameter()
{
return diameter(root);
}
private int diameter(Node p)
{
if(p==null) return 0;
//the path goes through the root
int len1 = height(p.left) + height(p.right) +3;
//the path does not pass the root
int len2 = Math.max(diameter(p.left), diameter(p.right));
return Math.max(len1, len2);
10. }
/*****************************************************
*
* TREE ITERATOR
*
******************************************************/
public Iterator iterator()
{
return new MyIterator();
}
//pre-order
private class MyIterator implements Iterator
{
Stack> stk = new Stack>();
public MyIterator()
{
if(root != null) stk.push(root);
}
public boolean hasNext()
{
return !stk.isEmpty();
}
public T next()
{
Node cur = stk.peek();
if(cur.left != null)
{
stk.push(cur.left);
}
else
{
Node tmp = stk.pop();
while( tmp.right == null )
{
if(stk.isEmpty()) return cur.data;
11. tmp = stk.pop();
}
stk.push(tmp.right);
}
return cur.data;
}//end of next()
public void remove()
{
}
}//end of MyIterator
/*****************************************************
*
* the Node class
*
******************************************************/
private class Node
{
private T data;
private Node left, right;
public Node(T data, Node l, Node r)
{
left = l; right = r;
this.data = data;
}
public Node(T data)
{
this(data, null, null);
}
public String toString()
{
return data.toString();
}
} //end of Node
}//end of BST
class MyComp1 implements Comparator
{