usingpackage util;import java.util.;This class implements.pdf
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using package util; import java.util.*; /* This class implements Binary Node for Binary Trees Methods: I) Two constructors II) Two toString methods III) height and size methods IV) preorder, postorder, and inorder traversals V) BFS and DFS traversal */ publicclass BinaryNode { public E element;//data public BinaryNode left;//left child public BinaryNode right;//right child //constructor for leaves public BinaryNode(E element){ this(element, null, null); } //constructor for internal nodes public BinaryNode(E element, BinaryNode left, BinaryNode right){ this.left = left; this.right = right; this.element = element; } @Override public String toString(){ if(left == null && right == null)//base case return element + ""; return element + "(" + left + ", " + right + ")"; } publicint height() { if(left == null && right == null) return 0; if(left == null) return 1 + right.height(); if(right == null) return 1 + left.height(); return 1 + Math.max(left.height(), right.height()); } publicint size(){ int size = 1;//counting root if(left != null)//counting left subtree nodes size += left.size(); if(right != null)//counting right subtree nodes size += right.size(); return size; } publicvoid printPreOrder(){ System.out.print(element + " "); if(left != null) left.printPreOrder(); if(right != null) right.printPreOrder(); } publicvoid printPostOrder(){ if(left != null) left.printPostOrder(); if(right != null) right.printPostOrder(); System.out.print(element + " "); } publicvoid printInOrder(){ if(left != null) left.printInOrder(); System.out.print(element + " "); if(right != null) right.printInOrder(); } publicvoid printBFS(){//breadth first search traversal - non-recursive method Queue q = new LinkedList<>(); q.add(this); while(!q.isEmpty()){ BinaryNode cur = q.remove(); System.out.print(cur.element + " "); if(cur.left != null) q.add(cur.left); if(cur.right != null) q.add(cur.right); } } publicvoid printDFS(){//depth first search traversal - equivalent to pre-order traversal Stack stack = new Stack<>(); stack.add(this); while(!stack.empty()){ BinaryNode cur = stack.pop(); System.out.print(cur.element + " "); if(cur.right != null) stack.push(cur.right); if(cur.left != null) stack.push(cur.left); } } public String toString2() { if(left == null && right == null && element == null) return ""; Queue list = new LinkedList<>(); String result = ""; list.add(this); list.add(null); int level = (int) Math.pow(2, height()); BinaryNode dummy = new BinaryNode(null); while(!list.isEmpty()) { boolean allDummies = true; for(BinaryNode b: list) if(b != dummy && b != null) { allDummies = false; break; } BinaryNode cur = list.remove(); if(cur == null || allDummies) break; for(int i = 0; i < level - 1;i++) result += '\t'; if(cur != dummy) result += cur.element; for(int i = 0; i < level + 1;i++) result += '\t'; if(cur.left != null) list.add(cur.left); else list.add(dummy); if(cur.right != null) list.add(cur.right); else list.add(dummy); if(list.peek() == null) { for(int i = 0; i < he.
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Given BinaryNode.javapackage util;import java.util.;T.pdf
Given BinaryNode.java
package util;
import java.util.*;
/*
This class implements Binary Node for Binary Trees
Methods:
I) Two constructors
II) Two toString methods
III) height and size methods
IV) preorder, postorder, and inorder traversals
V) BFS and DFS traversal
*/
public class BinaryNode {
public E element;//data
public BinaryNode left;//left child
public BinaryNode right;//right child
//constructor for leaves
public BinaryNode(E element) {
this(element, null, null);
}
//constructor for internal nodes
public BinaryNode(E element, BinaryNode left, BinaryNode right) {
this.left = left;
this.right = right;
this.element = element;
}
public String toString2() {
if (left == null && right == null)//base case
return element + "";
return element + "(" + left + ", " + right + ")";
}
public int height() {
if (left == null && right == null)
return 0;
if (left == null)
return 1 + right.height();
if (right == null)
return 1 + left.height();
return 1 + Math.max(left.height(), right.height());
}
public int size() {
int size = 1;//counting root
if (left != null)//counting left subtree nodes
size += left.size();
if (right != null)//counting right subtree nodes
size += right.size();
return size;
}
public void printPreOrder() {
System.out.print(element + " ");
if (left != null)
left.printPreOrder();
if (right != null)
right.printPreOrder();
}
public void printPostOrder() {
if (left != null)
left.printPostOrder();
if (right != null)
right.printPostOrder();
System.out.print(element + " ");
}
public void printInOrder() {
if (left != null)
left.printInOrder();
System.out.print(element + " ");
if (right != null)
right.printInOrder();
}
public void printBFS() {//breadth first search traversal - non-recursive method
Queue q = new LinkedList<>();
q.add(this);
while (!q.isEmpty()) {
BinaryNode cur = q.remove();
System.out.print(cur.element + " ");
if (cur.left != null)
q.add(cur.left);
if (cur.right != null)
q.add(cur.right);
}
}
public void printDFS() {//depth first search traversal - equivalent to pre-order traversal
Stack stack = new Stack<>();
stack.add(this);
while (!stack.empty()) {
BinaryNode cur = stack.pop();
System.out.print(cur.element + " ");
if (cur.right != null)
stack.push(cur.right);
if (cur.left != null)
stack.push(cur.left);
}
}
public String toString() {
if (left == null && right == null && element == null)
return "";
Queue list = new LinkedList<>();
String result = "";
list.add(this);
list.add(null);
int level = (int) Math.pow(2, height());
BinaryNode dummy = new BinaryNode(null);
while (!list.isEmpty()) {
boolean allDummies = true;
for (BinaryNode b : list)
if (b != dummy && b != null) {
allDummies = false;
break;
}
BinaryNode cur = list.remove();
if (cur == null || allDummies)
break;
for (int i = 0; i < level - 1; i++)
result += '\t';
if (cur != dummy)
result += cur.element;
for (int i = 0; i < level + 1; i++)
result += '\t';
if (cur.left != null)
list.add(cur.left);
else
list.add(dummy);
if (cur.right != null)
list.add(cur.right);
else
list.add.
Given the following codepackage data1;import java.util.;p.pdf
Given the following code
package data1;
import java.util.*;
/*public class BST> implementing a set ADT and containing the following:
* private inner class BinaryNode representing a node with a (possibly) left child and a (possibly)
right child
** instance fields BinaryNode root, int size
* contains/insert/remove method - w/ O(height) complexity
** size O(1), isEmpty O(1), clear O(1),
*** findMin, findMax, findHeight methods - w/ O(height) complexity
**** toString() method printing set (in-order traversal) and the tree (BFS traversal)
**
*/
publicclass BST> {
private BinaryNode root;
privateint size;
//Search opertion of Set ADT
publicboolean contains(E value) {
return contains(root, value);
}
//Insert opertion of Set ADT
publicvoid insert(E value) {
root = insert(root, value);
size++;
}
//Remove operation of Set ADT
publicvoid remove(E value){
root = remove(root, value);
size--;
}
publicint size(){
return size;
}
publicboolean isEmpty(){
return root == null;
}
publicvoid clear(){
root = null;
size = 0;
}
public E findMin(){
return findMin(root);
}
public E findMax(){
return findMax(root);
}
publicint findHeight(){
return root.height();
}
public String toString(){
if(root == null)
return "set {} stored in an empty tree.\n";
String elements = root.inOrder().toString();
return "set {" + elements.substring(1,elements.length()-1) + "} stored in tree \n" + root;
}
private E findMin(BinaryNode node){
if(node == null)
returnnull;
if(node.left == null)
return node.element;
return findMin(node.left);
}
private E findMax(BinaryNode node){
if(node == null)
returnnull;
if(node.right == null)
return node.element;
return findMax(node.right);
}
privateboolean contains(BinaryNode node, E value) {
if (node == null)//node represents an empty substree
returnfalse;
int comparisonResult = value.compareTo(node.element);
if(comparisonResult < 0)//if value is less than root's value
return contains(node.left, value);
if(comparisonResult > 0)//if value is greater than root's value
return contains(node.right, value);
returntrue;//successful search
}
private BinaryNode insert(BinaryNode node, E value) {
if (node == null)//base case: empty tree
returnnew BinaryNode<>(value);
if (value.compareTo(node.element) < 0)
node.left = insert(node.left, value);//insert recursively to left-subtree
elseif (value.compareTo(node.element) > 0)
node.right = insert(node.right, value);//insert recursively to right-subtree
else {//duplicate value cannot be inserted in a BST implementing the Set ADT
size--;//insertion failed!
//System.out.print("BST.insert: Warning: " + value + " is already stored in the tree \n" + node);
}
return node;
}
private BinaryNode remove(BinaryNode node, E value) {
if (node == null) {//base case: empty tree
System.out.println("BST.remove: Warning: " + value + " doesn't exist in the tree.");
size++;//removal failed!
return node;
}
if (value.compareTo(node.element) < 0)
node.left = remove(node.left, value);
elseif (value.compareTo(node.element) > 0)
node.right = remov.
create a binary search tree from an empty one by adding the key valu.pdf
create a binary search tree from an empty one by adding the key value alphabetically in c++
Solution
//Binary Search Tree Program
#include
#include
using namespace std;
class BinarySearchTree
{
private:
struct tree_node //structure to hold Binary search tree
{
tree_node* left;
tree_node* right;
int data;
};
tree_node* root;
public:
BinarySearchTree() //constructor of Binary search tree
{
root = NULL;
}
//function declarations
bool isEmpty() const { return root==NULL; }
void print_inorder();
void inorder(tree_node*);
void print_preorder();
void preorder(tree_node*);
void print_postorder();
void postorder(tree_node*);
void insert(int);
void remove(int);
};
// Smaller elements go left
// larger elements go right
void BinarySearchTree::insert(int d) //insert function to BST
{
tree_node* t = new tree_node;
tree_node* parent;
t->data = d;
t->left = NULL;
t->right = NULL;
parent = NULL;
// is this a new tree?
if(isEmpty()) root = t;
else
{
//Note: ALL insertions are as leaf nodes
tree_node* curr;
curr = root;
// Find the Node\'s parent
while(curr)
{
parent = curr;
if(t->data > curr->data) curr = curr->right;
else curr = curr->left;
}
if(t->data < parent->data)
parent->left = t;
else
parent->right = t;
}
}
void BinarySearchTree::remove(int d)
{
//Locate the element
bool found = false;
if(isEmpty())
{
cout<<\" This Tree is empty! \"<data == d)
{
found = true;
break;
}
else
{
parent = curr;
if(d>curr->data) curr = curr->right;
else curr = curr->left;
}
}
if(!found)
{
cout<<\" Data not found! \"<left == NULL && curr->right != NULL)|| (curr->left !=
NULL
&& curr->right == NULL))
{
if(curr->left == NULL && curr->right != NULL)
{
if(parent->left == curr)
{
parent->left = curr->right;
delete curr;
}
else
{
parent->right = curr->right;
delete curr;
}
}
else // left child present, no right child
{
if(parent->left == curr)
{
parent->left = curr->left;
delete curr;
}
else
{
parent->right = curr->left;
delete curr;
}
}
return;
}
//We\'re looking at a leaf node
if( curr->left == NULL && curr->right == NULL)
{
if(parent->left == curr) parent->left = NULL;
else parent->right = NULL;
delete curr;
return;
}
//Node with 2 children
// replace node with smallest value in right subtree
if (curr->left != NULL && curr->right != NULL)
{
tree_node* chkr;
chkr = curr->right;
if((chkr->left == NULL) && (chkr->right == NULL))
{
curr = chkr;
delete chkr;
curr->right = NULL;
}
else // right child has children
{
//if the node\'s right child has a left child
// Move all the way down left to locate smallest element
if((curr->right)->left != NULL)
{
tree_node* lcurr;
tree_node* lcurrp;
lcurrp = curr->right;
lcurr = (curr->right)->left;
while(lcurr->left != NULL)
{
lcurrp = lcurr;
lcurr = lcurr->left;
}
curr->data = lcurr->data;
delete lcurr;
lcurrp->left = NULL;
}
else
{
tree_node* tmp;
tmp = curr->right;
curr->data = tmp->data;
curr->right = tmp->right;
delete tmp;
}
}
return;
}
}
void BinarySearchTree::print_inorder()
{
inorder(root);
}
void BinarySearchTree::inorder(tree_node* p) .
Using the provided table interface table.h and the sample linked lis.pdf
Using the provided table interface table.h and the sample linked list code linkedList.c, complete
an implementation of the Table ADT. Make sure that you apply the concepts of design by
contract (DbC) to your implementation.
Once you have fully implemented the table, create a main.c file that implements a testing
framework for your table.
Your table implementation must ensure that values inserted are unique, and internally sorted
within a linked list.
table.h
linkedList.c
Solution
khsdg
#include
#include
typedef enum BOOL { false, true } bool;
// Linked list node definition
typedef struct Node node;
struct Node
{
int number;
node *next;
};
static node *top = NULL;
// used to track where we are for the list traversal methods
static node *traverseNode = NULL;
// \"destroy\" will deallocate all nodes in a linked list object
// and will set \"top\" to NULL.
void destroy()
{
node *curr = top;
node *temp = NULL;
while ( curr != NULL )
{
// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// \"build\" will create an ordered linked list consisting
// of the first \"size\" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don\'t have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}
// gets the data at the current traversal node and increments the traversal.
// returns false if we\'re at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// \"print\" will output an object\'s entire linked list
// to the standard output device -- one \"number\" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( \"%d\ \", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;
}.
Write a program that displays an AVL tree along with its balance fac.docx
Write a program that displays an AVL tree along with its balance fac
A)B) C++ program to create a Complete Binary tree from its Lin.pdf
A)
B)
// C++ program to create a Complete Binary tree from its Linked List
// Representation
#include
#include
#include
using namespace std;
// Linked list node
struct ListNode
{
int data;
ListNode* next;
};
// Binary tree node structure
struct BinaryTreeNode
{
int data;
BinaryTreeNode *left, *right;
};
// Function to insert a node at the beginning of the Linked List
void push(struct ListNode** head_ref, int new_data)
{
// allocate node and assign data
struct ListNode* new_node = new ListNode;
new_node->data = new_data;
// link the old list off the new node
new_node->next = (*head_ref);
// move the head to point to the new node
(*head_ref) = new_node;
}
// method to create a new binary tree node from the given data
BinaryTreeNode* newBinaryTreeNode(int data)
{
BinaryTreeNode *temp = new BinaryTreeNode;
temp->data = data;
temp->left = temp->right = NULL;
return temp;
}
// converts a given linked list representing a complete binary tree into the
// linked representation of binary tree.
void convertList2Binary(ListNode *head, BinaryTreeNode* &root)
{
// queue to store the parent nodes
queue q;
// Base Case
if (head == NULL)
{
root = NULL; // Note that root is passed by reference
return;
}
// 1.) The first node is always the root node, and add it to the queue
root = newBinaryTreeNode(head->data);
q.push(root);
// advance the pointer to the next node
head = head->next;
// until the end of linked list is reached, do the following steps
while (head)
{
// 2.a) take the parent node from the q and remove it from q
BinaryTreeNode* parent = q.front();
q.pop();
// 2.c) take next two nodes from the linked list. We will add
// them as children of the current parent node in step 2.b. Push them
// into the queue so that they will be parents to the future nodes
BinaryTreeNode *leftChild = NULL, *rightChild = NULL;
leftChild = newBinaryTreeNode(head->data);
q.push(leftChild);
head = head->next;
if (head)
{
rightChild = newBinaryTreeNode(head->data);
q.push(rightChild);
head = head->next;
}
// 2.b) assign the left and right children of parent
parent->left = leftChild;
parent->right = rightChild;
}
}
// Utility function to traverse the binary tree after conversion
void inorderTraversal(BinaryTreeNode* root)
{
if (root)
{
inorderTraversal( root->left );
cout << root->data << \" \";
inorderTraversal( root->right );
}
}
// Driver program to test above functions
int main()
{
// create a linked list shown in above diagram
struct ListNode* head = NULL;
push(&head, 36); /* Last node of Linked List */
push(&head, 30);
push(&head, 25);
push(&head, 15);
push(&head, 12);
push(&head, 10); /* First node of Linked List */
BinaryTreeNode *root;
convertList2Binary(head, root);
cout << \"Inorder Traversal of the constructed Binary Tree is: \ \";
inorderTraversal(root);
return 0;
}
c)
#include
#include
using namespace std;
template
class bintree
{
bintree *left;
T data;
bintree *right;
public :
bintree()
{
left=right=NULL;
}
void create();
void preorder();
void inorder();
void pos.
Modify HuffmanTree.java and HuffmanNode.java to allow the user to se.pdf
Modify HuffmanTree.java and HuffmanNode.java to allow the user to select the value of n 9 to
construct an n ary Huffman Tree. Once finished, verify the accuracy of your tree by running it
for the English Alphabet for n = 3, 4, 5, 6, 7, 8, 9. For each value of n, compute the average
codeword length. Write these in a table (n vs. ACW L(Cn)).
/ HuffmanTree.java
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
public class HuffmanTree {
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = in.nextLine();
ArrayList nodes = new ArrayList<>();
ArrayList temp = new ArrayList<>();
try {
Scanner fin = new Scanner(new FileReader(fileName));
String symbol;
double prob;
while(fin.hasNext()){
symbol = fin.next();
prob = fin.nextDouble();
nodes.add(findInsertIndex(nodes, prob), new HuffmanNode(symbol, prob));
}
fin.close();
temp.addAll(nodes);
HuffmanNode root = createHuffmanTree(temp);
setCodeWords(root);
double avg = 0;
for (HuffmanNode node : nodes) {
System.out.println(node.getS() + \": \" + node.getC() + \": \" + node.getL());
avg += node.getL();
}
if(avg != 0)
avg /= nodes.size();
System.out.println(\"Average code length is: \" + avg);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
private static HuffmanNode createHuffmanTree(ArrayList nodes){
HuffmanNode root = null;
if(nodes.size() > 0) {
HuffmanNode node0, node1, node;
while (nodes.size() > 1) {
node0 = nodes.get(0);
node1 = nodes.get(1);
node = new HuffmanNode(null, node0.getP() + node1.getP());
node.setLeft(node0);
node.setRight(node1);
nodes.remove(0);
nodes.remove(0);
nodes.add(findInsertIndex(nodes, node.getP()), node);
}
root = nodes.get(0);
}
return root;
}
private static void setCodeWords(HuffmanNode root){
if(root != null){
setCodeWords(root, \"\");
}
}
private static void setCodeWords(HuffmanNode root, String codeWord){
if(root.getS() != null){
root.setC(codeWord);
root.setL(codeWord.length());
}
else{
setCodeWords(root.getLeft(), codeWord + \"0\");
setCodeWords(root.getRight(), codeWord + \"1\");
}
}
private static int findInsertIndex(ArrayList nodes, double prob){
for(int i = 0; i < nodes.size(); ++i){
if(prob < nodes.get(i).getP()){
return i;
}
}
return nodes.size();
}
}
// HuffmanNode.java
public class HuffmanNode {
private String S;
private double P;
private String C;
private int L;
private HuffmanNode left, right;
public HuffmanNode(String s, double p) {
S = s;
P = p;
}
public String getS() {
return S;
}
public void setS(String s) {
S = s;
}
public double getP() {
return P;
}
public void setP(double p) {
P = p;
}
public String getC() {
return C;
}
public void setC(String c) {
C = c;
}
public int getL() {
return L;
}
public void setL(int l) {
L = l;
}
public HuffmanNode getLeft() {
return left;
}
public void setLeft(HuffmanNode left) {
this.left = left;
}
public HuffmanNode getRight() {
return right;
}
public void se.
ReversePoem.java ---------------------------------- public cl.pdf
ReversePoem.java :-
---------------------------------
public class ReversePoem {
/*This programs has you display a pessimistic poem from a list of phrases*/
// and then reverse the phrases to find another more optimistic poem.
public static void main(String[] args) throws Exception
{
//Queue object
MyQueue queue = new MyQueue<>();
//Stack object
MyStack stack = new MyStack<>();
//String buffer to apppend all Strings
StringBuffer sb = new StringBuffer();
// Create a single String object from the 16 Strings below
String set1 = \"I am part of a lost generation#and I refuse to believe that#\";
sb.append(set1);
String set2 = \"I can change the world#I realize this may be a shock but#\";
sb.append(set2);
String set3 = \"\'Happiness comes from within\'#is a lie, and#\";
sb.append(set3);
String set4 = \"\'Money will make me happy\'#So in 30 years I will tell my children#\";
sb.append(set4);
String set5 = \"they are not the most important thing in my life#\";
sb.append(set5);
String set6 = \"My employer will know that#I have my priorities straight because#\";
sb.append(set6);
String set7 = \"work#is more important than#family#I tell you this#\";
sb.append(set7);
String set8 = \"Once upon a time#Families stayed together#\";
sb.append(set8);
String set9 = \"but this will not be true in my era#\";
sb.append(set9);
String set10 = \"This is a quick fix society#Experts tell me#\";
sb.append(set10);
String set11 = \"30 years from now, I will be celebrating the 10th anniversary of my
divorce#\";
sb.append(set11);
String set12 = \"I do not concede that#I will live in a country of my own making#\";
sb.append(set12);
String set13 = \"In the future#Environmental destruction will be the norm#\";
sb.append(set13);
String set14 = \"No longer can it be said that#My peers and I care about this earth#\";
sb.append(set14);
String set15 = \"It will be evident that#My generation is apathetic and lethargic#\";
sb.append(set15);
String set16 = \"It is foolish to presume that#There is hope#\";
sb.append(set16);
String finalString = sb.toString();
String itmes[] = finalString.split(\"#\");
System.out.println(\"========== Original Phrase ==============\");
for(int i = 0 ; i < itmes.length;i++){
queue.enqueue(itmes[i]);
System.out.println(itmes[i]);
}
for(int i = 0 ; i < itmes.length;i++){
stack.push(queue.dequeue());
}
System.out.println(\"========== Reverse Phrase ==============\");
for(int i = 0 ; i < itmes.length;i++){
System.out.println(stack.pop());
}
/* You are given a list of phrases in Strings; the phrases
are separated by pound signs: \'#\':
1. Create a single String object from this list.
2. Then, split the String of phrases into an array of
phrases using the String split method.
3. Display a poem by walking through the array and
displaying each phrase one per line.
4. And, at the same time, place each phrase on a
MyQueue object using only the enqueue method.
5. After all the phrases have been placed on the queue,
transfer the phrases from the MyQueue object to a
MyS.
Recommended
Given BinaryNode.javapackage util;import java.util.;T.pdf
Given BinaryNode.java
package util;
import java.util.*;
/*
This class implements Binary Node for Binary Trees
Methods:
I) Two constructors
II) Two toString methods
III) height and size methods
IV) preorder, postorder, and inorder traversals
V) BFS and DFS traversal
*/
public class BinaryNode {
public E element;//data
public BinaryNode left;//left child
public BinaryNode right;//right child
//constructor for leaves
public BinaryNode(E element) {
this(element, null, null);
}
//constructor for internal nodes
public BinaryNode(E element, BinaryNode left, BinaryNode right) {
this.left = left;
this.right = right;
this.element = element;
}
public String toString2() {
if (left == null && right == null)//base case
return element + "";
return element + "(" + left + ", " + right + ")";
}
public int height() {
if (left == null && right == null)
return 0;
if (left == null)
return 1 + right.height();
if (right == null)
return 1 + left.height();
return 1 + Math.max(left.height(), right.height());
}
public int size() {
int size = 1;//counting root
if (left != null)//counting left subtree nodes
size += left.size();
if (right != null)//counting right subtree nodes
size += right.size();
return size;
}
public void printPreOrder() {
System.out.print(element + " ");
if (left != null)
left.printPreOrder();
if (right != null)
right.printPreOrder();
}
public void printPostOrder() {
if (left != null)
left.printPostOrder();
if (right != null)
right.printPostOrder();
System.out.print(element + " ");
}
public void printInOrder() {
if (left != null)
left.printInOrder();
System.out.print(element + " ");
if (right != null)
right.printInOrder();
}
public void printBFS() {//breadth first search traversal - non-recursive method
Queue q = new LinkedList<>();
q.add(this);
while (!q.isEmpty()) {
BinaryNode cur = q.remove();
System.out.print(cur.element + " ");
if (cur.left != null)
q.add(cur.left);
if (cur.right != null)
q.add(cur.right);
}
}
public void printDFS() {//depth first search traversal - equivalent to pre-order traversal
Stack stack = new Stack<>();
stack.add(this);
while (!stack.empty()) {
BinaryNode cur = stack.pop();
System.out.print(cur.element + " ");
if (cur.right != null)
stack.push(cur.right);
if (cur.left != null)
stack.push(cur.left);
}
}
public String toString() {
if (left == null && right == null && element == null)
return "";
Queue list = new LinkedList<>();
String result = "";
list.add(this);
list.add(null);
int level = (int) Math.pow(2, height());
BinaryNode dummy = new BinaryNode(null);
while (!list.isEmpty()) {
boolean allDummies = true;
for (BinaryNode b : list)
if (b != dummy && b != null) {
allDummies = false;
break;
}
BinaryNode cur = list.remove();
if (cur == null || allDummies)
break;
for (int i = 0; i < level - 1; i++)
result += '\t';
if (cur != dummy)
result += cur.element;
for (int i = 0; i < level + 1; i++)
result += '\t';
if (cur.left != null)
list.add(cur.left);
else
list.add(dummy);
if (cur.right != null)
list.add(cur.right);
else
list.add.
Given the following codepackage data1;import java.util.;p.pdf
Given the following code
package data1;
import java.util.*;
/*public class BST> implementing a set ADT and containing the following:
* private inner class BinaryNode representing a node with a (possibly) left child and a (possibly)
right child
** instance fields BinaryNode root, int size
* contains/insert/remove method - w/ O(height) complexity
** size O(1), isEmpty O(1), clear O(1),
*** findMin, findMax, findHeight methods - w/ O(height) complexity
**** toString() method printing set (in-order traversal) and the tree (BFS traversal)
**
*/
publicclass BST> {
private BinaryNode root;
privateint size;
//Search opertion of Set ADT
publicboolean contains(E value) {
return contains(root, value);
}
//Insert opertion of Set ADT
publicvoid insert(E value) {
root = insert(root, value);
size++;
}
//Remove operation of Set ADT
publicvoid remove(E value){
root = remove(root, value);
size--;
}
publicint size(){
return size;
}
publicboolean isEmpty(){
return root == null;
}
publicvoid clear(){
root = null;
size = 0;
}
public E findMin(){
return findMin(root);
}
public E findMax(){
return findMax(root);
}
publicint findHeight(){
return root.height();
}
public String toString(){
if(root == null)
return "set {} stored in an empty tree.\n";
String elements = root.inOrder().toString();
return "set {" + elements.substring(1,elements.length()-1) + "} stored in tree \n" + root;
}
private E findMin(BinaryNode node){
if(node == null)
returnnull;
if(node.left == null)
return node.element;
return findMin(node.left);
}
private E findMax(BinaryNode node){
if(node == null)
returnnull;
if(node.right == null)
return node.element;
return findMax(node.right);
}
privateboolean contains(BinaryNode node, E value) {
if (node == null)//node represents an empty substree
returnfalse;
int comparisonResult = value.compareTo(node.element);
if(comparisonResult < 0)//if value is less than root's value
return contains(node.left, value);
if(comparisonResult > 0)//if value is greater than root's value
return contains(node.right, value);
returntrue;//successful search
}
private BinaryNode insert(BinaryNode node, E value) {
if (node == null)//base case: empty tree
returnnew BinaryNode<>(value);
if (value.compareTo(node.element) < 0)
node.left = insert(node.left, value);//insert recursively to left-subtree
elseif (value.compareTo(node.element) > 0)
node.right = insert(node.right, value);//insert recursively to right-subtree
else {//duplicate value cannot be inserted in a BST implementing the Set ADT
size--;//insertion failed!
//System.out.print("BST.insert: Warning: " + value + " is already stored in the tree \n" + node);
}
return node;
}
private BinaryNode remove(BinaryNode node, E value) {
if (node == null) {//base case: empty tree
System.out.println("BST.remove: Warning: " + value + " doesn't exist in the tree.");
size++;//removal failed!
return node;
}
if (value.compareTo(node.element) < 0)
node.left = remove(node.left, value);
elseif (value.compareTo(node.element) > 0)
node.right = remov.
create a binary search tree from an empty one by adding the key valu.pdf
create a binary search tree from an empty one by adding the key value alphabetically in c++
Solution
//Binary Search Tree Program
#include
#include
using namespace std;
class BinarySearchTree
{
private:
struct tree_node //structure to hold Binary search tree
{
tree_node* left;
tree_node* right;
int data;
};
tree_node* root;
public:
BinarySearchTree() //constructor of Binary search tree
{
root = NULL;
}
//function declarations
bool isEmpty() const { return root==NULL; }
void print_inorder();
void inorder(tree_node*);
void print_preorder();
void preorder(tree_node*);
void print_postorder();
void postorder(tree_node*);
void insert(int);
void remove(int);
};
// Smaller elements go left
// larger elements go right
void BinarySearchTree::insert(int d) //insert function to BST
{
tree_node* t = new tree_node;
tree_node* parent;
t->data = d;
t->left = NULL;
t->right = NULL;
parent = NULL;
// is this a new tree?
if(isEmpty()) root = t;
else
{
//Note: ALL insertions are as leaf nodes
tree_node* curr;
curr = root;
// Find the Node\'s parent
while(curr)
{
parent = curr;
if(t->data > curr->data) curr = curr->right;
else curr = curr->left;
}
if(t->data < parent->data)
parent->left = t;
else
parent->right = t;
}
}
void BinarySearchTree::remove(int d)
{
//Locate the element
bool found = false;
if(isEmpty())
{
cout<<\" This Tree is empty! \"<data == d)
{
found = true;
break;
}
else
{
parent = curr;
if(d>curr->data) curr = curr->right;
else curr = curr->left;
}
}
if(!found)
{
cout<<\" Data not found! \"<left == NULL && curr->right != NULL)|| (curr->left !=
NULL
&& curr->right == NULL))
{
if(curr->left == NULL && curr->right != NULL)
{
if(parent->left == curr)
{
parent->left = curr->right;
delete curr;
}
else
{
parent->right = curr->right;
delete curr;
}
}
else // left child present, no right child
{
if(parent->left == curr)
{
parent->left = curr->left;
delete curr;
}
else
{
parent->right = curr->left;
delete curr;
}
}
return;
}
//We\'re looking at a leaf node
if( curr->left == NULL && curr->right == NULL)
{
if(parent->left == curr) parent->left = NULL;
else parent->right = NULL;
delete curr;
return;
}
//Node with 2 children
// replace node with smallest value in right subtree
if (curr->left != NULL && curr->right != NULL)
{
tree_node* chkr;
chkr = curr->right;
if((chkr->left == NULL) && (chkr->right == NULL))
{
curr = chkr;
delete chkr;
curr->right = NULL;
}
else // right child has children
{
//if the node\'s right child has a left child
// Move all the way down left to locate smallest element
if((curr->right)->left != NULL)
{
tree_node* lcurr;
tree_node* lcurrp;
lcurrp = curr->right;
lcurr = (curr->right)->left;
while(lcurr->left != NULL)
{
lcurrp = lcurr;
lcurr = lcurr->left;
}
curr->data = lcurr->data;
delete lcurr;
lcurrp->left = NULL;
}
else
{
tree_node* tmp;
tmp = curr->right;
curr->data = tmp->data;
curr->right = tmp->right;
delete tmp;
}
}
return;
}
}
void BinarySearchTree::print_inorder()
{
inorder(root);
}
void BinarySearchTree::inorder(tree_node* p) .
Using the provided table interface table.h and the sample linked lis.pdf
Using the provided table interface table.h and the sample linked list code linkedList.c, complete
an implementation of the Table ADT. Make sure that you apply the concepts of design by
contract (DbC) to your implementation.
Once you have fully implemented the table, create a main.c file that implements a testing
framework for your table.
Your table implementation must ensure that values inserted are unique, and internally sorted
within a linked list.
table.h
linkedList.c
Solution
khsdg
#include
#include
typedef enum BOOL { false, true } bool;
// Linked list node definition
typedef struct Node node;
struct Node
{
int number;
node *next;
};
static node *top = NULL;
// used to track where we are for the list traversal methods
static node *traverseNode = NULL;
// \"destroy\" will deallocate all nodes in a linked list object
// and will set \"top\" to NULL.
void destroy()
{
node *curr = top;
node *temp = NULL;
while ( curr != NULL )
{
// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// \"build\" will create an ordered linked list consisting
// of the first \"size\" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don\'t have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}
// gets the data at the current traversal node and increments the traversal.
// returns false if we\'re at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// \"print\" will output an object\'s entire linked list
// to the standard output device -- one \"number\" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( \"%d\ \", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;
}.
Write a program that displays an AVL tree along with its balance fac.docx
Write a program that displays an AVL tree along with its balance fac
A)B) C++ program to create a Complete Binary tree from its Lin.pdf
A)
B)
// C++ program to create a Complete Binary tree from its Linked List
// Representation
#include
#include
#include
using namespace std;
// Linked list node
struct ListNode
{
int data;
ListNode* next;
};
// Binary tree node structure
struct BinaryTreeNode
{
int data;
BinaryTreeNode *left, *right;
};
// Function to insert a node at the beginning of the Linked List
void push(struct ListNode** head_ref, int new_data)
{
// allocate node and assign data
struct ListNode* new_node = new ListNode;
new_node->data = new_data;
// link the old list off the new node
new_node->next = (*head_ref);
// move the head to point to the new node
(*head_ref) = new_node;
}
// method to create a new binary tree node from the given data
BinaryTreeNode* newBinaryTreeNode(int data)
{
BinaryTreeNode *temp = new BinaryTreeNode;
temp->data = data;
temp->left = temp->right = NULL;
return temp;
}
// converts a given linked list representing a complete binary tree into the
// linked representation of binary tree.
void convertList2Binary(ListNode *head, BinaryTreeNode* &root)
{
// queue to store the parent nodes
queue q;
// Base Case
if (head == NULL)
{
root = NULL; // Note that root is passed by reference
return;
}
// 1.) The first node is always the root node, and add it to the queue
root = newBinaryTreeNode(head->data);
q.push(root);
// advance the pointer to the next node
head = head->next;
// until the end of linked list is reached, do the following steps
while (head)
{
// 2.a) take the parent node from the q and remove it from q
BinaryTreeNode* parent = q.front();
q.pop();
// 2.c) take next two nodes from the linked list. We will add
// them as children of the current parent node in step 2.b. Push them
// into the queue so that they will be parents to the future nodes
BinaryTreeNode *leftChild = NULL, *rightChild = NULL;
leftChild = newBinaryTreeNode(head->data);
q.push(leftChild);
head = head->next;
if (head)
{
rightChild = newBinaryTreeNode(head->data);
q.push(rightChild);
head = head->next;
}
// 2.b) assign the left and right children of parent
parent->left = leftChild;
parent->right = rightChild;
}
}
// Utility function to traverse the binary tree after conversion
void inorderTraversal(BinaryTreeNode* root)
{
if (root)
{
inorderTraversal( root->left );
cout << root->data << \" \";
inorderTraversal( root->right );
}
}
// Driver program to test above functions
int main()
{
// create a linked list shown in above diagram
struct ListNode* head = NULL;
push(&head, 36); /* Last node of Linked List */
push(&head, 30);
push(&head, 25);
push(&head, 15);
push(&head, 12);
push(&head, 10); /* First node of Linked List */
BinaryTreeNode *root;
convertList2Binary(head, root);
cout << \"Inorder Traversal of the constructed Binary Tree is: \ \";
inorderTraversal(root);
return 0;
}
c)
#include
#include
using namespace std;
template
class bintree
{
bintree *left;
T data;
bintree *right;
public :
bintree()
{
left=right=NULL;
}
void create();
void preorder();
void inorder();
void pos.
Modify HuffmanTree.java and HuffmanNode.java to allow the user to se.pdf
Modify HuffmanTree.java and HuffmanNode.java to allow the user to select the value of n 9 to
construct an n ary Huffman Tree. Once finished, verify the accuracy of your tree by running it
for the English Alphabet for n = 3, 4, 5, 6, 7, 8, 9. For each value of n, compute the average
codeword length. Write these in a table (n vs. ACW L(Cn)).
/ HuffmanTree.java
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
public class HuffmanTree {
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = in.nextLine();
ArrayList nodes = new ArrayList<>();
ArrayList temp = new ArrayList<>();
try {
Scanner fin = new Scanner(new FileReader(fileName));
String symbol;
double prob;
while(fin.hasNext()){
symbol = fin.next();
prob = fin.nextDouble();
nodes.add(findInsertIndex(nodes, prob), new HuffmanNode(symbol, prob));
}
fin.close();
temp.addAll(nodes);
HuffmanNode root = createHuffmanTree(temp);
setCodeWords(root);
double avg = 0;
for (HuffmanNode node : nodes) {
System.out.println(node.getS() + \": \" + node.getC() + \": \" + node.getL());
avg += node.getL();
}
if(avg != 0)
avg /= nodes.size();
System.out.println(\"Average code length is: \" + avg);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
private static HuffmanNode createHuffmanTree(ArrayList nodes){
HuffmanNode root = null;
if(nodes.size() > 0) {
HuffmanNode node0, node1, node;
while (nodes.size() > 1) {
node0 = nodes.get(0);
node1 = nodes.get(1);
node = new HuffmanNode(null, node0.getP() + node1.getP());
node.setLeft(node0);
node.setRight(node1);
nodes.remove(0);
nodes.remove(0);
nodes.add(findInsertIndex(nodes, node.getP()), node);
}
root = nodes.get(0);
}
return root;
}
private static void setCodeWords(HuffmanNode root){
if(root != null){
setCodeWords(root, \"\");
}
}
private static void setCodeWords(HuffmanNode root, String codeWord){
if(root.getS() != null){
root.setC(codeWord);
root.setL(codeWord.length());
}
else{
setCodeWords(root.getLeft(), codeWord + \"0\");
setCodeWords(root.getRight(), codeWord + \"1\");
}
}
private static int findInsertIndex(ArrayList nodes, double prob){
for(int i = 0; i < nodes.size(); ++i){
if(prob < nodes.get(i).getP()){
return i;
}
}
return nodes.size();
}
}
// HuffmanNode.java
public class HuffmanNode {
private String S;
private double P;
private String C;
private int L;
private HuffmanNode left, right;
public HuffmanNode(String s, double p) {
S = s;
P = p;
}
public String getS() {
return S;
}
public void setS(String s) {
S = s;
}
public double getP() {
return P;
}
public void setP(double p) {
P = p;
}
public String getC() {
return C;
}
public void setC(String c) {
C = c;
}
public int getL() {
return L;
}
public void setL(int l) {
L = l;
}
public HuffmanNode getLeft() {
return left;
}
public void setLeft(HuffmanNode left) {
this.left = left;
}
public HuffmanNode getRight() {
return right;
}
public void se.
ReversePoem.java ---------------------------------- public cl.pdf
ReversePoem.java :-
---------------------------------
public class ReversePoem {
/*This programs has you display a pessimistic poem from a list of phrases*/
// and then reverse the phrases to find another more optimistic poem.
public static void main(String[] args) throws Exception
{
//Queue object
MyQueue queue = new MyQueue<>();
//Stack object
MyStack stack = new MyStack<>();
//String buffer to apppend all Strings
StringBuffer sb = new StringBuffer();
// Create a single String object from the 16 Strings below
String set1 = \"I am part of a lost generation#and I refuse to believe that#\";
sb.append(set1);
String set2 = \"I can change the world#I realize this may be a shock but#\";
sb.append(set2);
String set3 = \"\'Happiness comes from within\'#is a lie, and#\";
sb.append(set3);
String set4 = \"\'Money will make me happy\'#So in 30 years I will tell my children#\";
sb.append(set4);
String set5 = \"they are not the most important thing in my life#\";
sb.append(set5);
String set6 = \"My employer will know that#I have my priorities straight because#\";
sb.append(set6);
String set7 = \"work#is more important than#family#I tell you this#\";
sb.append(set7);
String set8 = \"Once upon a time#Families stayed together#\";
sb.append(set8);
String set9 = \"but this will not be true in my era#\";
sb.append(set9);
String set10 = \"This is a quick fix society#Experts tell me#\";
sb.append(set10);
String set11 = \"30 years from now, I will be celebrating the 10th anniversary of my
divorce#\";
sb.append(set11);
String set12 = \"I do not concede that#I will live in a country of my own making#\";
sb.append(set12);
String set13 = \"In the future#Environmental destruction will be the norm#\";
sb.append(set13);
String set14 = \"No longer can it be said that#My peers and I care about this earth#\";
sb.append(set14);
String set15 = \"It will be evident that#My generation is apathetic and lethargic#\";
sb.append(set15);
String set16 = \"It is foolish to presume that#There is hope#\";
sb.append(set16);
String finalString = sb.toString();
String itmes[] = finalString.split(\"#\");
System.out.println(\"========== Original Phrase ==============\");
for(int i = 0 ; i < itmes.length;i++){
queue.enqueue(itmes[i]);
System.out.println(itmes[i]);
}
for(int i = 0 ; i < itmes.length;i++){
stack.push(queue.dequeue());
}
System.out.println(\"========== Reverse Phrase ==============\");
for(int i = 0 ; i < itmes.length;i++){
System.out.println(stack.pop());
}
/* You are given a list of phrases in Strings; the phrases
are separated by pound signs: \'#\':
1. Create a single String object from this list.
2. Then, split the String of phrases into an array of
phrases using the String split method.
3. Display a poem by walking through the array and
displaying each phrase one per line.
4. And, at the same time, place each phrase on a
MyQueue object using only the enqueue method.
5. After all the phrases have been placed on the queue,
transfer the phrases from the MyQueue object to a
MyS.
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdf
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD
OR REMOVE NAME. DO NOT HARD CODE NAME. AGAIN MAKE SURE THE
PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR REMOVE NAME. PLEASE
MAKE SURE THE CODE RUNS WITHOUT ANY ERRORS.
Write a class that maintains the scores for a game application. Implement the addition and
removal function to update the database. The gamescore.txt contains player’ name and score data
record fields separated by comma. For Removal function, uses the name field to select record to
remove the game score record.
Use the List.java, LList.java, Dlink.java, GameEntry.java and gamescore.txt found below
Read gamescore.txt to initialize the Linked list in sorted order by score.
Ask the user to add or remove users to update the sorted linked list.
Display “Name exist” when add an exist name to the list.
Display “Name does not exist” when remove a name not on the list.
List.java File:
/** Source code example for \"A Practical Introduction to Data
Structures and Algorithm Analysis, 3rd Edition (Java)\"
by Clifford A. Shaffer
Copyright 2008-2011 by Clifford A. Shaffer
*/
/** List ADT */
public interface List
{
/**
* Remove all contents from the list, so it is once again empty. Client is
* responsible for reclaiming storage used by the list elements.
*/
public void clear();
/**
* Insert an element at the current location. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be inserted.
*/
public void insert(E item);
/**
* Append an element at the end of the list. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be appended.
*/
public void append(E item);
/**
* Remove and return the current element.
*
* @return The element that was removed.
*/
public E remove();
/** Set the current position to the start of the list */
public void moveToStart();
/** Set the current position to the end of the list */
public void moveToEnd();
/**
* Move the current position one step left. No change if already at
* beginning.
*/
public void prev();
/**
* Move the current position one step right. No change if already at end.
*/
public void next();
/** @return The number of elements in the list. */
public int length();
/** @return The position of the current element. */
public int currPos();
/**
* Set current position.
*
* @param pos
* The position to make current.
*/
public void moveToPos(int pos);
/** @return The current element. */
public E getValue();
}
LList.java File:
/**
* Source code example for \"A Practical Introduction to Data Structures and
* Algorithm Analysis, 3rd Edition (Java)\" by Clifford A. Shaffer Copyright
* 2008-2011 by Clifford A. Shaffer
*/
// Doubly linked list implementation
class LList implements List
{
private DLink head; // Pointer to list header
private DLink tail; // Pointer to last element in list
protected DLink curr; // Pointer ahead of current element
int cnt; // Size of list
// Constructors
LList(int size)
{
th.
Note Given Code modified as required and required met.pdf
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void setData(String data)
{
this.data = data;
}
// method to get the next data
public Node getNext()
{
return next;
}
// method to set the next data
public void setNext(Node next)
{
this.next = next;
}
}
// class for a linked list
class MyLInkedList
{
Node head;alue into a list
// method to add the v
public void add(String num)
{
if (head == null)
{
head = new Node(num);
}
else{
Node temp = new Node(num);
Node current = head;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(temp);
}
}
}
// method to search a value from a list
public void search(String num)
{
Node current = head;
boolean flag=true;
if (current != null)
{
while (current != null)
{
if(current.getData() == num)
{
System.out.println(\"Search value \"+
current.getData()+\" is available\");
flag=false;
}
current = current.getNext();
}
if (flag==true)
{
System.out.println(\"Search value \"+
current.getData()+\" is not available\");
}
}
else
{
System.out.println(\"Linked list is empty\");
}
}
// method to delete a value from a list
public void delete(String num)
{
//Node current = head;
boolean flag=true;
if (head == null)
{
System.out.println(\"Can\'t Delete, Linked list is
empty\");
return;
}
if(head.getData() == num)
{
head=head.getNext();
return;
}
Node temp = new Node(num);
Node cr = head;
Node prev=null;
while ((cr != null) && !(cr.getData() == num))
{
prev=cr;
cr = cr.getNext();
}
prev.setNext(cr.getNext());
}
// method to print the list
public void print()
{
Node current = head;
if (current != null) {
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
}
}
// method to test the class
public class MyLInkedListTester
{
// main method to perform the linked list operatrions
public static void main(String args[])
{
MyLInkedList llist = new MyLInkedList();
// insert the values into list
llist.add(\"1\");
llist.add(\"2\");
llist.add(\"3\");
llist.add(\"4\");
// print the list values
llist.print();
// sear the values in a list
llist.search(\"1\");
llist.print();
// delete the value from a list
llist.delete(\"4\");
System.out.println(\"List after deletion:\");
llist.print();
}
}
Result:
1
2
3
4
Search value 1 is available
1
2
3
4
List after deletion:
1
2
3
Solution
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void se.
in this assignment you are asked to write a simple driver program an.pdf
in this assignment you are asked to write a simple driver program and set of functions (maybein
a library) that can be performed on a binary search tree.
Your program should allow user to insert/delete integer values into the binary search tree along
with several other operations on the binary search tree. You can use the code given in slides. But
this time your key will be int! Specifically, your program will ask user to enter a command and
related parameters (if any) in a loop, and then perform the given commands. Here is the list of
commands that your program must implement:
* insert
*find\'
*delete
*list inorder
*list preorder
*list postorder
*list levelorder
* max
* min
* height
*count
* sum
*quit
As always, make sure you release (free) the dynamically allocated memories if you allocate any
memory in your programs. So, before submitting your program, run it with valgrind to see if
there is any memory leakage
//my proggram in C
struct tree_node {
int data;
struct tree_node *left, *right;
}
typedef struct nodeT {
int key;
struct nodeT *left, *right;
} nodeT, *treeT;
int main(){
while (TRUE) {
printf(\"> \");
line = GetLine();
ch = toupper(line[0]);
switch (ch) {
case \'I\': insert(); break;
case \'F\': find(); break;
case \'D\': delete(); break;
case \'LI\': listInorder; break;
case \'LPR\': listPreorder(); break;
case \'LPO\': listPostorder(); break;
case \'MAX\': max(); break;
case \'min\': min(); break;
case \'H\': height(); break;
case \'C\': count(); break;
case \'S\': sum(); break;
case \'Q\': exit(0);
default:printf(\"Illegal command\ \"); break;
}
}
}
nodeT *FindNode(nodeT *t, int key){
while(t !=NULL) {
if (key == t->key) return t;
if (key < t->key) {
t = t->left;
} else {
t = t->right;
}
return NULL;
}
void delete(nodeT **p){
nodeT
*target;
target=*p;
if (target->left==NULL && target->right==NULL) {
*p=NULL;
} else if (target->left == NULL) {
*p=target->right;
} else
if (target->right == NULL) {
*p=target->left;
} else {
/* target has two children, see next slide */
}
free(target);
}
void listInorder(nodeT *T){
if (t != NULL) {
DisplayTree(t->left);
printf(“%d “, t->key);
DisplayTree(t->right);
}
}
void listPreorder(nodeT *t) {
if (t != NULL) {
printf(“%d “, t->key);
DisplayTree(t->left);
DisplayTree(t->right);
}
}
void listPostOrder(nodeT *t){
if (t != NULL) {
DisplayTree(t->left);
DisplayTree(t->right);
printf(“%d “, t->key);
}
}
void intsert(nodeT **tptr, int key){
nodeT*t, *tmp;
t=*tptr;
if (t == NULL) {
tmp=New(nodeT*);
tmp->key = key;
tmp->left=tmp->right=NULL;
*tptr=tmp;
return;
}
if (key < t->key) {
InsertNode
(&t->left, key);
} else {
InsertNode(&t->right, key);
}
}
int height(nodeT *t){
if (t == NULL)
return 0;
else
return (1 + maximumof(
height(t->left),
height(t->right)) );
}
int sum(struct tree_node *p){
if (p == NULL)
return 0;
else
return (p->data +
sum(p->left) +
sum(p->right) );
}
Solution
1. /*
2. * Java Program to Implement Binary Search Tree
3. */
4.
5. import java.util.Scanner;
6.
7. /* Class BSTNode */
8. cl.
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
For the code below complete the preOrder() method so that it perform.pdf
For the code below complete the preOrder() method so that it performs a preOrder traversal of
the tree. For each node it traverses, it should call sb.append() to add a \"[\" the results of
traversing the subtree rooted at that node, and then a \"]\". You should add a space before the
results of the left and right child traversals, but only if the node exists.
code:
Solution
In preorder Nodes visited are in the order of
code:
package edu.buffalo.cse116;
import java.util.AbstractSet;
import java.util.Iterator;
public class BinarySearchTree> extends AbstractSet {
protected Entry root;
protected int size;
/**
* Initializes this BinarySearchTree object to be empty, to contain only
* elements of type E, to be ordered by the Comparable interface, and to
* contain no duplicate elements.
*/
public BinarySearchTree() {
root = null;
size = 0;
}
/**
* Initializes this BinarySearchTree object to contain a shallow copy of a
* specified BinarySearchTree object. The worstTime(n) is O(n), where n is the
* number of elements in the specified BinarySearchTree object.
*
* @param otherTree - the specified BinarySearchTree object that this
* BinarySearchTree object will be assigned a shallow copy of.
*/
public BinarySearchTree(BinarySearchTree otherTree) {
root = copy(otherTree.root, null);
size = otherTree.size;
}
/* Method to complete is here! */
public void preOrder(Entry ent, StringBuilder sb) {
preorder(root)
protected Entry copy(Entry p, Entry parent) {
if (p != null) {
Entry q = new Entry(p.element, parent);
q.left = copy(p.left, q);
q.right = copy(p.right, q);
return q;
}
return null;
} // method copy
@SuppressWarnings(\"unchecked\")
@Override
public boolean equals(Object obj) {
if (!(obj instanceof BinarySearchTree)) {
return false;
}
return equals(root, ((BinarySearchTree) obj).root);
}
public boolean equals(Entry p, Entry q) {
if ((p == null) || (q == null)) {
return p == q;
}
if (!p.element.equals(q.element)) {
return false;
}
if (equals(p.left, q.left) && equals(p.right, q.right)) {
return true;
}
return false;
}
/**
* Returns the size of this BinarySearchTree object.
*
* @return the size of this BinarySearchTree object.
*/
@Override
public int size() {
return size;
}
/**
* Iterator method will be implemented for a future
*
* @return an iterator positioned at the smallest element in this
* BinarySearchTree object.
*/
@Override
public Iterator iterator() {
throw new UnsupportedOperationException(\"Not implemented yet!\");
}
/**
* Determines if there is at least one element in this BinarySearchTree object
* that equals a specified element. The worstTime(n) is O(n) and
* averageTime(n) is O(log n).
*
* @param obj - the element sought in this BinarySearchTree object.
* @return true - if there is an element in this BinarySearchTree object that
* equals obj; otherwise, return false.
* @throws ClassCastException - if obj cannot be compared to the elements in
* this BinarySearchTree object.
* @throws NullPointerException - if obj is null.
*/
@Override
public .
Please read the comment ins codeExpressionTree.java-------------.pdf
Please read the comment ins code
ExpressionTree.java
----------------------------------
/**
* This is the class for Expression Tree.
* Used to create Expression Tree and Evaluate it
*/
/**
* Following logic is used to construct a Tree
* Here we use stack for Preparing Tree
* Loop through given Expression String
* If Character is Operand , Create node and push to stack
* If Character is Operator then
* 1)Create Node for Operator
* 2)Pop 2 nodes from Stack and Made
* OpretorNode--> left == first node pop
* OpretorNode--> right == second node pop
* At the end of creation of Expression Tree, Stack have only one node , which is root of
Expression tree
*/
/** Class ExpressionTree **/
class ExpressionTree
{
/** class TreeNode
* Stored Character ==> Digit(0..9) or a Operator +,-,*,/
* Left Node and Right Node
*
* **/
class TreeNode
{
char data;
TreeNode left, right;
/** constructor **/
public TreeNode(char data)
{
this.data = data;
this.left = null;
this.right = null;
}
}
/** class StackNode **/
class StackNode
{
TreeNode treeNode;
StackNode next;
/** constructor **/
public StackNode(TreeNode treeNode)
{
this.treeNode = treeNode;
next = null;
}
}
private static StackNode top;
/** constructor
* Constructor takes input string like \"+-+7*935*82*625\"
* Input should be in Prefix notation
* **/
public ExpressionTree(String expression)
{
top = null;
//Call Method for prepare expression tree
buildTree(expression);
}
/** function to clear tree **/
public void clear()
{
top = null;
}
/** function to push a node **/
private void push(TreeNode ptr)
{
if (top == null)
top = new StackNode(ptr);
else
{
StackNode nptr = new StackNode(ptr);
nptr.next = top;
top = nptr;
}
}
/** function to pop a node
* When it find operator pop 2 elements from Stack
*
* **/
private TreeNode pop()
{
if (top == null)
throw new RuntimeException(\"Underflow\");
else
{
TreeNode ptr = top.treeNode;
top = top.next;
return ptr;
}
}
/** function to get top node **/
private TreeNode peek()
{
return top.treeNode;
}
/** function to insert character **/
private void insert(char val)
{
try
{
//If Operand , Create node and push to Stack
if (isDigit(val))
{
TreeNode nptr = new TreeNode(val);
push(nptr);
}
//If Operator , Create node and popup 2 elements and make them its right and left
else if (isOperator(val))
{
TreeNode nptr = new TreeNode(val);
nptr.left = pop();
nptr.right = pop();
push(nptr);
}
}
catch (Exception e)
{
System.out.println(\"Invalid Expression\");
}
}
/** function to check if digit **/
private boolean isDigit(char ch)
{
return ch >= \'0\' && ch <= \'9\';
}
/** function to check if operator **/
private boolean isOperator(char ch)
{
return ch == \'+\' || ch == \'-\' || ch == \'*\' || ch == \'/\';
}
/** function to convert character to digit **/
private int toDigit(char ch)
{
return ch - \'0\';
}
/** function to build tree from input */
public void buildTree(String eqn)
{
for (int i = eqn.length() - 1; i >= 0; i--)
insert(eqn.charAt(i));
}
/** function to evaluate tree */
public dou.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
JAVA A double-ended queue is a list that allows the addition and.pdf
**JAVA** A double-ended queue is a list that allows the addition and removal of items from
either end. One end is arbitrarily called the front and other the rear, but the two ends behave
identically. Specify, design and implement a class for a double-ended queue. Include operations
to check if it is empty and to return the number of items in the list. For each end, include
operations for adding and deleting items. Use doubly linked list for your implementation. Call
your class Deque (pronounced \"deck\").
Solution
//package com.java2novice.ds.queue;
public class DequeDblLinkedListImpl {
private LinkedNode front;
private LinkedNode rear;
public void insertFront(T item){
//add element at the beginning of the queue
System.out.println(\"adding at front: \"+item);
LinkedNode nd = new LinkedNode();
nd.setValue(item);
nd.setNext(front);
if(front != null) front.setPrev(nd);
if(front == null) rear = nd;
front = nd;
}
public void insertRear(T item){
//add element at the end of the queue
System.out.println(\"adding at rear: \"+item);
LinkedNode nd = new LinkedNode();
nd.setValue(item);
nd.setPrev(rear);
if(rear != null) rear.setNext(nd);
if(rear == null) front = nd;
rear = nd;
}
public void removeFront(){
if(front == null){
System.out.println(\"Deque underflow!! unable to remove.\");
return;
}
//remove an item from the beginning of the queue
LinkedNode tmpFront = front.getNext();
if(tmpFront != null) tmpFront.setPrev(null);
if(tmpFront == null) rear = null;
System.out.println(\"removed from front: \"+front.getValue());
front = tmpFront;
}
public int size(){
if(front == null && rear ==null){
return 0;
}
//remove an item from the beginning of the queue
LinkedNode tmpFront = front;
LinkedNode tmpRear = rear;
int i=0;
while(tmpFront != rear)
{
i++;
tmpFront=tmpFront.getNext();
}
i++;
return i;
}
public void removeRear(){
if(rear == null){
System.out.println(\"Deque underflow!! unable to remove.\");
return;
}
//remove an item from the beginning of the queue
LinkedNode tmpRear = rear.getPrev();
if(tmpRear != null) tmpRear.setNext(null);
if(tmpRear == null) front = null;
System.out.println(\"removed from rear: \"+rear.getValue());
rear = tmpRear;
}
public static void main(String a[]){
DequeDblLinkedListImpl deque = new DequeDblLinkedListImpl();
deque.insertFront(34);
deque.insertFront(67);
System.out.println(\"Size of the queue : \"+deque.size());
deque.insertFront(29);
deque.insertFront(765);
deque.removeFront();
deque.removeFront();
deque.removeFront();
deque.insertRear(43);
deque.insertRear(83);
deque.insertRear(84);
deque.insertRear(546);
deque.insertRear(356);
deque.removeRear();
deque.removeRear();
deque.removeRear();
deque.removeRear();
deque.removeFront();
deque.removeFront();
deque.removeFront();
}
}
class LinkedNode{
private LinkedNode prev;
private LinkedNode next;
private T value;
public LinkedNode getPrev() {
return prev;
}
public void setPrev(LinkedNode prev) {
this.prev = prev;
}
public LinkedNode getNext() {
return next;
}
public void setNext(L.
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
import java.util.Scanner;
class BinaryNode
{
BinaryNode left, right;
int data;
public BinaryNode()
{
left = null;
right = null;
data = 0;
}
public BinaryNode(int n)
{
left = null;
right = null;
data = n;
}
public void setLeft(BinaryNode n)
{
left = n;
}
public void setRight(BinaryNode n)
{
right = n;
}
public BinaryNode getLeft()
{
return left;
}
public BinaryNode getRight()
{
return right;
}
public void setData(int d)
{
data = d;
}
public int getData()
{
return data;
}
}
class Binary
{
private BinaryNode root;
public Binary()
{
root = null;
}
public boolean isEmpty()
{
return root == null;
}
public void insert(int data)
{
root = insert(root, data);
}
private BinaryNode insert(BinaryNode node, int data)
{
if (node == null)
node = new BinaryNode(data);
else
{
if (data <= node.getData())
node.left = insert(node.left, data);
else
node.right = insert(node.right, data);
}
return node;
}
public void delete(int k)
{
if (isEmpty())
System.out.println(\"Tree Empty\");
else if (search(k) == false)
System.out.println(\"Sorry \"+ k +\" is not present\");
else
{
root = delete(root, k);
System.out.println(k+ \" deleted from the tree\");
}
}
private BinaryNode delete(BinaryNode root, int k)
{
BinaryNode p, p2, n;
if (root.getData() == k)
{
BinaryNode lt, rt;
lt = root.getLeft();
rt = root.getRight();
if (lt == null && rt == null)
return null;
else if (lt == null)
{
p = rt;
return p;
}
else if (rt == null)
{
p = lt;
return p;
}
else
{
p2 = rt;
p = rt;
while (p.getLeft() != null)
p = p.getLeft();
p.setLeft(lt);
return p2;
}
}
if (k < root.getData())
{
n = delete(root.getLeft(), k);
root.setLeft(n);
}
else
{
n = delete(root.getRight(), k);
root.setRight(n);
}
return root;
}
public boolean search(int val)
{
return search(root, val);
}
private boolean search(BinaryNode r, int val)
{
boolean found = false;
while ((r != null) && !found)
{
int rval = r.getData();
if (val < rval)
r = r.getLeft();
else if (val > rval)
r = r.getRight();
else
{
found = true;
break;
}
found = search(r, val);
}
return found;
}
public void inorder()
{
inorder(root);
}
private void inorder(BinaryNode r)
{
if (r != null)
{
inorder(r.getLeft());
System.out.print(r.getData() +\" \");
inorder(r.getRight());
}
}
public void preorder()
{
preorder(root);
}
private void preorder(BinaryNode r)
{
if (r != null)
{
System.out.print(r.getData() +\" \");
preorder(r.getLeft());
preorder(r.getRight());
}
}
public void postorder()
{
postorder(root);
}
private void postorder(BinaryNode r)
{
if (r != null)
{
postorder(r.getLeft());
postorder(r.getRight());
System.out.print(r.getData() +\" \");
}
}
}
public class BinarySearchTree
{
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
Binary Binary = new Binary();
System.out.println(\"Binary Search Tree Test\ \");
char ch;
do
{
System.out.println(\"\ Binary Search Tree Operations\ \");
System.out.println(\"1. insert \");
System.out.println(\"2. delete\");
System.out.println(\"3. search\");
System.out.println(\"4. check empty\");
int .
tested on eclipseDoublyLinkedList class.pdf
//tested on eclipse
/*************DoublyLinkedList class*******************/
public class DoublyLinkedList {
/*Data member variable declaration*/
private Node head;
private int count;
/**default constructor*/
public DoublyLinkedList() {
/*Initializing variable*/
head=null;
count =0;
}
/*Insert at beginning in doubly linked list*/
public void insertBeginning(String name){
/*checking head is null then we will add node at head*/
if(head==null){
head=new Node(name, null, null);
count++;
}else{
/*else create temp node and setting next to head
* and then making temp to head*/
Node temp=new Node(name,null,null);
temp.setNext(head);
head.setPrev(temp);
head=temp;
count++;
}
}
public void printList(){
Node temp=head;
/*Printing element of doubly list*/
while(temp!=null){
System.out.println(temp.getData());
temp=temp.getNext();
}
}
/*Returning count from doubly linked list*/
public int count(){
return count;
}
/*deleting specific node from doubly linked list*/
public void delete(String name){
Node current=head,previous=head;
/*if it is head node to be deleted*/
if(head.getData().equals(name)){
current=head.getNext();
current.setPrev(null);
head=current;
previous=head;
}else{
/*If node in middle of list*/
while(current.getNext()!=null){
if(current.getData().equals(name)){
current.getNext().setPrev(previous);
previous.setNext(current.getNext());
count--;
break;
}
previous=current;
current=current.getNext();
}
/*If node is at last*/
if(current.getNext()==null){
if(current.getData().equals(name)){
previous.setNext(null);
count--;
}
}
}
}
/*deleting all nodes from list by assigning head to null
* and memory releasing take care by garbage collector*/
public void clear(){
head=null;
count=0;
}
/*Inserting element in alphabetic order*/
public void insertAlpha(String name){
Node current=head,previous=head;
/*creating new node*/
Node newNode=new Node(name,null,null);
/*if head node is null*/
if(head==null){
head=newNode;
count++;
}else{
/*please read about compareTo() method about returning value*/
if(head.getData().compareTo(name)>0){
newNode.setNext(head);
head=newNode;
count++;
}else{
/*condition for getting position of node to be inserted*/
while(current!=null&¤t.getData().compareTo(name)<=0){
previous=current;
current=current.getNext();
}
/*if node need to be inserted at last*/
if(current==null){
previous=newNode;
}else{
/*If node need to inserted in middle*/
newNode.setNext(current);
previous.setNext(newNode);
current.setPrev(newNode);
newNode.setPrev(previous);
}
count++;
}
}
}
/*Main method start*/
public static void main(String args[]){
/*creating object of doubly linked list*/
DoublyLinkedList doublyLinkedList=new DoublyLinkedList();
doublyLinkedList.insertBeginning(\"sunita\");
doublyLinkedList.insertBeginning(\"lalchand\");
/*calling alphabetic order method*/
doublyLinkedList.insertAlpha(\"ramsingh\");
doublyLinkedList.insertBeginning(\"Lokesh\");
doublyLinkedList.insertBeginning(\"Pritam\");
/*****printing list********/
doublyLinkedList.printL.
Once you have all the structures working as intended- it is time to co.docx
Once you have all the structures working as intended, it is time to compare the
performances of the 2. Use runBenchmark() to start.
a. First, generate an increasing number (N) of random integers (1000, 5000, 10000,
50000, 75000, 100000, 500000 or as far as your computing power will let you)
i. Time and print how long it takes to insert the random integers into an initially
empty BST. Do not print the tree.
You can get a random list using the java class Random, located in
java.util.Random. To test the speed of the insertion algorithm, you should use
the System.currentTimeMillis() method, which returns a long that contains the
current time (in milliseconds). Call System.currentTimeMillis() before and after
the algorithm runs and subtract the two times. (Instant.now() is an alternative
way of recording the time.)
ii. Time and print how long it takes to insert the same random integers into an
initially empty AVL tree. Do not print the tree.
iii. If T(N) is the time function, how does the growth of TBST(N) compare with the
growth of TAVL(N)?
Plot a simple graph to of time against N for the two types of BSTs to visualize
your results.
b. Second, generate a list of k random integers. k is also some large value.
i. Time how long it takes to search your various N-node BSTs for all k random
integers. It does not matter whether the search succeeds.
ii. Time how long it takes to search your N-node AVL trees for the same k random
integers.
iii. Compare the growth rates of these two search time-functions with a graph the
same way you did in part a.
public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
/**
* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
* @return
*/
private int countLeafNodes(BinaryNode<AnyType> root) {
// If the root is null, it means the tree is empty, so we return 0
if (root == null) {
return 0;
}
// If the root has no children, it means it is a leaf node, so we return 1
if (root.left == .
A perfect left-sided binary tree is a binary tree where every intern.pdf
A perfect left-sided binary tree is a binary tree where every internal node has two children, and
every left child is a leaf. Write an algorithm, based on DFS or BFS, that takes as input an
undirected graph G, and returns whether or not G is (or can be viewed as) a perfect left-sided
binary tree. Analyze the time complexity of your algorithm.
Solution
bfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from start of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
dfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from end of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
search(vertex v)
{
visit(v);
for each edge (v,w)
add edge (v,w) to end of L
}
mport java.util.*;
public class BST > implements Iterable
{
public static void main(String[] args)
{
Integer[] a = {1,5,2,7,4};
BST bst = new BST();
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
//testing comparator
//build a mirror BST with a rule: Left > Parent > Right
//code for the comparator at the bottom of the file
bst = new BST(new MyComp1());
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
System.out.println();
for(Integer n : bst) System.out.print(n);
System.out.println();
System.out.println(bst);
//testing restoring a tree from two given traversals
bst.restore(new Integer[] {11,8,6,4,7,10,19,43,31,29,37,49},
new Integer[] {4,6,7,8,10,11,19,29,31,37,43,49});
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
System.out.println();
//testing diameter
System.out.println(\"diameter = \" + bst.diameter());
//testing width
System.out.println(\"width = \" + bst.width());
}
private Node root;
private Comparator comparator;
public BST()
{
root = null;
comparator = null;
}
public BST(Comparator comp)
{
root = null;
comparator = comp;
}
private int compare(T x, T y)
{
if(comparator == null) return x.compareTo(y);
else
return comparator.compare(x,y);
}
/*****************************************************
*
* INSERT
*
******************************************************/
public void insert(T data)
{
root = insert(root, data);
}
private Node insert(Node p, T toInsert)
{
if (p == null)
return new Node(toInsert);
if (compare(toInsert, p.data) == 0)
return p;
if (compare(toInsert, p.data) < 0)
p.left = insert(p.left, toInsert);
else
p.right = insert(p.right, toInsert);
return p;
}
/*****************************************************
*
* SEARCH
*
******************************************************/
public boolean search(T toSearch)
{
return search(root, toSearch);
}
private boolean search(Node p, T toSearch)
{
if (p == null)
return false;
else
if (compare(toSearch, p.data) == 0)
return true;
else
if (compare(toSearch, p.data) < 0)
return search(p.left, toSearch);
else
return search(p.right, toSearch);
}
/*****************************************************.
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
#include iostream using namespace std; const int nil = 0; cl.docx
#include iostream using namespace std; const int nil = 0; cl
Please refer this solution. This is working file for IntegersHeade.pdf
Please refer this solution. This is working file for Integers
Header file :-
-----------------------------------
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
struct node{
void * data;
node * next;
};
class LinkedList
{
private:
node* head ;
int size;
public:
LinkedList();
//method to create a node
node * create(void* data);
//method to append
void append(node * item);
//method to prepend
void prepend(node * item);
//insert in ascending order
void insertAscend(node * item);
//insert in ascending order
void insertDescend(node * item);
//display all nodes
void display();
//free the list
void freeUp();
};
#endif // LINKEDLIST_H
Source file :-
----------------------------------
#include \"linkedlist.h\"
#include
#include
#include
LinkedList::LinkedList()
{
//head = (node *)malloc(sizeof(node));
size = 0;
head = NULL;
}
//method to create a node
node * LinkedList::create(void* data){
node * newNode = (node *)malloc(sizeof(node));
newNode->data = malloc(sizeof(data));
memcpy(newNode->data,data,sizeof(data));
newNode->next = NULL;
return newNode;
}
//method to append
void LinkedList::append(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
while (current->next!=NULL )
{
current = current->next;
}
current->next = item ;
size++;
}
//method to prepend
void LinkedList::prepend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
item->next = head;
head = item;
size++;
}
//insert in ascending order
void LinkedList::insertAscend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data < *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//insert in Descending order
void LinkedList::insertDescend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data > *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//display all nodes
void LinkedList::display(){
int idx = 0;
node* current;
current = head;
while (current != NULL ){
idx++;
int *data = static_cast(current->data);
printf(\"data for item ::%dis :: %d\ \",idx,*data);
current = current->next;
}
}
//free the list
void LinkedList::freeUp(){
node* current;
current = head;
while (current->next!=NULL ){
head = current->next;
delete current;
current = head;
}
}
Main f.
mainpublic class AssignmentThree { public static void ma.pdf
// main
public class AssignmentThree
{
public static void main(String[] args)
{
List myList = new List(15);
// Cause List Empty Message
myList.removeFront();
myList.removeRear();
myList.removeItem(\"a\");
// Cause Not found message
myList.addToFront(\"x\");
myList.removeItem(\"y\");
myList.removeItem(\"x\");
myList.addAfterItem(\"x\", \"z\");
myList.addBeforeItem(\"x\", \"z\");
// Normal behavior
myList.addToFront(\"not.\");
myList.addToFront(\"or\");
myList.addToRear(\"is\");
myList.addToRear(\"try.\");
myList.addAfterItem(\"is\", \"no\");
myList.addBeforeItem(\"is\", \"There\");
myList.addToFront(\"Do\");
myList.addAfterItem(\"or\", \"do\");
myList.print(\"Original list\");
myList.printSorted(\"Sorted Original List\");
sop(\"\ Front is \" + myList.getFront());
sop(\"Rear is \" + myList.getRear());
sop(\"Count is \" + myList.askCount());
sop(\"Is There present? \" + myList.isPresent(\"There\"));
sop(\"Is Dog present? \" + myList.isPresent(\"Dog\"));
myList.addToFront(\"junk\");
myList.addToRear(\"morejunk\");
myList.addAfterItem(\"or\", \"moremorejunk\");
myList.print(\"List with junk\");
sop(\"Count is \" + myList.askCount());
myList.removeFront();
myList.removeRear();
myList.removeItem(\"moremorejunk\");
myList.print(\"List with junk removed\");
sop(\"Count is \" + myList.askCount());
sop(\"\");
// Cause List Full message
for(int ii = 0; ii < 10; ++ii)
{
myList.addToFront(DUMMY);
}
myList.addToRear(DUMMY);
myList.addBeforeItem(\"no\", DUMMY);
myList.addAfterItem(\"There\", DUMMY);
myList.print(\"After filling List\");
sop(\"Count is \" + myList.askCount());
while(myList.isPresent(DUMMY)) myList.removeItem(DUMMY);
myList.print(\"After removing \" + DUMMY );
sop(\"Count is \" + myList.askCount());
}
private static void sop(String s)
{
System.out.println(s);
}
private static final String DUMMY = \"dummy\";
}
Solution
Following is MyList implementation for your output as:
Java Code:
import java.util.Comparator;
public class MyList {
private Node start;
private Node end;
private int size;
private int capacity;
public MyList(int capacity) {
start = null;
end = null;
size = 0;
this.capacity = capacity;
}
/* Function to check if list is empty */
public boolean isEmpty() {
return start == null;
}
public void removeFront() {
if (isEmpty()) {
System.out.println(\"List Empty\");
return;
} else {
start = start.next;
size--;
return;
}
}
public void removeRear() {
if (size == 0) {
System.out.println(\"List Empty\");
return;
}
if (start.next == null) {
start=null;
end=null;
size=0;
}
Node node = start.next;
while (node.next != null) {
node = node.next;
}
node.next = null;
end = node;
size--;
}
public void removeItem(String key) {
if (size == 0) {
System.out.println(\"List Empty\");
return;
}
if (start.next == null) {
if (start.key.equals(key)) {
start=null;
end=null;
size=0;
} else {
System.out.println(\"\");
}
return;
}
Node node = start;
Node nodeNext = node.next;
while (nodeNext.next != null) {
if (nodeNext.key.equals(key)) {
node.next=nodeNext.next;
}.
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using java
Given a class ‘Node’ and ‘NodeList’, that contains the below information diagram.
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
NodeList
-size: int
-root: Node
+add(node: Node): void
+size(): int
+findNode(node: Node): boolean
Implement add(Node), findNode(Node) and size methods in the NodeList class which is
provided to you. The methods should work as:
Using the following main method:
public static void main(String[] args)
{
NodeList list = new NodeList();
Node node = new Node(1, \"Book\");
Node node2 = new Node(2, \"Lappy\");
list.add(node);
list.add(node2);
System.out.println(\"Length : \"+list.size());
Node node3 = new Node(3, \"Glass\");
Node node4 = new Node(4, \"Pen\");
list.add(node3);
System.out.println(\"Length : \"+list.size());
if(list.findNode(node3)) System.out.println(\"Node found: \"+ node3.getName());
else
System.out.println(\"Node not found: \"+ node3.getName());
if(list.findNode(node4)) System.out.println(\"Node found: \"+ node4.getName());
else
System.out.println(\"Node not found: \"+ node4.getName());
}
Then it should return the following output:
Length : 2
Length : 3
Node found: Glass
Node not found: Pen
The given Node class is:
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this.name = name;
this.next = null;
}
public Node getNext()
{
return next;
}
public void setNext(Node node)
{
this.next = node
}
public int getId()
{
return id;
{
public void setId(int id)
{
this.id = id;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public String toString()
{
return \"ID : \"+this.id+\" Name : \"+this.name;
}
}
The given NodeList class is:
public class NodeList
{
private int size = 0;
private Node root = null;
/*
* It has to take a new Node and add that to the next address of previous Node.
* If the list is empty, assign it as the \"root\"
* @Param - Node
*/
public void add(Node node)
{
// Implement this method!!!
}
/*
* It has to return the size of the NodeList
*
* @return size
*/
public int size()
{
// Implement this method!!!
}
/*
* It has to take a Node and checks if the node is in the list.
* If it finds the node, it returns true, otherwise false
*
* @param - Node
* @return boolean true/false
*/
public boolean findNode(Node node)
{
// Implement this method!!!
}
}Node
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
############ Node.java #############
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this..
You�ve been hired by the local government to determine which employe.pdf
Youve been hired by the local government to determine which employees are most essential in
the Parks & Recreation department.
You plan to conduct a social network analysis. You find that people (in bold below) list the
following others as ones they work well with:
Leslie: Andy, Ann, Donna
Ron: April
Ben: Ann
April: Donna, Ron
Andy: Chris, Tim, Leslie
Donna: Leslie, April, Gerry
Gerry: Donna
Tom: Andy, Ann, Donna
Ann: Ben, Leslie, Tim, Chris
Chris: Andy, Ann
- A. B. C. D. E. F. G. H. I. J.
Who is the central connector?- A. B. C. D. E. F. G.
H. I. J. Who is the
broker?A.ChrisB.AnnC.GerryD.BenE.DonnaF.TomG.AprilH.AndyI.RonJ.Leslie.
you will implement some sorting algorithms for arrays and linked lis.pdf
you will implement some sorting algorithms for arrays and linked lists.
Insertion Sort and Quicksort of an array
Implement the insertion sort and quicksort for an integer array. The functions are defined in the
"sorting.h" header file.
/**
* @brief Insertion sort algorithm
* @param array Array to be sorted. The array is modified in place.
* @param lowindex Lowest index of the array
* @param highindex Highest index of the array
* @param reversed If reversed = true, the array should be sorted in descending order, otherwise
in ascending order
*/
void insertionSort(int array[], int lowindex, int highindex, bool reversed = false);
and
**
* @brief Quick sort algorithm
*
* @param array Array to be sorted. The array is modified in place.
* @param lowindex Lowest index of the array
* @param highindex Highest index of the array
* @param reversed If reversed = true, the array should be sorted in descending order, otherwise
in ascending order
*/
void quickSort(int array[], int lowindex, int highindex, bool reversed = false);
The array should be sorted in place. Compared to the examples in the textbook, those functions
have an additional parameter reversed. If reversed = true, the array should be sorted in
descending order, otherwise in ascending order. You should complete the implementations of
those two functions in the "sorting_basic.cpp" file.
A better quicksort algorithm
Quicksort is a very fast comparison sorting algorithm, especially wheb the array or list gets large.
However, when the arrays/lists are small enough, quicksort may run slower than some of the
(n^2) algorithms. This might not seem important until you note that when sorting a large array
with quicksort, many small sublists must be sorted. While the savings on sorting one small list
with a faster algorithm might be negligible, sorting hundreds of small lists with a faster algorithm
can make a difference in the overall efficiency of the sort. For this part of the assignment, you
will combine quicksort with another sorting algorithm to build a faster sorting algorithm. One
option is to
use quicksort until the array/list gets small enough, and then use insertion sort or another sort to
sort the small arrays/lists
What does "small enough" mean? You can try a percentage of the list (say, 5% or 10%), or an
absolute number (5 elements, 8 elements, 10 elements, 15 elements, 100 elements, etc), or
something else of your choosing. Based on your tests, choose the one that is the most efficient.
You should also tests to ensure that your hybrid quicksort has reasonable performance on all lists
-- most notably, it should be efficient on sorted and inverse sorted lists as well as random lists.
The definition of the hybrid quicksort function is as the following:
/**
* @brief A hybrid of insertion sort and quick sort algorithm. The algorithm is based on the idea
that if the array is short, it is better to use insertion sort.
* It uses quicksort until the list gets small enough, and then uses insertion s.
More Related Content
Similar to usingpackage util;import java.util.;This class implements.pdf
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdf
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD
OR REMOVE NAME. DO NOT HARD CODE NAME. AGAIN MAKE SURE THE
PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR REMOVE NAME. PLEASE
MAKE SURE THE CODE RUNS WITHOUT ANY ERRORS.
Write a class that maintains the scores for a game application. Implement the addition and
removal function to update the database. The gamescore.txt contains player’ name and score data
record fields separated by comma. For Removal function, uses the name field to select record to
remove the game score record.
Use the List.java, LList.java, Dlink.java, GameEntry.java and gamescore.txt found below
Read gamescore.txt to initialize the Linked list in sorted order by score.
Ask the user to add or remove users to update the sorted linked list.
Display “Name exist” when add an exist name to the list.
Display “Name does not exist” when remove a name not on the list.
List.java File:
/** Source code example for \"A Practical Introduction to Data
Structures and Algorithm Analysis, 3rd Edition (Java)\"
by Clifford A. Shaffer
Copyright 2008-2011 by Clifford A. Shaffer
*/
/** List ADT */
public interface List
{
/**
* Remove all contents from the list, so it is once again empty. Client is
* responsible for reclaiming storage used by the list elements.
*/
public void clear();
/**
* Insert an element at the current location. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be inserted.
*/
public void insert(E item);
/**
* Append an element at the end of the list. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be appended.
*/
public void append(E item);
/**
* Remove and return the current element.
*
* @return The element that was removed.
*/
public E remove();
/** Set the current position to the start of the list */
public void moveToStart();
/** Set the current position to the end of the list */
public void moveToEnd();
/**
* Move the current position one step left. No change if already at
* beginning.
*/
public void prev();
/**
* Move the current position one step right. No change if already at end.
*/
public void next();
/** @return The number of elements in the list. */
public int length();
/** @return The position of the current element. */
public int currPos();
/**
* Set current position.
*
* @param pos
* The position to make current.
*/
public void moveToPos(int pos);
/** @return The current element. */
public E getValue();
}
LList.java File:
/**
* Source code example for \"A Practical Introduction to Data Structures and
* Algorithm Analysis, 3rd Edition (Java)\" by Clifford A. Shaffer Copyright
* 2008-2011 by Clifford A. Shaffer
*/
// Doubly linked list implementation
class LList implements List
{
private DLink head; // Pointer to list header
private DLink tail; // Pointer to last element in list
protected DLink curr; // Pointer ahead of current element
int cnt; // Size of list
// Constructors
LList(int size)
{
th.
Note Given Code modified as required and required met.pdf
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void setData(String data)
{
this.data = data;
}
// method to get the next data
public Node getNext()
{
return next;
}
// method to set the next data
public void setNext(Node next)
{
this.next = next;
}
}
// class for a linked list
class MyLInkedList
{
Node head;alue into a list
// method to add the v
public void add(String num)
{
if (head == null)
{
head = new Node(num);
}
else{
Node temp = new Node(num);
Node current = head;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(temp);
}
}
}
// method to search a value from a list
public void search(String num)
{
Node current = head;
boolean flag=true;
if (current != null)
{
while (current != null)
{
if(current.getData() == num)
{
System.out.println(\"Search value \"+
current.getData()+\" is available\");
flag=false;
}
current = current.getNext();
}
if (flag==true)
{
System.out.println(\"Search value \"+
current.getData()+\" is not available\");
}
}
else
{
System.out.println(\"Linked list is empty\");
}
}
// method to delete a value from a list
public void delete(String num)
{
//Node current = head;
boolean flag=true;
if (head == null)
{
System.out.println(\"Can\'t Delete, Linked list is
empty\");
return;
}
if(head.getData() == num)
{
head=head.getNext();
return;
}
Node temp = new Node(num);
Node cr = head;
Node prev=null;
while ((cr != null) && !(cr.getData() == num))
{
prev=cr;
cr = cr.getNext();
}
prev.setNext(cr.getNext());
}
// method to print the list
public void print()
{
Node current = head;
if (current != null) {
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
}
}
// method to test the class
public class MyLInkedListTester
{
// main method to perform the linked list operatrions
public static void main(String args[])
{
MyLInkedList llist = new MyLInkedList();
// insert the values into list
llist.add(\"1\");
llist.add(\"2\");
llist.add(\"3\");
llist.add(\"4\");
// print the list values
llist.print();
// sear the values in a list
llist.search(\"1\");
llist.print();
// delete the value from a list
llist.delete(\"4\");
System.out.println(\"List after deletion:\");
llist.print();
}
}
Result:
1
2
3
4
Search value 1 is available
1
2
3
4
List after deletion:
1
2
3
Solution
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void se.
in this assignment you are asked to write a simple driver program an.pdf
in this assignment you are asked to write a simple driver program and set of functions (maybein
a library) that can be performed on a binary search tree.
Your program should allow user to insert/delete integer values into the binary search tree along
with several other operations on the binary search tree. You can use the code given in slides. But
this time your key will be int! Specifically, your program will ask user to enter a command and
related parameters (if any) in a loop, and then perform the given commands. Here is the list of
commands that your program must implement:
* insert
*find\'
*delete
*list inorder
*list preorder
*list postorder
*list levelorder
* max
* min
* height
*count
* sum
*quit
As always, make sure you release (free) the dynamically allocated memories if you allocate any
memory in your programs. So, before submitting your program, run it with valgrind to see if
there is any memory leakage
//my proggram in C
struct tree_node {
int data;
struct tree_node *left, *right;
}
typedef struct nodeT {
int key;
struct nodeT *left, *right;
} nodeT, *treeT;
int main(){
while (TRUE) {
printf(\"> \");
line = GetLine();
ch = toupper(line[0]);
switch (ch) {
case \'I\': insert(); break;
case \'F\': find(); break;
case \'D\': delete(); break;
case \'LI\': listInorder; break;
case \'LPR\': listPreorder(); break;
case \'LPO\': listPostorder(); break;
case \'MAX\': max(); break;
case \'min\': min(); break;
case \'H\': height(); break;
case \'C\': count(); break;
case \'S\': sum(); break;
case \'Q\': exit(0);
default:printf(\"Illegal command\ \"); break;
}
}
}
nodeT *FindNode(nodeT *t, int key){
while(t !=NULL) {
if (key == t->key) return t;
if (key < t->key) {
t = t->left;
} else {
t = t->right;
}
return NULL;
}
void delete(nodeT **p){
nodeT
*target;
target=*p;
if (target->left==NULL && target->right==NULL) {
*p=NULL;
} else if (target->left == NULL) {
*p=target->right;
} else
if (target->right == NULL) {
*p=target->left;
} else {
/* target has two children, see next slide */
}
free(target);
}
void listInorder(nodeT *T){
if (t != NULL) {
DisplayTree(t->left);
printf(“%d “, t->key);
DisplayTree(t->right);
}
}
void listPreorder(nodeT *t) {
if (t != NULL) {
printf(“%d “, t->key);
DisplayTree(t->left);
DisplayTree(t->right);
}
}
void listPostOrder(nodeT *t){
if (t != NULL) {
DisplayTree(t->left);
DisplayTree(t->right);
printf(“%d “, t->key);
}
}
void intsert(nodeT **tptr, int key){
nodeT*t, *tmp;
t=*tptr;
if (t == NULL) {
tmp=New(nodeT*);
tmp->key = key;
tmp->left=tmp->right=NULL;
*tptr=tmp;
return;
}
if (key < t->key) {
InsertNode
(&t->left, key);
} else {
InsertNode(&t->right, key);
}
}
int height(nodeT *t){
if (t == NULL)
return 0;
else
return (1 + maximumof(
height(t->left),
height(t->right)) );
}
int sum(struct tree_node *p){
if (p == NULL)
return 0;
else
return (p->data +
sum(p->left) +
sum(p->right) );
}
Solution
1. /*
2. * Java Program to Implement Binary Search Tree
3. */
4.
5. import java.util.Scanner;
6.
7. /* Class BSTNode */
8. cl.
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
For the code below complete the preOrder() method so that it perform.pdf
For the code below complete the preOrder() method so that it performs a preOrder traversal of
the tree. For each node it traverses, it should call sb.append() to add a \"[\" the results of
traversing the subtree rooted at that node, and then a \"]\". You should add a space before the
results of the left and right child traversals, but only if the node exists.
code:
Solution
In preorder Nodes visited are in the order of
code:
package edu.buffalo.cse116;
import java.util.AbstractSet;
import java.util.Iterator;
public class BinarySearchTree> extends AbstractSet {
protected Entry root;
protected int size;
/**
* Initializes this BinarySearchTree object to be empty, to contain only
* elements of type E, to be ordered by the Comparable interface, and to
* contain no duplicate elements.
*/
public BinarySearchTree() {
root = null;
size = 0;
}
/**
* Initializes this BinarySearchTree object to contain a shallow copy of a
* specified BinarySearchTree object. The worstTime(n) is O(n), where n is the
* number of elements in the specified BinarySearchTree object.
*
* @param otherTree - the specified BinarySearchTree object that this
* BinarySearchTree object will be assigned a shallow copy of.
*/
public BinarySearchTree(BinarySearchTree otherTree) {
root = copy(otherTree.root, null);
size = otherTree.size;
}
/* Method to complete is here! */
public void preOrder(Entry ent, StringBuilder sb) {
preorder(root)
protected Entry copy(Entry p, Entry parent) {
if (p != null) {
Entry q = new Entry(p.element, parent);
q.left = copy(p.left, q);
q.right = copy(p.right, q);
return q;
}
return null;
} // method copy
@SuppressWarnings(\"unchecked\")
@Override
public boolean equals(Object obj) {
if (!(obj instanceof BinarySearchTree)) {
return false;
}
return equals(root, ((BinarySearchTree) obj).root);
}
public boolean equals(Entry p, Entry q) {
if ((p == null) || (q == null)) {
return p == q;
}
if (!p.element.equals(q.element)) {
return false;
}
if (equals(p.left, q.left) && equals(p.right, q.right)) {
return true;
}
return false;
}
/**
* Returns the size of this BinarySearchTree object.
*
* @return the size of this BinarySearchTree object.
*/
@Override
public int size() {
return size;
}
/**
* Iterator method will be implemented for a future
*
* @return an iterator positioned at the smallest element in this
* BinarySearchTree object.
*/
@Override
public Iterator iterator() {
throw new UnsupportedOperationException(\"Not implemented yet!\");
}
/**
* Determines if there is at least one element in this BinarySearchTree object
* that equals a specified element. The worstTime(n) is O(n) and
* averageTime(n) is O(log n).
*
* @param obj - the element sought in this BinarySearchTree object.
* @return true - if there is an element in this BinarySearchTree object that
* equals obj; otherwise, return false.
* @throws ClassCastException - if obj cannot be compared to the elements in
* this BinarySearchTree object.
* @throws NullPointerException - if obj is null.
*/
@Override
public .
Please read the comment ins codeExpressionTree.java-------------.pdf
Please read the comment ins code
ExpressionTree.java
----------------------------------
/**
* This is the class for Expression Tree.
* Used to create Expression Tree and Evaluate it
*/
/**
* Following logic is used to construct a Tree
* Here we use stack for Preparing Tree
* Loop through given Expression String
* If Character is Operand , Create node and push to stack
* If Character is Operator then
* 1)Create Node for Operator
* 2)Pop 2 nodes from Stack and Made
* OpretorNode--> left == first node pop
* OpretorNode--> right == second node pop
* At the end of creation of Expression Tree, Stack have only one node , which is root of
Expression tree
*/
/** Class ExpressionTree **/
class ExpressionTree
{
/** class TreeNode
* Stored Character ==> Digit(0..9) or a Operator +,-,*,/
* Left Node and Right Node
*
* **/
class TreeNode
{
char data;
TreeNode left, right;
/** constructor **/
public TreeNode(char data)
{
this.data = data;
this.left = null;
this.right = null;
}
}
/** class StackNode **/
class StackNode
{
TreeNode treeNode;
StackNode next;
/** constructor **/
public StackNode(TreeNode treeNode)
{
this.treeNode = treeNode;
next = null;
}
}
private static StackNode top;
/** constructor
* Constructor takes input string like \"+-+7*935*82*625\"
* Input should be in Prefix notation
* **/
public ExpressionTree(String expression)
{
top = null;
//Call Method for prepare expression tree
buildTree(expression);
}
/** function to clear tree **/
public void clear()
{
top = null;
}
/** function to push a node **/
private void push(TreeNode ptr)
{
if (top == null)
top = new StackNode(ptr);
else
{
StackNode nptr = new StackNode(ptr);
nptr.next = top;
top = nptr;
}
}
/** function to pop a node
* When it find operator pop 2 elements from Stack
*
* **/
private TreeNode pop()
{
if (top == null)
throw new RuntimeException(\"Underflow\");
else
{
TreeNode ptr = top.treeNode;
top = top.next;
return ptr;
}
}
/** function to get top node **/
private TreeNode peek()
{
return top.treeNode;
}
/** function to insert character **/
private void insert(char val)
{
try
{
//If Operand , Create node and push to Stack
if (isDigit(val))
{
TreeNode nptr = new TreeNode(val);
push(nptr);
}
//If Operator , Create node and popup 2 elements and make them its right and left
else if (isOperator(val))
{
TreeNode nptr = new TreeNode(val);
nptr.left = pop();
nptr.right = pop();
push(nptr);
}
}
catch (Exception e)
{
System.out.println(\"Invalid Expression\");
}
}
/** function to check if digit **/
private boolean isDigit(char ch)
{
return ch >= \'0\' && ch <= \'9\';
}
/** function to check if operator **/
private boolean isOperator(char ch)
{
return ch == \'+\' || ch == \'-\' || ch == \'*\' || ch == \'/\';
}
/** function to convert character to digit **/
private int toDigit(char ch)
{
return ch - \'0\';
}
/** function to build tree from input */
public void buildTree(String eqn)
{
for (int i = eqn.length() - 1; i >= 0; i--)
insert(eqn.charAt(i));
}
/** function to evaluate tree */
public dou.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
JAVA A double-ended queue is a list that allows the addition and.pdf
**JAVA** A double-ended queue is a list that allows the addition and removal of items from
either end. One end is arbitrarily called the front and other the rear, but the two ends behave
identically. Specify, design and implement a class for a double-ended queue. Include operations
to check if it is empty and to return the number of items in the list. For each end, include
operations for adding and deleting items. Use doubly linked list for your implementation. Call
your class Deque (pronounced \"deck\").
Solution
//package com.java2novice.ds.queue;
public class DequeDblLinkedListImpl {
private LinkedNode front;
private LinkedNode rear;
public void insertFront(T item){
//add element at the beginning of the queue
System.out.println(\"adding at front: \"+item);
LinkedNode nd = new LinkedNode();
nd.setValue(item);
nd.setNext(front);
if(front != null) front.setPrev(nd);
if(front == null) rear = nd;
front = nd;
}
public void insertRear(T item){
//add element at the end of the queue
System.out.println(\"adding at rear: \"+item);
LinkedNode nd = new LinkedNode();
nd.setValue(item);
nd.setPrev(rear);
if(rear != null) rear.setNext(nd);
if(rear == null) front = nd;
rear = nd;
}
public void removeFront(){
if(front == null){
System.out.println(\"Deque underflow!! unable to remove.\");
return;
}
//remove an item from the beginning of the queue
LinkedNode tmpFront = front.getNext();
if(tmpFront != null) tmpFront.setPrev(null);
if(tmpFront == null) rear = null;
System.out.println(\"removed from front: \"+front.getValue());
front = tmpFront;
}
public int size(){
if(front == null && rear ==null){
return 0;
}
//remove an item from the beginning of the queue
LinkedNode tmpFront = front;
LinkedNode tmpRear = rear;
int i=0;
while(tmpFront != rear)
{
i++;
tmpFront=tmpFront.getNext();
}
i++;
return i;
}
public void removeRear(){
if(rear == null){
System.out.println(\"Deque underflow!! unable to remove.\");
return;
}
//remove an item from the beginning of the queue
LinkedNode tmpRear = rear.getPrev();
if(tmpRear != null) tmpRear.setNext(null);
if(tmpRear == null) front = null;
System.out.println(\"removed from rear: \"+rear.getValue());
rear = tmpRear;
}
public static void main(String a[]){
DequeDblLinkedListImpl deque = new DequeDblLinkedListImpl();
deque.insertFront(34);
deque.insertFront(67);
System.out.println(\"Size of the queue : \"+deque.size());
deque.insertFront(29);
deque.insertFront(765);
deque.removeFront();
deque.removeFront();
deque.removeFront();
deque.insertRear(43);
deque.insertRear(83);
deque.insertRear(84);
deque.insertRear(546);
deque.insertRear(356);
deque.removeRear();
deque.removeRear();
deque.removeRear();
deque.removeRear();
deque.removeFront();
deque.removeFront();
deque.removeFront();
}
}
class LinkedNode{
private LinkedNode prev;
private LinkedNode next;
private T value;
public LinkedNode getPrev() {
return prev;
}
public void setPrev(LinkedNode prev) {
this.prev = prev;
}
public LinkedNode getNext() {
return next;
}
public void setNext(L.
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
import java.util.Scanner;
class BinaryNode
{
BinaryNode left, right;
int data;
public BinaryNode()
{
left = null;
right = null;
data = 0;
}
public BinaryNode(int n)
{
left = null;
right = null;
data = n;
}
public void setLeft(BinaryNode n)
{
left = n;
}
public void setRight(BinaryNode n)
{
right = n;
}
public BinaryNode getLeft()
{
return left;
}
public BinaryNode getRight()
{
return right;
}
public void setData(int d)
{
data = d;
}
public int getData()
{
return data;
}
}
class Binary
{
private BinaryNode root;
public Binary()
{
root = null;
}
public boolean isEmpty()
{
return root == null;
}
public void insert(int data)
{
root = insert(root, data);
}
private BinaryNode insert(BinaryNode node, int data)
{
if (node == null)
node = new BinaryNode(data);
else
{
if (data <= node.getData())
node.left = insert(node.left, data);
else
node.right = insert(node.right, data);
}
return node;
}
public void delete(int k)
{
if (isEmpty())
System.out.println(\"Tree Empty\");
else if (search(k) == false)
System.out.println(\"Sorry \"+ k +\" is not present\");
else
{
root = delete(root, k);
System.out.println(k+ \" deleted from the tree\");
}
}
private BinaryNode delete(BinaryNode root, int k)
{
BinaryNode p, p2, n;
if (root.getData() == k)
{
BinaryNode lt, rt;
lt = root.getLeft();
rt = root.getRight();
if (lt == null && rt == null)
return null;
else if (lt == null)
{
p = rt;
return p;
}
else if (rt == null)
{
p = lt;
return p;
}
else
{
p2 = rt;
p = rt;
while (p.getLeft() != null)
p = p.getLeft();
p.setLeft(lt);
return p2;
}
}
if (k < root.getData())
{
n = delete(root.getLeft(), k);
root.setLeft(n);
}
else
{
n = delete(root.getRight(), k);
root.setRight(n);
}
return root;
}
public boolean search(int val)
{
return search(root, val);
}
private boolean search(BinaryNode r, int val)
{
boolean found = false;
while ((r != null) && !found)
{
int rval = r.getData();
if (val < rval)
r = r.getLeft();
else if (val > rval)
r = r.getRight();
else
{
found = true;
break;
}
found = search(r, val);
}
return found;
}
public void inorder()
{
inorder(root);
}
private void inorder(BinaryNode r)
{
if (r != null)
{
inorder(r.getLeft());
System.out.print(r.getData() +\" \");
inorder(r.getRight());
}
}
public void preorder()
{
preorder(root);
}
private void preorder(BinaryNode r)
{
if (r != null)
{
System.out.print(r.getData() +\" \");
preorder(r.getLeft());
preorder(r.getRight());
}
}
public void postorder()
{
postorder(root);
}
private void postorder(BinaryNode r)
{
if (r != null)
{
postorder(r.getLeft());
postorder(r.getRight());
System.out.print(r.getData() +\" \");
}
}
}
public class BinarySearchTree
{
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
Binary Binary = new Binary();
System.out.println(\"Binary Search Tree Test\ \");
char ch;
do
{
System.out.println(\"\ Binary Search Tree Operations\ \");
System.out.println(\"1. insert \");
System.out.println(\"2. delete\");
System.out.println(\"3. search\");
System.out.println(\"4. check empty\");
int .
tested on eclipseDoublyLinkedList class.pdf
//tested on eclipse
/*************DoublyLinkedList class*******************/
public class DoublyLinkedList {
/*Data member variable declaration*/
private Node head;
private int count;
/**default constructor*/
public DoublyLinkedList() {
/*Initializing variable*/
head=null;
count =0;
}
/*Insert at beginning in doubly linked list*/
public void insertBeginning(String name){
/*checking head is null then we will add node at head*/
if(head==null){
head=new Node(name, null, null);
count++;
}else{
/*else create temp node and setting next to head
* and then making temp to head*/
Node temp=new Node(name,null,null);
temp.setNext(head);
head.setPrev(temp);
head=temp;
count++;
}
}
public void printList(){
Node temp=head;
/*Printing element of doubly list*/
while(temp!=null){
System.out.println(temp.getData());
temp=temp.getNext();
}
}
/*Returning count from doubly linked list*/
public int count(){
return count;
}
/*deleting specific node from doubly linked list*/
public void delete(String name){
Node current=head,previous=head;
/*if it is head node to be deleted*/
if(head.getData().equals(name)){
current=head.getNext();
current.setPrev(null);
head=current;
previous=head;
}else{
/*If node in middle of list*/
while(current.getNext()!=null){
if(current.getData().equals(name)){
current.getNext().setPrev(previous);
previous.setNext(current.getNext());
count--;
break;
}
previous=current;
current=current.getNext();
}
/*If node is at last*/
if(current.getNext()==null){
if(current.getData().equals(name)){
previous.setNext(null);
count--;
}
}
}
}
/*deleting all nodes from list by assigning head to null
* and memory releasing take care by garbage collector*/
public void clear(){
head=null;
count=0;
}
/*Inserting element in alphabetic order*/
public void insertAlpha(String name){
Node current=head,previous=head;
/*creating new node*/
Node newNode=new Node(name,null,null);
/*if head node is null*/
if(head==null){
head=newNode;
count++;
}else{
/*please read about compareTo() method about returning value*/
if(head.getData().compareTo(name)>0){
newNode.setNext(head);
head=newNode;
count++;
}else{
/*condition for getting position of node to be inserted*/
while(current!=null&¤t.getData().compareTo(name)<=0){
previous=current;
current=current.getNext();
}
/*if node need to be inserted at last*/
if(current==null){
previous=newNode;
}else{
/*If node need to inserted in middle*/
newNode.setNext(current);
previous.setNext(newNode);
current.setPrev(newNode);
newNode.setPrev(previous);
}
count++;
}
}
}
/*Main method start*/
public static void main(String args[]){
/*creating object of doubly linked list*/
DoublyLinkedList doublyLinkedList=new DoublyLinkedList();
doublyLinkedList.insertBeginning(\"sunita\");
doublyLinkedList.insertBeginning(\"lalchand\");
/*calling alphabetic order method*/
doublyLinkedList.insertAlpha(\"ramsingh\");
doublyLinkedList.insertBeginning(\"Lokesh\");
doublyLinkedList.insertBeginning(\"Pritam\");
/*****printing list********/
doublyLinkedList.printL.
Once you have all the structures working as intended- it is time to co.docx
Once you have all the structures working as intended, it is time to compare the
performances of the 2. Use runBenchmark() to start.
a. First, generate an increasing number (N) of random integers (1000, 5000, 10000,
50000, 75000, 100000, 500000 or as far as your computing power will let you)
i. Time and print how long it takes to insert the random integers into an initially
empty BST. Do not print the tree.
You can get a random list using the java class Random, located in
java.util.Random. To test the speed of the insertion algorithm, you should use
the System.currentTimeMillis() method, which returns a long that contains the
current time (in milliseconds). Call System.currentTimeMillis() before and after
the algorithm runs and subtract the two times. (Instant.now() is an alternative
way of recording the time.)
ii. Time and print how long it takes to insert the same random integers into an
initially empty AVL tree. Do not print the tree.
iii. If T(N) is the time function, how does the growth of TBST(N) compare with the
growth of TAVL(N)?
Plot a simple graph to of time against N for the two types of BSTs to visualize
your results.
b. Second, generate a list of k random integers. k is also some large value.
i. Time how long it takes to search your various N-node BSTs for all k random
integers. It does not matter whether the search succeeds.
ii. Time how long it takes to search your N-node AVL trees for the same k random
integers.
iii. Compare the growth rates of these two search time-functions with a graph the
same way you did in part a.
public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
/**
* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
* @return
*/
private int countLeafNodes(BinaryNode<AnyType> root) {
// If the root is null, it means the tree is empty, so we return 0
if (root == null) {
return 0;
}
// If the root has no children, it means it is a leaf node, so we return 1
if (root.left == .
A perfect left-sided binary tree is a binary tree where every intern.pdf
A perfect left-sided binary tree is a binary tree where every internal node has two children, and
every left child is a leaf. Write an algorithm, based on DFS or BFS, that takes as input an
undirected graph G, and returns whether or not G is (or can be viewed as) a perfect left-sided
binary tree. Analyze the time complexity of your algorithm.
Solution
bfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from start of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
dfs(G)
{
list L = empty
tree T = empty
choose a starting vertex x
search(x)
while(L nonempty)
remove edge (v,w) from end of L
if w not yet visited
{
add (v,w) to T
search(w)
}
}
search(vertex v)
{
visit(v);
for each edge (v,w)
add edge (v,w) to end of L
}
mport java.util.*;
public class BST > implements Iterable
{
public static void main(String[] args)
{
Integer[] a = {1,5,2,7,4};
BST bst = new BST();
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
//testing comparator
//build a mirror BST with a rule: Left > Parent > Right
//code for the comparator at the bottom of the file
bst = new BST(new MyComp1());
for(Integer n : a) bst.insert(n);
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
System.out.println();
for(Integer n : bst) System.out.print(n);
System.out.println();
System.out.println(bst);
//testing restoring a tree from two given traversals
bst.restore(new Integer[] {11,8,6,4,7,10,19,43,31,29,37,49},
new Integer[] {4,6,7,8,10,11,19,29,31,37,43,49});
bst.preOrderTraversal();
System.out.println();
bst.inOrderTraversal();
System.out.println();
//testing diameter
System.out.println(\"diameter = \" + bst.diameter());
//testing width
System.out.println(\"width = \" + bst.width());
}
private Node root;
private Comparator comparator;
public BST()
{
root = null;
comparator = null;
}
public BST(Comparator comp)
{
root = null;
comparator = comp;
}
private int compare(T x, T y)
{
if(comparator == null) return x.compareTo(y);
else
return comparator.compare(x,y);
}
/*****************************************************
*
* INSERT
*
******************************************************/
public void insert(T data)
{
root = insert(root, data);
}
private Node insert(Node p, T toInsert)
{
if (p == null)
return new Node(toInsert);
if (compare(toInsert, p.data) == 0)
return p;
if (compare(toInsert, p.data) < 0)
p.left = insert(p.left, toInsert);
else
p.right = insert(p.right, toInsert);
return p;
}
/*****************************************************
*
* SEARCH
*
******************************************************/
public boolean search(T toSearch)
{
return search(root, toSearch);
}
private boolean search(Node p, T toSearch)
{
if (p == null)
return false;
else
if (compare(toSearch, p.data) == 0)
return true;
else
if (compare(toSearch, p.data) < 0)
return search(p.left, toSearch);
else
return search(p.right, toSearch);
}
/*****************************************************.
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
#include iostream using namespace std; const int nil = 0; cl.docx
#include iostream using namespace std; const int nil = 0; cl
Please refer this solution. This is working file for IntegersHeade.pdf
Please refer this solution. This is working file for Integers
Header file :-
-----------------------------------
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
struct node{
void * data;
node * next;
};
class LinkedList
{
private:
node* head ;
int size;
public:
LinkedList();
//method to create a node
node * create(void* data);
//method to append
void append(node * item);
//method to prepend
void prepend(node * item);
//insert in ascending order
void insertAscend(node * item);
//insert in ascending order
void insertDescend(node * item);
//display all nodes
void display();
//free the list
void freeUp();
};
#endif // LINKEDLIST_H
Source file :-
----------------------------------
#include \"linkedlist.h\"
#include
#include
#include
LinkedList::LinkedList()
{
//head = (node *)malloc(sizeof(node));
size = 0;
head = NULL;
}
//method to create a node
node * LinkedList::create(void* data){
node * newNode = (node *)malloc(sizeof(node));
newNode->data = malloc(sizeof(data));
memcpy(newNode->data,data,sizeof(data));
newNode->next = NULL;
return newNode;
}
//method to append
void LinkedList::append(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
while (current->next!=NULL )
{
current = current->next;
}
current->next = item ;
size++;
}
//method to prepend
void LinkedList::prepend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
item->next = head;
head = item;
size++;
}
//insert in ascending order
void LinkedList::insertAscend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data < *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//insert in Descending order
void LinkedList::insertDescend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data > *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//display all nodes
void LinkedList::display(){
int idx = 0;
node* current;
current = head;
while (current != NULL ){
idx++;
int *data = static_cast(current->data);
printf(\"data for item ::%dis :: %d\ \",idx,*data);
current = current->next;
}
}
//free the list
void LinkedList::freeUp(){
node* current;
current = head;
while (current->next!=NULL ){
head = current->next;
delete current;
current = head;
}
}
Main f.
mainpublic class AssignmentThree { public static void ma.pdf
// main
public class AssignmentThree
{
public static void main(String[] args)
{
List myList = new List(15);
// Cause List Empty Message
myList.removeFront();
myList.removeRear();
myList.removeItem(\"a\");
// Cause Not found message
myList.addToFront(\"x\");
myList.removeItem(\"y\");
myList.removeItem(\"x\");
myList.addAfterItem(\"x\", \"z\");
myList.addBeforeItem(\"x\", \"z\");
// Normal behavior
myList.addToFront(\"not.\");
myList.addToFront(\"or\");
myList.addToRear(\"is\");
myList.addToRear(\"try.\");
myList.addAfterItem(\"is\", \"no\");
myList.addBeforeItem(\"is\", \"There\");
myList.addToFront(\"Do\");
myList.addAfterItem(\"or\", \"do\");
myList.print(\"Original list\");
myList.printSorted(\"Sorted Original List\");
sop(\"\ Front is \" + myList.getFront());
sop(\"Rear is \" + myList.getRear());
sop(\"Count is \" + myList.askCount());
sop(\"Is There present? \" + myList.isPresent(\"There\"));
sop(\"Is Dog present? \" + myList.isPresent(\"Dog\"));
myList.addToFront(\"junk\");
myList.addToRear(\"morejunk\");
myList.addAfterItem(\"or\", \"moremorejunk\");
myList.print(\"List with junk\");
sop(\"Count is \" + myList.askCount());
myList.removeFront();
myList.removeRear();
myList.removeItem(\"moremorejunk\");
myList.print(\"List with junk removed\");
sop(\"Count is \" + myList.askCount());
sop(\"\");
// Cause List Full message
for(int ii = 0; ii < 10; ++ii)
{
myList.addToFront(DUMMY);
}
myList.addToRear(DUMMY);
myList.addBeforeItem(\"no\", DUMMY);
myList.addAfterItem(\"There\", DUMMY);
myList.print(\"After filling List\");
sop(\"Count is \" + myList.askCount());
while(myList.isPresent(DUMMY)) myList.removeItem(DUMMY);
myList.print(\"After removing \" + DUMMY );
sop(\"Count is \" + myList.askCount());
}
private static void sop(String s)
{
System.out.println(s);
}
private static final String DUMMY = \"dummy\";
}
Solution
Following is MyList implementation for your output as:
Java Code:
import java.util.Comparator;
public class MyList {
private Node start;
private Node end;
private int size;
private int capacity;
public MyList(int capacity) {
start = null;
end = null;
size = 0;
this.capacity = capacity;
}
/* Function to check if list is empty */
public boolean isEmpty() {
return start == null;
}
public void removeFront() {
if (isEmpty()) {
System.out.println(\"List Empty\");
return;
} else {
start = start.next;
size--;
return;
}
}
public void removeRear() {
if (size == 0) {
System.out.println(\"List Empty\");
return;
}
if (start.next == null) {
start=null;
end=null;
size=0;
}
Node node = start.next;
while (node.next != null) {
node = node.next;
}
node.next = null;
end = node;
size--;
}
public void removeItem(String key) {
if (size == 0) {
System.out.println(\"List Empty\");
return;
}
if (start.next == null) {
if (start.key.equals(key)) {
start=null;
end=null;
size=0;
} else {
System.out.println(\"\");
}
return;
}
Node node = start;
Node nodeNext = node.next;
while (nodeNext.next != null) {
if (nodeNext.key.equals(key)) {
node.next=nodeNext.next;
}.
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using java
Given a class ‘Node’ and ‘NodeList’, that contains the below information diagram.
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
NodeList
-size: int
-root: Node
+add(node: Node): void
+size(): int
+findNode(node: Node): boolean
Implement add(Node), findNode(Node) and size methods in the NodeList class which is
provided to you. The methods should work as:
Using the following main method:
public static void main(String[] args)
{
NodeList list = new NodeList();
Node node = new Node(1, \"Book\");
Node node2 = new Node(2, \"Lappy\");
list.add(node);
list.add(node2);
System.out.println(\"Length : \"+list.size());
Node node3 = new Node(3, \"Glass\");
Node node4 = new Node(4, \"Pen\");
list.add(node3);
System.out.println(\"Length : \"+list.size());
if(list.findNode(node3)) System.out.println(\"Node found: \"+ node3.getName());
else
System.out.println(\"Node not found: \"+ node3.getName());
if(list.findNode(node4)) System.out.println(\"Node found: \"+ node4.getName());
else
System.out.println(\"Node not found: \"+ node4.getName());
}
Then it should return the following output:
Length : 2
Length : 3
Node found: Glass
Node not found: Pen
The given Node class is:
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this.name = name;
this.next = null;
}
public Node getNext()
{
return next;
}
public void setNext(Node node)
{
this.next = node
}
public int getId()
{
return id;
{
public void setId(int id)
{
this.id = id;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public String toString()
{
return \"ID : \"+this.id+\" Name : \"+this.name;
}
}
The given NodeList class is:
public class NodeList
{
private int size = 0;
private Node root = null;
/*
* It has to take a new Node and add that to the next address of previous Node.
* If the list is empty, assign it as the \"root\"
* @Param - Node
*/
public void add(Node node)
{
// Implement this method!!!
}
/*
* It has to return the size of the NodeList
*
* @return size
*/
public int size()
{
// Implement this method!!!
}
/*
* It has to take a Node and checks if the node is in the list.
* If it finds the node, it returns true, otherwise false
*
* @param - Node
* @return boolean true/false
*/
public boolean findNode(Node node)
{
// Implement this method!!!
}
}Node
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
############ Node.java #############
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this..
Similar to usingpackage util;import java.util.;This class implements.pdf (20)
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdf
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdf
Note Given Code modified as required and required met.pdf
Note Given Code modified as required and required met.pdf
in this assignment you are asked to write a simple driver program an.pdf
in this assignment you are asked to write a simple driver program an.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
For the code below complete the preOrder() method so that it perform.pdf
For the code below complete the preOrder() method so that it perform.pdf
Please read the comment ins codeExpressionTree.java-------------.pdf
Please read the comment ins codeExpressionTree.java-------------.pdf
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a pro.pdf
JAVA A double-ended queue is a list that allows the addition and.pdf
JAVA A double-ended queue is a list that allows the addition and.pdf
The LinkedList1 class implements a Linked list. class.pdf
The LinkedList1 class implements a Linked list. class.pdf
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
Once you have all the structures working as intended- it is time to co.docx
Once you have all the structures working as intended- it is time to co.docx
A perfect left-sided binary tree is a binary tree where every intern.pdf
A perfect left-sided binary tree is a binary tree where every intern.pdf
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
Data Structures and Agorithm: DS 14 Binary Expression Tree.pptx
#include iostream using namespace std; const int nil = 0; cl.docx
#include iostream using namespace std; const int nil = 0; cl.docx
Please refer this solution. This is working file for IntegersHeade.pdf
Please refer this solution. This is working file for IntegersHeade.pdf
mainpublic class AssignmentThree { public static void ma.pdf
mainpublic class AssignmentThree { public static void ma.pdf
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
More from info335653
You�ve been hired by the local government to determine which employe.pdf
Youve been hired by the local government to determine which employees are most essential in
the Parks & Recreation department.
You plan to conduct a social network analysis. You find that people (in bold below) list the
following others as ones they work well with:
Leslie: Andy, Ann, Donna
Ron: April
Ben: Ann
April: Donna, Ron
Andy: Chris, Tim, Leslie
Donna: Leslie, April, Gerry
Gerry: Donna
Tom: Andy, Ann, Donna
Ann: Ben, Leslie, Tim, Chris
Chris: Andy, Ann
- A. B. C. D. E. F. G. H. I. J.
Who is the central connector?- A. B. C. D. E. F. G.
H. I. J. Who is the
broker?A.ChrisB.AnnC.GerryD.BenE.DonnaF.TomG.AprilH.AndyI.RonJ.Leslie.
you will implement some sorting algorithms for arrays and linked lis.pdf
you will implement some sorting algorithms for arrays and linked lists.
Insertion Sort and Quicksort of an array
Implement the insertion sort and quicksort for an integer array. The functions are defined in the
"sorting.h" header file.
/**
* @brief Insertion sort algorithm
* @param array Array to be sorted. The array is modified in place.
* @param lowindex Lowest index of the array
* @param highindex Highest index of the array
* @param reversed If reversed = true, the array should be sorted in descending order, otherwise
in ascending order
*/
void insertionSort(int array[], int lowindex, int highindex, bool reversed = false);
and
**
* @brief Quick sort algorithm
*
* @param array Array to be sorted. The array is modified in place.
* @param lowindex Lowest index of the array
* @param highindex Highest index of the array
* @param reversed If reversed = true, the array should be sorted in descending order, otherwise
in ascending order
*/
void quickSort(int array[], int lowindex, int highindex, bool reversed = false);
The array should be sorted in place. Compared to the examples in the textbook, those functions
have an additional parameter reversed. If reversed = true, the array should be sorted in
descending order, otherwise in ascending order. You should complete the implementations of
those two functions in the "sorting_basic.cpp" file.
A better quicksort algorithm
Quicksort is a very fast comparison sorting algorithm, especially wheb the array or list gets large.
However, when the arrays/lists are small enough, quicksort may run slower than some of the
(n^2) algorithms. This might not seem important until you note that when sorting a large array
with quicksort, many small sublists must be sorted. While the savings on sorting one small list
with a faster algorithm might be negligible, sorting hundreds of small lists with a faster algorithm
can make a difference in the overall efficiency of the sort. For this part of the assignment, you
will combine quicksort with another sorting algorithm to build a faster sorting algorithm. One
option is to
use quicksort until the array/list gets small enough, and then use insertion sort or another sort to
sort the small arrays/lists
What does "small enough" mean? You can try a percentage of the list (say, 5% or 10%), or an
absolute number (5 elements, 8 elements, 10 elements, 15 elements, 100 elements, etc), or
something else of your choosing. Based on your tests, choose the one that is the most efficient.
You should also tests to ensure that your hybrid quicksort has reasonable performance on all lists
-- most notably, it should be efficient on sorted and inverse sorted lists as well as random lists.
The definition of the hybrid quicksort function is as the following:
/**
* @brief A hybrid of insertion sort and quick sort algorithm. The algorithm is based on the idea
that if the array is short, it is better to use insertion sort.
* It uses quicksort until the list gets small enough, and then uses insertion s.
You are the chief data scientist of the marketing company �VisualZ.�.pdf
You are the chief data scientist of the marketing company VisualZ. VisualZ is specialized in
executive management consulting and has built a reputation for developing illustrations that are
particularly easy to understand for the target audience.
ProduceRs CEO has approached you two weeks ago and mentioned that she is particularly
interested in a report on the social media KPIs. Together with ProduceR, you identified Social
Media Reach as a key metric for ProduceR. Social Media Reach refers to the number of users
who have come across specific content on a social platform.
ProduceR has invested equal amounts in promoting their products on Facebook and Instagram
and created public profiles for their firm to introduce their products and services. Your team
proposes four different ways to compare ProduceRs Social Media Reach between Instagram and
Facebook. Based on what you learned about choosing and interpreting visualizations in your
business analytics class at The University of Queensland, please answer the following
question.A.Use a bigger share of the total marketing budget for Instagram marketing.B.Use a
bigger share of the total marketing budget for Twitter marketing.C.The data does not show
differences in trends between platforms that would justify any changes to the budget
allocation.D.The data does not allow you to make any meaningful assumptions about trends over
time. Social Media Facebook Instagram 3.0M2.5M2.0M1.5M1.0M0.5M0.0M 2012 2014 2016
2018 2020.
Write a program that displays a table of the Celsius temperatures 0 .pdf
Write a program that displays a table of the Celsius temperatures 0 through 20 and their
Fahrenheit equivalents. The formula for converting a temperature from Celsius toFahrenheit is
F=9 / 5 *C + 32
where F is the Fahrenheit temperature and C is the Celsius temperature. Your program must use
a loop to display the table.
Results will be similar:
C F
0 32.0
1 33.8
2 35.6
20 68.0
USING THIS TEMPLATE :
import java.text.DecimalFormat;
/**
This program demonstrates a solution to the
Celsius to Fahrenheit Table programming challenge.
*/
public class CelsiusToFahrenheitTable
{
public static void main(String[] args)
{
double fahrenheit; // The Fahrenheit temperature
double celsius; // The Celsius temperature
// Create a DecimalFormat class to format output.
DecimalFormat fmt = new DecimalFormat(" 0.0");
// Display the table headings.
System.out.println("Celsius\t\tFahrenheit");
System.out.println("------------------------------");
// Display the table.
}
}.
Why is the release of GDP statistics less interesting to investors t.pdf
Why is the release of GDP statistics less interesting to investors than the release of other
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A. Because the formula for GDP includes not only private investment but also other irrelevant
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B. Because governments consistently alter their GDP measurement methods
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Winds of Change in Klickitat CountyThe Harvest Wind ProjectM..pdf
Winds of Change in Klickitat County:
The Harvest Wind Project
M. Phillips, D. Watson, B. Barnes, and H. Feldman
The following case describes a proposal by four Pacific Northwest utilities to build another wind
farm in the Columbia River Gorge. The local county planning director is responsible for deciding
on a permit for the project, but there are organizations and citizens both for and against
approving the permit, including local farmers, environmental groups, county citizens worried
about health and noise effects, and, of course, the local utilities who are proposing the project. If
approved, and completed by the end of the year, the costs of the project could be reduced by
almost a third through a grant by the U.S. Treasury Department.
Introduction
It was early April 2009, and Klickitat County planning director Curt Dreyer was weary but
happy to be writing up his permitting decision. On a tight timeline, he had worked for months
gathering information and vetting the Harvest Wind Project proposal that had been submitted by
four Pacific Northwest consumer owned utilities: the Public Utility District (PUD) No. 1 of
Cowlitz County, the Eugene Water and Electric Board. Lakeview Green Energy. Inc., and
Peninsula Light Company. The pressure had been high: hanging in the balance was a $60.76
million US Treasury Department grant which represented 30 percent of eligible construction
costs, made available through the American Recovery and Reinvestment Act of 2009 (ARRA).
To qualify for the full amount, the wind project had to be completed within the year 2009.
The proposed construction schedule was one of the most aggressive ever and in order to
complete it on time approval had to come in April. Wind projects were complicated and required
months of constructiontypically half a year or more. If Curt approved the project, construction
could commence by early May, concluding by December 2009 at the latest to qualify for the
$60.76 million grant.
Approving the permit was not a forgone conclusion. Although Klickitat County was often called
the capital of wind energy in the Pacific Northwest due to its 14 operating wind farms and its
prime location in the Columbia River Gorge, concerns about wind power among
stakeholdersincluding negative economic, environmental, and health effectswere increasingly
being voiced in the region and nationally. With imperfect information on health effects and
environmental effects, the true costs of wind were uncertain. And yet each new wind proposal
had to be evaluated given leading edge knowledge at the time, and every affected party and
viewpoint had to be taken into consideration before approving or turning down the projects
permit application for the county. Given these concerns and the uncertainty, would the gains to
project stakeholders justify signing off on the project? As he reflected on the past few months,
Curt felt he had done his best to collect as much information as possible and to weigh the
concerns and needs.
With reference to the case study, define social media marketing and cr.pdf
With reference to the case study, define social media marketing and critically discuss 2 ways
(i.e., use of existing social media; or setting up their own), that marketers can use social media.
Case Study with 3 Finalsite Schools Andrew Martin Social media has quickly become the go-to
method for modern marketing and communications for independent schools and districts. It
delivers your message directly to your targeted audience; its always readily available and easy-
to-use for consumers; and its oftentimes free all things that schools love when marketing their
culture, community, events, and more. Fortunately for schools, social media is also a place where
prospective, current and former families spend a lot of their time. But despite the promise of
social medias ability to reach your audience, earning their attention and engagement has gotten
increasingly more difficult, as social media networks morph into pay-to-play platforms, forcing
brands to invest in ads if they want their content to be seen. Whats more, social media has
become a battleground where youre not just competing with other schools for attention; youre
competing with yourself. Just think about the sheer amount of variety in content your school is
likely to publish on any given day. Recruiting new applicants, engaging active alumni,
distributing daily and weekly news, releasing event information, managing and maintaining the
schools brand, and continuously building an active social media community. Your ever-growing
catalogue of social media content looks amazing, but all that time and energy spent creating it is
wasted if it ends up buried under a mountain of other posts, or goes unnoticed by the target
audience. This phenomenon explains why social media advertising has become so useful and
impactful, cutting through the ocean of content (including your own), and providing what is
essentially a front-row ticket for everyone viewing your social media accounts. Ads can nearly
guarantee that someone viewing your Facebook or Twitter feed is going to see the content that
you need them to see, much more so than if published in a regular post amidst a daily stream of a
dozen or more other posts. To help you decide how to approach social media advertising, weve
selected three Finalsite schools that increased website traffic through social media advertising.
Finalsites social media consulting team helped these schools develop their advertising campaign
at a fraction of the cost of traditional advertising. School Year Abroad Up first is School Year
Abroad (SYA), a high school study abroad program that helps juniors and seniors spend a year
abroad in Italy, Spain, France, and China. SYA had three campaign goals to accomplish between
December 2017 and August 2018: Build brand awareness and differentiation Increase
awareness of study abroad opportunities and deadlines Increase interest of applying to School
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Will upvote Please fix the following code and post your inputs and o.pdf
Will upvote Please fix the following code and post your inputs and outputs please run your code
to make sure it works
import sys
import heapq
import copy
class PriorityQueue():
def __init__(self):
self.thisQueue = []
def push(self, thisNode):
heapq.heappush(self.thisQueue, (thisNode.val, -thisNode.id, thisNode))
def pop(self):
return heapq.heappop(self.thisQueue)[2]
def isEmpty(self):
return len(self.thisQueue) == 0
def length(self):
return len(self.thisQueue)
class Set():
def __init__(self):
self.thisSet = set()
def add(self, entry):
if entry is not None:
self.thisSet.add(entry.__hash__())
def length(self):
return len(self.thisSet)
def isMember(self, query):
return query.__hash__() in self.thisSet
class Node():
def __init__(self, val, startstate, endstate, depth):
global nodeid
self.id = nodeid
nodeid += 1
self.val = val
self.state = startstate
self.endstate = endstate
self.depth = depth
def __str__(self):
return 'Node: id=%d val=%d' % (self.id, self.val)
def expand(current_node, closedlist, goal_state):
closedlist.add(current_node.state)
successors = []
up_child = current_node.state.up()
down_child = current_node.state.down()
right_child = current_node.state.right()
left_child = current_node.state.left()
children = [left_child, right_child, up_child, down_child]
for child in children:
if child is not None and not closedlist.isMember(child):
s = Node(0, child, None, current_node.depth + 1)
s.parent_node = current_node
if child == left_child:
s.action = "left"
elif child == right_child:
s.action = "right"
elif child == up_child:
s.action = "up"
elif child == down_child:
s.action = "down"
successors.append(s)
return successors
def h0(currenttiles, stiles):
misplaced = 0
for i in range(len(stiles)):
for j in range(len(currenttiles)):
if stiles[i][j] != currenttiles[i][j]:
misplaced += 1
return misplaced
def manhattan(currenttiles, stiles):
total = 0
for i in range(len(stiles)):
for j in range(len(currenttiles)):
if stiles[i][j] != currenttiles[i][j]:
y = stiles[i][j]
a = i
b = j
for k in range(len(stiles)):
for l in range(len(stiles)):
if currenttiles[k][l] == y:
d = k
e = l
count = (abs(d - a) + abs(e - b))
total += count
return total
class State():
def __init__(self):
self.xpos = 0
self.ypos = 0
self.tiles = [[0, 1, 2], [3, 4, 5], [6, 7, 8]]
def left(self):
if self.ypos == 0:
return None
s = self.copy()
s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos][s.ypos - 1]
s.ypos -= 1
s.tiles[s.xpos][s.ypos] = 0
return s
def right(self):
if self.ypos == 2:
return None
s = self.copy()
s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos][s.ypos + 1]
s.ypos += 1
s.tiles[s.xpos][s.ypos] = 0
return s
def up(self):
if self.xpos == 0:
return None
s = self.copy()
s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos - 1][s.ypos]
s.xpos -= 1
s.tiles[s.xpos][s.ypos] = 0
return s
def down(self):
if self.xpos == 2:
return None
s = self.copy()
s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos + 1][s.ypos]
s.xpos += 1
s.tiles[s.xpos][s.ypos] = 0
return s
def __hash__(self):
return (tuple(self.tiles[0]), t.
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