a) False (because it is not always the case).Many electronegative .pdf
•
0 likes•2 views
a) False (because it is not always the case). Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate. For example, HF is less acidic than HBr (even though Fis more electronegative than Br) b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off easily. c) True. (F is more electronegative and has a smaller diameter soweaker acid) d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid. e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds the O-H bond. f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through inductive effects. Solution a) False (because it is not always the case). Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate. For example, HF is less acidic than HBr (even though Fis more electronegative than Br) b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off easily. c) True. (F is more electronegative and has a smaller diameter soweaker acid) d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid. e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds the O-H bond. f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through inductive effects..
Report
Share
Report
Share
Download to read offline
Recommended
7- Consider the following statements (i) HBr is a stronger acid than H.docx
7. Consider the following statements (i) HBr is a stronger acid than HF (i) NHs is a stronger acid than H20 (ii) H2POs is a stronger acid than H3PO4 (iv) HCIO is a stronger acid than HCIO2 (v) CFsCOOH is a stronger acid than CH2FCOOH Which of the following is correct (a) only (i) and (v) are true (d) only (), (iv) and (v) are true (e) none of the previous are correct (b) only (v) is true (c) only (iv) and (v) are true 8. Consider the reaction 4 NHs(g) 302(g)2 Na(g)+ 6 H200) AH
Solution
7.ans:- Option (a) is correct
Explanation:-
# HBr is stronger acid than HF , because down the group of the \"hydrides of halogens ( i.e HX )\" bond dissociation enthalpy of H - X bond decreases as the size of the halogen (X) increases .therefore bond dissociation enthalpy of HBr is less than HF and hence HBr will give H + more easily than HF .
# CF 3 COOH is more acidic than CH 2 FCOOH , because of the presence of three electron withdrawing groups( i.e F ) at the alpha position of CF 3 COOH . on the other hand CH 2 FCOOH have only one electron withdrawing group at alpha position . Presence of electron withdrawing group at the alpha position of acetic acid increases its acidic strength while presence of electron releasing group decreases its acidic strength .
# NH 3 is stronger base than H 2 O , because N in NH 3 has more proton (H + ) affinity than O in H 2 O .
# H 3 PO 4 is stronger acid than H 2 PO 4 - , because it is difficult to remove one H + ion from an anion i.e H 2 PO 4 - .
# HClO 2 is stronger acid than HClO , because of the resonance stabalized structures of its conjugate base i.e ClO 2 - ( in which negative charge delocalized over two oxygen atoms ) . on the other hand ClO - ( conjugate base of HClO) do not form resonance structures .
.
t a solution containing an of the as the Chem 102 Test 3 review 1-) Is.docx
t a solution containing an of the as the Chem 102 Test 3 review 1.) Is H,S0, the conjugate acid of So,\'? Select the single best answer a Yes, because both contain SO, b No, because both contain S0. D No, because they differ by two hydrogen ions. d. Yes, because they differ by two hydrogen ions. 2) Could you use the p-notation for the concentration of a very dillute solution of chloride ion for a solution made when a tablespoon of water is added to a gallon of water? defined? How would it be a. Yes. The equation would be pH JoglCH1 b. No, you cannot. c. Yes. The equation would be pCl . logIC-1 d. Yes. The equation would be pCI-loglCH a.neutralization involves the formation of a coordinate covalent bond between the acid 3.) In the Lewis model of acids and bases, and the base. b. all acids produce H+ while bases give OH- c. acids are oxidizing agents that gain electrons d. bases are reducing agents that lose electrons. 4) Consider the following: CO, is a weaker base than hydroxide ion, and HCO, is a stronger acid than water. In the equation below, would the position of equilibrium lie to the left or to the right? Select the single best answer. a. The left, because the stronger acid and stronger base are favored. b. The right, because the stronger acid and stronger base are favored. c. The right, because the weaker acid and weaker base are favored. d. The left, because the weaker acid and weaker base are favored e. None of these. 5.) The pK, of HCN is 9.31 and that of HF is 3.46. Which is the stronger Brensted base, CN or F? Select the single best answer a. CN, because HCN is a stronger acid than HF b. CN, because HCN is a weaker acid than HF c. F, because HCN is a stronger acid than HF. d. F, because HCN is a weaker acid than HF e. None of these. 6) Nitric acid, HNO, is a very strong acid. It is 100% ionized in water. In the reaction below, would the position of equilibrium lie to the left or to the right?
Solution
1. ans:- Option (c)
Explanation :-
Conjugate acid or base pairs are differ by only one H + ion .
here, Conjugate acid of SO 4 2- ( base) is HSO 4 - .
also HSO 4 - can act as an acid as well as a base , because HSO 4 - can donate H + and can also accept one H + ion.
Conjugate acid of HSO 4 - (base) is H 2 SO 4 .
Conjugate base of HSO 4 - (acid) is SO 4 2- .
.
Generally the formula for an acid is a hydrogen atom bonded with eit.pdf
Generally the formula for an acid is a hydrogen atom bonded with either another atom that is an
anion, such as Cl- (chlorine anion) or another molecule that is an anion, such as SO42- (sulfate
anion). What makes an acid an acid is that the hydrogen cation can fall off the molecule, known
as protonation, leaving behind a relatively stable anion. This anion is known as the acid\'s
conjugate base. A strong acid, such as HCl, has a weak conjugate base. A weak acid, such as HF,
would have a strong conjugate base. A strong acid is dictated by how much it protonates in
water, that is, how much the H+ cation dissociates from the anion in water. In HCl\'s case, the
acid protonates almost completely, making it a strong acid. The acidity of an acid is measured by
the well known pH scale. As you go upwards in difficulty of chemistry, molecules with multiple
hydrogens can have different acidities because when different hydrogens leave, they can form a
more or less stable anion behind.
I hope this helps!
Solution
Generally the formula for an acid is a hydrogen atom bonded with either another atom that is an
anion, such as Cl- (chlorine anion) or another molecule that is an anion, such as SO42- (sulfate
anion). What makes an acid an acid is that the hydrogen cation can fall off the molecule, known
as protonation, leaving behind a relatively stable anion. This anion is known as the acid\'s
conjugate base. A strong acid, such as HCl, has a weak conjugate base. A weak acid, such as HF,
would have a strong conjugate base. A strong acid is dictated by how much it protonates in
water, that is, how much the H+ cation dissociates from the anion in water. In HCl\'s case, the
acid protonates almost completely, making it a strong acid. The acidity of an acid is measured by
the well known pH scale. As you go upwards in difficulty of chemistry, molecules with multiple
hydrogens can have different acidities because when different hydrogens leave, they can form a
more or less stable anion behind.
I hope this helps!.
ionicequilibrium-150530122047-lva1-app6891.pdf
chemistry ionic equilibrium presentation maharashtra board std 12th
Ionic equilibrium
Ionic Equilibrium
Powerpoint presentation for the topics covered under Ionic Equilibrium in class 11.
Recommended
7- Consider the following statements (i) HBr is a stronger acid than H.docx
7. Consider the following statements (i) HBr is a stronger acid than HF (i) NHs is a stronger acid than H20 (ii) H2POs is a stronger acid than H3PO4 (iv) HCIO is a stronger acid than HCIO2 (v) CFsCOOH is a stronger acid than CH2FCOOH Which of the following is correct (a) only (i) and (v) are true (d) only (), (iv) and (v) are true (e) none of the previous are correct (b) only (v) is true (c) only (iv) and (v) are true 8. Consider the reaction 4 NHs(g) 302(g)2 Na(g)+ 6 H200) AH
Solution
7.ans:- Option (a) is correct
Explanation:-
# HBr is stronger acid than HF , because down the group of the \"hydrides of halogens ( i.e HX )\" bond dissociation enthalpy of H - X bond decreases as the size of the halogen (X) increases .therefore bond dissociation enthalpy of HBr is less than HF and hence HBr will give H + more easily than HF .
# CF 3 COOH is more acidic than CH 2 FCOOH , because of the presence of three electron withdrawing groups( i.e F ) at the alpha position of CF 3 COOH . on the other hand CH 2 FCOOH have only one electron withdrawing group at alpha position . Presence of electron withdrawing group at the alpha position of acetic acid increases its acidic strength while presence of electron releasing group decreases its acidic strength .
# NH 3 is stronger base than H 2 O , because N in NH 3 has more proton (H + ) affinity than O in H 2 O .
# H 3 PO 4 is stronger acid than H 2 PO 4 - , because it is difficult to remove one H + ion from an anion i.e H 2 PO 4 - .
# HClO 2 is stronger acid than HClO , because of the resonance stabalized structures of its conjugate base i.e ClO 2 - ( in which negative charge delocalized over two oxygen atoms ) . on the other hand ClO - ( conjugate base of HClO) do not form resonance structures .
.
t a solution containing an of the as the Chem 102 Test 3 review 1-) Is.docx
t a solution containing an of the as the Chem 102 Test 3 review 1.) Is H,S0, the conjugate acid of So,\'? Select the single best answer a Yes, because both contain SO, b No, because both contain S0. D No, because they differ by two hydrogen ions. d. Yes, because they differ by two hydrogen ions. 2) Could you use the p-notation for the concentration of a very dillute solution of chloride ion for a solution made when a tablespoon of water is added to a gallon of water? defined? How would it be a. Yes. The equation would be pH JoglCH1 b. No, you cannot. c. Yes. The equation would be pCl . logIC-1 d. Yes. The equation would be pCI-loglCH a.neutralization involves the formation of a coordinate covalent bond between the acid 3.) In the Lewis model of acids and bases, and the base. b. all acids produce H+ while bases give OH- c. acids are oxidizing agents that gain electrons d. bases are reducing agents that lose electrons. 4) Consider the following: CO, is a weaker base than hydroxide ion, and HCO, is a stronger acid than water. In the equation below, would the position of equilibrium lie to the left or to the right? Select the single best answer. a. The left, because the stronger acid and stronger base are favored. b. The right, because the stronger acid and stronger base are favored. c. The right, because the weaker acid and weaker base are favored. d. The left, because the weaker acid and weaker base are favored e. None of these. 5.) The pK, of HCN is 9.31 and that of HF is 3.46. Which is the stronger Brensted base, CN or F? Select the single best answer a. CN, because HCN is a stronger acid than HF b. CN, because HCN is a weaker acid than HF c. F, because HCN is a stronger acid than HF. d. F, because HCN is a weaker acid than HF e. None of these. 6) Nitric acid, HNO, is a very strong acid. It is 100% ionized in water. In the reaction below, would the position of equilibrium lie to the left or to the right?
Solution
1. ans:- Option (c)
Explanation :-
Conjugate acid or base pairs are differ by only one H + ion .
here, Conjugate acid of SO 4 2- ( base) is HSO 4 - .
also HSO 4 - can act as an acid as well as a base , because HSO 4 - can donate H + and can also accept one H + ion.
Conjugate acid of HSO 4 - (base) is H 2 SO 4 .
Conjugate base of HSO 4 - (acid) is SO 4 2- .
.
Generally the formula for an acid is a hydrogen atom bonded with eit.pdf
Generally the formula for an acid is a hydrogen atom bonded with either another atom that is an
anion, such as Cl- (chlorine anion) or another molecule that is an anion, such as SO42- (sulfate
anion). What makes an acid an acid is that the hydrogen cation can fall off the molecule, known
as protonation, leaving behind a relatively stable anion. This anion is known as the acid\'s
conjugate base. A strong acid, such as HCl, has a weak conjugate base. A weak acid, such as HF,
would have a strong conjugate base. A strong acid is dictated by how much it protonates in
water, that is, how much the H+ cation dissociates from the anion in water. In HCl\'s case, the
acid protonates almost completely, making it a strong acid. The acidity of an acid is measured by
the well known pH scale. As you go upwards in difficulty of chemistry, molecules with multiple
hydrogens can have different acidities because when different hydrogens leave, they can form a
more or less stable anion behind.
I hope this helps!
Solution
Generally the formula for an acid is a hydrogen atom bonded with either another atom that is an
anion, such as Cl- (chlorine anion) or another molecule that is an anion, such as SO42- (sulfate
anion). What makes an acid an acid is that the hydrogen cation can fall off the molecule, known
as protonation, leaving behind a relatively stable anion. This anion is known as the acid\'s
conjugate base. A strong acid, such as HCl, has a weak conjugate base. A weak acid, such as HF,
would have a strong conjugate base. A strong acid is dictated by how much it protonates in
water, that is, how much the H+ cation dissociates from the anion in water. In HCl\'s case, the
acid protonates almost completely, making it a strong acid. The acidity of an acid is measured by
the well known pH scale. As you go upwards in difficulty of chemistry, molecules with multiple
hydrogens can have different acidities because when different hydrogens leave, they can form a
more or less stable anion behind.
I hope this helps!.
ionicequilibrium-150530122047-lva1-app6891.pdf
chemistry ionic equilibrium presentation maharashtra board std 12th
Ionic equilibrium
Ionic Equilibrium
Powerpoint presentation for the topics covered under Ionic Equilibrium in class 11.
Solubility in water happens when something is pol.pdf
Solubility in water happens when something is polar or charged. Charged is much
easier to understand--it\'s when there\'s an actual positive or negative charge on any given
molecule. Polarity is just like charge, but instead of the electrons being specifically on a given
atom and not on another (like in Na+ and Cl-), they\'re shared in a way such that they spend
more time on one atom vs another (like CH3OH--the electrons spend more time on the O than
they do on either the C or the Hs). How do you know which atoms like to hold onto electrons
more than other atoms? Electronegativity differences. Certain atoms like F, N, and O are really
electronegative, which means they like to hold onto electrons more than other atoms, like, say, C
and H. So, if F were bound to C, the electrons would be on the F more often than the C. On the
other hand, if you have to atoms, like C and H, which have very similar electronegativity values,
they will share the electrons more readily, and the electrons don\'t stay on one or the other atoms
more often. Such molecules are called non-polar, and are, in fact, not soluble in water. Instead,
they\'re fat-soluble, because fat is just a whole bunch of C-H bonds next to each other. So,
looking at the structures of those given vitamins, vitamin A consists mostly of a bunch of C-H
bonds; it\'s likely fat soluble. Vitamin B6 has a bunch of C-O-H bonds and an N, too. It\'s much
more polar, and likely water soluble. Vitamin C has tons of oxygens and is definitely water
soluble. Vitamin E is mostly C-H bonds and not too many O-H or O-C bonds, so it\'s likely fat
soluble. Hope that helps! :)
Solution
Solubility in water happens when something is polar or charged. Charged is much
easier to understand--it\'s when there\'s an actual positive or negative charge on any given
molecule. Polarity is just like charge, but instead of the electrons being specifically on a given
atom and not on another (like in Na+ and Cl-), they\'re shared in a way such that they spend
more time on one atom vs another (like CH3OH--the electrons spend more time on the O than
they do on either the C or the Hs). How do you know which atoms like to hold onto electrons
more than other atoms? Electronegativity differences. Certain atoms like F, N, and O are really
electronegative, which means they like to hold onto electrons more than other atoms, like, say, C
and H. So, if F were bound to C, the electrons would be on the F more often than the C. On the
other hand, if you have to atoms, like C and H, which have very similar electronegativity values,
they will share the electrons more readily, and the electrons don\'t stay on one or the other atoms
more often. Such molecules are called non-polar, and are, in fact, not soluble in water. Instead,
they\'re fat-soluble, because fat is just a whole bunch of C-H bonds next to each other. So,
looking at the structures of those given vitamins, vitamin A consists mostly of a bunch of C-H
bonds; it\'s likely fat soluble. Vi.
Netralization titration- Pharmaceutical Analysis
Acid base Theories
Role of the solvents
Acid base dissociation constant,
Relative strength of acids and bases
Distribution of acid base species with pH
Buffer solution
Henderson Hasselbalch equation,
Indicators, Mixed indicators
Different type of titrations (Neutralization curves)
Polyprotic systems,
Phosphoric acid system,
Polyamine and amino acid systems.
Titration of sodium carbonate
Lavoisier definition
Liebig definition
Arrhenius Acids and Bases
Bronsted-Lowry Acid and Base
Lewis Acid and Base
Solvent-system Concept
Lux-Flood Concept
Pearson’s Concept
Historically, the first of the scientific concepts of acids and bases was provided by the French chemist Antoine Lavoisier, circa 1776.
Lavoisier's knowledge of strong acids was mainly restricted to oxyacids, which tend to contain central atoms in high oxidation states surrounded by oxygen, such as HNO3 and H2SO4, and he was not aware of the true composition of the hydrohalic acids, HCl, HBr, and HI. From his limited knowledge,
He defined acids in terms of their content of oxygen, and he named oxygen from Greek words meaning "acid-former"
146- Explain why Al2(S04)s produces an acidic solution when it is diss.docx
146. Explain why Al2(S04)s produces an acidic solution when it is dissolved in water. ANSWER: The ions from this salt are: Ar and So,. The sulfate ion is the anion of a strong acid. It is the anion from the second ionization of HySO4, for which Ka2 1.2 x 102 The with water to produce AlroH), (whichi actually only sightly soluble), thus increasi 42 1.2x 10. The aluminum ion us increasing [H\'].
Solution
For question no 146
When we dissolve Al 2 ( SO 4 ) 3 we get Al +3 and SO 4 -2 ion. Now aluminum ion reacts with water and does the polarisation of water now it seems like any cation can do that but No since aluminum ion has sufficient value of charge density, therefore, it interacts with water( Al +3 + 3H 2 O = Al(OH) 3 + 3H + ) to form Alumnimum hydroxide and releases hydronium ion or H + ion which makes water acidic. So from this, we can say that if any cation has more charge density it will on hydrolysis make water more acidic.
For question no 131
Acidic nature of HX(where X can be any halogen) is determined by
Polarity difference between hydrogen and halide will try to generate positive and negative end which can only possible if bond dissociates as the one which takes the electron away will have the negative charge (usual halide ) while hydrogen will have the positive charge.
Now acidic nature of hydrogen halide is also determined by how easily any hydrogen halide give the H + ion in water since release of hydrogen ion is directly related to bond dissociation energy of hydrogen and halide so strength of H-X decide the strength of acid since bond dissociation energy of HI is weak so it is strongest amongst all.
So it depends upon two factors so D option is correct.
.
P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm
Solution
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm.
NaCl it has two atoms in a molecule for 1 mole of.pdf
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-
Solution
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-.
just find the moles and then use PV = nRT to fin.pdf
just find the moles and then use: PV = nRT to find the volume at STP.
Solution
just find the moles and then use: PV = nRT to find the volume at STP..
Water might be the most possible item through which bacteria entered.pdf
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems.
Solution
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems..
Total particles = 1000Number of particles entering the small apert.pdf
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second.
Solution
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second..
These both are inflammatory bowel diseases characterized by chronic .pdf
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly associated with smoking
Predicts a worse course of disease
Increases risk of surgery & further surgery
Solution
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly .
The topological structure is mainly gives the representaion of the n.pdf
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there exists one and only one path between any pair of nodes. (there cannot be
anyother path)
2. Alteast on tree will be there between every connected grwph.
3. A graph of the tree contains all the nodes.
4. The tree is mainly circuitless where there is no closed path in a tree.
5. (n-1) is called as rank of the tree.
Solution
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there.
The main components of protein family members of RISC complex are.pdf
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down.
Solution
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down..
Solution It is for the auditors and other people involved in the .pdf
Solution
:
It is for the auditors and other people involved in the investigation to identify who is the culprit .
The company had no further additional loss , therefore I would advise Harry never to do it again
and allow the auditors to determine who is the culprit..
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins.
Solution
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins..
relation between concentration and cell potential is given as Ecel.pdf
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER
Solution
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER.
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
Part I
Identifying Your Customer’s
Needs and Goals
Chapter 1 Analyzing Business Goals and Constraints
Chapter 2 Analyzing Technical Goals and Tradeoffs
Chapter 3 Characterizing the Existing Internetwork
Chapter 4 Characterizing Network Traffic
Chapter 1
Analyzing Business
Goals and Constraints
This chapter serves as an introduction to the rest of the book by describing top-down
network design. The first section explains how to use a systematic, top-down process
when designing computer networks for your customers. Depending on your job, your
customers might consist of other departments within your company, those to whom you
are trying to sell products, or clients of your consulting business.
After describing the methodology, this chapter focuses on the first step in top-down network
design: analyzing your customer’s business goals. Business goals include the capability
to run network applications to meet corporate business objectives, and the need to
work within business constraints, such as budgets, limited networking personnel, and
tight timeframes.
This chapter also covers an important business constraint that some people call the
eighth layer of the Open System Interconnection (OSI) reference model: workplace politics.
To ensure the success of your network design project, you should gain an understanding
of any corporate politics and policies at your customer’s site that could affect
your project.
The chapter concludes with a checklist to help you determine if you have addressed the
business issues in a network design project.
Using a Top-Down Network Design Methodology
According to Albert Einstein:
“The world we’ve made as a result of the level of thinking we have done thus far creates
problems that we cannot solve at the same level at which we created them.”
To paraphrase Einstein, networking professionals have the ability to create networks that
are so complex that when problems arise they can’t be solved using the same sort of
thinking that was used to create the networks. Add to this the fact that each upgrade,
patch, and modification to a network can also be created using complex and sometimes
4 Top-Down Network Design
convoluted thinking, and you soon realize that the result is a network that is hard to
understand and troubleshoot. A network created with this complexity often doesn’t perform
as well as expected, doesn’t scale as the need for growth arises (as it almost always
does), and doesn’t match a customer’s requirements. A solution to this problem is to use a
streamlined, systematic methodology in which the network or upgrade is designed in a
top-down fashion.
Many network design tools and methodologies in use today resemble the “connect-thedots”
game that some of us played as children. These tools let you place internetworking
devices on a palette and connect them with LAN or WAN media. The problem with this
methodology is that it skips the steps of analyzing a customer’s requirements and selecting
devices and media based on .
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i
Solution
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i.
Existence of hydrogen bonding increases boiling p.pdf
Existence of hydrogen bonding increases boiling point of compound
Solution
Existence of hydrogen bonding increases boiling point of compound.
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
JellyBean.java
package jellybeantester;
public class JellyBean
{
//These are the 3 instance variables of a JellyBean object:
private String flavor;
private String color;
private boolean eatMe;
/**
* The purpose of this constructor is to move the parameters passed to the constructor
* into the instance variables of the JellyBean object The 2 parameters are:
* @param aFlavor
* @param aColor
*/
public JellyBean(String aFlavor, String aColor)
{
//Initialize each of the instance variables of the JellyBean object with the parameters passed to
the constructor
//Then, set eatMe attribute to false
this.flavor=aFlavor;
this.color=aColor;
}
//Setters and getters.
public String getFlavor()
{
return flavor;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public boolean isEatMe() {
return eatMe;
}
public void setEatMe(boolean eatMe) {
this.eatMe = eatMe;
}
public void setFlavor(String aFlavor)
{
flavor = aFlavor;
}
/**
*
* @return a String representation of all the attributes in the JellyBean class
*/
public String toString()
{
return \"\ Flavour = \"+getFlavor()+\"\ Color = \"+getColor()+\"\ Eat Me = \"+isEatMe()+\"\ \";
}
}
______________________________________________
JellyBeanTester.java
package jellybeantester;
import java.util.Scanner;
public class JellyBeanTester
{
// These are the 3 global variables that will each hold a JellyBean object. These variables
// can be accessed by any method in the tester class because they are global.
static JellyBean jb1;
static JellyBean jb2;
static JellyBean jb3;
static Scanner sc=new Scanner(System.in);
/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
createJellyBeanBag();
processJellyBeanBag();
}
/**
* The createJellyBeanBag method will ask the user for input, and will
* use that input to create 3 JellyBean objects.
*/
public static void createJellyBeanBag()
{
String userInputJBColor;
String userInputJBFlavor;
//Ask the user to enter the color of the first jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"Enter the Color of the First Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the first jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of First the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor and userInputJBColor:
jb1 = new JellyBean(userInputJBFlavor, userInputJBColor);
//Ask the user to enter the color of the second jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"\ Enter the Color of the second Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the second jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of Second the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor an.
More Related Content
Similar to a) False (because it is not always the case).Many electronegative .pdf
Solubility in water happens when something is pol.pdf
Solubility in water happens when something is polar or charged. Charged is much
easier to understand--it\'s when there\'s an actual positive or negative charge on any given
molecule. Polarity is just like charge, but instead of the electrons being specifically on a given
atom and not on another (like in Na+ and Cl-), they\'re shared in a way such that they spend
more time on one atom vs another (like CH3OH--the electrons spend more time on the O than
they do on either the C or the Hs). How do you know which atoms like to hold onto electrons
more than other atoms? Electronegativity differences. Certain atoms like F, N, and O are really
electronegative, which means they like to hold onto electrons more than other atoms, like, say, C
and H. So, if F were bound to C, the electrons would be on the F more often than the C. On the
other hand, if you have to atoms, like C and H, which have very similar electronegativity values,
they will share the electrons more readily, and the electrons don\'t stay on one or the other atoms
more often. Such molecules are called non-polar, and are, in fact, not soluble in water. Instead,
they\'re fat-soluble, because fat is just a whole bunch of C-H bonds next to each other. So,
looking at the structures of those given vitamins, vitamin A consists mostly of a bunch of C-H
bonds; it\'s likely fat soluble. Vitamin B6 has a bunch of C-O-H bonds and an N, too. It\'s much
more polar, and likely water soluble. Vitamin C has tons of oxygens and is definitely water
soluble. Vitamin E is mostly C-H bonds and not too many O-H or O-C bonds, so it\'s likely fat
soluble. Hope that helps! :)
Solution
Solubility in water happens when something is polar or charged. Charged is much
easier to understand--it\'s when there\'s an actual positive or negative charge on any given
molecule. Polarity is just like charge, but instead of the electrons being specifically on a given
atom and not on another (like in Na+ and Cl-), they\'re shared in a way such that they spend
more time on one atom vs another (like CH3OH--the electrons spend more time on the O than
they do on either the C or the Hs). How do you know which atoms like to hold onto electrons
more than other atoms? Electronegativity differences. Certain atoms like F, N, and O are really
electronegative, which means they like to hold onto electrons more than other atoms, like, say, C
and H. So, if F were bound to C, the electrons would be on the F more often than the C. On the
other hand, if you have to atoms, like C and H, which have very similar electronegativity values,
they will share the electrons more readily, and the electrons don\'t stay on one or the other atoms
more often. Such molecules are called non-polar, and are, in fact, not soluble in water. Instead,
they\'re fat-soluble, because fat is just a whole bunch of C-H bonds next to each other. So,
looking at the structures of those given vitamins, vitamin A consists mostly of a bunch of C-H
bonds; it\'s likely fat soluble. Vi.
Netralization titration- Pharmaceutical Analysis
Acid base Theories
Role of the solvents
Acid base dissociation constant,
Relative strength of acids and bases
Distribution of acid base species with pH
Buffer solution
Henderson Hasselbalch equation,
Indicators, Mixed indicators
Different type of titrations (Neutralization curves)
Polyprotic systems,
Phosphoric acid system,
Polyamine and amino acid systems.
Titration of sodium carbonate
Lavoisier definition
Liebig definition
Arrhenius Acids and Bases
Bronsted-Lowry Acid and Base
Lewis Acid and Base
Solvent-system Concept
Lux-Flood Concept
Pearson’s Concept
Historically, the first of the scientific concepts of acids and bases was provided by the French chemist Antoine Lavoisier, circa 1776.
Lavoisier's knowledge of strong acids was mainly restricted to oxyacids, which tend to contain central atoms in high oxidation states surrounded by oxygen, such as HNO3 and H2SO4, and he was not aware of the true composition of the hydrohalic acids, HCl, HBr, and HI. From his limited knowledge,
He defined acids in terms of their content of oxygen, and he named oxygen from Greek words meaning "acid-former"
146- Explain why Al2(S04)s produces an acidic solution when it is diss.docx
146. Explain why Al2(S04)s produces an acidic solution when it is dissolved in water. ANSWER: The ions from this salt are: Ar and So,. The sulfate ion is the anion of a strong acid. It is the anion from the second ionization of HySO4, for which Ka2 1.2 x 102 The with water to produce AlroH), (whichi actually only sightly soluble), thus increasi 42 1.2x 10. The aluminum ion us increasing [H\'].
Solution
For question no 146
When we dissolve Al 2 ( SO 4 ) 3 we get Al +3 and SO 4 -2 ion. Now aluminum ion reacts with water and does the polarisation of water now it seems like any cation can do that but No since aluminum ion has sufficient value of charge density, therefore, it interacts with water( Al +3 + 3H 2 O = Al(OH) 3 + 3H + ) to form Alumnimum hydroxide and releases hydronium ion or H + ion which makes water acidic. So from this, we can say that if any cation has more charge density it will on hydrolysis make water more acidic.
For question no 131
Acidic nature of HX(where X can be any halogen) is determined by
Polarity difference between hydrogen and halide will try to generate positive and negative end which can only possible if bond dissociates as the one which takes the electron away will have the negative charge (usual halide ) while hydrogen will have the positive charge.
Now acidic nature of hydrogen halide is also determined by how easily any hydrogen halide give the H + ion in water since release of hydrogen ion is directly related to bond dissociation energy of hydrogen and halide so strength of H-X decide the strength of acid since bond dissociation energy of HI is weak so it is strongest amongst all.
So it depends upon two factors so D option is correct.
.
Similar to a) False (because it is not always the case).Many electronegative .pdf (7)
Solubility in water happens when something is pol.pdf
Solubility in water happens when something is pol.pdf
146- Explain why Al2(S04)s produces an acidic solution when it is diss.docx
146- Explain why Al2(S04)s produces an acidic solution when it is diss.docx
More from anandatalapatra
P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm
Solution
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm.
NaCl it has two atoms in a molecule for 1 mole of.pdf
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-
Solution
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-.
just find the moles and then use PV = nRT to fin.pdf
just find the moles and then use: PV = nRT to find the volume at STP.
Solution
just find the moles and then use: PV = nRT to find the volume at STP..
Water might be the most possible item through which bacteria entered.pdf
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems.
Solution
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems..
Total particles = 1000Number of particles entering the small apert.pdf
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second.
Solution
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second..
These both are inflammatory bowel diseases characterized by chronic .pdf
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly associated with smoking
Predicts a worse course of disease
Increases risk of surgery & further surgery
Solution
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly .
The topological structure is mainly gives the representaion of the n.pdf
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there exists one and only one path between any pair of nodes. (there cannot be
anyother path)
2. Alteast on tree will be there between every connected grwph.
3. A graph of the tree contains all the nodes.
4. The tree is mainly circuitless where there is no closed path in a tree.
5. (n-1) is called as rank of the tree.
Solution
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there.
The main components of protein family members of RISC complex are.pdf
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down.
Solution
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down..
Solution It is for the auditors and other people involved in the .pdf
Solution
:
It is for the auditors and other people involved in the investigation to identify who is the culprit .
The company had no further additional loss , therefore I would advise Harry never to do it again
and allow the auditors to determine who is the culprit..
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins.
Solution
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins..
relation between concentration and cell potential is given as Ecel.pdf
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER
Solution
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER.
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
Part I
Identifying Your Customer’s
Needs and Goals
Chapter 1 Analyzing Business Goals and Constraints
Chapter 2 Analyzing Technical Goals and Tradeoffs
Chapter 3 Characterizing the Existing Internetwork
Chapter 4 Characterizing Network Traffic
Chapter 1
Analyzing Business
Goals and Constraints
This chapter serves as an introduction to the rest of the book by describing top-down
network design. The first section explains how to use a systematic, top-down process
when designing computer networks for your customers. Depending on your job, your
customers might consist of other departments within your company, those to whom you
are trying to sell products, or clients of your consulting business.
After describing the methodology, this chapter focuses on the first step in top-down network
design: analyzing your customer’s business goals. Business goals include the capability
to run network applications to meet corporate business objectives, and the need to
work within business constraints, such as budgets, limited networking personnel, and
tight timeframes.
This chapter also covers an important business constraint that some people call the
eighth layer of the Open System Interconnection (OSI) reference model: workplace politics.
To ensure the success of your network design project, you should gain an understanding
of any corporate politics and policies at your customer’s site that could affect
your project.
The chapter concludes with a checklist to help you determine if you have addressed the
business issues in a network design project.
Using a Top-Down Network Design Methodology
According to Albert Einstein:
“The world we’ve made as a result of the level of thinking we have done thus far creates
problems that we cannot solve at the same level at which we created them.”
To paraphrase Einstein, networking professionals have the ability to create networks that
are so complex that when problems arise they can’t be solved using the same sort of
thinking that was used to create the networks. Add to this the fact that each upgrade,
patch, and modification to a network can also be created using complex and sometimes
4 Top-Down Network Design
convoluted thinking, and you soon realize that the result is a network that is hard to
understand and troubleshoot. A network created with this complexity often doesn’t perform
as well as expected, doesn’t scale as the need for growth arises (as it almost always
does), and doesn’t match a customer’s requirements. A solution to this problem is to use a
streamlined, systematic methodology in which the network or upgrade is designed in a
top-down fashion.
Many network design tools and methodologies in use today resemble the “connect-thedots”
game that some of us played as children. These tools let you place internetworking
devices on a palette and connect them with LAN or WAN media. The problem with this
methodology is that it skips the steps of analyzing a customer’s requirements and selecting
devices and media based on .
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i
Solution
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i.
Existence of hydrogen bonding increases boiling p.pdf
Existence of hydrogen bonding increases boiling point of compound
Solution
Existence of hydrogen bonding increases boiling point of compound.
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
JellyBean.java
package jellybeantester;
public class JellyBean
{
//These are the 3 instance variables of a JellyBean object:
private String flavor;
private String color;
private boolean eatMe;
/**
* The purpose of this constructor is to move the parameters passed to the constructor
* into the instance variables of the JellyBean object The 2 parameters are:
* @param aFlavor
* @param aColor
*/
public JellyBean(String aFlavor, String aColor)
{
//Initialize each of the instance variables of the JellyBean object with the parameters passed to
the constructor
//Then, set eatMe attribute to false
this.flavor=aFlavor;
this.color=aColor;
}
//Setters and getters.
public String getFlavor()
{
return flavor;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public boolean isEatMe() {
return eatMe;
}
public void setEatMe(boolean eatMe) {
this.eatMe = eatMe;
}
public void setFlavor(String aFlavor)
{
flavor = aFlavor;
}
/**
*
* @return a String representation of all the attributes in the JellyBean class
*/
public String toString()
{
return \"\ Flavour = \"+getFlavor()+\"\ Color = \"+getColor()+\"\ Eat Me = \"+isEatMe()+\"\ \";
}
}
______________________________________________
JellyBeanTester.java
package jellybeantester;
import java.util.Scanner;
public class JellyBeanTester
{
// These are the 3 global variables that will each hold a JellyBean object. These variables
// can be accessed by any method in the tester class because they are global.
static JellyBean jb1;
static JellyBean jb2;
static JellyBean jb3;
static Scanner sc=new Scanner(System.in);
/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
createJellyBeanBag();
processJellyBeanBag();
}
/**
* The createJellyBeanBag method will ask the user for input, and will
* use that input to create 3 JellyBean objects.
*/
public static void createJellyBeanBag()
{
String userInputJBColor;
String userInputJBFlavor;
//Ask the user to enter the color of the first jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"Enter the Color of the First Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the first jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of First the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor and userInputJBColor:
jb1 = new JellyBean(userInputJBFlavor, userInputJBColor);
//Ask the user to enter the color of the second jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"\ Enter the Color of the second Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the second jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of Second the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor an.
In present DNA microarray technology, the different test-samples are.pdf
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end.
Solution
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end..
In computer graphics vectors perform the operations are...1.Rotati.pdf
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations.
Solution
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations..
copper iodide are incompatible in oxidising media.pdf
copper iodide are incompatible in oxidising media
Solution
copper iodide are incompatible in oxidising media.
Dirac theoremFor a simple network with n 3 vertices, if each ver.pdf
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle.
Solution
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle..
Construction Supervisor ResponsibilitiesCompletes construction pr.pdf
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:
Solution
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:.
More from anandatalapatra (20)
P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
NaCl it has two atoms in a molecule for 1 mole of.pdf
NaCl it has two atoms in a molecule for 1 mole of.pdf
just find the moles and then use PV = nRT to fin.pdf
just find the moles and then use PV = nRT to fin.pdf
Water might be the most possible item through which bacteria entered.pdf
Water might be the most possible item through which bacteria entered.pdf
Total particles = 1000Number of particles entering the small apert.pdf
Total particles = 1000Number of particles entering the small apert.pdf
These both are inflammatory bowel diseases characterized by chronic .pdf
These both are inflammatory bowel diseases characterized by chronic .pdf
The topological structure is mainly gives the representaion of the n.pdf
The topological structure is mainly gives the representaion of the n.pdf
The main components of protein family members of RISC complex are.pdf
The main components of protein family members of RISC complex are.pdf
Solution It is for the auditors and other people involved in the .pdf
Solution It is for the auditors and other people involved in the .pdf
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
relation between concentration and cell potential is given as Ecel.pdf
relation between concentration and cell potential is given as Ecel.pdf
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
Existence of hydrogen bonding increases boiling p.pdf
Existence of hydrogen bonding increases boiling p.pdf
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
In present DNA microarray technology, the different test-samples are.pdf
In present DNA microarray technology, the different test-samples are.pdf
In computer graphics vectors perform the operations are...1.Rotati.pdf
In computer graphics vectors perform the operations are...1.Rotati.pdf
copper iodide are incompatible in oxidising media.pdf
copper iodide are incompatible in oxidising media.pdf
Dirac theoremFor a simple network with n 3 vertices, if each ver.pdf
Dirac theoremFor a simple network with n 3 vertices, if each ver.pdf
Construction Supervisor ResponsibilitiesCompletes construction pr.pdf
Construction Supervisor ResponsibilitiesCompletes construction pr.pdf
Recently uploaded
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
for studentd in cabridge board
Model Attribute Check Company Auto Property
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
Instructions for Submissions thorugh G- Classroom.pptx
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Thesis Statement for students diagnonsed withADHD.ppt
Presentation required for the master in Education.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
The Art Pastor's Guide to Sabbath | Steve Thomason
What is the purpose of the Sabbath Law in the Torah. It is interesting to compare how the context of the law shifts from Exodus to Deuteronomy. Who gets to rest, and why?
How to Create Map Views in the Odoo 17 ERP
The map views are useful for providing a geographical representation of data. They allow users to visualize and analyze the data in a more intuitive manner.
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdfFundacja Rozwoju Społeczeństwa Przedsiębiorczego
Wolontariat grupowyChapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Template Jadual Bertugas Kelas (Boleh Edit)
Jadual Bertugas kelas dalam bentuk softcopy PowerPoint. Cikgu boleh download >> edit >> print >> laminate. Semoga bermanfaat.
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
Let us know about Maruti Suzuki, a successful Joint venture in India.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
How to Break the cycle of negative Thoughts
We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
Recently uploaded (20)
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
The Art Pastor's Guide to Sabbath | Steve Thomason
The Art Pastor's Guide to Sabbath | Steve Thomason
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
a) False (because it is not always the case).Many electronegative .pdf
- 1. a) False (because it is not always the case). Many electronegative anions are more stable by themselves andwon't form strong acids (such as HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate. For example, HF is less acidic than HBr (even though Fis more electronegative than Br) b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off easily. c) True. (F is more electronegative and has a smaller diameter soweaker acid) d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid. e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds the O-H bond. f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through inductive effects. Solution a) False (because it is not always the case). Many electronegative anions are more stable by themselves andwon't form strong acids (such as HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate. For example, HF is less acidic than HBr (even though Fis more electronegative than Br) b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off easily. c) True. (F is more electronegative and has a smaller diameter soweaker acid) d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid. e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds
- 2. the O-H bond. f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through inductive effects.