relation between concentration and cell potential is given as Ecell = Eocell - (0.059/n) ln Q where Q = concentration of product / concentration of substrate Ecell =0.77 - ln (3e-4 / 4e-3) = 0.77 - ln 3 + ln4 +1 = - 0.70 eV ANSWER Solution relation between concentration and cell potential is given as Ecell = Eocell - (0.059/n) ln Q where Q = concentration of product / concentration of substrate Ecell =0.77 - ln (3e-4 / 4e-3) = 0.77 - ln 3 + ln4 +1 = - 0.70 eV ANSWER.