copper iodide are incompatible in oxidising media.pdf
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P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm
Solution
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm.
NaCl it has two atoms in a molecule for 1 mole of.pdf
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-
Solution
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-.
just find the moles and then use PV = nRT to fin.pdf
just find the moles and then use: PV = nRT to find the volume at STP.
Solution
just find the moles and then use: PV = nRT to find the volume at STP..
Water might be the most possible item through which bacteria entered.pdf
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems.
Solution
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems..
Total particles = 1000Number of particles entering the small apert.pdf
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second.
Solution
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second..
These both are inflammatory bowel diseases characterized by chronic .pdf
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly associated with smoking
Predicts a worse course of disease
Increases risk of surgery & further surgery
Solution
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly .
The topological structure is mainly gives the representaion of the n.pdf
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there exists one and only one path between any pair of nodes. (there cannot be
anyother path)
2. Alteast on tree will be there between every connected grwph.
3. A graph of the tree contains all the nodes.
4. The tree is mainly circuitless where there is no closed path in a tree.
5. (n-1) is called as rank of the tree.
Solution
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there.
The main components of protein family members of RISC complex are.pdf
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down.
Solution
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down..
Recommended
P(helium) + p(oxygen) = P(total) = P(helium) = P.pdf
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm
Solution
P(helium) + p(oxygen) = P(total) => P(helium) = P(total) - p(oxygen) = 7 - 0.21 =
6.79 atm.
NaCl it has two atoms in a molecule for 1 mole of.pdf
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-
Solution
NaCl it has two atoms in a molecule for 1 mole of NaCl it have 2*1=2moles atoms
1mole Na+ 1mole of Cl-.
just find the moles and then use PV = nRT to fin.pdf
just find the moles and then use: PV = nRT to find the volume at STP.
Solution
just find the moles and then use: PV = nRT to find the volume at STP..
Water might be the most possible item through which bacteria entered.pdf
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems.
Solution
Water might be the most possible item through which bacteria entered inside the body. Name of
the bacteria is Escherichia coli which is an enteric bacteria enters into body through
contaminated food and water.
Normally MacConkey agar media is used to isolate and culture from negative enteric bacteria.
As E-coli is also an enteric bacteria this media is suitable. E.coli cause UTI related problems ,
intestinal problems..
Total particles = 1000Number of particles entering the small apert.pdf
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second.
Solution
Total particles = 1000
Number of particles entering the small aperture = (1/(1+3))*1000 = 1000/4 = 250
This is beacause the smaller aperture is three times thinner than the other .
If 350 particles are observed then the flow pattern has changed to approximately 4*350 = 1400
airborne particles per second..
These both are inflammatory bowel diseases characterized by chronic .pdf
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly associated with smoking
Predicts a worse course of disease
Increases risk of surgery & further surgery
Solution
These both are inflammatory bowel diseases characterized by chronic inflammation of the
digestive tract.
SimilaritiesFactorulcerative colitisCrohn diseaseDistributionAffects large bowel onlyAffects
small bowel and large bowelHistologyGranulomata absent
Inflammation usually confined to mucosa
The increase in white cells tend to be polymorphsPresence of granulomas are almost diagnostic
Inflammation extends through the mucosa and
muscle of the bowel
The increase in white cells tend to be lymphocytesRadiologyStrictures and fissures are much
less common in UC
Symmetrical inflammationStrictures are common
Deep fissures and fistulae are common
Asymmetrical inflammationEndoscopy findingRectum always aff ected
Inflammation is uniform
Bowel wall is thin with loss of vascular pattern
(blood vessels not visible)Rectum frequently spared
Inflammation not continuous (presence
of skip lesions)
Bowel wall is thickened and has a ‘cobblestoned’
appearance due to deep ulcers and swelling
of the tissue
DietUnaffected by dietRemission achieved with enteral feed followed by
exclusion/ elimination dietClinical appearanceWeight loss usually related to the severity of
active disease
Bloody diarrhoea
Abdominal mass uncommonPatients often thin and may be malnourished due to
intestinal malabsorption of nutrients
Diarrhoea - only sometimes with blood
Abdominal mass commonSmokingAssociated with non-smokers
Appears to protect against diseaseStrongly .
The topological structure is mainly gives the representaion of the n.pdf
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there exists one and only one path between any pair of nodes. (there cannot be
anyother path)
2. Alteast on tree will be there between every connected grwph.
3. A graph of the tree contains all the nodes.
4. The tree is mainly circuitless where there is no closed path in a tree.
5. (n-1) is called as rank of the tree.
Solution
The topological structure is mainly gives the representaion of the network. It is called as the
heart of the topological structure. Following are the elements that are represented as the edges of
the graph.
Here the edges is drawn as a line , there are terminating on dots or small circles from which the
edges (elements ) may be present. In the virtual circuit analysis the branches are mainly called
from the edges of the graphs that is represented.
There are various topologies present they are as follows :
1. Series topology
2.Parallel topology
3. Parallel series topology
4.series parallel topology
The network topology is mainly explained in the form of the consept tree.
The connected graph of a network mainly , a connected subgraph is known as the tree. As a
result the topology that was formed is called as NETWORK TOPOLOGY.
Here the grap as well subgraph mainly has the nodes , but there will not be any loops in it.
Here the TWIGS , the branches of the tree are called as the twigs or tree branches.
The number of tree branches are mainly lesser than the nodes that is present.
Twigs = (n-1) , here \"n\" is the number of nodes of the graph.
Also, the branches of the co - tree may not be interconnected , where as the branches of a tree are
always remain connected.
Here are the properties of the Tree:
1. In a Tree, there.
The main components of protein family members of RISC complex are.pdf
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down.
Solution
The main components of protein family members of RISC complex are:
Highly abundant and expressive genes get more easily available for silencing process. siRNA
activities are all dependent on the expression level of the RNA strands.
Pri-Mi RNA are transported out of the nucleus by exportin protein. Dicer converts it into double
stranded micro RNA form. The micro RNA produced is complementary to the target mRNA. It
can bind with the complementary strand of target mRNA and breaks it down..
Solution It is for the auditors and other people involved in the .pdf
Solution
:
It is for the auditors and other people involved in the investigation to identify who is the culprit .
The company had no further additional loss , therefore I would advise Harry never to do it again
and allow the auditors to determine who is the culprit..
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins.
Solution
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins..
relation between concentration and cell potential is given as Ecel.pdf
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER
Solution
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER.
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
Part I
Identifying Your Customer’s
Needs and Goals
Chapter 1 Analyzing Business Goals and Constraints
Chapter 2 Analyzing Technical Goals and Tradeoffs
Chapter 3 Characterizing the Existing Internetwork
Chapter 4 Characterizing Network Traffic
Chapter 1
Analyzing Business
Goals and Constraints
This chapter serves as an introduction to the rest of the book by describing top-down
network design. The first section explains how to use a systematic, top-down process
when designing computer networks for your customers. Depending on your job, your
customers might consist of other departments within your company, those to whom you
are trying to sell products, or clients of your consulting business.
After describing the methodology, this chapter focuses on the first step in top-down network
design: analyzing your customer’s business goals. Business goals include the capability
to run network applications to meet corporate business objectives, and the need to
work within business constraints, such as budgets, limited networking personnel, and
tight timeframes.
This chapter also covers an important business constraint that some people call the
eighth layer of the Open System Interconnection (OSI) reference model: workplace politics.
To ensure the success of your network design project, you should gain an understanding
of any corporate politics and policies at your customer’s site that could affect
your project.
The chapter concludes with a checklist to help you determine if you have addressed the
business issues in a network design project.
Using a Top-Down Network Design Methodology
According to Albert Einstein:
“The world we’ve made as a result of the level of thinking we have done thus far creates
problems that we cannot solve at the same level at which we created them.”
To paraphrase Einstein, networking professionals have the ability to create networks that
are so complex that when problems arise they can’t be solved using the same sort of
thinking that was used to create the networks. Add to this the fact that each upgrade,
patch, and modification to a network can also be created using complex and sometimes
4 Top-Down Network Design
convoluted thinking, and you soon realize that the result is a network that is hard to
understand and troubleshoot. A network created with this complexity often doesn’t perform
as well as expected, doesn’t scale as the need for growth arises (as it almost always
does), and doesn’t match a customer’s requirements. A solution to this problem is to use a
streamlined, systematic methodology in which the network or upgrade is designed in a
top-down fashion.
Many network design tools and methodologies in use today resemble the “connect-thedots”
game that some of us played as children. These tools let you place internetworking
devices on a palette and connect them with LAN or WAN media. The problem with this
methodology is that it skips the steps of analyzing a customer’s requirements and selecting
devices and media based on .
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i
Solution
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i.
Existence of hydrogen bonding increases boiling p.pdf
Existence of hydrogen bonding increases boiling point of compound
Solution
Existence of hydrogen bonding increases boiling point of compound.
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
JellyBean.java
package jellybeantester;
public class JellyBean
{
//These are the 3 instance variables of a JellyBean object:
private String flavor;
private String color;
private boolean eatMe;
/**
* The purpose of this constructor is to move the parameters passed to the constructor
* into the instance variables of the JellyBean object The 2 parameters are:
* @param aFlavor
* @param aColor
*/
public JellyBean(String aFlavor, String aColor)
{
//Initialize each of the instance variables of the JellyBean object with the parameters passed to
the constructor
//Then, set eatMe attribute to false
this.flavor=aFlavor;
this.color=aColor;
}
//Setters and getters.
public String getFlavor()
{
return flavor;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public boolean isEatMe() {
return eatMe;
}
public void setEatMe(boolean eatMe) {
this.eatMe = eatMe;
}
public void setFlavor(String aFlavor)
{
flavor = aFlavor;
}
/**
*
* @return a String representation of all the attributes in the JellyBean class
*/
public String toString()
{
return \"\ Flavour = \"+getFlavor()+\"\ Color = \"+getColor()+\"\ Eat Me = \"+isEatMe()+\"\ \";
}
}
______________________________________________
JellyBeanTester.java
package jellybeantester;
import java.util.Scanner;
public class JellyBeanTester
{
// These are the 3 global variables that will each hold a JellyBean object. These variables
// can be accessed by any method in the tester class because they are global.
static JellyBean jb1;
static JellyBean jb2;
static JellyBean jb3;
static Scanner sc=new Scanner(System.in);
/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
createJellyBeanBag();
processJellyBeanBag();
}
/**
* The createJellyBeanBag method will ask the user for input, and will
* use that input to create 3 JellyBean objects.
*/
public static void createJellyBeanBag()
{
String userInputJBColor;
String userInputJBFlavor;
//Ask the user to enter the color of the first jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"Enter the Color of the First Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the first jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of First the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor and userInputJBColor:
jb1 = new JellyBean(userInputJBFlavor, userInputJBColor);
//Ask the user to enter the color of the second jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"\ Enter the Color of the second Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the second jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of Second the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor an.
In present DNA microarray technology, the different test-samples are.pdf
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end.
Solution
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end..
In computer graphics vectors perform the operations are...1.Rotati.pdf
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations.
Solution
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations..
Dirac theoremFor a simple network with n 3 vertices, if each ver.pdf
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle.
Solution
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle..
Construction Supervisor ResponsibilitiesCompletes construction pr.pdf
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:
Solution
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:.
Border Gateway Protocol (BGP) is the protocol whi.pdf
Border Gateway Protocol (BGP) is the protocol which is used to make core routing
decisions on the Internet; it involves a table of IP networks or \"prefixes\" which designate
network reach-ability among autonomous systems (AS). BGP is a path vector protocol, or a
variant of a Distance-vector routing protocol. BGP does not involve traditional Interior Gateway
Protocol (IGP) metrics, but routing decisions are made based on path, network policies, and/or
rule-sets. For this reason, it is more appropriately termed a reach-ability protocol rather than
routing protocol. BGP was created to replace the Exterior Gateway Protocol (EGP) to allow fully
decentralized routing in order to transition from the core ARPAnet model to a decentralized
system that included the NSFNET backbone and its associated regional networks. This allowed
the Internet to become a truly decentralized system. Since 1994, version four of the BGP has
been in use on the Internet. All previous versions are now obsolete. The major enhancement in
version 4 was support of Classless Inter-Domain Routing and use of route aggregation to
decrease the size of routing tables. Since January 2006, version 4 is codified in RFC 4271, which
went through more than 20 drafts based on the earlier RFC 1771 version 4. RFC 4271 version
corrected a number of errors, clarified ambiguities and brought the RFC much closer to industry
practices. Most Internet service providers must use BGP to establish routing between one another
(especially if they are multihomed). Therefore, even though most Internet users do not use it
directly, BGP is one of the most important protocols of the Internet. Compare this with Signaling
System 7 (SS7), which is the inter-provider core call setup protocol on the PSTN. Very large
private IP networks use BGP internally. An example would be the joining of a number of large
OSPF (Open Shortest Path First) networks where OSPF by itself would not scale to size. Another
reason to use BGP is multihoming a network for better redundancy, either to multiple access
points of a single ISP (RFC 1998), or to multiple ISPs.
Solution
Border Gateway Protocol (BGP) is the protocol which is used to make core routing
decisions on the Internet; it involves a table of IP networks or \"prefixes\" which designate
network reach-ability among autonomous systems (AS). BGP is a path vector protocol, or a
variant of a Distance-vector routing protocol. BGP does not involve traditional Interior Gateway
Protocol (IGP) metrics, but routing decisions are made based on path, network policies, and/or
rule-sets. For this reason, it is more appropriately termed a reach-ability protocol rather than
routing protocol. BGP was created to replace the Exterior Gateway Protocol (EGP) to allow fully
decentralized routing in order to transition from the core ARPAnet model to a decentralized
system that included the NSFNET backbone and its associated regional networks. This allowed
the Internet to become a truly decentralize.
Answer-The hierarchical aspect of the Ip addressesnetwork -host .pdf
Answer:-
The hierarchical aspect of the Ip addresses:network -host parts of the address.This allows routers
to \'route\' network address only.
IP addresses include the network/subnet, so that interfaces on differentnetworks must have
different network portions of the address.Alternatively ,addresses include location information
and different interfaces are at different locations , topologically.
All host attached to the same network have the same network part of their IP address.The host
part identifies that host uniquely on the network
point-to-point interfaces can be assigned a duplicate address because the other endpoint of the
lint doesnt use the address to reach the interface ;it just sends .Such interfaces ,however ,cannot
be addressed by any other host in the network.
Solution
Answer:-
The hierarchical aspect of the Ip addresses:network -host parts of the address.This allows routers
to \'route\' network address only.
IP addresses include the network/subnet, so that interfaces on differentnetworks must have
different network portions of the address.Alternatively ,addresses include location information
and different interfaces are at different locations , topologically.
All host attached to the same network have the same network part of their IP address.The host
part identifies that host uniquely on the network
point-to-point interfaces can be assigned a duplicate address because the other endpoint of the
lint doesnt use the address to reach the interface ;it just sends .Such interfaces ,however ,cannot
be addressed by any other host in the network..
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes a.pdf
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes aegypti mosquito, culicinae,
Psorophora, Mansonia and Yellow fever mosquito are some of the disease spreading species
found in Florida and reported that currently 80 species of mosquitoes occurs in Florida and 33
species is capable of causing pest problems and 13 species transmits the pathogens.
Most effective control measures for mosquitoes, is to drain all sources of stagnating water, so
that they cannot breed and try to drain out the garbage cans, pool covers, house gutters, toys
flower pots etc and try to dispose the old tires, drums etc and change bird baths frequently and
keep the house with screens closed all the time, no broken screens. Ask people and children to
wear long pants, long sleeves etc and wear socks and shoes. Apply mosquito repellent to bare
skin and use repellents with DEET, neem oil, lemon eucalyptus oil, picaridins and IR3535.
Ponds and lakes will have stagnant water and will have steep slope and shallow, so mosquito
breeding will be high here, circulate the water by artificial fountains and spray mosquito-killing
chemicals like Malathion (adulticide-kills adult mosquitoes) and Scourge (kills mosquitoes).
How much every possible keep the swamp sites dry and in agricultural land, after crop
harvesting, drain out the water completely and use the pesticides in such a way it can also kill the
mosquitoes.
Solution
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes aegypti mosquito, culicinae,
Psorophora, Mansonia and Yellow fever mosquito are some of the disease spreading species
found in Florida and reported that currently 80 species of mosquitoes occurs in Florida and 33
species is capable of causing pest problems and 13 species transmits the pathogens.
Most effective control measures for mosquitoes, is to drain all sources of stagnating water, so
that they cannot breed and try to drain out the garbage cans, pool covers, house gutters, toys
flower pots etc and try to dispose the old tires, drums etc and change bird baths frequently and
keep the house with screens closed all the time, no broken screens. Ask people and children to
wear long pants, long sleeves etc and wear socks and shoes. Apply mosquito repellent to bare
skin and use repellents with DEET, neem oil, lemon eucalyptus oil, picaridins and IR3535.
Ponds and lakes will have stagnant water and will have steep slope and shallow, so mosquito
breeding will be high here, circulate the water by artificial fountains and spray mosquito-killing
chemicals like Malathion (adulticide-kills adult mosquitoes) and Scourge (kills mosquitoes).
How much every possible keep the swamp sites dry and in agricultural land, after crop
harvesting, drain out the water completely and use the pesticides in such a way it can also kill the
mosquitoes..
Ans.)C) Lower right-hand corner (Ruderal)In climates where streams.pdf
Ans.)C) Lower right-hand corner (Ruderal)
In climates where streams are subject to recurrent flash floods that rub the stream bed, removing
nearly all of the vegetation. Few plants grow in well-lit stream channels. And these are ruderal.
Ruderal plants have the ability to grow and colonize in disturbed lands.
Solution
Ans.)C) Lower right-hand corner (Ruderal)
In climates where streams are subject to recurrent flash floods that rub the stream bed, removing
nearly all of the vegetation. Few plants grow in well-lit stream channels. And these are ruderal.
Ruderal plants have the ability to grow and colonize in disturbed lands..
All chordates possess the same four structures in the early embryo. .pdf
All chordates possess the same four structures in the early embryo. What are they?
Characteristics OF CHORDATES
Four unmistakable determined attributes of chordates recognize them from their precursors:
A. Notochord, or a bar of vacuolated cells, encased by a firm sheath that falsehoods ventral to the
neural tube in vertebrate fetuses and a few grown-ups.
B. Empty nerve rope that falsehoods dorsal to the notochord
C. Pharyngeal pockets
D. Endostyle - extended section in the pharynx floor of protochordates that may create as the
thyroid organ in chordates
In the subphylum Vertebrata, all individuals have the four chordate qualities eventually being
developed, however frequently these structures are adjusted fundamentally in grown-up
creatures.
These four attributes might be found in a portion of the predecessors of chordates and are
normally put in a casual gathering called Protochordates. These serve as living representations of
the missing fossils in vertebrate advancement.
What are the differences between deuterostome, and chordate, and amniote? Provide examples
from lab of each of these. Can animal fall in to more than one of these categories? Which
categories do human fall into?
deuterostome,
chordate
amniote
The name deuterostome signifies \"mouth second\", and alludes to one vital formative element
exceptional to this gathering.
Deuterostomes are any individuals from a superphylum of creatures. It is a sister clade of
Protostomia, with which it shapes the Nephrozoa clade.
Deuterostomia is a subtaxon of the Bilateria branch of the subkingdom Eumetazoa, inside
Animalia, and are recognized from protostomes by their embryonic improvement; in
deuterostomes, the principal opening (the blastopore) turns into the butt, while in protostomes, it
turns into the mouth.
Most deuterostomes show uncertain cleavage, in which the formative destiny of the cells in the
creating fetus are not controlled by the personality of the parent cell. In this manner, if the initial
four cells are isolated, every cell is equipped for shaping an entire little hatchling; and if a cell is
expelled from the blastula, alternate cells will adjust.
In deuterostomes the mesoderm frames as evaginations of the created gut that squeeze off,
shaping the coelom. This is called enterocoely.
lancelets, four-limbed vertebrates - well evolved creatures, reptiles, creatures of land and water,
and birds,sea stars and weak stars)
Chordates are creatures having a notochord, an empty dorsal nerve string, pharyngeal openings,
an endostyle, and a post-butt-centric tail for at any rate some time of their life cycles. The
Chordata, together with sister clade Ambulacraria, shape the deuterostomes as in the incipient
organism improvement organize the rear-end frames before the mouth.
Systematically, the phylum incorporates the subphyla Vertebrata, which incorporates angle,
creatures of land and water, reptiles, winged animals, and warm blooded creatures; Tunicata,
which incorporates salps and o.
a) False (because it is not always the case).Many electronegative .pdf
a) False (because it is not always the case).
Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as
HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid
mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate.
For example, HF is less acidic than HBr (even though Fis more electronegative than Br)
b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off
easily.
c) True. (F is more electronegative and has a smaller diameter soweaker acid)
d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid.
e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds
the O-H bond.
f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through
inductive effects.
Solution
a) False (because it is not always the case).
Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as
HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid
mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate.
For example, HF is less acidic than HBr (even though Fis more electronegative than Br)
b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off
easily.
c) True. (F is more electronegative and has a smaller diameter soweaker acid)
d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid.
e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds
the O-H bond.
f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through
inductive effects..
1.The Open Systems Interconnect (OSI) model has seven layers.The mod.pdf
1.The Open Systems Interconnect (OSI) model has seven layers.The model partitions a
communication system into abstraction layers. The original version of the model defined seven
layers.OSI means Open Systems Interconnectionis reference model for how applications can
communicate over a network This article describes and explains them, beginning with the lowest
in the hierarchy the physical and proceeding to the highest the application. The layers are stay in
this way:
Application
Presentation
Session
Transport
Network
Data Link
Physical
features osi model:
If network communications need to happen with out any trouble, many problems must be
solved. Coordinating all these problems are so complex and not easy to manage.
Big picture of communication over network is understandable through this OSI model.
We can understand new technologies as they are developed.
Troubleshooting is easier by separate network.
2.
the Data process that takes placethe message from one host to another cab be done as such:
The data to be passed from one host to another can be composed at the first top layer of the
passing device layer N into a protocol data unit.
The protocal data unit is passed to next layer, where it is known as the service data unit.
At next layer let us consider that layer be N-1 the service data unit is observed the with a
header,a footer,some times both,producing a layer next protocal data unit. It is then passed to
layer next layer N-2.
The process repeated until reaching the lower level,from which the data is transmitted to the
receiving device.
At the receiving device the data is passed from the lowest to the highest layer as a series of
SDUs while being successively stripped from each layer\'s header and/or footer, until reaching
the topmost layer, where the last of the data is consumed.
3.
ISO
1.OSI is a generic, protocol independent standard, acting as a communication gateway between
the network and end user.
2.OSI is a conceptual model that characterizes and standardizes the communication functions of
a computing or telecommunication system irrespective of their underlying structure and
technology being used.
3.OSI is a reference model.
4.The OSI model consists of 7 architectural layers
TCp/IP
1. TCP/IP model is based on standard protocols around which the Internet has developed. It is a
communication protocol, which allows connection of hosts over a network.
2.TCP/IP is a core protocol of the Internet Protocol Suite (IPS). It is the basic communication
language or protocol of the internet. It can be used as a communications protocol in a private
network either an intranet or an extranet
3.TCP/IP is an implementation of OSI model.
4.The tcp/ip can contains only 4 laters
4.1.network inerface layer:The most widely-known Application layer protocols are those used
for the exchange of user information.
2.internet layer:The Internet layer is responsible for addressing, packaging, and routing
functions. The core protocols of the Internet layer are I.
(1) ACQUISITION EXPENSES Acquirers may incur millions in direct an.pdf
(1) ACQUISITION EXPENSES
Acquirers may incur millions in direct and indirect costs finding targets, gathering and analyzing
information, seeking funds and negotiating deals. The question is how to report these costs.
Current GAAP . These costs are deferred by adding them to the purchase price. In all likelihood,
they increase recorded goodwill, where they remain until and unless impairment is recognized.
Deficiency . Although pre-transaction costs are necessary, they don’t add value to acquired
assets (including goodwill) and they are not assets on their own. It’s questionable whether
putting them on a balance sheet is useful.
New standard . Statement no. 141(R) follows the tenet that only real assets should be recorded
for a combination. Because acquisition-related costs are not assets, they will be charged to
expense. Exhibit 1 shows them being moved off the statement of financial position and onto the
income statement
(2) BARGAIN PURCHASE GAIN
In rare circumstances, an acquirer strikes a favorable deal and pays less than the aggregate fair
value of purchased net assets. These transactions raise two issues—at what amounts should
individual assets and liabilities be recorded, and is it useful to recognize a bargain purchase gain?
Current GAAP. The excess value is considered “negative goodwill.” Because of its focus on
cost, current practice selectively reduces certain asset carrying values until the aggregate total
equals the purchase price. (In very rare circumstances, any unallocated difference is treated as an
extraordinary gain.)
Deficiency. The balance sheet underreports the value at hand and available to management for
earning returns. In addition, management’s successful negotiation is not immediately reflected in
reported income.
New standard. Acquired assets and liabilities will be recorded at fair value and any excess over
the purchase price will be credited to a gain that flows to the income statement, net of deferred
taxes. The outcome will likely be more complete and useful statements of financial position and
income.
(3) CONTINGENT CONSIDERATION
In major transactions such as combinations, sizable spreads initially exist between amounts
buyers and sellers offer to pay and accept. One way to close that gap is contingent consideration
arrangements in which, depending on future events, a buyer agrees to pay an additional amount
or a seller agrees to refund part of the purchase price. Because contingencies can be difficult to
pin down, many issues have been raised about their financial statement effects.
Current GAAP. Most contingent consideration arrangements are ignored in determining the
recorded price. When additional payments based on earnings targets occur, their amounts are
added to goodwill. If payments are tied to stock price changes, paid-in capital is credited. If
refunds are received, the buyer reduces goodwill or paid-in capital.
Deficiency. In these circumstances, not immediately recognizing the contingent assets or
li.
#include iostream #include cstring #include vector #i.pdf
#include
#include
#include
#include
#include \"textFile.hpp\"
using namespace std;
void displayHelp();
bool isInteger(const string &s);
bool askSave();
int main(int argc, const char * argv[]) {
int resultCode = 0;
// Convert to a vector.
vector args(argv, argv + argc);
// Process arguments, must be 1 argument, otherwise exit with code 1.
if (args.size() < 2) {
cout << \"Missing command line argument!\" << endl;
cout << \"Usage: ./myEditor \" << endl;
resultCode = 1;
} else {
string fileName = args[1];
textFile dataFile(fileName);
// Check if the file is ok to use, if it is, lets go.
if (!dataFile.checkFile()) {
resultCode = 2;
} else {
// We can now assume the file is good, so we can work with it.
dataFile.loadFile();
// Display some text to help the user.
displayHelp();
// Now get user input.
bool done = false;
string userInput = \"\";
while (!done) {
cout << \"> \";
getline(cin, userInput);
char cmd = tolower(userInput.c_str()[0]);
char cmd2 = \' \';
if (userInput.size() > 1) {
cmd2 = userInput.c_str()[1];
}
// This check makes sure the command format is correct
// so that commands don\'t fire off by mistake.
if (strncmp(&cmd, \" \", 1) != 0 && strncmp(&cmd2, \" \", 1) == 0) {
switch(cmd) {
case \'q\': {
done = true;
break;
}
case \'i\': {
unsigned long lineIndex = dataFile.textLines() + 1;
string newLine;
if (userInput.size() > 1) {
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
}
cout << to_string(lineIndex) << \"> \";
getline(cin, newLine);
dataFile.insertLine(lineIndex - 1, newLine);
break;
}
case \'d\': {
if (userInput.size() > 1) {
unsigned long lineIndex;
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
dataFile.removeLine(lineIndex - 1);
}
break;
}
case \'l\': {
for (int x = 0; x < dataFile.textLines(); x++) {
cout << to_string(x + 1) << \"> \" << dataFile.getLine(x) << endl;
}
break;
}
case \'h\': {
displayHelp();
break;
}
case \'s\': {
dataFile.saveFile();
break;
}
}
}
}
// Ask about saving the file before exiting.
bool save = askSave();
if (save) {
dataFile.saveFile();
}
cout << \"Thank you for using myEditor.\" << endl;
}
}
return resultCode;
}
/*
Asks the user if they\'d like to save or not, returns true if they do. Anything
other than \"y\" or \"Y\" will be interpreted as a negative answer.
*/
bool askSave()
{
bool result = false;
string userInput = \"\";
cout << \"Do you wan to save the change? (Y - yes; N - no) \";
getline(cin, userInput);
userInput = tolower(*userInput.c_str());
if (strncmp(userInput.c_str(), \"y\", 1) == 0) {
result = true;
}
return result;
}
/*
Displays help text.
*/
void displayHelp()
{
cout << \"Welcome to my text editor.\" << endl;
cout << \"\\tTo insert text at the end of the file, type \'I\'\" << endl;
cout << \"followed by the text.\" << endl;
cout << \"\\tTo insert text at a certain line number, type \'I\'\" << endl;
cout << \"followed by a space and the desired line number.\" << endl;
cout << \"\\tTo delete a line, type \'D\' followed by a space and the\" << endl;
cou.
Overview on Edible Vaccine: Pros & Cons with Mechanism
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
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Solution It is for the auditors and other people involved in the .pdf
Solution
:
It is for the auditors and other people involved in the investigation to identify who is the culprit .
The company had no further additional loss , therefore I would advise Harry never to do it again
and allow the auditors to determine who is the culprit..
Ques-1 Answer C. neutrophilsReasonInnate immune system is wit.pdf
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins.
Solution
Ques-1: Answer: C. neutrophils
Reason:
Innate immune system is with first line of defense first come to combat against this infection.
Neutrophiols are the host cell fist line defence factors, which act against S. aureus infection
(myriad anti -immunity factors). The main immunological inflammatory factors that were
involved in his tonsil swelling as follow. The Toll like receptors (TLRs) are signaling receptors,
and their activation leading to enhancement of the antimicrobial activity of neutrophils result in
the generation of cytokines predominantly by macrophages at the site of infection followed by
TLR s activation to present antigen to naïve T cells. This process of macropinocytosis (microbial
engulfing) occur through TLRs that induces the dendritic cells maturation finally cell migration.
Gram positive organisms live primarily on the surface of your external barriers but if they reach
systemic circulation and cause infective endocarditis (eample,Staphylococcus aureus).
Sometimes Gram- positive bacteria causes’ disease inside the body, i.e. S. aureus cause septic
arthritis inside the body. Increased risk of disease resulted if they became resistant to antibiotics
due to release of immunosppressant virulent exotoxins and endotoxins..
relation between concentration and cell potential is given as Ecel.pdf
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER
Solution
relation between concentration and cell potential is given as
Ecell = Eocell - (0.059/n) ln Q
where Q = concentration of product / concentration of substrate
Ecell =0.77 - ln (3e-4 / 4e-3)
= 0.77 - ln 3 + ln4 +1
= - 0.70 eV
ANSWER.
Part I Identifying Your Customer’s Needs and Goals Chapter 1 A.pdf
Part I
Identifying Your Customer’s
Needs and Goals
Chapter 1 Analyzing Business Goals and Constraints
Chapter 2 Analyzing Technical Goals and Tradeoffs
Chapter 3 Characterizing the Existing Internetwork
Chapter 4 Characterizing Network Traffic
Chapter 1
Analyzing Business
Goals and Constraints
This chapter serves as an introduction to the rest of the book by describing top-down
network design. The first section explains how to use a systematic, top-down process
when designing computer networks for your customers. Depending on your job, your
customers might consist of other departments within your company, those to whom you
are trying to sell products, or clients of your consulting business.
After describing the methodology, this chapter focuses on the first step in top-down network
design: analyzing your customer’s business goals. Business goals include the capability
to run network applications to meet corporate business objectives, and the need to
work within business constraints, such as budgets, limited networking personnel, and
tight timeframes.
This chapter also covers an important business constraint that some people call the
eighth layer of the Open System Interconnection (OSI) reference model: workplace politics.
To ensure the success of your network design project, you should gain an understanding
of any corporate politics and policies at your customer’s site that could affect
your project.
The chapter concludes with a checklist to help you determine if you have addressed the
business issues in a network design project.
Using a Top-Down Network Design Methodology
According to Albert Einstein:
“The world we’ve made as a result of the level of thinking we have done thus far creates
problems that we cannot solve at the same level at which we created them.”
To paraphrase Einstein, networking professionals have the ability to create networks that
are so complex that when problems arise they can’t be solved using the same sort of
thinking that was used to create the networks. Add to this the fact that each upgrade,
patch, and modification to a network can also be created using complex and sometimes
4 Top-Down Network Design
convoluted thinking, and you soon realize that the result is a network that is hard to
understand and troubleshoot. A network created with this complexity often doesn’t perform
as well as expected, doesn’t scale as the need for growth arises (as it almost always
does), and doesn’t match a customer’s requirements. A solution to this problem is to use a
streamlined, systematic methodology in which the network or upgrade is designed in a
top-down fashion.
Many network design tools and methodologies in use today resemble the “connect-thedots”
game that some of us played as children. These tools let you place internetworking
devices on a palette and connect them with LAN or WAN media. The problem with this
methodology is that it skips the steps of analyzing a customer’s requirements and selecting
devices and media based on .
PrintTest.java import java.util.Scanner;public class PrintTest.pdf
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i
Solution
PrintTest.java
import java.util.Scanner;
public class PrintTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter the value :\");
int n = scan.nextInt();
for(int i =0; i.
Existence of hydrogen bonding increases boiling p.pdf
Existence of hydrogen bonding increases boiling point of compound
Solution
Existence of hydrogen bonding increases boiling point of compound.
JellyBean.javapackage jellybeantester;public class JellyBean {.pdf
JellyBean.java
package jellybeantester;
public class JellyBean
{
//These are the 3 instance variables of a JellyBean object:
private String flavor;
private String color;
private boolean eatMe;
/**
* The purpose of this constructor is to move the parameters passed to the constructor
* into the instance variables of the JellyBean object The 2 parameters are:
* @param aFlavor
* @param aColor
*/
public JellyBean(String aFlavor, String aColor)
{
//Initialize each of the instance variables of the JellyBean object with the parameters passed to
the constructor
//Then, set eatMe attribute to false
this.flavor=aFlavor;
this.color=aColor;
}
//Setters and getters.
public String getFlavor()
{
return flavor;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public boolean isEatMe() {
return eatMe;
}
public void setEatMe(boolean eatMe) {
this.eatMe = eatMe;
}
public void setFlavor(String aFlavor)
{
flavor = aFlavor;
}
/**
*
* @return a String representation of all the attributes in the JellyBean class
*/
public String toString()
{
return \"\ Flavour = \"+getFlavor()+\"\ Color = \"+getColor()+\"\ Eat Me = \"+isEatMe()+\"\ \";
}
}
______________________________________________
JellyBeanTester.java
package jellybeantester;
import java.util.Scanner;
public class JellyBeanTester
{
// These are the 3 global variables that will each hold a JellyBean object. These variables
// can be accessed by any method in the tester class because they are global.
static JellyBean jb1;
static JellyBean jb2;
static JellyBean jb3;
static Scanner sc=new Scanner(System.in);
/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
createJellyBeanBag();
processJellyBeanBag();
}
/**
* The createJellyBeanBag method will ask the user for input, and will
* use that input to create 3 JellyBean objects.
*/
public static void createJellyBeanBag()
{
String userInputJBColor;
String userInputJBFlavor;
//Ask the user to enter the color of the first jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"Enter the Color of the First Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the first jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of First the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor and userInputJBColor:
jb1 = new JellyBean(userInputJBFlavor, userInputJBColor);
//Ask the user to enter the color of the second jelly bean object, and save their answer in
userInputJBColor:
System.out.print(\"\ Enter the Color of the second Jelly Bean :\");
userInputJBColor=sc.next();
//Ask the user to enter the flavor of the second jelly bean object, and save their answer in
userInputJBFlavor:
System.out.print(\"Enter the Flavour of Second the Jelly Bean :\");
userInputJBFlavor=sc.next();
//Instantiate a JellyBean object using the userInputJBFlavor an.
In present DNA microarray technology, the different test-samples are.pdf
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end.
Solution
In present DNA microarray technology, the different test-samples are pre-tagged with different
kind of fluorescnet tags whose intensity is automatically monitored by a computed software. This
software not only captures the signal from the array, but also quantizes the intensity of this signal
into a calculated number. This number deciphers the extent of expression levels of the gene to
which the fluorphore was attached to.
Here, the most crucial step is to detemine where the signal is coming from and if the signal is
present or not. Since a microarray contains millions of array data points, it is not possible for
normal human eyes to differentiate between two spots based upon their color and intensity. It is
not even required ot perform this function manually because millions of data points cannot be
quantized by human eye. Thus, the software is initially informed the emission and excitation
wavelengths of the fluorophores and thus, the laser equipped in the detection system
automatically records and quantizes the signal intensity without minutest involvement of human.
Thus, is does not matter if the researcher has normal vision or is a color blind, the data
acquisition will be performed solely by the software. Thus it is possible for a person who is
colorblind to successfully interpret a microarray scan becuase the data will be quantized into
numerical format in the end..
In computer graphics vectors perform the operations are...1.Rotati.pdf
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations.
Solution
In computer graphics vectors perform the operations are...
1.Rotation
2.Movement
3.Mirroring
4.Stretching
5.Skewing
6.Combination of primitives into complex objects
7.Transformations include set operations..
Dirac theoremFor a simple network with n 3 vertices, if each ver.pdf
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle.
Solution
Dirac theorem:
For a simple network with n 3 vertices, if each vertex has degree
at least n/2 (i.e., ki n/2, i), then the network has a Hamiltonian cycle,.
Proof: Let G be the connected graph
Let L = (i1,iL) = (i1, i2, . . . , iL) be the longest path.
The neighbors of vertex i1 must lie on
(i1, iL); the same is true for vertex iL, since if say i is not a neighbour, i i1 i2 ...iiL would be the
longest path contradicting our selection of the longest path.
The same for iL also.
So both i1 and iL are adjacent to vertices in the longest path L only,
Since degree of i1>k/2 and i1 is not adjacent to itself, k> n/2 +1
Let us assume a claim
There is some value of j (1jk) such that:
Incase claim is not true,
Since all vertices adjacent to L1 or Lk lie on L, there must be at least deg(L1) vertices on P not
adjacent to Lk.
Since all the vertices adjacent to Lk and pk itself also lie on P, the path must have at least
deg(L1)+deg(Lk)+1n+1 vertices.
But L has only n vertices: a contradiction.
This gives a cycle C=Lj+1Lj+2…LkLjLj1…L2L1Lj+1.
Suppose LC is nonempty.
Then since L is connected, there must be a vertex vGC adjacent to some Li.
So the path from v to Li and then around C to the vertex adjacent to Li is longer than L,
contradicting the definition of L.
Hence our assumption/claim is true.
Therefore all vertices in L are contained in C, making C a Hamilton cycle..
Construction Supervisor ResponsibilitiesCompletes construction pr.pdf
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:
Solution
Construction Supervisor Responsibilities:
Completes construction projects by planning, organizing, and controlling projects; completing
quality inspections; supervising sub-contractors and staff.
Construction Supervisor Duties:.
Border Gateway Protocol (BGP) is the protocol whi.pdf
Border Gateway Protocol (BGP) is the protocol which is used to make core routing
decisions on the Internet; it involves a table of IP networks or \"prefixes\" which designate
network reach-ability among autonomous systems (AS). BGP is a path vector protocol, or a
variant of a Distance-vector routing protocol. BGP does not involve traditional Interior Gateway
Protocol (IGP) metrics, but routing decisions are made based on path, network policies, and/or
rule-sets. For this reason, it is more appropriately termed a reach-ability protocol rather than
routing protocol. BGP was created to replace the Exterior Gateway Protocol (EGP) to allow fully
decentralized routing in order to transition from the core ARPAnet model to a decentralized
system that included the NSFNET backbone and its associated regional networks. This allowed
the Internet to become a truly decentralized system. Since 1994, version four of the BGP has
been in use on the Internet. All previous versions are now obsolete. The major enhancement in
version 4 was support of Classless Inter-Domain Routing and use of route aggregation to
decrease the size of routing tables. Since January 2006, version 4 is codified in RFC 4271, which
went through more than 20 drafts based on the earlier RFC 1771 version 4. RFC 4271 version
corrected a number of errors, clarified ambiguities and brought the RFC much closer to industry
practices. Most Internet service providers must use BGP to establish routing between one another
(especially if they are multihomed). Therefore, even though most Internet users do not use it
directly, BGP is one of the most important protocols of the Internet. Compare this with Signaling
System 7 (SS7), which is the inter-provider core call setup protocol on the PSTN. Very large
private IP networks use BGP internally. An example would be the joining of a number of large
OSPF (Open Shortest Path First) networks where OSPF by itself would not scale to size. Another
reason to use BGP is multihoming a network for better redundancy, either to multiple access
points of a single ISP (RFC 1998), or to multiple ISPs.
Solution
Border Gateway Protocol (BGP) is the protocol which is used to make core routing
decisions on the Internet; it involves a table of IP networks or \"prefixes\" which designate
network reach-ability among autonomous systems (AS). BGP is a path vector protocol, or a
variant of a Distance-vector routing protocol. BGP does not involve traditional Interior Gateway
Protocol (IGP) metrics, but routing decisions are made based on path, network policies, and/or
rule-sets. For this reason, it is more appropriately termed a reach-ability protocol rather than
routing protocol. BGP was created to replace the Exterior Gateway Protocol (EGP) to allow fully
decentralized routing in order to transition from the core ARPAnet model to a decentralized
system that included the NSFNET backbone and its associated regional networks. This allowed
the Internet to become a truly decentralize.
Answer-The hierarchical aspect of the Ip addressesnetwork -host .pdf
Answer:-
The hierarchical aspect of the Ip addresses:network -host parts of the address.This allows routers
to \'route\' network address only.
IP addresses include the network/subnet, so that interfaces on differentnetworks must have
different network portions of the address.Alternatively ,addresses include location information
and different interfaces are at different locations , topologically.
All host attached to the same network have the same network part of their IP address.The host
part identifies that host uniquely on the network
point-to-point interfaces can be assigned a duplicate address because the other endpoint of the
lint doesnt use the address to reach the interface ;it just sends .Such interfaces ,however ,cannot
be addressed by any other host in the network.
Solution
Answer:-
The hierarchical aspect of the Ip addresses:network -host parts of the address.This allows routers
to \'route\' network address only.
IP addresses include the network/subnet, so that interfaces on differentnetworks must have
different network portions of the address.Alternatively ,addresses include location information
and different interfaces are at different locations , topologically.
All host attached to the same network have the same network part of their IP address.The host
part identifies that host uniquely on the network
point-to-point interfaces can be assigned a duplicate address because the other endpoint of the
lint doesnt use the address to reach the interface ;it just sends .Such interfaces ,however ,cannot
be addressed by any other host in the network..
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes a.pdf
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes aegypti mosquito, culicinae,
Psorophora, Mansonia and Yellow fever mosquito are some of the disease spreading species
found in Florida and reported that currently 80 species of mosquitoes occurs in Florida and 33
species is capable of causing pest problems and 13 species transmits the pathogens.
Most effective control measures for mosquitoes, is to drain all sources of stagnating water, so
that they cannot breed and try to drain out the garbage cans, pool covers, house gutters, toys
flower pots etc and try to dispose the old tires, drums etc and change bird baths frequently and
keep the house with screens closed all the time, no broken screens. Ask people and children to
wear long pants, long sleeves etc and wear socks and shoes. Apply mosquito repellent to bare
skin and use repellents with DEET, neem oil, lemon eucalyptus oil, picaridins and IR3535.
Ponds and lakes will have stagnant water and will have steep slope and shallow, so mosquito
breeding will be high here, circulate the water by artificial fountains and spray mosquito-killing
chemicals like Malathion (adulticide-kills adult mosquitoes) and Scourge (kills mosquitoes).
How much every possible keep the swamp sites dry and in agricultural land, after crop
harvesting, drain out the water completely and use the pesticides in such a way it can also kill the
mosquitoes.
Solution
Aedes albopictus, Psorophora ciliate, floodwater mosquitoes, Aedes aegypti mosquito, culicinae,
Psorophora, Mansonia and Yellow fever mosquito are some of the disease spreading species
found in Florida and reported that currently 80 species of mosquitoes occurs in Florida and 33
species is capable of causing pest problems and 13 species transmits the pathogens.
Most effective control measures for mosquitoes, is to drain all sources of stagnating water, so
that they cannot breed and try to drain out the garbage cans, pool covers, house gutters, toys
flower pots etc and try to dispose the old tires, drums etc and change bird baths frequently and
keep the house with screens closed all the time, no broken screens. Ask people and children to
wear long pants, long sleeves etc and wear socks and shoes. Apply mosquito repellent to bare
skin and use repellents with DEET, neem oil, lemon eucalyptus oil, picaridins and IR3535.
Ponds and lakes will have stagnant water and will have steep slope and shallow, so mosquito
breeding will be high here, circulate the water by artificial fountains and spray mosquito-killing
chemicals like Malathion (adulticide-kills adult mosquitoes) and Scourge (kills mosquitoes).
How much every possible keep the swamp sites dry and in agricultural land, after crop
harvesting, drain out the water completely and use the pesticides in such a way it can also kill the
mosquitoes..
Ans.)C) Lower right-hand corner (Ruderal)In climates where streams.pdf
Ans.)C) Lower right-hand corner (Ruderal)
In climates where streams are subject to recurrent flash floods that rub the stream bed, removing
nearly all of the vegetation. Few plants grow in well-lit stream channels. And these are ruderal.
Ruderal plants have the ability to grow and colonize in disturbed lands.
Solution
Ans.)C) Lower right-hand corner (Ruderal)
In climates where streams are subject to recurrent flash floods that rub the stream bed, removing
nearly all of the vegetation. Few plants grow in well-lit stream channels. And these are ruderal.
Ruderal plants have the ability to grow and colonize in disturbed lands..
All chordates possess the same four structures in the early embryo. .pdf
All chordates possess the same four structures in the early embryo. What are they?
Characteristics OF CHORDATES
Four unmistakable determined attributes of chordates recognize them from their precursors:
A. Notochord, or a bar of vacuolated cells, encased by a firm sheath that falsehoods ventral to the
neural tube in vertebrate fetuses and a few grown-ups.
B. Empty nerve rope that falsehoods dorsal to the notochord
C. Pharyngeal pockets
D. Endostyle - extended section in the pharynx floor of protochordates that may create as the
thyroid organ in chordates
In the subphylum Vertebrata, all individuals have the four chordate qualities eventually being
developed, however frequently these structures are adjusted fundamentally in grown-up
creatures.
These four attributes might be found in a portion of the predecessors of chordates and are
normally put in a casual gathering called Protochordates. These serve as living representations of
the missing fossils in vertebrate advancement.
What are the differences between deuterostome, and chordate, and amniote? Provide examples
from lab of each of these. Can animal fall in to more than one of these categories? Which
categories do human fall into?
deuterostome,
chordate
amniote
The name deuterostome signifies \"mouth second\", and alludes to one vital formative element
exceptional to this gathering.
Deuterostomes are any individuals from a superphylum of creatures. It is a sister clade of
Protostomia, with which it shapes the Nephrozoa clade.
Deuterostomia is a subtaxon of the Bilateria branch of the subkingdom Eumetazoa, inside
Animalia, and are recognized from protostomes by their embryonic improvement; in
deuterostomes, the principal opening (the blastopore) turns into the butt, while in protostomes, it
turns into the mouth.
Most deuterostomes show uncertain cleavage, in which the formative destiny of the cells in the
creating fetus are not controlled by the personality of the parent cell. In this manner, if the initial
four cells are isolated, every cell is equipped for shaping an entire little hatchling; and if a cell is
expelled from the blastula, alternate cells will adjust.
In deuterostomes the mesoderm frames as evaginations of the created gut that squeeze off,
shaping the coelom. This is called enterocoely.
lancelets, four-limbed vertebrates - well evolved creatures, reptiles, creatures of land and water,
and birds,sea stars and weak stars)
Chordates are creatures having a notochord, an empty dorsal nerve string, pharyngeal openings,
an endostyle, and a post-butt-centric tail for at any rate some time of their life cycles. The
Chordata, together with sister clade Ambulacraria, shape the deuterostomes as in the incipient
organism improvement organize the rear-end frames before the mouth.
Systematically, the phylum incorporates the subphyla Vertebrata, which incorporates angle,
creatures of land and water, reptiles, winged animals, and warm blooded creatures; Tunicata,
which incorporates salps and o.
a) False (because it is not always the case).Many electronegative .pdf
a) False (because it is not always the case).
Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as
HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid
mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate.
For example, HF is less acidic than HBr (even though Fis more electronegative than Br)
b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off
easily.
c) True. (F is more electronegative and has a smaller diameter soweaker acid)
d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid.
e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds
the O-H bond.
f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through
inductive effects.
Solution
a) False (because it is not always the case).
Many electronegative anions are more stable by themselves andwon\'t form strong acids (such as
HF). However some larger anions,like Cl-, form stronger acids such as HCl. A strong acid
mustbe able to give off the hydrogen easily so if A is veryelectronegative, it wont dissociate.
For example, HF is less acidic than HBr (even though Fis more electronegative than Br)
b) False. Weak H-A bonds create strong acids. Strong acids haveprotons that can break off
easily.
c) True. (F is more electronegative and has a smaller diameter soweaker acid)
d) True. Chloric acid is a strong acid, and hypochlorous acid is aweak acid.
e) False. The H+ dissociates more easily from the BrO- because adense electron cloud surrounds
the O-H bond.
f) False. More electronegative substitutions on carboxylic acidsincrease the acidity through
inductive effects..
1.The Open Systems Interconnect (OSI) model has seven layers.The mod.pdf
1.The Open Systems Interconnect (OSI) model has seven layers.The model partitions a
communication system into abstraction layers. The original version of the model defined seven
layers.OSI means Open Systems Interconnectionis reference model for how applications can
communicate over a network This article describes and explains them, beginning with the lowest
in the hierarchy the physical and proceeding to the highest the application. The layers are stay in
this way:
Application
Presentation
Session
Transport
Network
Data Link
Physical
features osi model:
If network communications need to happen with out any trouble, many problems must be
solved. Coordinating all these problems are so complex and not easy to manage.
Big picture of communication over network is understandable through this OSI model.
We can understand new technologies as they are developed.
Troubleshooting is easier by separate network.
2.
the Data process that takes placethe message from one host to another cab be done as such:
The data to be passed from one host to another can be composed at the first top layer of the
passing device layer N into a protocol data unit.
The protocal data unit is passed to next layer, where it is known as the service data unit.
At next layer let us consider that layer be N-1 the service data unit is observed the with a
header,a footer,some times both,producing a layer next protocal data unit. It is then passed to
layer next layer N-2.
The process repeated until reaching the lower level,from which the data is transmitted to the
receiving device.
At the receiving device the data is passed from the lowest to the highest layer as a series of
SDUs while being successively stripped from each layer\'s header and/or footer, until reaching
the topmost layer, where the last of the data is consumed.
3.
ISO
1.OSI is a generic, protocol independent standard, acting as a communication gateway between
the network and end user.
2.OSI is a conceptual model that characterizes and standardizes the communication functions of
a computing or telecommunication system irrespective of their underlying structure and
technology being used.
3.OSI is a reference model.
4.The OSI model consists of 7 architectural layers
TCp/IP
1. TCP/IP model is based on standard protocols around which the Internet has developed. It is a
communication protocol, which allows connection of hosts over a network.
2.TCP/IP is a core protocol of the Internet Protocol Suite (IPS). It is the basic communication
language or protocol of the internet. It can be used as a communications protocol in a private
network either an intranet or an extranet
3.TCP/IP is an implementation of OSI model.
4.The tcp/ip can contains only 4 laters
4.1.network inerface layer:The most widely-known Application layer protocols are those used
for the exchange of user information.
2.internet layer:The Internet layer is responsible for addressing, packaging, and routing
functions. The core protocols of the Internet layer are I.
(1) ACQUISITION EXPENSES Acquirers may incur millions in direct an.pdf
(1) ACQUISITION EXPENSES
Acquirers may incur millions in direct and indirect costs finding targets, gathering and analyzing
information, seeking funds and negotiating deals. The question is how to report these costs.
Current GAAP . These costs are deferred by adding them to the purchase price. In all likelihood,
they increase recorded goodwill, where they remain until and unless impairment is recognized.
Deficiency . Although pre-transaction costs are necessary, they don’t add value to acquired
assets (including goodwill) and they are not assets on their own. It’s questionable whether
putting them on a balance sheet is useful.
New standard . Statement no. 141(R) follows the tenet that only real assets should be recorded
for a combination. Because acquisition-related costs are not assets, they will be charged to
expense. Exhibit 1 shows them being moved off the statement of financial position and onto the
income statement
(2) BARGAIN PURCHASE GAIN
In rare circumstances, an acquirer strikes a favorable deal and pays less than the aggregate fair
value of purchased net assets. These transactions raise two issues—at what amounts should
individual assets and liabilities be recorded, and is it useful to recognize a bargain purchase gain?
Current GAAP. The excess value is considered “negative goodwill.” Because of its focus on
cost, current practice selectively reduces certain asset carrying values until the aggregate total
equals the purchase price. (In very rare circumstances, any unallocated difference is treated as an
extraordinary gain.)
Deficiency. The balance sheet underreports the value at hand and available to management for
earning returns. In addition, management’s successful negotiation is not immediately reflected in
reported income.
New standard. Acquired assets and liabilities will be recorded at fair value and any excess over
the purchase price will be credited to a gain that flows to the income statement, net of deferred
taxes. The outcome will likely be more complete and useful statements of financial position and
income.
(3) CONTINGENT CONSIDERATION
In major transactions such as combinations, sizable spreads initially exist between amounts
buyers and sellers offer to pay and accept. One way to close that gap is contingent consideration
arrangements in which, depending on future events, a buyer agrees to pay an additional amount
or a seller agrees to refund part of the purchase price. Because contingencies can be difficult to
pin down, many issues have been raised about their financial statement effects.
Current GAAP. Most contingent consideration arrangements are ignored in determining the
recorded price. When additional payments based on earnings targets occur, their amounts are
added to goodwill. If payments are tied to stock price changes, paid-in capital is credited. If
refunds are received, the buyer reduces goodwill or paid-in capital.
Deficiency. In these circumstances, not immediately recognizing the contingent assets or
li.
#include iostream #include cstring #include vector #i.pdf
#include
#include
#include
#include
#include \"textFile.hpp\"
using namespace std;
void displayHelp();
bool isInteger(const string &s);
bool askSave();
int main(int argc, const char * argv[]) {
int resultCode = 0;
// Convert to a vector.
vector args(argv, argv + argc);
// Process arguments, must be 1 argument, otherwise exit with code 1.
if (args.size() < 2) {
cout << \"Missing command line argument!\" << endl;
cout << \"Usage: ./myEditor \" << endl;
resultCode = 1;
} else {
string fileName = args[1];
textFile dataFile(fileName);
// Check if the file is ok to use, if it is, lets go.
if (!dataFile.checkFile()) {
resultCode = 2;
} else {
// We can now assume the file is good, so we can work with it.
dataFile.loadFile();
// Display some text to help the user.
displayHelp();
// Now get user input.
bool done = false;
string userInput = \"\";
while (!done) {
cout << \"> \";
getline(cin, userInput);
char cmd = tolower(userInput.c_str()[0]);
char cmd2 = \' \';
if (userInput.size() > 1) {
cmd2 = userInput.c_str()[1];
}
// This check makes sure the command format is correct
// so that commands don\'t fire off by mistake.
if (strncmp(&cmd, \" \", 1) != 0 && strncmp(&cmd2, \" \", 1) == 0) {
switch(cmd) {
case \'q\': {
done = true;
break;
}
case \'i\': {
unsigned long lineIndex = dataFile.textLines() + 1;
string newLine;
if (userInput.size() > 1) {
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
}
cout << to_string(lineIndex) << \"> \";
getline(cin, newLine);
dataFile.insertLine(lineIndex - 1, newLine);
break;
}
case \'d\': {
if (userInput.size() > 1) {
unsigned long lineIndex;
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
dataFile.removeLine(lineIndex - 1);
}
break;
}
case \'l\': {
for (int x = 0; x < dataFile.textLines(); x++) {
cout << to_string(x + 1) << \"> \" << dataFile.getLine(x) << endl;
}
break;
}
case \'h\': {
displayHelp();
break;
}
case \'s\': {
dataFile.saveFile();
break;
}
}
}
}
// Ask about saving the file before exiting.
bool save = askSave();
if (save) {
dataFile.saveFile();
}
cout << \"Thank you for using myEditor.\" << endl;
}
}
return resultCode;
}
/*
Asks the user if they\'d like to save or not, returns true if they do. Anything
other than \"y\" or \"Y\" will be interpreted as a negative answer.
*/
bool askSave()
{
bool result = false;
string userInput = \"\";
cout << \"Do you wan to save the change? (Y - yes; N - no) \";
getline(cin, userInput);
userInput = tolower(*userInput.c_str());
if (strncmp(userInput.c_str(), \"y\", 1) == 0) {
result = true;
}
return result;
}
/*
Displays help text.
*/
void displayHelp()
{
cout << \"Welcome to my text editor.\" << endl;
cout << \"\\tTo insert text at the end of the file, type \'I\'\" << endl;
cout << \"followed by the text.\" << endl;
cout << \"\\tTo insert text at a certain line number, type \'I\'\" << endl;
cout << \"followed by a space and the desired line number.\" << endl;
cout << \"\\tTo delete a line, type \'D\' followed by a space and the\" << endl;
cou.
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