1. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
Specific Heat
2. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
𝑪
Cv
constant Volume
Cp
constant Pressure
Cv = Cp=C
solids & liquids
𝑸 − 𝑾 = 𝑬𝟐 − 𝑬𝟏
الحرارية للديناميكا األول القانون
H , U, C
3. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
𝑸 − 𝑾 = ( dU ) 𝑸 − 𝑾 = ( dU )
احلجم ثبوت الضغط ثبوت
𝒌𝑱
𝑲𝒈 ∗𝑲
𝒅𝒒
𝒅𝑻
( C )
Q = 𝒎 ∗ 𝑪 ∗ ΔT
𝒒 = ( du )
𝑪𝒗 ∗ dT = du
C𝒗=
𝒅𝒖
𝒅𝑻
𝒒 - PdV = ( du )
𝒒 = du + PdV
dh
𝒒 = dh = CpdT
C𝒑=
𝒅𝒉
𝒅𝑻
4. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
A 50 kg iron block at 80°Cis dropped into an insulated tank that contains 0.5 m3 of liquid water at 25°C.
Determine the temperature when thermal equilibrium is reached.
Specific heat iron: 0.45 kJ/kgK, specific heat of water: 4.184 kJ/kgK
Solution
𝟎 = (𝑼𝟐 − 𝑼𝟏)
𝑻𝟐 = 25.6 °C
ΔU= (𝑼𝒊𝒓𝒐𝒏 + 𝑼𝒘𝒂𝒕𝒆𝒓) = 0
ΔU System
𝒎𝒊𝒓𝒐𝒏 * 𝑪𝒊𝒓𝒐𝒏 *ΔT + 𝒎𝒘𝒂𝒕𝒆𝒓 * 𝑪𝒘𝒂𝒕𝒆𝒓 *ΔT =0
𝑻𝟐 − 𝑻𝒊𝒓𝒐𝒏 𝑻𝟐 − 𝑻𝒘𝒂𝒕𝒆𝒓
𝒎𝒘𝒂𝒕𝒆𝒓= 500 Kg ( density*volume)