4. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
is the ratio of the mass of vapor to
the total mass of the mixture
Between 0 and1.
π£=π£π+π₯(π£πβπ£π)=π£π+π₯π£ππ
β=βπ+π₯(βπββπ)=βπ+π₯βππ
π’=π’π+π₯(π’πβπ’π)=π’π+π₯π’ππ
π =π π+π₯π (πβπ π)=π π+π₯π ππ
π₯=
(π£βπ£π)
(π£πβπ£π)
=
(π£βπ£π)
π£ππ
10. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
11. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
12. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
13. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
14. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
ππππ£ππ>ππ ππ‘@ππππ£ππ or ππππ£ππ<ππ ππ‘@ππππ£ππ Superheated Steam
15. Ahmed Medhat - Thermodynamics 1 - ahmedhatfa@hotmail.com
An80-Lvessel contains 4 kg of water at a pressure of 175kPa.
Determine
(a)The saturation temperature,(b)the quality,(c)the enthalpy of the water,
and(d)the volume occupied by the vapor phase.
Solution
At 175kPa
βΈͺππ=π.ππππππ ππ/ππ , ππ=π.ππππ ππ/ππ
π=π½/π=π.ππ/π=π.ππ π3π
water is in the saturated mixture region.
ππ ππ‘@0.175πππ=116.06β a
π₯=
(π£βπ£π)
(π£πβπ£π)
=
(π£βπ£π)
π£ππ =
0.02β0.001057
1.0036β0.001057
=0.0189 b
GET
hf=486.97kJ/kg , hfg=2213.6kJ/kg.
β=βπ+π₯(βπββπ)=βπ+π₯βππ=486.97+0.0189Γ2213.6=528.8ππ½/ππ C
ππ=ππ*π£π ππ=π₯*ππ‘=0.0189Γ4=0.0756ππ
ππ=0.0756Γ1.0036=0.07587π3 D
