1.5: Measuring Segments and AnglesPrentice Hall Geometry
CEABD0-88-2-4-1246-6The numerical location of a point on a number line.Coordinate :On a number line length AB = AB =  |B - A|Length :On a number line, midpoint of AB = 1/2 (B+A) Midpoint :
Find which two of the segments XY, ZY, and ZW are congruent. Because XY = ZW,  XYZW.Measuring Segments and AnglesGEOMETRY  LESSON 1-4Find the length of each segment.XY = | –5 – (–1)| = | –4| = 4ZY = | 2 – (–1)| = |3| = 3ZW = | 2 – 6| = |–4| = 4
The Segment Addition PostulateIf three points A, B, and C are collinear and B is between A and C, then AB + BC = AC.ABC
AN = 2x – 6 = 2(8) – 6 = 10NB = x + 7 = (8) + 7 = 15Substitute 8 for x.If AB = 25, find the value of x. Then find AN and NB.Use the Segment Addition Postulate to write an equation.AN + NB = ABSegment Addition Postulate(2x – 6) + (x + 7) = 25	  Substitute.3x + 1 = 25	Simplify the left side.      3x = 24	Subtract 1 from each side.x = 8	Divide each side by 3.AN = 10 and NB = 15, which checks because the sum of the segment lengths equals 25.
RM = 5x + 9 = 5(15) + 9 = 84	MT = 8x – 36 = 8(15) – 36 = 84Substitute 15 for x.RM and MT are each 84, which is half of 168, the length of RT.Mis the midpoint of RT. Find RM, MT, and RT.Use the definition of midpoint to write an equation.RM = MTDefinition of midpoint5x + 9 = 8x – 36Substitute.5x + 45 = 8xAdd 36 to each side.      45 = 3xSubtract 5x from each side.        15 = xDivide each side by 3.RT = RM + MT= 168
Homework: P. 33 (2-14EVENS, 29-37, 39-43, 45-52 WRITE OUT SENTENCESQuiz tomorrow!!

1.5 measuring segments

  • 1.
    1.5: Measuring Segmentsand AnglesPrentice Hall Geometry
  • 2.
    CEABD0-88-2-4-1246-6The numerical locationof a point on a number line.Coordinate :On a number line length AB = AB = |B - A|Length :On a number line, midpoint of AB = 1/2 (B+A) Midpoint :
  • 3.
    Find which twoof the segments XY, ZY, and ZW are congruent. Because XY = ZW, XYZW.Measuring Segments and AnglesGEOMETRY LESSON 1-4Find the length of each segment.XY = | –5 – (–1)| = | –4| = 4ZY = | 2 – (–1)| = |3| = 3ZW = | 2 – 6| = |–4| = 4
  • 4.
    The Segment AdditionPostulateIf three points A, B, and C are collinear and B is between A and C, then AB + BC = AC.ABC
  • 5.
    AN = 2x– 6 = 2(8) – 6 = 10NB = x + 7 = (8) + 7 = 15Substitute 8 for x.If AB = 25, find the value of x. Then find AN and NB.Use the Segment Addition Postulate to write an equation.AN + NB = ABSegment Addition Postulate(2x – 6) + (x + 7) = 25 Substitute.3x + 1 = 25 Simplify the left side. 3x = 24 Subtract 1 from each side.x = 8 Divide each side by 3.AN = 10 and NB = 15, which checks because the sum of the segment lengths equals 25.
  • 6.
    RM = 5x+ 9 = 5(15) + 9 = 84 MT = 8x – 36 = 8(15) – 36 = 84Substitute 15 for x.RM and MT are each 84, which is half of 168, the length of RT.Mis the midpoint of RT. Find RM, MT, and RT.Use the definition of midpoint to write an equation.RM = MTDefinition of midpoint5x + 9 = 8x – 36Substitute.5x + 45 = 8xAdd 36 to each side. 45 = 3xSubtract 5x from each side. 15 = xDivide each side by 3.RT = RM + MT= 168
  • 7.
    Homework: P. 33(2-14EVENS, 29-37, 39-43, 45-52 WRITE OUT SENTENCESQuiz tomorrow!!