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Mark Scheme (Results)

November 2011



Modular Mathematics (GCSE)
Unit 2: 5MB2F_01 (Foundation)
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November 2011
Publications Code UG029766
All the material in this publication is copyright
© Pearson Education Ltd 2011
NOTES ON MARKING PRINCIPLES

1   All candidates must receive the same treatment. Examiners must mark the first candidate in exactly the same way as they mark
    the last.

2   Mark schemes should be applied positively. Candidates must be rewarded for what they have shown they can do rather than
    penalised for omissions.

3   All the marks on the mark scheme are designed to be awarded. Examiners should always award full marks if deserved, i.e if the
    answer matches the mark scheme. Examiners should also be prepared to award zero marks if the candidate’s response is not
    worthy of credit according to the mark scheme.

4   Where some judgement is required, mark schemes will provide the principles by which marks will be awarded and exemplification
    may be limited.

5   Crossed out work should be marked UNLESS the candidate has replaced it with an alternative response.

6   Mark schemes will indicate within the table where, and which strands of QWC, are being assessed. The strands are as follows:

    i) ensure that text is legible and that spelling, punctuation and grammar are accurate so that meaning is clear
           Comprehension and meaning is clear by using correct notation and labeling conventions.

    ii) select and use a form and style of writing appropriate to purpose and to complex subject matter
             Reasoning, explanation or argument is correct and appropriately structured to convey mathematical reasoning.

    iii) organise information clearly and coherently, using specialist vocabulary when appropriate.
             The mathematical methods and processes used are coherently and clearly organised and the appropriate mathematical
             vocabulary used.
7    With working
     If there is a wrong answer indicated on the answer line always check the working in the body of the script (and on any diagrams),
     and award any marks appropriate from the mark scheme.
     If working is crossed out and still legible, then it should be given any appropriate marks, as long as it has not been replaced by
     alternative work.
     If it is clear from the working that the “correct” answer has been obtained from incorrect working, award 0 marks. Send the
     response to review, and discuss each of these situations with your Team Leader.
     If there is no answer on the answer line then check the working for an obvious answer.
     Any case of suspected misread loses A (and B) marks on that part, but can gain the M marks. Discuss each of these situations
     with your Team Leader.
     If there is a choice of methods shown, then no marks should be awarded, unless the answer on the answer line makes clear the
     method that has been used.

8    Follow through marks
     Follow through marks which involve a single stage calculation can be awarded without working since you can check the answer
     yourself, but if ambiguous do not award.
     Follow through marks which involve more than one stage of calculation can only be awarded on sight of the relevant working,
     even if it appears obvious that there is only one way you could get the answer given.

9    Ignoring subsequent work
     It is appropriate to ignore subsequent work when the additional work does not change the answer in a way that is inappropriate
     for the question: e.g. incorrect canceling of a fraction that would otherwise be correct
     It is not appropriate to ignore subsequent work when the additional work essentially makes the answer incorrect e.g. algebra.
     Transcription errors occur when candidates present a correct answer in working, and write it incorrectly on the answer line; mark
     the correct answer.

10   Probability
     Probability answers must be given a fractions, percentages or decimals. If a candidate gives a decimal equivalent to a probability,
     this should be written to at least 2 decimal places (unless tenths).
     Incorrect notation should lose the accuracy marks, but be awarded any implied method marks.
     If a probability answer is given on the answer line using both incorrect and correct notation, award the marks.
     If a probability fraction is given then cancelled incorrectly, ignore the incorrectly cancelled answer.
11   Linear equations
     Full marks can be gained if the solution alone is given on the answer line, or otherwise unambiguously indicated in working
     (without contradiction elsewhere). Where the correct solution only is shown substituted, but not identified as the solution, the
     accuracy mark is lost but any method marks can be awarded.

12   Parts of questions
     Unless allowed by the mark scheme, the marks allocated to one part of the question CANNOT be awarded in another.

13   Range of answers
     Unless otherwise stated, when an answer is given as a range (e.g 3.5 – 4.2) then this is inclusive of the end points (e.g 3.5, 4.2)
     and includes all numbers within the range (e.g 4, 4.1)



      Guidance on the use of codes within this mark scheme


      M1 – method mark
      A1 – accuracy mark
      B1 – Working mark
      C1 – communication mark
      QWC – quality of written communication
      oe – or equivalent
      cao – correct answer only
      ft – follow through
      sc – special case
      dep – dependent (on a previous mark or conclusion)
      indep – independent
      isw – ignore subsequent working
5MB2F_01
  Question     Working         Answer             Mark                               Notes
 1      (a)                    rhombus             1     B1 cao


        (b)                                        1     B1 for both lines seen do not accept any extras but accept
                                                         freehand Lines.



 2      (a)                     10 570             1     B1 for 10 570

        (b)                       560              1     B1 cao

        (c)              2.17, 3.95, 5.03, 6.84    1     B1 cao

      (d)(i)                      49               1     B1 cao

        (ii)                       8               1     B1 cao

 3      (a)                       8.6              1     B1 for 8.6 ± 0.2 cm

        (b)                    correct ×           1     B1 for × 5 cm from Q ± 0.2 cm use overlay provided

      (c)(i)                    obtuse             2     B1 ignore spelling

        (ii)                      120                    B1 for 120 ± 2°
5MB2F_01
  Question                 Working                 Answer   Mark                                 Notes
 4              2 × 60 + 3 × 50                     530      4     M1 for 2 × 60 or 3 × 50 or 7 × 45 or 7 × 55 oe
                 = 120 + 150 = 270                                 M1 for ‘2 × 60’ + ‘3 × 50’ + ‘7 × 45’ + ‘7 × 55’ oe
                7 × (45 + 55) = 700                                M1 for 1500 – (‘2 × 60’ + ‘3 × 50’ + ‘7 × 45’ + ‘7 × 55’ ) oe
                1500 – 970                                         A1 cao
                or                                                 or
                2 × 60 + 3 × 50 + 7 × 45 +7 × 55                   M1 for 2 × 60 or 3 × 50 or 45 + 55 oe
                120 + 150 + 315 +385 = 970                         M1 for ‘2 × 60’ + ‘3 × 50’ + ‘(45 + 55)’ × 7
                1500 – 970 =                                       M1 for 1500 – (‘2 × 60’ + ‘3 × 50’ + ‘(45 + 55) × 7)’ oe
                or for doubling travel costs                       A1 cao
                2 × 2 × 60 + 2 × 3 × 50                            Or for doubling travel costs
                 = 240 + 300 = 540                                 M1for 2 × 2 × 60 or 2 × 3 × 50 or 7 × 45 or 7 × 55 oe
                7 × (45 + 55) = 700                                M1for ‘2 × 2 × 60’ + ‘2 × 3 × 50’ + ‘7 × 45’+ ‘7 × 55’ oe
                1500 – 1240 = 260                                  M1for 1500 – (‘2 × 2 × 60’ + ‘2 × 3 × 50’ + ‘7 × 45’ +‘7 × 55’) oe
                                                                   A1 for 260

 5      (a)                                          2             B1 cao
                                                             1
                                                   Monday    2     B1 for Monday oe
       (b)(i)
                                                     7             B1 ft for their (b)(i) accept positive and negative answers for 7
        (ii)
 6      (a)                                         5.6      1     B1 cao

        (b)                                         9.58     1     B1 ft from their weight in part (a) may be shown by selecting
                                                                   correct value in the table

 7      (i)                                          70      2     B1 for 70 look for answer on diagram

        (ii)                                       reason          C1 for angles (on a) straight line (add up to) 180°
5MB2F_01
  Question               Working              Answer        Mark                                 Notes
 *8           28 = (4+1) + (4+1) + (4+1) +   Yes + reason    3     M1 for attempt to account for 1 free
              (4+1) + (4+1) + 3                                          e.g. (4+1) + (4+1) ... with at least 2 seen
              Buy 4 + 4 + 4 + 4 + 4 + 3                                  e.g. 140÷24 = 5 so 5 free eg every £24 get 1 free
              23 × 6 = 138                                               e.g. 23lots of £6 so 5 free
              or                                                   M1 for using £140 in a calculation that could lead to the correct
              140 ÷ 6 (= 23 rem 2)                                 conclusion (need not be explicit) or for a method that leads to a
              23 ÷ 4 = 5 free                                      total cost of 138
              23 + 5 = 28
                                                                   C1 (dep on M1) for ‘Yes’ and reason eg “138” is less than 140
                                                                   oe or “Yes” and “23 with 5 free gives £2” left over oe

                                                                   NB Needs a statement to this effect

 9      (a)     × 240                            36          2     M1 for 15 ÷ 100 or 10% + 5% attempted with correct values of
                                                                   24 and 12 seen or 24 and 12 seen or 0.15 seen
                                                                   A1 cao

        (b)   240 ÷ 3                            80          1     B1 cao

        (c)   80 : 60 = 8 : 6                   4:3          2     M1 for any correct ratio eg 80:60, 40 : 30, 8 : 6 or 4 gap 3
                                                                   seen without ratio sign or 4 dot 3
                                                                   A1 for 4 : 3 or 4 to 3

                                                                   SC B1 for an answer of 3:4 or 3 to 4 if M1 not scored
5MB2F_01
  Question                   Working         Answer         Mark                                Notes
 10     (a)                                     16           1     B1for answer in range 15.5 to 16.5

        (b)                                     2.4          1     B1for answer in range 2.3 to 2.5

       (c)(i)                                 Debbie         1     B1 for Debbie

       (c)(ii)                             Correct reason    1     C1for Debbie in Part (i) with a valid explanation e.g. It is
                                                                   higher or with a correct conversion ± 1 sq
                                                                   or Stefan in part (i) with an incorrect conversion but valid
                                                                   explanation

                                                                   Note:   6 mph     = 9.6 km/h (accept 9-10)
                                                                           10.5 km/h = 6.5625 mph (accept 6.4 – 6.8)

 11     (a)                                      6           2     M1for any valid method e.g. drawing diagrams, counting in 2s
                                                                   which may be on the diagram or table of values
                                                                   A1cao

        (b)      nth term is 2n + 2 so          102          2     M1for 50 + 50 + 2 or any other valid method
                 50th term is 50 × 2 + 2                           A1cao

 12                                           4x + 9y        2     B2for 4x + 9y
                                                                   (B1for 4x or 9y seen)
5MB2F_01
  Question                   Working    Answer        Mark                              Notes
 13     (a)                                17          1     B1 cao

        (b)                            (5+3)×2+1       1     B1 cao

        (c)                                24          1     B1 for 24 or + 24

        (d)   7    1   7     2             9           2     M1 for a suitable common denominator (multiple of 10)
                 +   =    +                                                                        7
              10   5   10   10             10                with one fraction out of two (not       ) correct or 0.7 +
                                                                                                  10
                         1      5                            0.2 or all cells correct if cell method used
                                                                       9
                7              35                            A1 for       oe, accept 0.9
                                                                      10
               10    10        50

*14           96 ÷ 22                      No          3     M1 for 96 ÷ 22 oe
              = 96 ÷ 4                      +                A1 for 24
              = 24                     calculations          C1 dep on M1for “No” with a calculation to support their
                                                             conclusion
                                                             SC B1: for 96 ÷ 2 and a correct conclusion seen

                                                             NB To award the marks in this question working must be
                                                             shown
5MB2F_01
  Question               Working                   Answer    Mark                               Notes
 15     (a)   Missing sides are                    16x + 8    3     M1 for 5x + 1 –3x or 2x + 3 + x or identifying a missing side
              2x + 1 and 3x + 3                                     as 2x + 1 or 3x + 3(maybe on the diagram)
              Perimeter = 5x + 1 + x + 3x + 2x +                    M1 for adding 5 or 6 sides from x, 5x + 1, 3x, 2x + 3, ‘2x + 1’,
              3 +2x + 1 + 3x + 3                                    ‘3x + 3’ where the missing sides are in the form ax ± b (a and
              OR                                                    b ≠ 0)
              2(5x + 1) + 2(2x + 3 + x)                             or 2(5x + 1) + 2(2x + 3 + x) oe

                                                                    A1 for 16x + 8 oe for unsimplified expression

        (b)                                        4x + 2     1     B1 ft for [‘2(5x + 1) + 2(2x + 3 + x)’] ÷ 4 or (”16x + 8”) ÷ 4
                                                                    oe where the answer is an algebraic expression in x
5MB2F_01
  Question               Working               Answer   Mark                             Notes
 16          Big area = 144                      20      4     M1 for 12 × 12 or 8 × 8 or 144 seen or 64 seen as
             Small area = 64                                   area
             Area frame = 144 – 64                             M1 for 12 × 12 − 8 × 8 or ‘144’ − ‘64’ or 80 seen as
                         = 80                                  area
             80 ÷ 4                                            M1 for (12 × 12 − 8 × 8) ÷ 4 or ‘(144 − 64)’ ÷ 4 or ‘80’
             or                                                ÷ 4 seen as area
             Area one piece is a trapezium                     A1 for 20 cao
             ½ (12+8) × (12– 8)÷2                              or
             ½ × 20 × 2 = 20                                   M1 for 12 − 8 or 4 seen as difference in lengths
             or                                                M1 for height of trapezium = (12 − 8) ÷ 2 or ‘4’ ÷ 2 or 2
             Area of rectangle + 2 triangles                   M1 for area trapezium = ½ (12 + 8) × ‘2’ oe
             8 × 2 + 2× ( ½ × 2 × 2)                           A1 for 20 cao
             16 + 4                                            or
             or                                                M1 for ½ × (12 – 8 ) or 2 for width of frame
             Area of rectangle – 2 triangles                   M1 for 8 × 2 = 16 for rectangle
             12×2 – 2× ( ½ × 2 × 2)                            M1 for 2× ( ½ × 2 × 2) or 4 for 2 triangles
             24 – 4                                            A1 for 20 cao
                                                               or
                                                                M1 for ½ × (12 – 8 ) or 2 for width of frame
                                                               M1 for 12 × 2 = 24 for rectangle
                                                               M1 for 2× ( ½ × 2 × 2) or 4 for 2 triangles
                                                               A1 for 20 cao

                                                               NB marks can be awarded for correct measurements indicated
                                                               on the diagram
                                                               Note:-If 80 seen on the answer line following a correct
                                                               calculation of one piece of card, full marks can be earned
5MB2F_01
  Question               Working                 Answer   Mark                               Notes
*17
             Angle ACB = 35°                      135      4     M1 for angle ACB = (180 – 110) ÷ 2 or 35 seen
             (base angles of an isosceles                        M1 for angle CAE = angle ACB or “35”
             triangle are equal)                                     (this could be marked on diagram)
             (angles in a triangle add up to                     A1 x = 135 cao
             180)                                                C1 (dep on M1) for alternate angles are equal or allied angles
             Angle CAE = 35°                                     (co-interior angles) are supplementary (add to 180º)
             (alternate angles are equal)                             AND any one of
             x = 360 – (100 + 90 + 35)                               • (base) or 2 angles of an isosceles triangle are equal oe
                = 135                                                • angles in a triangle (add up to) 180
             (angles in a quadrilateral add up                       • angles in a quadrilateral (add up to) 360°
             to 360°)                                                • angles in a pentagon (add up to)540º
Further copies of this publication are available from
Edexcel Publications, Adamsway, Mansfield, Notts, NG18 4FN


Telephone 01623 467467
Fax 01623 450481
Email publication.orders@edexcel.com
Order Code UG029766 November 2011



For more information on Edexcel qualifications, please visit
www.edexcel.com/quals



Pearson Education Limited. Registered company number 872828
with its registered office at Edinburgh Gate, Harlow, Essex CM20 2JE

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04a 5 mb2f_unit_2_november_2011_mark_scheme

  • 1. Mark Scheme (Results) November 2011 Modular Mathematics (GCSE) Unit 2: 5MB2F_01 (Foundation)
  • 2. Edexcel is one of the leading examining and awarding bodies in the UK and throughout the world. We provide a wide range of qualifications including academic, vocational, occupational and specific programmes for employers. Through a network of UK and overseas offices, Edexcel’s centres receive the support they need to help them deliver their education and training programmes to learners. For further information, please call our GCE line on 0844 576 0025, our GCSE team on 0844 576 0027, or visit our website at www.edexcel.com. If you have any subject specific questions about the content of this Mark Scheme that require the help of a subject specialist, you may find our Ask The Expert email service helpful. Ask The Expert can be accessed online at the following link: http://www.edexcel.com/Aboutus/contact-us/ November 2011 Publications Code UG029766 All the material in this publication is copyright © Pearson Education Ltd 2011
  • 3. NOTES ON MARKING PRINCIPLES 1 All candidates must receive the same treatment. Examiners must mark the first candidate in exactly the same way as they mark the last. 2 Mark schemes should be applied positively. Candidates must be rewarded for what they have shown they can do rather than penalised for omissions. 3 All the marks on the mark scheme are designed to be awarded. Examiners should always award full marks if deserved, i.e if the answer matches the mark scheme. Examiners should also be prepared to award zero marks if the candidate’s response is not worthy of credit according to the mark scheme. 4 Where some judgement is required, mark schemes will provide the principles by which marks will be awarded and exemplification may be limited. 5 Crossed out work should be marked UNLESS the candidate has replaced it with an alternative response. 6 Mark schemes will indicate within the table where, and which strands of QWC, are being assessed. The strands are as follows: i) ensure that text is legible and that spelling, punctuation and grammar are accurate so that meaning is clear Comprehension and meaning is clear by using correct notation and labeling conventions. ii) select and use a form and style of writing appropriate to purpose and to complex subject matter Reasoning, explanation or argument is correct and appropriately structured to convey mathematical reasoning. iii) organise information clearly and coherently, using specialist vocabulary when appropriate. The mathematical methods and processes used are coherently and clearly organised and the appropriate mathematical vocabulary used.
  • 4. 7 With working If there is a wrong answer indicated on the answer line always check the working in the body of the script (and on any diagrams), and award any marks appropriate from the mark scheme. If working is crossed out and still legible, then it should be given any appropriate marks, as long as it has not been replaced by alternative work. If it is clear from the working that the “correct” answer has been obtained from incorrect working, award 0 marks. Send the response to review, and discuss each of these situations with your Team Leader. If there is no answer on the answer line then check the working for an obvious answer. Any case of suspected misread loses A (and B) marks on that part, but can gain the M marks. Discuss each of these situations with your Team Leader. If there is a choice of methods shown, then no marks should be awarded, unless the answer on the answer line makes clear the method that has been used. 8 Follow through marks Follow through marks which involve a single stage calculation can be awarded without working since you can check the answer yourself, but if ambiguous do not award. Follow through marks which involve more than one stage of calculation can only be awarded on sight of the relevant working, even if it appears obvious that there is only one way you could get the answer given. 9 Ignoring subsequent work It is appropriate to ignore subsequent work when the additional work does not change the answer in a way that is inappropriate for the question: e.g. incorrect canceling of a fraction that would otherwise be correct It is not appropriate to ignore subsequent work when the additional work essentially makes the answer incorrect e.g. algebra. Transcription errors occur when candidates present a correct answer in working, and write it incorrectly on the answer line; mark the correct answer. 10 Probability Probability answers must be given a fractions, percentages or decimals. If a candidate gives a decimal equivalent to a probability, this should be written to at least 2 decimal places (unless tenths). Incorrect notation should lose the accuracy marks, but be awarded any implied method marks. If a probability answer is given on the answer line using both incorrect and correct notation, award the marks. If a probability fraction is given then cancelled incorrectly, ignore the incorrectly cancelled answer.
  • 5. 11 Linear equations Full marks can be gained if the solution alone is given on the answer line, or otherwise unambiguously indicated in working (without contradiction elsewhere). Where the correct solution only is shown substituted, but not identified as the solution, the accuracy mark is lost but any method marks can be awarded. 12 Parts of questions Unless allowed by the mark scheme, the marks allocated to one part of the question CANNOT be awarded in another. 13 Range of answers Unless otherwise stated, when an answer is given as a range (e.g 3.5 – 4.2) then this is inclusive of the end points (e.g 3.5, 4.2) and includes all numbers within the range (e.g 4, 4.1) Guidance on the use of codes within this mark scheme M1 – method mark A1 – accuracy mark B1 – Working mark C1 – communication mark QWC – quality of written communication oe – or equivalent cao – correct answer only ft – follow through sc – special case dep – dependent (on a previous mark or conclusion) indep – independent isw – ignore subsequent working
  • 6.
  • 7. 5MB2F_01 Question Working Answer Mark Notes 1 (a) rhombus 1 B1 cao (b) 1 B1 for both lines seen do not accept any extras but accept freehand Lines. 2 (a) 10 570 1 B1 for 10 570 (b) 560 1 B1 cao (c) 2.17, 3.95, 5.03, 6.84 1 B1 cao (d)(i) 49 1 B1 cao (ii) 8 1 B1 cao 3 (a) 8.6 1 B1 for 8.6 ± 0.2 cm (b) correct × 1 B1 for × 5 cm from Q ± 0.2 cm use overlay provided (c)(i) obtuse 2 B1 ignore spelling (ii) 120 B1 for 120 ± 2°
  • 8. 5MB2F_01 Question Working Answer Mark Notes 4 2 × 60 + 3 × 50 530 4 M1 for 2 × 60 or 3 × 50 or 7 × 45 or 7 × 55 oe = 120 + 150 = 270 M1 for ‘2 × 60’ + ‘3 × 50’ + ‘7 × 45’ + ‘7 × 55’ oe 7 × (45 + 55) = 700 M1 for 1500 – (‘2 × 60’ + ‘3 × 50’ + ‘7 × 45’ + ‘7 × 55’ ) oe 1500 – 970 A1 cao or or 2 × 60 + 3 × 50 + 7 × 45 +7 × 55 M1 for 2 × 60 or 3 × 50 or 45 + 55 oe 120 + 150 + 315 +385 = 970 M1 for ‘2 × 60’ + ‘3 × 50’ + ‘(45 + 55)’ × 7 1500 – 970 = M1 for 1500 – (‘2 × 60’ + ‘3 × 50’ + ‘(45 + 55) × 7)’ oe or for doubling travel costs A1 cao 2 × 2 × 60 + 2 × 3 × 50 Or for doubling travel costs = 240 + 300 = 540 M1for 2 × 2 × 60 or 2 × 3 × 50 or 7 × 45 or 7 × 55 oe 7 × (45 + 55) = 700 M1for ‘2 × 2 × 60’ + ‘2 × 3 × 50’ + ‘7 × 45’+ ‘7 × 55’ oe 1500 – 1240 = 260 M1for 1500 – (‘2 × 2 × 60’ + ‘2 × 3 × 50’ + ‘7 × 45’ +‘7 × 55’) oe A1 for 260 5 (a) 2 B1 cao 1 Monday 2 B1 for Monday oe (b)(i) 7 B1 ft for their (b)(i) accept positive and negative answers for 7 (ii) 6 (a) 5.6 1 B1 cao (b) 9.58 1 B1 ft from their weight in part (a) may be shown by selecting correct value in the table 7 (i) 70 2 B1 for 70 look for answer on diagram (ii) reason C1 for angles (on a) straight line (add up to) 180°
  • 9. 5MB2F_01 Question Working Answer Mark Notes *8 28 = (4+1) + (4+1) + (4+1) + Yes + reason 3 M1 for attempt to account for 1 free (4+1) + (4+1) + 3 e.g. (4+1) + (4+1) ... with at least 2 seen Buy 4 + 4 + 4 + 4 + 4 + 3 e.g. 140÷24 = 5 so 5 free eg every £24 get 1 free 23 × 6 = 138 e.g. 23lots of £6 so 5 free or M1 for using £140 in a calculation that could lead to the correct 140 ÷ 6 (= 23 rem 2) conclusion (need not be explicit) or for a method that leads to a 23 ÷ 4 = 5 free total cost of 138 23 + 5 = 28 C1 (dep on M1) for ‘Yes’ and reason eg “138” is less than 140 oe or “Yes” and “23 with 5 free gives £2” left over oe NB Needs a statement to this effect 9 (a) × 240 36 2 M1 for 15 ÷ 100 or 10% + 5% attempted with correct values of 24 and 12 seen or 24 and 12 seen or 0.15 seen A1 cao (b) 240 ÷ 3 80 1 B1 cao (c) 80 : 60 = 8 : 6 4:3 2 M1 for any correct ratio eg 80:60, 40 : 30, 8 : 6 or 4 gap 3 seen without ratio sign or 4 dot 3 A1 for 4 : 3 or 4 to 3 SC B1 for an answer of 3:4 or 3 to 4 if M1 not scored
  • 10. 5MB2F_01 Question Working Answer Mark Notes 10 (a) 16 1 B1for answer in range 15.5 to 16.5 (b) 2.4 1 B1for answer in range 2.3 to 2.5 (c)(i) Debbie 1 B1 for Debbie (c)(ii) Correct reason 1 C1for Debbie in Part (i) with a valid explanation e.g. It is higher or with a correct conversion ± 1 sq or Stefan in part (i) with an incorrect conversion but valid explanation Note: 6 mph = 9.6 km/h (accept 9-10) 10.5 km/h = 6.5625 mph (accept 6.4 – 6.8) 11 (a) 6 2 M1for any valid method e.g. drawing diagrams, counting in 2s which may be on the diagram or table of values A1cao (b) nth term is 2n + 2 so 102 2 M1for 50 + 50 + 2 or any other valid method 50th term is 50 × 2 + 2 A1cao 12 4x + 9y 2 B2for 4x + 9y (B1for 4x or 9y seen)
  • 11. 5MB2F_01 Question Working Answer Mark Notes 13 (a) 17 1 B1 cao (b) (5+3)×2+1 1 B1 cao (c) 24 1 B1 for 24 or + 24 (d) 7 1 7 2 9 2 M1 for a suitable common denominator (multiple of 10) + = + 7 10 5 10 10 10 with one fraction out of two (not ) correct or 0.7 + 10 1 5 0.2 or all cells correct if cell method used 9 7 35 A1 for oe, accept 0.9 10 10 10 50 *14 96 ÷ 22 No 3 M1 for 96 ÷ 22 oe = 96 ÷ 4 + A1 for 24 = 24 calculations C1 dep on M1for “No” with a calculation to support their conclusion SC B1: for 96 ÷ 2 and a correct conclusion seen NB To award the marks in this question working must be shown
  • 12. 5MB2F_01 Question Working Answer Mark Notes 15 (a) Missing sides are 16x + 8 3 M1 for 5x + 1 –3x or 2x + 3 + x or identifying a missing side 2x + 1 and 3x + 3 as 2x + 1 or 3x + 3(maybe on the diagram) Perimeter = 5x + 1 + x + 3x + 2x + M1 for adding 5 or 6 sides from x, 5x + 1, 3x, 2x + 3, ‘2x + 1’, 3 +2x + 1 + 3x + 3 ‘3x + 3’ where the missing sides are in the form ax ± b (a and OR b ≠ 0) 2(5x + 1) + 2(2x + 3 + x) or 2(5x + 1) + 2(2x + 3 + x) oe A1 for 16x + 8 oe for unsimplified expression (b) 4x + 2 1 B1 ft for [‘2(5x + 1) + 2(2x + 3 + x)’] ÷ 4 or (”16x + 8”) ÷ 4 oe where the answer is an algebraic expression in x
  • 13. 5MB2F_01 Question Working Answer Mark Notes 16 Big area = 144 20 4 M1 for 12 × 12 or 8 × 8 or 144 seen or 64 seen as Small area = 64 area Area frame = 144 – 64 M1 for 12 × 12 − 8 × 8 or ‘144’ − ‘64’ or 80 seen as = 80 area 80 ÷ 4 M1 for (12 × 12 − 8 × 8) ÷ 4 or ‘(144 − 64)’ ÷ 4 or ‘80’ or ÷ 4 seen as area Area one piece is a trapezium A1 for 20 cao ½ (12+8) × (12– 8)÷2 or ½ × 20 × 2 = 20 M1 for 12 − 8 or 4 seen as difference in lengths or M1 for height of trapezium = (12 − 8) ÷ 2 or ‘4’ ÷ 2 or 2 Area of rectangle + 2 triangles M1 for area trapezium = ½ (12 + 8) × ‘2’ oe 8 × 2 + 2× ( ½ × 2 × 2) A1 for 20 cao 16 + 4 or or M1 for ½ × (12 – 8 ) or 2 for width of frame Area of rectangle – 2 triangles M1 for 8 × 2 = 16 for rectangle 12×2 – 2× ( ½ × 2 × 2) M1 for 2× ( ½ × 2 × 2) or 4 for 2 triangles 24 – 4 A1 for 20 cao or M1 for ½ × (12 – 8 ) or 2 for width of frame M1 for 12 × 2 = 24 for rectangle M1 for 2× ( ½ × 2 × 2) or 4 for 2 triangles A1 for 20 cao NB marks can be awarded for correct measurements indicated on the diagram Note:-If 80 seen on the answer line following a correct calculation of one piece of card, full marks can be earned
  • 14. 5MB2F_01 Question Working Answer Mark Notes *17 Angle ACB = 35° 135 4 M1 for angle ACB = (180 – 110) ÷ 2 or 35 seen (base angles of an isosceles M1 for angle CAE = angle ACB or “35” triangle are equal) (this could be marked on diagram) (angles in a triangle add up to A1 x = 135 cao 180) C1 (dep on M1) for alternate angles are equal or allied angles Angle CAE = 35° (co-interior angles) are supplementary (add to 180º) (alternate angles are equal) AND any one of x = 360 – (100 + 90 + 35) • (base) or 2 angles of an isosceles triangle are equal oe = 135 • angles in a triangle (add up to) 180 (angles in a quadrilateral add up • angles in a quadrilateral (add up to) 360° to 360°) • angles in a pentagon (add up to)540º
  • 15.
  • 16. Further copies of this publication are available from Edexcel Publications, Adamsway, Mansfield, Notts, NG18 4FN Telephone 01623 467467 Fax 01623 450481 Email publication.orders@edexcel.com Order Code UG029766 November 2011 For more information on Edexcel qualifications, please visit www.edexcel.com/quals Pearson Education Limited. Registered company number 872828 with its registered office at Edinburgh Gate, Harlow, Essex CM20 2JE