2. 2x-3y=1
2x-3(0)=1
2x=1
x=1/2
Ex. 1: Solve the system: 2x-3y=1 and
5x+2y=12
2x-3y=1
2(0)-3y=1
-3y=1
y=-1/3
5x+2y=12
5x+2(0)=12
5x=12
x=12/5
x=2 2/5
5x+2y=12
5(0)+2y=12
2y=12
y=12/2
y=6
x 0 1/2
y -1/3 0
x 0 2 2/5
y 6 0
3. We then plot the points (0,-⅓) and (½, 0) and (0,6) and (2 ⅖, 0) in the
coordinate plane.
x 0 1/2
y -1/3 0
x 0 2 2/5
y 6 0
Based on the point of intersection of the
lines, the solution set of the system is (2,1).
To check, we compute the set of ordered
pairs from both the equations.
2x-3y=1
2(2)-3(1)=1
4-3=1
1=1
5x+2y=12
5(2)+2(1)=12
10+2=12
12=12
5. We then plot the points (0,6) and (3, 0) and (0,8) and (2, 0) in the
coordinate plane.
x 0 3
y 6 0
x 0 2
y 8 0
Based on the point of intersection of the
lines, the solution set of the system is (1,4).
To check, we compute the set of ordered
pairs from both the equations.
2x+y=6
2(1)+4=6
2+4=6
6=6
4x+y=8
4(1)+4=8
4+4=8
8=8