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Perpendicular Distance
      Formula
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 


                                                       Ax + By + C = 0
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d

                                                       Ax + By + C = 0
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d
            Ax1  By1  C
       d
               A2  B 2                                Ax + By + C = 0
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d
            Ax1  By1  C
       d
                A2  B 2                              Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d
            Ax1  By1  C
       d
                A2  B 2                              Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).



            1, 4 
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d
            Ax1  By1  C
       d
                A2  B 2                              Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).
              3x – 4y – 12 = 0


            1, 4 
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                               x1 , y1 
                                          d
            Ax1  By1  C
       d
                A2  B 2                              Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).
              3x – 4y – 12 = 0
             r
            1, 4 
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                                  x1 , y1 
                                            d
            Ax1  By1  C
       d
                A2  B 2                                  Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).                   3 1  4  4   12
                                 r
              3x – 4y – 12 = 0           3  4  
                                           2          2


             r
            1, 4 
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                                  x1 , y1 
                                            d
            Ax1  By1  C
       d
                A2  B 2                                  Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).                   3 1  4  4   12
                                 r
              3x – 4y – 12 = 0           3  4  
                                           2          2


             r                        25
                                    
            1, 4                     25
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                                  x1 , y1 
                                            d
            Ax1  By1  C
       d
                A2  B 2                                  Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).                   3 1  4  4   12
                                 r
              3x – 4y – 12 = 0           3  4  
                                           2          2


             r                         25
                                    
            1, 4                      25
                                     5 units
Perpendicular Distance
         Formula
The shortest distance from a point to a line is the perpendicular distance.
                                                  x1 , y1 
                                            d
            Ax1  By1  C
       d
                A2  B 2                                  Ax + By + C = 0
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
     centre (1,4).                   3 1  4  4   12
                                 r
              3x – 4y – 12 = 0           3  4  
                                           2          2


             r                         25
                                                               the circle is
            1, 4                      25
                                                        x  1   y  4   25
                                                               2           2
                                     5 units
If  Ax1  By1  C  has different signs for different points, they
are on different sides of the line.
If  Ax1  By1  C  has different signs for different points, they
are on different sides of the line.




                                             Ax + By + C = 0
If  Ax1  By1  C  has different signs for different points, they
are on different sides of the line.


                                  Ax + By + C > 0


                                             Ax + By + C = 0
If  Ax1  By1  C  has different signs for different points, they
are on different sides of the line.


                                  Ax + By + C > 0
         Ax + By + C < 0
                                             Ax + By + C = 0
If  Ax1  By1  C  has different signs for different points, they
are on different sides of the line.


                                  Ax + By + C > 0
         Ax + By + C < 0
                                             Ax + By + C = 0




             Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b,
                     9abc, 10, 13, 14, 18*

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11X1 T06 05 perpendicular distance (2011)

  • 2. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.
  • 3. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1 
  • 4. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  Ax + By + C = 0
  • 5. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax + By + C = 0
  • 6. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0
  • 7. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4).
  • 8. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 1, 4 
  • 9. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3x – 4y – 12 = 0 1, 4 
  • 10. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3x – 4y – 12 = 0 r 1, 4 
  • 11. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3 1  4  4   12 r 3x – 4y – 12 = 0 3  4   2 2 r 1, 4 
  • 12. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3 1  4  4   12 r 3x – 4y – 12 = 0 3  4   2 2 r 25  1, 4  25
  • 13. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3 1  4  4   12 r 3x – 4y – 12 = 0 3  4   2 2 r 25  1, 4  25  5 units
  • 14. Perpendicular Distance Formula The shortest distance from a point to a line is the perpendicular distance.  x1 , y1  d Ax1  By1  C d A2  B 2 Ax + By + C = 0 e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and centre (1,4). 3 1  4  4   12 r 3x – 4y – 12 = 0 3  4   2 2 r 25   the circle is 1, 4  25  x  1   y  4   25 2 2  5 units
  • 15. If  Ax1  By1  C  has different signs for different points, they are on different sides of the line.
  • 16. If  Ax1  By1  C  has different signs for different points, they are on different sides of the line. Ax + By + C = 0
  • 17. If  Ax1  By1  C  has different signs for different points, they are on different sides of the line. Ax + By + C > 0 Ax + By + C = 0
  • 18. If  Ax1  By1  C  has different signs for different points, they are on different sides of the line. Ax + By + C > 0 Ax + By + C < 0 Ax + By + C = 0
  • 19. If  Ax1  By1  C  has different signs for different points, they are on different sides of the line. Ax + By + C > 0 Ax + By + C < 0 Ax + By + C = 0 Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b, 9abc, 10, 13, 14, 18*