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Chap15 analysis of variance
1.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall Statistics for Business and Economics 7th Edition Chapter 15 Analysis of Variance Ch. 15-1
2.
Chapter Goals After completing
this chapter, you should be able to: Recognize situations in which to use analysis of variance Understand different analysis of variance designs Perform a one-way and two-way analysis of variance and interpret the results Conduct and interpret a Kruskal-Wallis test Analyze two-factor analysis of variance tests with more than one observation per cell Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Ch. 15-2
3.
One-Way Analysis of
Variance Evaluate the difference among the means of three or more groups Examples: Average production for 1st, 2nd, and 3rd shifts Expected mileage for five brands of tires Assumptions Populations are normally distributed Populations have equal variances Samples are randomly and independently drawn Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 15.2 Ch. 15-3
4.
Hypotheses of One-Way
ANOVA All population means are equal i.e., no variation in means between groups At least one population mean is different i.e., there is variation between groups Does not mean that all population means are different (some pairs may be the same) Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall K3210 μμμμ:H pairji,oneleastatforμμ:H ji1 Ch. 15-4
5.
One-Way ANOVA Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall All Means are the same: The Null Hypothesis is True (No variation between groups) K3210 μμμμ:H sametheareμallNot:H i1 321 μμμ Ch. 15-5
6.
One-Way ANOVA Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall At least one mean is different: The Null Hypothesis is NOT true (Variation is present between groups) 321 μμμ 321 μμμ or (continued) K3210 μμμμ:H sametheareμallNot:H i1 Ch. 15-6
7.
Variability The variability
of the data is key factor to test the equality of means In each case below, the means may look different, but a large variation within groups in B makes the evidence that the means are different weak Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Small variation within groups A B C Group A B C Group Large variation within groups A B Ch. 15-7
8.
Partitioning the Variation
Total variation can be split into two parts: Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall SST = Total Sum of Squares Total Variation = the aggregate dispersion of the individual data values across the various groups SSW = Sum of Squares Within Groups Within-Group Variation = dispersion that exists among the data values within a particular group SSG = Sum of Squares Between Groups Between-Group Variation = dispersion between the group sample means SST = SSW + SSG Ch. 15-8
9.
Partition of Total
Variation Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Variation due to differences between groups (SSG) Variation due to random sampling (SSW) Total Sum of Squares (SST) = + Ch. 15-9
10.
Total Sum of
Squares Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Where: SST = Total sum of squares K = number of groups (levels or treatments) ni = number of observations in group i xij = jth observation from group i x = overall sample mean SST = SSW + SSG K 1i n 1j 2 ij i )x(xSST Ch. 15-10
11.
Total Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Group 1 Group 2 Group 3 Response, X 2 Kn 2 12 2 11 )x(x...)x(X)x(xSST K (continued) x Ch. 15-11
12.
Within-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Where: SSW = Sum of squares within groups K = number of groups ni = sample size from group i xi = sample mean from group i xij = jth observation in group i SST = SSW + SSG K 1i n 1j 2 iij i )x(xSSW Ch. 15-12
13.
Within-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Summing the variation within each group and then adding over all groups Kn SSW MSW Mean Square Within = SSW/degrees of freedom (continued) K 1i n 1j 2 iij i )x(xSSW iμ Ch. 15-13
14.
Within-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Group 1 Group 2 Group 3 Response, X 2 KKn 2 112 2 111 )x(x...)x(x)x(xSSW K (continued) 1x 2x 3x Ch. 15-14
15.
Between-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Where: SSG = Sum of squares between groups K = number of groups ni = sample size from group i xi = sample mean from group i x = grand mean (mean of all data values) 2 i K 1i i )xx(nSSG SST = SSW + SSG Ch. 15-15
16.
Between-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Variation Due to Differences Between Groups 1K SSG MSG Mean Square Between Groups = SSG/degrees of freedom (continued) 2 i K 1i i )xx(nSSG iμ jμ Ch. 15-16
17.
Between-Group Variation Copyright ©
2010 Pearson Education, Inc. Publishing as Prentice Hall Group 1 Group 2 Group 3 Response, X 2 KK 2 22 2 11 )xx(n...)xx(n)xx(nSSG (continued) 1x 2x 3x x Ch. 15-17
18.
Obtaining the Mean
Squares Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Kn SSW MSW 1K SSG MSG 1n SST MST Ch. 15-18
19.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall One-Way ANOVA Table Source of Variation dfSS MS (Variance) Between Groups SSG MSG = Within Groups n - KSSW MSW = Total n - 1 SST = SSG+SSW K - 1 MSG MSW F ratio K = number of groups n = sum of the sample sizes from all groups df = degrees of freedom SSG K - 1 SSW n - K F = Ch. 15-19
20.
One-Factor ANOVA F Test
Statistic Test statistic MSG is mean squares between variances MSW is mean squares within variances Degrees of freedom df1 = K – 1 (K = number of groups) df2 = n – K (n = sum of sample sizes from all groups) Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall MSW MSG F H0: μ1= μ2 = … = μK H1: At least two population means are different Ch. 15-20
21.
Interpreting the F
Statistic The F statistic is the ratio of the between estimate of variance and the within estimate of variance The ratio must always be positive df1 = K -1 will typically be small df2 = n - K will typically be large Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Decision Rule: Reject H0 if F > FK-1,n-K, 0 = .05 Reject H0Do not reject H0 FK-1,n-K, Ch. 15-21
22.
One-Factor ANOVA F Test
Example You want to see if three different golf clubs yield different distances. You randomly select five measurements from trials on an automated driving machine for each club. At the .05 significance level, is there a difference in mean distance? Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 Ch. 15-22
23.
One-Factor ANOVA Example: Scatter
Diagram Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall •• •• • 270 260 250 240 230 220 210 200 190 • • • • • •• • •• Distance 227.0x 205.8x226.0x249.2x 321 Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 Club 1 2 3 1x 2x 3x x Ch. 15-23
24.
One-Factor ANOVA Example Computations Copyright
© 2010 Pearson Education, Inc. Publishing as Prentice Hall Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 x1 = 249.2 x2 = 226.0 x3 = 205.8 x = 227.0 n1 = 5 n2 = 5 n3 = 5 n = 15 K = 3 SSG = 5 (249.2 – 227)2 + 5 (226 – 227)2 + 5 (205.8 – 227)2 = 4716.4 SSW = (254 – 249.2)2 + (263 – 249.2)2 +…+ (204 – 205.8)2 = 1119.6 MSG = 4716.4 / (3-1) = 2358.2 MSW = 1119.6 / (15-3) = 93.3 25.275 93.3 2358.2 F Ch. 15-24
25.
One-Factor ANOVA Example Solution H0:
μ1 = μ2 = μ3 H1: μi not all equal = .05 df1= 2 df2 = 12 Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall F = 25.275 Test Statistic: Decision: Conclusion: Reject H0 at = 0.05 There is evidence that at least one μi differs from the rest 0 = .05 Reject H0Do not reject H0 25.275 93.3 2358.2 MSW MSA F Critical Value: F2,12,.05= 3.89 F2,12,.05 = 3.89 Ch. 15-25
26.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall SUMMARY Groups Count Sum Average Variance Club 1 5 1246 249.2 108.2 Club 2 5 1130 226 77.5 Club 3 5 1029 205.8 94.2 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 4716.4 2 2358.2 25.275 4.99E-05 3.89 Within Groups 1119.6 12 93.3 Total 5836.0 14 ANOVA -- Single Factor: Excel Output EXCEL: data | data analysis | ANOVA: single factor Ch. 15-26
27.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall Multiple Comparisons Between Subgroup Means To test which population means are significantly different e.g.: μ1 = μ2 ≠ μ3 Done after rejection of equal means in single factor ANOVA design Allows pair-wise comparisons Compare absolute mean differences with critical range x = 1 2 3 Ch. 15-27
28.
Two Subgroups When
there are only two subgroups, compute the minimum significant difference (MSD) Where Sp is a pooled estimate of the variance Use hypothesis testing methods of Ch. 10 Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall n 2 StMSD pα/2 Ch. 15-28
29.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall Multiple Supgroups q is a factor from appendix Table 13 for the chosen level of k = number of subgroups, and MSW = Mean square within from ANOVA table n S qMSD(k) p The minimum significant difference between k subgroups is where MSWSp Ch. 15-29
30.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall ...etc xx xx xx 32 31 21 If the absolute mean difference is greater than MSD then there is a significant difference between that pair of means at the chosen level of significance. Compare: ?MSD(k)xxIs ji Multiple Supgroups (continued) n S qMSD(k) p Ch. 15-30
31.
Copyright © 2010
Pearson Education, Inc. Publishing as Prentice Hall 20.2xx 43.4xx 23.2xx 32 31 21 Since each difference is greater than 9.387, we conclude that all three means are different from one another at the .05 level of significance. (where q = 3.77 is from Table 13 for = .05 and 12 df) Multiple Supgroups: Example 9.387 15 93.3 3.77 n S qMSD(k) p x1 = 249.2 x2 = 226.0 x3 = 205.8 n1 = 5 n2 = 5 n3 = 5 Ch. 15-31
32.
Kruskal-Wallis Test Use
when the normality assumption for one- way ANOVA is violated Assumptions: The samples are random and independent variables have a continuous distribution the data can be ranked populations have the same variability populations have the same shape Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 15.3 Ch. 15-32
33.
Kruskal-Wallis Test Procedure
Obtain relative rankings for each value In event of tie, each of the tied values gets the average rank Sum the rankings for data from each of the K groups Compute the Kruskal-Wallis test statistic Evaluate using the chi-square distribution with K – 1 degrees of freedom Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Ch. 15-33
34.
Kruskal-Wallis Test Procedure
The Kruskal-Wallis test statistic: (chi-square with K – 1 degrees of freedom) Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 1)3(n n R 1)n(n 12 W K 1i i 2 i where: n = sum of sample sizes in all groups K = Number of samples Ri = Sum of ranks in the ith group ni = Size of the ith group (continued) Ch. 15-34
35.
Kruskal-Wallis Test Procedure Decision
rule Reject H0 if W > 2 K–1, Otherwise do not reject H0 Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall (continued) Complete the test by comparing the calculated H value to a critical 2 value from the chi-square distribution with K – 1 degrees of freedom 2 2 K–1, 0 Reject H0Do not reject H0 Ch. 15-35
36.
Kruskal-Wallis Example Do
different departments have different class sizes? Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Class size (Math, M) Class size (English, E) Class size (Biology, B) 23 45 54 78 66 55 60 72 45 70 30 40 18 34 44 Ch. 15-36
37.
Kruskal-Wallis Example Do
different departments have different class sizes? Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Class size (Math, M) Ranking Class size (English, E) Ranking Class size (Biology, B) Ranking 23 41 54 78 66 2 6 9 15 12 55 60 72 45 70 10 11 14 8 13 30 40 18 34 44 3 5 1 4 7 = 44 = 56 = 20 Ch. 15-37
38.
Kruskal-Wallis Example The
W statistic is Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall (continued) 6.721)3(15 5 20 5 56 5 44 1)15(15 12 1)3(n n R 1)n(n 12 W 222 K 1i i 2 i equalaremeanspopulationallNot:H MeanMeanMean:H 1 BEM0 Ch. 15-38
39.
Kruskal-Wallis Example Since H
= 6.72 > , reject H0 Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall (continued) 5.9912 2,0.05 χ Compare W = 6.72 to the critical value from the chi-square distribution for 3 – 1 = 2 degrees of freedom and = .05: 5.9912 2,0.05 There is sufficient evidence to reject that the population means are all equal Ch. 15-39
40.
Two-Way Analysis of
Variance Examines the effect of Two factors of interest on the dependent variable e.g., Percent carbonation and line speed on soft drink bottling process Interaction between the different levels of these two factors e.g., Does the effect of one particular carbonation level depend on which level the line speed is set? Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 15.4 Ch. 15-40
41.
Two-Way ANOVA Assumptions
Populations are normally distributed Populations have equal variances Independent random samples are drawn Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall (continued) Ch. 15-41
42.
Randomized Block Design Copyright
© 2010 Pearson Education, Inc. Publishing as Prentice Hall Two Factors of interest: A and B K = number of groups of factor A H = number of levels of factor B (sometimes called a blocking variable) Block Group 1 2 … K 1 2 . . H x11 x12 . . x1H x21 x22 . . x2H … … . . … xK1 xK2 . . xKH Ch. 15-42
43.
Two-Way Notation Let
xji denote the observation in the jth group and ith block Suppose that there are K groups and H blocks, for a total of n = KH observations Let the overall mean be x Denote the group sample means by Denote the block sample means by Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall K),1,2,(jxj )H,1,2,(ix i Ch. 15-43
44.
Partition of Total
Variation SST = SSG + SSB + SSE Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Variation due to differences between groups (SSG) Variation due to random sampling (unexplained error) (SSE) Total Sum of Squares (SST) = + Variation due to differences between blocks (SSB) + The error terms are assumed to be independent, normally distributed, and have the same variance Ch. 15-44
45.
Two-Way Sums of
Squares The sums of squares are Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall H 1i 2 i )x(xKSSB:Blocks-Between K 1j 2 j )xx(HSSG:Groups-Between K 1j H 1i 2 ji )x(xSST:Total K 1j H 1i 2 ijji )xxx(xSSE:Error Degrees of Freedom: n – 1 K – 1 H – 1 (K – 1)(K – 1) Ch. 15-45
46.
Two-Way Mean Squares
The mean squares are Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 1)1)(H(K SSE MSE 1H SST MSB 1K SST MSG 1n SST MST Ch. 15-46
47.
Two-Way ANOVA: The F
Test Statistic Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall F Test for Blocks H0: The K population group means are all the same F Test for Groups H0: The H population block means are the same Reject H0 if F > FK-1,(K-1)(H-1), MSE MSG F MSE MSB F Reject H0 if F > FH-1,(K-1)(H-1), Ch. 15-47
48.
General Two-Way Table
Format Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Source of Variation Sum of Squares Degrees of Freedom Mean Squares F Ratio Between groups Between blocks Error Total SSG SSB SSE SST K – 1 H – 1 (K – 1)(H – 1) n - 1 1K SSG MSG 1H SSB MSB 1)1)(H(K SSE MSE MSE MSG MSE MSB Ch. 15-48
49.
More than One Observation
per Cell A two-way design with more than one observation per cell allows one further source of variation The interaction between groups and blocks can also be identified Let K = number of groups H = number of blocks L = number of observations per cell n = KHL = total number of observations Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 15.5 Ch. 15-49
50.
More than One Observation
per Cell Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall SST Total Variation SSG Between-group variation SSB Between-block variation SSI Variation due to interaction between groups and blocks SSE Random variation (Error) Degrees of Freedom: K – 1 H – 1 (K – 1)(H – 1) KH(L – 1) n – 1 SST = SSG + SSB + SSI + SSE (continued) Ch. 15-50
51.
Sums of Squares
with Interaction Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall H 1i 2 i )x(xKLSSB:blocks-Between K 1j 2 j )xx(HLSSG:groups-Between 2 j i l jil )x(xSST:Total 2 ji i j l jil )x(xSSE:Error K 1j H 1i 2 ijji )xxxx(LSSI:nInteractio Degrees of Freedom: K – 1 H – 1 (K – 1)(H – 1) KH(L – 1) n - 1 Ch. 15-51
52.
Two-Way Mean Squares with
Interaction The mean squares are Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall 1)KH(L SSE MSE 1)1)(H-(K SSI MSI 1H SST MSB 1K SST MSG 1n SST MST Ch. 15-52
53.
Two-Way ANOVA: The F
Test Statistic Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall F Test for block effect F Test for interaction effect H0: the interaction of groups and blocks is equal to zero F Test for group effect MSE MSG F MSE MSB F MSE MSI F H0: The K population group means are all the same H0: The H population block means are the same Reject H0 if F > FK-1,KH(L-1), Reject H0 if F > FH-1,KH(L-1), Reject H0 if F > F(K-1)(H-1),KH(L-1), Ch. 15-53
54.
Two-Way ANOVA Summary Table Copyright
© 2010 Pearson Education, Inc. Publishing as Prentice Hall Source of Variation Sum of Squares Degrees of Freedom Mean Squares F Statistic Between groups SSG K – 1 MSG = SSG / (K – 1) MSG MSE Between blocks SSB H – 1 MSB = SSB / (H – 1) MSB MSE Interaction SSI (K – 1)(H – 1) MSI = SSI / (K – 1)(H – 1) MSI MSE Error SSE KH(L – 1) MSE = SSE / KH(L – 1) Total SST n – 1 Ch. 15-54
55.
Features of Two-Way ANOVA
F Test Degrees of freedom always add up n-1 = KHL-1 = (K-1) + (H-1) + (K-1)(H-1) + KH(L-1) Total = groups + blocks + interaction + error The denominator of the F Test is always the same but the numerator is different The sums of squares always add up SST = SSG + SSB + SSI + SSE Total = groups + blocks + interaction + error Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Ch. 15-55
56.
Examples: Interaction vs. No
Interaction No interaction: Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Block Level 1 Block Level 3 Block Level 2 Groups Block Level 1 Block Level 3 Block Level 2 Groups MeanResponse MeanResponse Interaction is present: A B C A B C Ch. 15-56
57.
Chapter Summary Described
one-way analysis of variance The logic of Analysis of Variance Analysis of Variance assumptions F test for difference in K means Applied the Kruskal-Wallis test when the populations are not known to be normal Described two-way analysis of variance Examined effects of multiple factors Examined interaction between factors Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall Ch. 15-57
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