Drosophila melanogaster has one pair of sex chromosomes (XX or XY) and three pairs of autosomes, referred to as chromosomes II, III, and IV. A genetics student discovered a male fly with very short (sh) legs. Using this male, the student was able to establish a pure breeding stock of this mutant and found that it was recessive. She then incorporated the mutant into a stock containing the recessive gene black (b, body color located on chromosome II) and the recessive gene pink (p, eye color located on chromosome III). A female from the homozygous black, pink, short stock was then mated to a wild-type male. The F1 males of this cross were all wild type and were then backcrossed to the homozygous b, p, sh females. The F2 results appeared as shown in the following table. No other phenotypes were observed. Based on these results, the student was able to assign short to a linkage group (a chromosome). Which one was it? a. X chromosome b. chromosome II c. chromosome III d. chromosome IV Solution Image is not loading... upload the image in dropbox or google drive and paste the link in comment. I will answer the question.Categoryfemalesmaleswild6359122pink5865123black short5551106black pink short6960129.