Slideshare uses cookies to improve functionality and performance, and to provide you with relevant advertising. If you continue browsing the site, you agree to the use of cookies on this website. See our User Agreement and Privacy Policy.

Slideshare uses cookies to improve functionality and performance, and to provide you with relevant advertising. If you continue browsing the site, you agree to the use of cookies on this website. See our Privacy Policy and User Agreement for details.

Successfully reported this slideshow.

No Downloads

Total views

9,042

On SlideShare

0

From Embeds

0

Number of Embeds

23

Shares

0

Downloads

492

Comments

0

Likes

16

No embeds

No notes for slide

- 1. Analytical Geometry Ellipse T- 1-855-694-8886 Email- info@iTutor.com By iTutor.com
- 2. Ellipse An ellipse is the set of all points in a plane such that the sum of the distances from two points (foci) is a constant. When you go from point “F” to any point on the ellipse and hen go on to point "G", you will always travel the same distance. © iTutor. 2000-2013. All Rights Reserved
- 3. The two fixed points are called the foci(plural of „focus‟) of the ellipse . The mid point of the line segment joining the foci is called the centre of the ellipse. The line segment through the foci of the ellipse is called the major axis and the line segment through the centre and perpendicular to the major axis is called the minor axis. The end points of the major axis are called the vertices of the ellipse F G A B C D 0 Vertices Major axis Minoraxis Foci Centre Copyright reserved. 2012 The E Tutor
- 4. We denote the length of the major axis by 2a, the length of the minor axis by 2b and the distance between the foci by 2c. Thus, the length of the semi major axis is a and semi-minor axis is b Copyright reserved. 2012 The E Tutor
- 5. Relationship between semi-major axis, semi-minor axis and the distance of the focus from the centre of the ellipse Take a point P at one end of the major axis. Sum of the distances of the point P to the foci is FP + GP = FO + OP +GP (since FP = FO + OP) = c + a + a – c = 2a Take a point Q at one end of the minor axis. Sum of the distances from the point Q to the foci is FQ + GQ = F G R P Q 0 Foci b c c a a – c 2222 cbcb 22 2 cb 22 cb 22 cb Copyright reserved. 2012 The E Tutor
- 6. Since both P and Q lies on the ellipse. By the definition of ellipse, we have or acb 22 22 i.e., 22 cba 222 cba i.e., 22 bac Copyright reserved. 2012 The E Tutor
- 7. Eccentricity The eccentricity of an ellipse is the ratio of the distances from the centre of the ellipse to one of the foci and to one of the vertices of the ellipse (eccentricity is denoted by e) i.e., Then, since the focus is at a distance of c from the centre, in terms of the eccentricity the focus is at a distance of ae from the centre. a c e Copyright reserved. 2012 The E Tutor
- 8. Standard equations of an ellipse The equation of an ellipse is simplest if the centre of the ellipse is at the origin and the foci are on the x-axis or y-axis. A B F (-c ,0) G (c ,0) C D P (x, y) O X Y X Y O (0 ,-c) (0 , c) (-b ,0) (b ,0) a. Foci are on x-axis b. Foci are on y-axis 12 2 2 2 b y a x 12 2 2 2 a y b x Copyright reserved. 2012 The E Tutor
- 9. We will derive the equation for the ellipse shown above in Figure with foci on the x-axis. Let F and G be the foci and O be the mid-point of the line segment FG, Let O be the origin and the line from O through G be the positive x-axis and that through F as the negative x-axis. Let the coordinates of F be (-c , 0 ) and G be ( c, 0 ). Let P( x, y ) be any point on the ellipse such that the sum of the distances from P to the two foci be 2a so given PF + PG = 2a --------------- (1) A B F (-c ,0) G (c ,0) C D P (x, y) O X Y Copyright reserved. 2012 The E Tutor
- 10. Using the distance formula, we have Squaring both side we get 2222 )(2)( ycxaycx aycxycx 2)()( 2222 or 2222222 )(4)(4)( ycxaycxaycx square binomials 2222222 )(4242 ycxaxccxaxccx 222 )(444 ycxaaxc x a c aycx 22 )( or or Copyright reserved. 2012 The E Tutor
- 11. Squaring again and simplifying, we get 122 2 2 2 ca y a x 12 2 2 2 b y a x (Since c2 = a2 – b2) Hence any point on the ellipse satisfies 12 2 2 2 b y a x ------------------ (2) Conversely, let P ( x, y) satisfy the equation (2) with 0 < c< a. Then, Therefore, 2 2 2 12 a x by 22 )( ycxPF Copyright reserved. 2012 The E Tutor
- 12. 2 22 22 )( a xa bcx 2 22 222 )()( a xa cacx (Since b2 = a2 – c2) 2 a cx a a cx aPF Similarly, a cx aPG Hence, PF + PG a a cx a a cx a 2 ----------------- (3) Copyright reserved. 2012 The E Tutor
- 13. So, any point that satisfies , satisfies the geometric condition and so P(x, y) lies on the ellipse. Hence from (2) and (3), we proved that the equation of an ellipse with centre of the origin and major axis along the x-axis is Similarly, the ellipse lies between the lines y= –b and y = b and touches these lines. Similarly, we can derive the equation of the ellipse in Fig (b) as These two equations are known as standard equations of the ellipses. 12 2 2 2 b y a x 12 2 2 2 b y a x 12 2 2 2 a y b x Copyright reserved. 2012 The E Tutor
- 14. • From the standard equations of the ellipses, we have the following observations: 1. Ellipse is symmetric with respect to both the coordinate axes since if ( x, y) is a point on the ellipse, then (–x, y), (x, –y) and (–x, –y) are also points on the ellipse. 2. The foci always lie on the major axis. The major axis can be determined by finding the intercepts on the axes of symmetry. That is, major axis is along the x-axis if the coefficient of x2 has the larger denominator and it is along the y-axis if the coefficient of y2 has the larger denominator. Copyright reserved. 2012 The E Tutor
- 15. Ellipse - Equation 2 2 2 2 1 x h y k a b The equation of an ellipse centered at (0, 0) is …. 2 2 2 2 1 x y a b where c2 = |a2 – b2| and c is the distance from the center to the foci. Shifting the graph over h units and up k units, the center is at (h, k) and the equation is where c2 = |a2 – b2| and c is the distance from the center to the foci. Copyright reserved. 2012 The E Tutor
- 16. Ellipse - Graphing 2 2 2 2 1 x h y k a b where c2 = |a2 – b2| and c is the distance from the center to the foci. Vertices are “a” units in the x direction and “b” units in the y direction. aa b b The foci are “c” units in the direction of the longer (major) axis. cc Copyright reserved. 2012 The E Tutor
- 17. Graph the ellipse x y a2 = 36 a = ±6 b2 = 16 b = ±4 (x – 2)2 36 (y + 5)2 16 + = 1 Center = (2,-5) Vertices: (8,-5) and (-4,-5) Co-vertices: (2,-1) and (2,-9) Horizontal Major Axis Copyright reserved. 2012 The E Tutor
- 18. Graph the ellipse x y a2 = 25 a = ±5 b2 = 81 b = ±9 (x + 3)2 25 (y + 1)2 81 + = 1 Center = (-3,-1) Vertices: (-3,8) and (-3,-10) Co-vertices: (-8,-1) and (2,-1) Vertical Major Axis Copyright reserved. 2012 The E Tutor
- 19. 9.4 Ellipses Horizontal Major Axis: a2 > b2 a2 – b2 = c2 x2 a2 y2 b2 + = 1 F1(–c, 0) F2 (c, 0) y x (–a, 0) (a, 0)(0, b) (0, –b) O length of major axis: 2a length of minor axis: 2b Copyright reserved. 2012 The E Tutor
- 20. 9.4 Ellipses F2(0, –c) F1 (0, c) y x (0, –b) (0, b) (a, 0)(–a, 0) O Vertical Major Axis: b2 > a2 b2 – a2 = c2 x2 a2 y2 b2 + = 1 length of major axis: 2b length of minor axis: 2a Copyright reserved. 2012 The E Tutor
- 21. Latus rectum of Ellipse Latus rectum of an ellipse is a line segment perpendicular to the major axis through any of the foci and whose end points lie on the ellipse. To find the length of the latus rectum of the ellipse A B F GO X Y Latus rectum D C 12 2 2 2 b y a x Copyright reserved. 2012 The E Tutor
- 22. Let the length of CG is l. Then the coordinate of the point c are (c , l) i.e., (a e , l) Since A lies on the ellipse we have , But, Since the ellipse is symmetric with respect to y-axis CG = DG so the length of the CD (latus rectum) 12 2 2 2 b y a x 1 )( 2 2 2 2 b l a ae 222 1 ebl 2 2 2 22 2 2 2 1 a b a ba a c e 2 2 22 11 a b bl a b l 2 a b CD 2 2 Copyright reserved. 2012 The E Tutor
- 23. The End Call us for more Information: www.iTutor.com Visit 1-855-694-8886

No public clipboards found for this slide

Be the first to comment