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Cantilever Beam
Uniformly Distributed + Concentrated Load
1 m 1 m 1 m
91 kn 16 kn
13 kn/m
ray
rax
ma
Uniformly Distributed + Concentrated Load
Uniformly Distributed Load
Concentrated Load
Reaction Forces
Moment
1. Solve for the moment
∑MA = 0
91 (1) + 16 (2) + 13 (3)(1.5) — MA = 0
MA = 181.5 kNm
1 m 1 m 1 m
91 kn 16 kn
13 kn/m
ray
rax
ma
Point of Origin
2. Solve for the reaction
forces
∑FX = 0
RAX = 0
∑FY = 0
RAY = 91 + 16 + 13(3)
RAY = 146 kN
1 m 1 m 1 m
91 kn 16 kn
13 kn/m
ray
rax
ma
Point of Origin
1 m 1 m 1 m
91 kn 16 kn
13 kn/m
Ray = 146 KN
Rax = 0
Ma = 181.5 KNM
91 kn 16 kn
13 kn/m
Ray = 146kn
1 m 1 m 1 m
146-13 = 133 kn
133-91 = 42 kn
42-13 = 29 kn
29-16 = 13 kn 13-13 = 0
MA = (—)181.5knm
—181.5+(((146+133)/2)(1))
= 42knm
—42+(((42+29)/2)(1)) = —6.5 knm
146kn
133 kn
42 kn
29 kn
13 kn 0
SHEAR FORCE
DIAGRAM
— 6.5((13 x 1)/2)= 0

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Steel

  • 2. 1 m 1 m 1 m 91 kn 16 kn 13 kn/m ray rax ma Uniformly Distributed + Concentrated Load Uniformly Distributed Load Concentrated Load Reaction Forces Moment
  • 3. 1. Solve for the moment ∑MA = 0 91 (1) + 16 (2) + 13 (3)(1.5) — MA = 0 MA = 181.5 kNm 1 m 1 m 1 m 91 kn 16 kn 13 kn/m ray rax ma Point of Origin
  • 4. 2. Solve for the reaction forces ∑FX = 0 RAX = 0 ∑FY = 0 RAY = 91 + 16 + 13(3) RAY = 146 kN 1 m 1 m 1 m 91 kn 16 kn 13 kn/m ray rax ma Point of Origin
  • 5. 1 m 1 m 1 m 91 kn 16 kn 13 kn/m Ray = 146 KN Rax = 0 Ma = 181.5 KNM
  • 6. 91 kn 16 kn 13 kn/m Ray = 146kn 1 m 1 m 1 m 146-13 = 133 kn 133-91 = 42 kn 42-13 = 29 kn 29-16 = 13 kn 13-13 = 0
  • 7. MA = (—)181.5knm —181.5+(((146+133)/2)(1)) = 42knm —42+(((42+29)/2)(1)) = —6.5 knm 146kn 133 kn 42 kn 29 kn 13 kn 0 SHEAR FORCE DIAGRAM — 6.5((13 x 1)/2)= 0