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Unit 2 Statics of Particles EGR 140 Engineering Mechanics: Statics Professor Mun
Learning Objectives ,[object Object],[object Object],[object Object],[object Object]
For the following two-force coplanar system, determine the resultant force,  R .   150 N 100 N 15  10  x y ) ) O
Method of Components ,[object Object],[object Object],[object Object],[object Object]
Review of Right Triangle and Trigonometry Creative Commons:  scherer.wikispaces.com/ Right + Triangle + Trigonometry +SOH+-+CAH+-+TOA  -  SOH CAH TOA
1. Resolve the force into its component forces along the axes: x- axis.  150 N 100 N 15  10  x y ) ) O 100 x 100 y 100 N 15  ) O 100 x 100 y Fx = F(cos   ) Fy = F(sin    ) 100 x  = 100N (cos15 °) = 96.5926 N  100 y  = 100N (sin15 °) = 25.8819 N
1. Resolve the force into its component forces along the axes: y- axis.  150 N 100 N 15  10  x y ) ) O 150 x 150 y Fx = F(sin   ) Fy = F(cos    ) 150 x  = 150N (sin10 °) = 26.0472 N  150 y  = 150N (cos10 °) = 147.7212 N 150 N 10  ) 150 x 150 y
2. Find the sum of the component forces in each direction.  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
3. Find the magnitude of the resultant force  R .  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
4. Find the direction and sense. x y O R x = 122.6398 N R y  = 173.6031 N R = 213 N )    x  Angle of Inclination tan  x  = R y /R x   = 173.6031 N  122.6398 N  tan  x  = 1.4156  x  = tan -1  (1.4156)  x  = 54.8º )    x  R Sense

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Mun unit5 cdp_slide_share

  • 1. Unit 2 Statics of Particles EGR 140 Engineering Mechanics: Statics Professor Mun
  • 2.
  • 3. For the following two-force coplanar system, determine the resultant force, R . 150 N 100 N 15  10  x y ) ) O
  • 4.
  • 5. Review of Right Triangle and Trigonometry Creative Commons: scherer.wikispaces.com/ Right + Triangle + Trigonometry +SOH+-+CAH+-+TOA - SOH CAH TOA
  • 6. 1. Resolve the force into its component forces along the axes: x- axis. 150 N 100 N 15  10  x y ) ) O 100 x 100 y 100 N 15  ) O 100 x 100 y Fx = F(cos  ) Fy = F(sin  ) 100 x = 100N (cos15 °) = 96.5926 N 100 y = 100N (sin15 °) = 25.8819 N
  • 7. 1. Resolve the force into its component forces along the axes: y- axis. 150 N 100 N 15  10  x y ) ) O 150 x 150 y Fx = F(sin  ) Fy = F(cos  ) 150 x = 150N (sin10 °) = 26.0472 N 150 y = 150N (cos10 °) = 147.7212 N 150 N 10  ) 150 x 150 y
  • 8.
  • 9.
  • 10. 4. Find the direction and sense. x y O R x = 122.6398 N R y = 173.6031 N R = 213 N )  x Angle of Inclination tan  x = R y /R x = 173.6031 N 122.6398 N tan  x = 1.4156  x = tan -1 (1.4156)  x = 54.8º )  x R Sense