ionic equation is 2 Cu+2(aq) + 4Cl-(aq) + 4 K+(aq)+ 4I-(aq) --> 2 CuI(s) + I2(aq) + 4 K+(aq)+ 4Cl-(aq) Solution ionic equation is 2 Cu+2(aq) + 4Cl-(aq) + 4 K+(aq)+ 4I-(aq) --> 2 CuI(s) + I2(aq) + 4 K+(aq)+ 4Cl-(aq).Read less