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Objectives: 
1. Write and use exponential functions
Any function where a > 0, 
b > 0, and b ≠ 1 is called an 
exponential function with base b. 
Domain: All Real Numbers 
Range: f(x) > 0 (positive real #s)
If f is an exponential function, 
f(0) = 3, and f(2) = 12, find f(-2). 
Solution: 
Substitute given values for x and f(x) 
into : 
f(0) = 3  3 = ab0 
b0 = 1, so a = 3 
f(2) = 12  12 = 3b2 
So b = 2 
 Therefore, f(x) = 3 ∙ 2x and f(-2) = ¾
If h is an exponential function such 
that h(0) = 5 and h(1) = 15, find h(x). 
Answer:
Remember, exp. growth and 
decay functions can be written 
A(t) = A0 (1 + r)t (Form 1) 
Can also be written A(t) = A0bt/k 
(Form 2) 
where 
k = time needed to multiply A0 by b
A bank states you can double 
your money in a savings account 
in 12 years. Express A(t) using 
both forms. What is the interest 
rate? 
Solution: 
(Form 2) A(t) = A0bt/k k = 12, b = 2 
 A(t) = A02t/12 Notice: A(12) = A0212/12 = 2A0 
(Form 1) A(t) = A0(21/12)t = A0(1.059)t 
 A(t) = A0(1 + 0.059)t 
r = 0.059  Interest rate = 5.9%
You invest $1000 in an 
account and your money triples 
in 15 years. What is the 
interest rate to the nearest 
tenth of a percent? 
Answer: 7.6%
A radioactive isotope has a half-life 
of 5 days. At what rate does 
the substance decay each day? 
Solution: 
A(t) = A0bt/k k = 5, b = 1/2 
 
r = 0.13  Rate = 13%
If a quantity is growing at rate r% 
per year (or month, etc.) then the 
doubling time is approximately 
(72 ÷ r) years (or months, etc.) 
For example, if a quantity grows 
at 8% per month, its doubling time 
will be about 72 ÷ 8 = 9 months.
An investment grows at a rate 
of 10% per year. About how 
long will it take to double your 
money? 
Solution: 
Use “Rule of 72”: (72 ÷ 10) = 7.2 
So, about 7 years.

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5 3 exponential functions

  • 1. Objectives: 1. Write and use exponential functions
  • 2. Any function where a > 0, b > 0, and b ≠ 1 is called an exponential function with base b. Domain: All Real Numbers Range: f(x) > 0 (positive real #s)
  • 3. If f is an exponential function, f(0) = 3, and f(2) = 12, find f(-2). Solution: Substitute given values for x and f(x) into : f(0) = 3  3 = ab0 b0 = 1, so a = 3 f(2) = 12  12 = 3b2 So b = 2  Therefore, f(x) = 3 ∙ 2x and f(-2) = ¾
  • 4. If h is an exponential function such that h(0) = 5 and h(1) = 15, find h(x). Answer:
  • 5. Remember, exp. growth and decay functions can be written A(t) = A0 (1 + r)t (Form 1) Can also be written A(t) = A0bt/k (Form 2) where k = time needed to multiply A0 by b
  • 6. A bank states you can double your money in a savings account in 12 years. Express A(t) using both forms. What is the interest rate? Solution: (Form 2) A(t) = A0bt/k k = 12, b = 2  A(t) = A02t/12 Notice: A(12) = A0212/12 = 2A0 (Form 1) A(t) = A0(21/12)t = A0(1.059)t  A(t) = A0(1 + 0.059)t r = 0.059  Interest rate = 5.9%
  • 7. You invest $1000 in an account and your money triples in 15 years. What is the interest rate to the nearest tenth of a percent? Answer: 7.6%
  • 8. A radioactive isotope has a half-life of 5 days. At what rate does the substance decay each day? Solution: A(t) = A0bt/k k = 5, b = 1/2  r = 0.13  Rate = 13%
  • 9. If a quantity is growing at rate r% per year (or month, etc.) then the doubling time is approximately (72 ÷ r) years (or months, etc.) For example, if a quantity grows at 8% per month, its doubling time will be about 72 ÷ 8 = 9 months.
  • 10. An investment grows at a rate of 10% per year. About how long will it take to double your money? Solution: Use “Rule of 72”: (72 ÷ 10) = 7.2 So, about 7 years.