I need help understanding how this linked list set method works in j.pdf

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I need help understanding how this linked list set method works in java, * Set value stored at location i to object o, returning old value. * * @pre 0 <= i < size() * @post sets ith entry of list to value o, returns old value * @param i location of entry to be changed. * @param o new value * @return former value of ith entry of list. */ public E set(int i, E o) { if (i >= size()) return null; Node finger = head; // search for ith element or end of list while (i > 0) { finger = finger.next(); i--; } // get old value, update new value E result = finger.value(); finger.setValue(o); return result; Solution Hi friend, Please go through comment, you can uderstand logic of set method. public E set(int i, E o) { // if given position number (i) is greater than current size of list, // then you can not set, because this is not valid position, so return null if (i >= size()) return null; Node finger = head; // initializing finger with head node of list // search for ith element or end of list while (i > 0) // traverse until we not hit ith node in list { finger = finger.next(); i--; } // now after above while loop, finger points ith node in list // get old value, update new value E result = finger.value(); // getting old value of ith node finger.setValue(o); // setting new value in ith node return result; }.

Education

// search for ith element or end of list
while (i > 0) // traverse until we not hit ith node in list
{
finger = finger.next();
i--;
}
// now after above while loop, finger points ith node in list
// get old value, update new value
E result = finger.value(); // getting old value of ith node
finger.setValue(o); // setting new value in ith node
return result;
}

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Java i have to make a method that takes a linked list and then returns a new linked list that is the reverse of the original this is the starting code /** * LinkedList lab. * @author Emma Cheney * @version 10/2/23 */ public class LinkedList { /** * Internal Node class used for the linked list. */ public class Node { String key; int value; Node next; /** * Node Constructor. * @param key The Key * @param value The Value */ public Node(String key, int value) { this.key = key; this.value = value; } } private Node head; private Node tail; /** * The default constructor. */ public LinkedList() { head = null; tail = null; } /** * Add the key, value pair to the head of the linkedlist. * @param key The Key * @param val The Value * */ public void addHead(String key, int val) { Node n = new Node(key, val); if (head == null) { head = n; tail = n; } else { n.next = head; head = n; } } /** * Add the key, val pair to the tail of the linkedlist. * @param key The Key * @param val The Value */ public void addTail(String key, int val) { Node n = new Node(key, val); if (tail == null) { head = n; tail = n; } else { tail.next = n; tail = n; } } /** * Returns the String format of the linkedlist. * @return String The String format. */ public String toString() { String ret = ""; Node curr = head; while (curr != null) { if (curr.next != null) { ret += curr.key + ":" + curr.value + ", "; } else { ret += curr.key + ":" + curr.value; } curr = curr.next; } return ret; } /** * Locate the Node in the linkedlist with the given key. * @param key The key to find in the LinkedList * @return Node Returns the Node with the given key or null if non-existent. */ private Node find(String key) { Node curr = head; while (curr != null) { if (curr.key.equals(key)) { return curr; } curr = curr.next; } return null; } A static method called reversed that takes a LinkedList as a parameter and returns a new LinkedList that is reversed. f; traverse through the input list (starting at the head). In order to reverse the ordering, you need to add the current node's key and value onto the head of the new list (addHead method). Do not change the input list or any values in it. Example (result in red) //assumelistcontainsthesekeysandvalues://ie:6,bi:48,bi:73,bi:63LinkedList.reversed(list);bi:63,bi: 73,bi:48,ie:6.

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According to analysts, the growth rate in dividends for YBM for the next five years is expected to be 20 percent. Suppose YBM meets this growth rate in dividends for the next five years and then the dividend growth rate falls to 5.25 percent, indefinitely. Assume investors require a return of 13 percent on YBM stock. According to the dividend growth model, what should the stock price be today? Note: Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Answer is complete but not entirely correct. Based on these assumptions, is the stock currently overvalued, undervalued, or correctly valued?.

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Note: Can someone help me with the Public boolean add(E value) method and Private void add(E value,Node n) method. I have everything but it is not working. Also need help with the remove methods. Both public and private methods for remove. package edu.ust.cisc; import java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList > implements CiscList { /** * A reference to this list's dummy node. Its next reference should refer to the node containing the first element * in this list, or it should refer to itself if the list is empty. The next reference within the node containing * the last element in this list should refer to dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list. */ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy = new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in this list. * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * This implementation should stop searching as soon as it is able to determine that the specified element is not * present. * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o==null){ throw new NullPointerException(); } return containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){ if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private Node prev = dummy; //private boolean canRemove = false; return new CiscLinkedListIterator(); } /** * Returns an array containing all of the elements in this list in proper sequence (from first to last element). * * The returned array will be "safe" in that no references to it are maintained by this list. (In other words, * this method must allocate a new array even if this list is backed by an array). The caller is thus free to modify * the returned array. * * @return an array containing all of the elements in this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new Object[size]; int i = 0; for(Node current = dummy;curren.

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Which of the following does NOT describe a mechanism that cells use to regulate enzyme activities? Cells control enzyme activity by phosphorylation and dephosphorylation of the enzyme Cells control enzyme activity by the binding of small molecules to regulatory sites on an enzyme Cells control the rates of diffusion of substrates to enzymes Cells control the rates of enzyme degradation Cells control the rates of enzyme synthesis Cells control the targeting of enzymes to specific organelles Solution The false statement is that cells control the rate of diffusion of substrates to enzymes. The mechanisms that regulate enzyme activities include-.

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Which of the following is NOT a reason to use frequency distribution.pdf

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When the body needs to conserve water, the kidneys excrete a hypertonic urine. What do the terms Isotonic and hypertonic mean? Since the fluid that is to become urine begins as plasma (an isotonic solution), what must happen change it to a hypertonic urine? Explain. Solution Answer An isotonic solution refers to two solutions that have same concentration of solutes, where as a hypertonic solution is the one where the concentration of solutes is greater than the other solution. So, the fluid that is to become urine begins as plasma is isotonic When this fluid passes through the different parts of Nephron (Bowmans capsule, Proximal convoluted tubule, distal convoluted tubule) it looses only water but not solutes Hence, the urine becomes more and more concentrated. This is known as hypertonic urine.

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What would be a typical phenotypic monohybrid ratio in which a lethal allele is involved?13:52:19:3:3:13:1 (it is not this one)6:2:3:1 Solution Answer- 2:1 Explanation- The normal genotypic ratio upon crossing two heterozygotes is 1(homozygous dominant) :2 (heterozygous):1(homozygous recessive). A 2:1 phenotypic ratio indicates that the homozygous recessive individuals show lethal gene effect and are not born..

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What two things are added to NADP+ to convert it into NADPH? H+ and electrons electrons and ATP H+ and ATP H+ and CO2 electrons and CO2 Solution H+ and electrons. NADP (Nicotinamide Adenine Dinucleotide Phosphate) exists in two forms: NADP+is the oxidized form andNADPHis the reduced form. NADP+ takes 2 electrons from Ferredoxin at the end of the electron transport chain to generate NADP. An H+ ion in the stroma binds through the extra electron, generating NADPH. All of this is facilitated by Ferredoxin-NADP+reductase..

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what is the medical term used for \" a dilated hair follicle filled with bacteria and sebum\"? Solution A dilated hair follicle filled with bacteria and sebum is medically called Comedo. Commonly it is said blackhead or whitehead. It is a clogged hair follicle in the skin. It comes from the latin word \"comedere\" meaning to eat up which was used to describe parasitic worms. In modern medical terminology it describes the worm like appearance of the expressed material..

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What is investigative reporting? How is it relevant to white collar crime? Why or Why not is it helpful in fighting white collar crime? Solution Investigative reporting: Criminal Investigative reporting also branded as criminal profiling is an analytical instrument use in the law enforcement group of people to assist solve aggressive crimes. The examination is based on an analysis of proof from the crime view and since witness and fatalities. Fraudulent and criminal activity include corruption and sleaze, fraud, fake accounting, possessions and money frauds, bank scam, income tax scam, insider commerce, money launder, cartel and standard fixing. Further business crime with trade standard and strength and security and surroundings breach. Defensive persons alongside whom allegation of scam have been ready, equally corporate entity and those Serving the fatalities of scam to locate, protect and recover thrift cash or property Representing witness in scam cases Conduct an inside examine for the acquire company in links with a likely scam in the gaining of a different corporation. The investigation result in the retailer recurring a important section of the sale proceeds to our customer, the acquirer. The FBI report in its Uniform Crime information that 14 million arrest for the entire crime in the US all through 2005, 118000+ be for forgery and counterfeit, 321000+ were for scam, and 18,900+ were for misappropriation. The prevalence of identity robbery has rise considerably in latest yrs as additional and more dealings of all type are handle slightly using telephone, Internet, and computers. Individuality thieves take personal data from fatalities, such as their social protection, credit/debit cards, or further recognition numbers, and then locate up new credit card accounts or else miss represent themselves as their fatalities to get currency, supplies, or services burdened..

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What impact did the Industrial Revolution have on American society between 1870 and 1940? Was it largely beneficial or not? Or was its impact more mixed? In your answer, be sure to consider the economic, social, and environmental consequences of industrialization. Solution Before the industrial revolution. America was an agrarian society. Almost everyone farmed. After the Industrial revolution, more people lived in cities and worked in factories than ever before. Cities grew larger and more crowded, which prompted the rise of better transportation, land speculation, real estate boom. The standard of living rose. The Industrial Revolution was a big turning point in American history. It changed the whole composition of families who had too move to the city so that they could work. It was one of the main contributions to the growth of cities. Frankly speaking early Industries weren\'t too fond of their workers either so this also led to the rise of labor unions that \'til this day still exist (your teacher is probably part of one). Big picture is that Industrial Revolution eventually led to the transportation revolution and also reduced the cost of production leading to mass production and cheaper items for Americans Considering the impact of the Industrial Revolution on American society is both complicated as well as interesting for the reason there are countless social issues to examine when analyzing the impact that this milestone era had upon the citizens of America. Primarily, though, the consequence of the Industrial Revolution is that, by means of making more effective the manufactured goods\' production, it aided to trim down the commodities costs for consumers, therefore allowing a number of items once measured luxuries to turn out to be within reach for vast sectors of American population. Together with the price structures reducing for a number of items, from crop tools to furniture to textiles, Americans took in a high standard of living. The increase in living standard of Americans translated to the nation\'s general public enjoying more amenities and conveniences for a comparatively economical cost. Moreover, the economy of the nation enjoyed spurts of outstanding growth all through this era on account of exports and consumer spending. One more advantage of the Industrial Revolution in this regard is that several jobs were created to fulfill the requirements of machinery operation and assembly lines..

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What are the major inputs to the MRP system? Solution Material requirements planning (MRP) is a computer-based inventory management system designed to assist production managers in scheduling and placing orders for items of dependent demand. Dependent demand items are components of finished goods—such as raw materials, component parts, and subassemblies—for which the amount of inventory needed depends on the level of production of the final product..

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Type I alveolar cells: (a) allow rapid diffusion of gases through their membranes. (b) secrete a chemical known as surfactant. (c) are phagocytic. (d) A, B, and C. (e) None of the above. Solution (a) allow rapid diffusion of gases through their membranes. Type I alveolar cells are squamous which gives more surface area to each cell and cover approximately 90–95% of the alveolar surface. Type I cells are involved in the process of gas exchange between the alveoli and blood. These cells are extremely thin.These cells need to be so thin to be readily permeable for enabling an easy gas exchange between the alveoli and the blood..

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The memory cycle times have been much longer than processor cycle times; this speed gap between the memory and the processor means that the processor must wait for memory to respond to an access request. The obvious method of increasing the speed of the memory system is by using a higher speed memory technology. Once the technology is selected, the access speeds can be increased further by different address decoding and access techniques. Described in details at least 3 of them Solution The different techniques are: 1. Banking: The main memory is built out of several physical-memory modules. Each and every module is a memory bank of a certain capacity and consists of a MAR and a MBR. In semiconductor memories, each module corresponds to either a memory IC or a memory board consisting of several memory ICs. The consecutive addresses lie in the same bank. If each bank contains 2n = N words and if there are 2m = M banks in the memor y, then the system MAR would contain n + m bits. 2. Multiport Memories: Multiple memories are available in which each port corresponds to an MAR and an MBR . Independent access to the memory can be made from each port. The memory system resolves the conflicts between the ports on a priority basis. Multiport memories are useful in an environment where more than one device accesses the memory. Examples of such systems are a single-processor system with a direct-memory access (DMA), I =O controller, and a multiprocessor system with more than one CPU. 3.Instruction Buffer: The instruction buffer, Providing a first-in, first-out (FIFO) buffer between the CPU and the primary memory enhances the instruction fetch speed . Instructions from the primary memory are fed into the buffer at one end and the CPU fetches the instructions from the other end. As long as the instruction execution is sequential, the two operations of filling the buffer and fetching from the buffer into CPU can go on simultaneously. But when a jump (conditional or unconditional) instruction is executed, the next instruction to be executed may or may not be in the buffer. The buffer management requires hardware component to manage the queue and mechanisms to identify the address range in the buffer and to freeze and unfreeze the buffer. INTEL 8086 processor uses a 6 -byte long instruction buffer organized as a queue. CDC 6600 uses an instruction buffer that can store eight 60-bit words, that is, 16–32 instructions, since the instructions are either 15- or 30-bits long..

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Suppose you land on a previously unexplored South Pacific island. You find three novel bird species. Two are small, one of these specializing in seed eating, the other in eating grubs and insects. Both show highly camouflaged coloration. The third bird species is substantially larger and is a dedicated predator; this third species specializes in preying on small rodents and the other two bird species. Its coat is brightly colored. Which of the following is the statement about the evolutionary relationships of these three species that we can make with the most confidence? [\"Relationship\" and \"relatedness\" here refers to phylogenetic history. Closely related species descended from the same ancestral species recently. In contrast, more distantly related species last had a common ancestor further in the past A) We cannot draw any conclusions about phylogenetic relationships of these species based on the data given; we would need additional data, like insights into selective history or fossil evidence. b.We cannot draw any conclusions about phylogenetic relationships of these species based on the data given; bird evolution works differently than mammalian evolution. Suppose you are a member of an island population of people that contains about 1000 individuals and that has remained stable in size (with no new immigration) for many dozens of generations. Now suppose you could time travel into the future 300 years (ten generations). Which of the answers below is the best description, first, of the fraction of the future population of the island that are expected to be your descendants (on average) and, second, how closely related you are to those future descendants in comparison to your relatedness to the other contemporary residents of the island? [Note that \"relatedness\" here refers to the specific parameter \"r\" as discussed it in TOPIC 5, that is, \"genetic relatedness\" from the gene\'s perspective.] Most or all of the future residents of the island would be my descendants and I would be more than twice as closely related to them than I am to any randomly chosen member of the contemporary population. Approximately 10% of the future population of the island would be my descendants and I would be roughly 10 times more closely related to them as I am to any randomly chosen member of the contemporary population. Most or all of the future residents of the island would be my descendants and I would be no more closely related to them than I am to any randomly chosen member of the contemporary population. d) Approximately 20% of the future population of the island would be my descendants and I would be roughly 5 times more closely related to them as I am to any randomly chosen member of the contemporary population. A) We cannot draw any conclusions about phylogenetic relationships of these species based on the data given; we would need additional data, like insights into selective history or fossil evidence. b.We cannot draw any conclusions abou.

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State two factors that have contributed to the development of emerging infectious diseases. For either Rabies or Anthrax, provide the following information: 1.Causative agent (e.g., viral, bacterial, parasitic) 2.Symptoms (at least two) 3.Geographic distribution 4.Host factors 5.Responsible vector 6.Potential human hazards 7.A method of control Solution 1. The causative agent of rabies is virus called Rabies virus (RV) or Lyssavirus which is a negative stranded ribonucleic acid virus belonging to rhabdovirus family. The causative agent of Anthrax is a bacillus bacterium called Bacillus anthracis which is a large Gram positive rod shaped aerobic belonging to Rhabdoviridae family. 2. The symptoms of Rabies are initially similar to flu which includes fever, muscle weakness and tingling. Other symptoms include insomnia, anxiety, excess salivation, hydrophobia, problems in swallowing etc. The symptoms of Anthrax are different depending upon the route of infection. The symptoms of cutaneous anthrax are raised itchy bump like insect bite alongwith swelling in the lymph glands and sore. The symptoms of gastrointestinal anthrax include nausea,vomiting, headache. loss of appetite, severe bloody diarrhoea, swollen neck etc. The symptoms of pulmonary anthrax include flu like symptoms with shortness of breath, coughing up blood, nausea etc.The symptoms of injection anthrax include redness and swelling of the area of infection, shock,meningitis, multiple organ failure etc. 3. Rabies is present in mammals in most parts of the world. Per year Most of the estimated 55 000 human rabies deaths occur in Africa and Asia. Sporadic cases of Anthrax occur in animals worldwide. However there are occasional outbreaks in Africa, central and southern Asia. 4. Like many rhabdoviruses, Rabies virus has an extremely wide host range. Many mammalian species in the wild has been found infecting , while in the laboratory it has been found that birds can be infected, as well as cell cultures from mammals, birds, reptiles and insects. Anthrax is spread from infectious animal products by contact with the spores of the bacteria. Contact is by breathing, eating, or through an area of broken skin. It does not typically spread directly between people. 5. There are three vectors for rabies: c. Tissue transplants (such as corneas) from infected humans. In its infectious form, anthrax is a spore that usually populates the soil but which, in rare cases, can become airborne and inhaled. With cutaneous anthrax, the bacteria infects the host through direct penetration of the host skin. It depends on the death of its host for propagation which is different from many pathogenic organisms. Once the host is dead, its body starts decaying and the bacteria in the bloodstream are exposed to oxygen. These bacteria turn into spores which populate the surrounding soil.. The spores can be eaten up by herbivores or from cutaneous infection. Anthrax does not appear to be transmissable from person to per.

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Recall the unambiguous grammar for arithmetic expressions discussed in class: Modify this grammar to allow an exponentiation operator, ^, so that we can write expressions like i+i^i*i. Of course, your modified grammar should be unambiguous. Give exponentiation higher precedence than the other binary operators and (unlike the other binary operators) make it associate to the right. Solution E -> E+T | E-T | T T -> T*Y | T/Y | Y Y -> F^Y | F F -> i | (E) with the above modified grammer you can easily write expresions like i+i^i*i and.

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Research and prepare a presentation to demonstrate a scenario in which object-based storage is a better choice over SAN and NAS. Solution Since there is no privelege to provide you an attachement of slide deck, we are providing you the scenario based idea in which object-based storage is a better choice over SAN and NAS.So here it is: Even though several storage type exists, a single type of storage solution doesnot fit everybody\'s needs. Object storage is of major importance (current pretty much good option) in large storage deployments, especially in the cloud based scenario. Representing the data may be different from storing data. Also, scaling out storage has strained both the NAS (Network Attached Storage) and SAN(Storage Attached Networks) storage models. SAN is a high speed network that makes connections between storage devices and servers.The server can only access data on the devices, which are directly attached to it.If server crashes or anything happens to the server, access to data will fail. There is a limit in the number of storage devices the server can access. SAN is primarily used for higher performance block level storage of data. Network Attached Storage shares files over the network. Not storage devices over the network. Any server that shares its own storage with others on the network and acts as a file server is an example for simplest form NAS. NAS devices are computers within themselves and shares their storage space with others. If you share a folder with access control using SAMBA, its NAS. NAS is primarily used for long distance small IO operations. Object storage which is famous in Cloud nowadays is like NAS but not exactly. Here each data block is replicated on serveral storage disks for integrity. Each of these storage models uses their own protocols. Object storage - Swift in OpenStack private cloud is good example. Ceph is also converged storage solution which is gaining momentum at highest rate nowadays.And Object storage is developer\'s choice where in data can be accessed anytime, easily & anywhere with an internet connection using REST APIs..

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QUESTION 1 Which ecological niche described below possesses the greatest number of prokaryotic cells (select one)? A. Oceanic and Terrestrial sub-surfaces B. In or on non-prokaryotic organisms (humans, animals and plants) C. Dry land D. Lakes, rivers and oceans E. Earth stratosphere 1 points Saved QUESTION 2 Which organism was primarily responsible for oxygenation of the earth approximately 2 billion years ago (select one)? A. cyanobacteria B. Wooly mammoths C. Green sulfur bacteria D. Thermophilic archaea E. algae 1 points Saved QUESTION 3 The earliest microorganisms were likely restricted to deep ocean and sub-surface ecological niches until which of the following (select one)? A. Ozone layer developed B. Aquatic life carried them to land C. Phototrophy evolved D. Chemolithotrophy developed E. The development of chemoorganotrophy 1 points Saved QUESTION 4 Two tubes are inoculated from one test tube of a bacterial culture. The cultures are then transferred every day for 2 months. All of the media and growth conditions are the same in every tube. After 2 months of cultivation, the fitness and genotype frequencies of the populations in the two tubes are compared. The fitness of the two cultures is the same, but the genotype frequencies are very different in the two cultures. How is this possible? A. This result is not possible because different genotype frequencies would result in different fitness levels under the same growth conditions. B. Genetic drift within the small populations in the test tubes resulted in different genotype frequencies. C. It is highly unlikely that any bacterial culture could be maintained for 2 months D. Natural selection caused the evolution of different genotype frequencies within the separate test tubes. E. Two months is not long enough for different fitness levels to evolve even if the genotype frequencies change. 1 points Saved QUESTION 5 If you allowed 20 identical parallel Listeria cultures to evolve for 20,000 generations under new growth conditions with very little nitrogen, the parallel cultures would do which of the following (select one)? A. Direct mutations to occur in nitrogen utilization and uptake genes in order to adapt rapidly to the culture conditions B. Each parallel culture would accumulate different random mutations resulting in different adaptations to use the nitrogen in the media. C. Evolve identical adaptations to use the nitrogen source provided in the media D. Not change or adapt significantly over this small number of generations E. Each culture would evolve to use arsenic in place of nitrogen 1 points Save Answer QUESTION 6 Which of the following statements are correct about the early formation of life on earth (select all that apply)? A. Lateral gene transfer is one plausible explanation as to why organisms in Archaea, Bacteria, and Eukarya still share so many genes among such distinct domains. B. The domains of life arose as barriers between gene exchange evolved between organisms C. W.

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Practice assembly question need help Given the following array declaration: .data matrix DWORD 50 DUP(10 DUP(?)) If matrix[0][0] is the 0th sequentially stored BYTE in memory, which sequentially stored BYTE is the first byte corresponding to matrix[37][0]? Solution here DWORD 50 DUP(10 DUP(?)) It defines a 50X10 matrix and initializes its element to the value what we give in place of (?) is taken. here 0 is the 0th sequential stored then 37th would be the 37th sequential byte.

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One of the main purposes of a bus system is to allow the exchange of information and/or data between different devices. Describe an activity that you engage in that involves features similar to those of a synchronous bus system and one that involves features similar to those of an asynchronous bus system. Explain in each case how the advantages and features of the bus system apply to the activities that you listed. Solution Advantages of bus system 1) It is easy to set-up and extend to any number of peers 2) Cable length required for this system is the least compared to other networks.so no clogging of wires 3) cheaper compared to other systems 4) Genarally benificial for local area networks 5)Easier maintainence syncronous:When information is sent to a particular host and expects a reply from the host .sender will wait for response for furtur continueed operation asyncronous:Information is sent randomly over the network.all the hosts can access and read it.sender wont wait for responce.

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Most American\'s are immune to the bacterium that causes Leprosy, does that mean that most American\'s are also, immune to TB and Crohn\'s disease? Or are the different strands of myobacterium much more contagious and less easy to fight off? Pathophysiciology Course question Solution 9. Leprosy Transmitted by nasal droplets. Leprosy occurs during close contact with those who are infected 10. TB can spread when patient cough, sneeze, speak, sing, or spit, they expel infectious aerosol droplets.

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