The first table contains data of the Student entry. Attributes are Si.pdf

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say you have some pictures each 500 KB in size. Say you also go to a store and buy a new desktop computer. Approximately how many pictures could you put on the hard disk, assuming you could use all the space on the disk for your pictures? there is a range of possible answers; you must use a hard disk size that is reasonable for a new desktop computer. show arithmetic. Solution say if u purchase a 1 GB hard disk,then 1 GB = 1000MB=10^6 KB ,so each 500 KB size then u can store upto 10^6/500 =2000 photos. similarly 1 TB HArd disk=1000GB = 10^9 KB= no of pictures can be stored is 2*10^6 ...

Education

The first table contains data of the Student entry. Attributes are Sid, Name. and GPA. The
second table is the Department entity. The attribute is DID (department ID). The foreign key is
student's ID (Sid) Insert value for the new attribute Age to the Student entity make the table like.
Solution
Writing stetements in SQL:
ALTER TABLE Student ADD Age int; //adds age column to table and initialize values to null
UPDATE Student SET Age = 20 WHERE Sid = 001; //updating 001 student age to 20
UPDATE Student SET Age = 22 WHERE Sid = 002;
UPDATE Student SET Age = 35 WHERE Sid = 003;
By wrirting these above SQL statements it modifies into new table.

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