The precations to be given to the workers areSolutionThe prec.pdf

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The precations to be given to the workers are: Solution The precations to be given to the workers are:.

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SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf

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oxygen double bond oxygen .pdf

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Once HCl is added in solution, the ions would dissociate into their component parts (H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle. Best of wishes! (: Solution Once HCl is added in solution, the ions would dissociate into their component parts (H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle. Best of wishes! (:.

Once HCl is added in solution, the ions would dis.pdf

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its e1 OMe attacks at 3-position by transfer of a.pdf

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H and F are identical, you just need to rotate H until it matches F, I is also identical to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super imposable on their mirror image) to each other. Solution H and F are identical, you just need to rotate H until it matches F, I is also identical to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super imposable on their mirror image) to each other..

H and F are identical, you just need to rotate H .pdf

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From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can hydrogen-bond because of the OH group so it would have the strongest intermolecular force. Pentane would have weakest because it has no electronegative atoms. Solution From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can hydrogen-bond because of the OH group so it would have the strongest intermolecular force. Pentane would have weakest because it has no electronegative atoms..

From weakest to strongest A, B, C Butanal is an .pdf

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Effusion is inversely proportional to the mass. .pdf

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Benzoin and methanol both have an alcohol group, but benzoin has a ketone group and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi system, meaning that electrons from the phenyl groups can shift around the double bonds throughout the whole molecule without effecting anything; this also impacts the ketone group. This is also known as resonance, you can see an example here http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R) If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant electrons will, in comparison, just look like... R-OH When placed side by side this is how both molecules will act with each other. Therefore the polarities of both molecules are similar because electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a conjugated R group). Solution Benzoin and methanol both have an alcohol group, but benzoin has a ketone group and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi system, meaning that electrons from the phenyl groups can shift around the double bonds throughout the whole molecule without effecting anything; this also impacts the ketone group. This is also known as resonance, you can see an example here http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R) If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant electrons will, in comparison, just look like... R-OH When placed side by side this is how both molecules will act with each other. Therefore the polarities of both molecules are similar because electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a conjugated R group)..

Benzoin and methanol both have an alcohol group, .pdf

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When acid and base react together they form salt and water.This reaction is known as Neutralization Reaction. ForExample HCl+NaOH ---------> NaCl + H2O HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt (table salt) These reactions are also reversible reactions. Solution When acid and base react together they form salt and water.This reaction is known as Neutralization Reaction. ForExample HCl+NaOH ---------> NaCl + H2O HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt (table salt) These reactions are also reversible reactions..

When acid and base react together they form salt and water.This reac.pdf

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There are 37 classes in java.lang package as per Java SE7 The java.pdf

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The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf

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At 1700 cm-1 a strong signal in an IR spectum is .pdf

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Result: best_fit_for_X1 = DistName: \'tlocationscale\' NLogL: 2.1206e+03 BIC: 4.2620e+03 AIC: 4.2472e+03 AICc: 4.2473e+03 ParamNames: {\'mu\' \'sigma\' \'nu\'} ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'} Params: [1.0071 1.9637 37.4643] Paramci: [2x3 double] ParamCov: [3x3 double] Support: [1x1 struct] best_fit_for_X2 = DistName: \'generalized extreme value\' NLogL: 2.4968e+03 BIC: 5.0142e+03 AIC: 4.9995e+03 AICc: 4.9995e+03 ParamNames: {\'k\' \'sigma\' \'mu\'} ParamDescription: {\'shape\' \'scale\' \'location\'} Params: [-0.2802 2.9571 1.0858] Paramci: [2x3 double] ParamCov: [3x3 double] Support: [1x1 struct] correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent) meanY = 3.1394 varY = 12.8269 meanZ = 4.1492 varZ = 25.1576 correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent) Code: function main load X.mat [D PD]=allfitdist(X1,\'NLogL\'); [D2 PD2]=allfitdist(X2,\'NLogL\'); %best fit using maximum likelihood best_fit_for_X1=D(1) best_fit_for_X2=D2(1) correlation_between_X1_X2=correlation(X1,X2) Y=X1+X2; Z=2*X1+X2; meanY=mean(Y) varY=var(Y) meanZ=mean(Z) varZ=var(Z) correlation_between_Y_Z=correlation(Y,Z) end function[r]=correlation(x,y) avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain, avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops exy = sum((x - avx).*(y - avy)); %Are interpreted slowly. r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual. end function [D PD] = allfitdist(data,sortby,varargin) %ALLFITDIST Fit all valid parametric probability distributions to data. % [D PD] = ALLFITDIST(DATA) fits all valid parametric probability % distributions to the data in vector DATA, and returns a struct D of % fitted distributions and parameters and a struct of objects PD % representing the fitted distributions. PD is an object in a class % derived from the ProbDist class. % % [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions % sorted by the parameter SORTBY % NLogL - Negative of the log likelihood % BIC - Bayesian information criterion (default) % AIC - Akaike information criterion % AICc - AIC with a correction for finite sample sizes % % [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete % distribution and does not attempt to fit a continuous distribution % to the data % % [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF % of a subset of the fitted distribution. The distributions are plotted in % order of fit, according to SORTBY. % % List of distributions it will try to fit % Continuous (default) % Beta % Birnbaum-Saunders % Exponential % Extreme value % Gamma % Generalized extreme value % Generalized Pareto % Inverse Gaussian % Logistic % Log-logistic % Lognormal % Nakagami % Normal % Rayleigh % Rician % t location-scale % Weibull % % Discrete (\'DISCRETE\') % Binomial % Negative binomial % Poisson % % Optional inputs: % [...] = ALLFITDIST(...,\'n\',N,...) % For the \'binomial\' .

Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf

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Please rate the solution give thumbs if this is helpful. Impact of data quality on business performance: Functions of the database technology: Differences between centralized and distributed database architecture: The role of a master reference file: Solution Please rate the solution give thumbs if this is helpful. Impact of data quality on business performance: Functions of the database technology: Differences between centralized and distributed database architecture: The role of a master reference file:.

Please rate the solution give thumbs if this is helpful.Impact of .pdf

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Please find the answers and explanations below: Part 1 (True/False) 1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction. .Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from it thus the orientation of transcription is necessarily 5\' to 3\' in nature) 2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme which is required for maintenance of terminal positions of chromosomes by self-replication and prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the body.) 3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information for translation is transcribed from the DNA template. The tRNA is utilized to transfer the transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal surface during translation) 4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA located upstream the gene to be transcribed and carries the consensus sequence which could be recognized by RNA polymerase for its binding and carrying on transcription) 5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only one kind of amino acid which it could carry. It is a highly stringent and specific nature of this biomolecule which determines the specificness for the amino acid which will be synthesized from the codon) Part 2 Please find the definitions below: 1. Semi-conservative replication: The mode of replication of double stranded DNA in which a daughter DNA molecules carries a strand from parent DNA and the complementary strand is synthesized de novo is called semi-conservative replication. 2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of DNA are finally conjoined together to form a continous strand of newly synthesized DNA. 3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA which remain similar (upto 99%) within organisms of same or different species and are actively engaged in crucial functions such as promoter region binding, transcription sites for transcription factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be highly deletrious for the cells. 4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order and encode for a specific type of amino acid upon translation. For example, the codon AAA encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .

Please find the answers and explanations belowPart 1 (TrueFalse).pdf

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Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf

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Instruction set architecture of a machine fill the semantic gap between the user And the machines. And serve as the early point for the design of a new machine or Modification of existing ones. ISA design must describe how memory addresses are interpret and specified in the Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique address. There are two different conventions for ordering bytes within a word one is Little Endian and the other Big Endian Example: Big Endian Little Endian Address value Address value 1000 90 1000 CD 1001 AB 1001 12 1002 12 1002 AB 1003 CD 1003 90 Physical register file is an array of computer registers in a CPU more difficult CPUs use register so that the mapping of which physical entry supplies a particular architectural register change dynamically throughout execution Example: Physical register Id LastUseItag --- --- (p-1) 145 Solution Instruction set architecture of a machine fill the semantic gap between the user And the machines. And serve as the early point for the design of a new machine or Modification of existing ones. ISA design must describe how memory addresses are interpret and specified in the Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique address. There are two different conventions for ordering bytes within a word one is Little Endian and the other Big Endian Example: Big Endian Little Endian Address value Address value 1000 90 1000 CD 1001 AB 1001 12 1002 12 1002 AB 1003 CD 1003 90 Physical register file is an array of computer registers in a CPU more difficult CPUs use register so that the mapping of which physical entry supplies a particular architectural register change dynamically throughout execution Example: Physical register Id LastUseItag --- --- (p-1) 145.

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all real numbers .pdf

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In the given text the following phrases reflect scientific approach of studying Homo floresiensis. Comparing height with the modern humans: would stand waist high. Studying the features of skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size of a chimpanzee’s. All these reflect a scientific approach where the species is compared with modern humans and conclusions drawn from the observations. Sometimes science cannot answer all questions like the existence of supernatural powers and beings. Moreover evolution denies the role of God in the universe. One theory beyond science is that life on earth is created by gods. Science does not explain the existence of gods or if super natural entities intervene in human affairs. This explanation is beyond the nature and so beyond the scope of what can be studied by science. This theory of origin of human beings is a belief. Science is an activity that seeks to explore the natural world using well-established, clearly- delineated methods. Scientific method is based on the fact of asking a question, formulating a hypothesis, performing experiments, collecting data and drawing conclusions. Studying human evolution in a scientific way enables in better understanding of our origin and evolution. Understanding the process by which Homo sapiens came into existence is crucial for understanding the kind of creature we are and this is possible by studying scientifically. Solution In the given text the following phrases reflect scientific approach of studying Homo floresiensis. Comparing height with the modern humans: would stand waist high. Studying the features of skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size of a chimpanzee’s. All these reflect a scientific approach where the species is compared with modern humans and conclusions drawn from the observations. Sometimes science cannot answer all questions like the existence of supernatural powers and beings. Moreover evolution denies the role of God in the universe. One theory beyond science is that life on earth is created by gods. Science does not explain the existence of gods or if super natural entities intervene in human affairs. This explanation is beyond the nature and so beyond the scope of what can be studied by science. This theory of origin of human beings is a belief. Science is an activity that seeks to explore the natural world using well-established, clearly- delineated methods. Scientific method is based on the fact of asking a question, formulating a hypothesis, performing experiments, collecting data and drawing conclusions. Studying human evolution in a scientific way enables in better understanding of our origin and evolution. Understanding the process by which Homo sapiens came into existence is crucial for understanding the kind of creature we are and this is possible by studying scientifically..

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