The area is how many Hydrogens are on the graph. .pdf
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The area is how many Hydrogens are on the graph. You would need a correlation table to determine what groups are on the figure. First, calculate the degrees of saturation. (18- 10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene Solution The area is how many Hydrogens are on the graph. You would need a correlation table to determine what groups are on the figure. First, calculate the degrees of saturation. (18- 10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
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When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Recommended
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
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Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
import java.util.ArrayList; import jave array list import javax.pdf
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i
Solution
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i.
Digital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments Unit - NGV Pavilion Concept Design
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Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
import java.util.ArrayList; import jave array list import javax.pdf
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i
Solution
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i.
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