its e1 OMe attacks at 3-position by transfer of a.pdf
•
0 likes•2 views
its e1 OMe attacks at 3-position by transfer of anion to stable form Solution its e1 OMe attacks at 3-position by transfer of anion to stable form.
Report
Share
Report
Share
Download to read offline
Recommended
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
Recommended
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
import java.util.ArrayList; import jave array list import javax.pdf
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i
Solution
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i.
The Diamonds of 2023-2024 in the IGRA collection
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
More Related Content
More from aparnatiwari291
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
import java.util.ArrayList; import jave array list import javax.pdf
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i
Solution
import java.util.ArrayList; // import jave array list
import javax.swing.JOptionPane; // import java option pane
// JoptioPane Demo from Class Handouts
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class AttackMonitor {
ArrayListattacks = new ArrayList(); //part I
// should we set it in \"private list?
// input function
void input(){
// declare same values from attack class
String Monstername, location, date;
int id;
int Victim_number;
// id monstername, location, date, victim number
id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id: \"));
Monstername = JOptionPane.showInputDialog(\"Enter the monster\'s name: \");
location = JOptionPane.showInputDialog(\"Enter the attacked location: \");
date = JOptionPane.showInputDialog(\"Enter the date: \");
Victim_number = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the Victim numbers:
\"));
//
attack temp = new attack(id,date,Monstername,location,Victim_number); //// id monstername,
location, date, victim number
attacks.add(temp);
} // end function
// display function
void display(){
for (int i= 0; i< attacks.size(); i++){ // keep doing it till i reach attacks time
System.out.println(attacks.get(i));
} // end for
} // end function
// delete function
void delete(){
display();
// get attack id to delete
int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\"));
int i;
for (i= 0; i.
More from aparnatiwari291 (20)
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dis.pdf
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H .pdf
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest A, B, C Butanal is an .pdf
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. .pdf
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, .pdf
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reac.pdf
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7 The java.pdf
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers areSolutionThe prec.pdf
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is .pdf
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap betw.pdf
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach .pdf
import java.util.ArrayList; import jave array list import javax.pdf
import java.util.ArrayList; import jave array list import javax.pdf
Recently uploaded
The Diamonds of 2023-2024 in the IGRA collection
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
Delivering Micro-Credentials in Technical and Vocational Education and Training
Explore how micro-credentials are transforming Technical and Vocational Education and Training (TVET) with this comprehensive slide deck. Discover what micro-credentials are, their importance in TVET, the advantages they offer, and the insights from industry experts. Additionally, learn about the top software applications available for creating and managing micro-credentials. This presentation also includes valuable resources and a discussion on the future of these specialised certifications.
For more detailed information on delivering micro-credentials in TVET, visit this https://tvettrainer.com/delivering-micro-credentials-in-tvet/
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...Nguyen Thanh Tu Collection
https://app.box.com/s/hqnndn05v4q5a4k4jd597rkdbda0fniiThe simplified electron and muon model, Oscillating Spacetime: The Foundation...
Discover the Simplified Electron and Muon Model: A New Wave-Based Approach to Understanding Particles delves into a groundbreaking theory that presents electrons and muons as rotating soliton waves within oscillating spacetime. Geared towards students, researchers, and science buffs, this book breaks down complex ideas into simple explanations. It covers topics such as electron waves, temporal dynamics, and the implications of this model on particle physics. With clear illustrations and easy-to-follow explanations, readers will gain a new outlook on the universe's fundamental nature.
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Digital Artifact 2 - Investigating Pavilion Designs
Digital Artifact 2 - Pavilions
NGV Architecture Commission Competition
MPavilion Commission Competition
Other Pavilion Designs
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaHow to Add Chatter in the odoo 17 ERP Module
In Odoo, the chatter is like a chat tool that helps you work together on records. You can leave notes and track things, making it easier to talk with your team and partners. Inside chatter, all communication history, activity, and changes will be displayed.
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
Advantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO Perspective
Top five deadliest dog breeds in America
Thinking of getting a dog? Be aware that breeds like Pit Bulls, Rottweilers, and German Shepherds can be loyal and dangerous. Proper training and socialization are crucial to preventing aggressive behaviors. Ensure safety by understanding their needs and always supervising interactions. Stay safe, and enjoy your furry friends!
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Recently uploaded (20)
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
Delivering Micro-Credentials in Technical and Vocational Education and Training
Delivering Micro-Credentials in Technical and Vocational Education and Training
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
Landownership in the Philippines under the Americans-2-pptx.pptx
Landownership in the Philippines under the Americans-2-pptx.pptx
Digital Artefact 1 - Tiny Home Environmental Design
Digital Artefact 1 - Tiny Home Environmental Design
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
Digital Artifact 2 - Investigating Pavilion Designs
Digital Artifact 2 - Investigating Pavilion Designs
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Advantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO Perspective
its e1 OMe attacks at 3-position by transfer of a.pdf
- 1. its e1 OMe attacks at 3-position by transfer of anion to stable form Solution its e1 OMe attacks at 3-position by transfer of anion to stable form