Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
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Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock + Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock + Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000 + - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 = 70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA (3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - = 17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + + 1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 = 70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000 Solution Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock + Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock + Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000 + - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 = 70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA (3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - = 17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + + 1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 = 70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
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Accounting question Assets Current - Long term Liabilities Curre.docx
Accounting question
Assets Current
=
Long term
Liabilities Current
+
Long term
Capital Stock
Retained
+Revenues
Stockholders Equity
+ Retained Earnings
Expenses
+Gains/
Losses Dividends
Cash Inventory Building
Accounts Payable
Unearned
Revenue Loan payable
Earnings from last
Cost of goods
sold Utilities Wages
$ 17,000
$
2,700
$ 46,000
$ 2,000
$ 900
$ 37,000
$ 20,000
$ 5,800
Balance from last accounting period
$ (5,000)
$ 50,000
$ 45,000
A
$
4,200
$ 4,200
Purchased $4,200 of inventory on credit
$ (950)
B
Paid 950 to employees for work during accounting period
$ 3,200
$
(1,400)
$ 3,200
$ (1,400)
C
D
$
(260)
Received bill for $260 for utilities
$ (50)
$ (50)
E
F
G
$ 14,200
$ 96,000
$ 6,460
$ 900
$ 20,000
$ 5,800
$ 3,200
$ (1,400) $
(260) $
(950) $
$ (50)
$
115,700
= H + $
26,340
Liabilities $ 115,700
Revenues COGS
$ 3,200
$ 1,400 (Not listed as negative since we always know expenses are subtracted) Beginning cash
$ 17,000
Gross Profit
I
Assets
Operating
Utilities
$ 260
Cash
L
Cash from sales
P
Other
$ 950
Inventory
$ 5,500
Payment to employees
$ (950)
Net Income
$ 590
Building
M
$ 2,250
Total
$ 115,700
Investing
Statement of Equity Capital Sto
Last Period $ 20,000
Retained Earnings Liabilities Cash paid for building
J Accounts Payable $ 6,460
Q
Sale of stock
Unearned Revenue
$ 900
Net Income
K
Loan Payable
$ 82,000
Financing
Dividends
$ (50)
Total
$ 89,360
End of period
$ 20,000 $ 6,340
Stockholders Equity
Dividends
$ (50)
Capital Stock
$ 20,000
$ (50)
Retained Earnings
N
Ending Cash
$ 14,200
Total Equity
$ 26,340
Liabilities and Equity
0
.
Introductory Financial Accounting for Business 1st Edition Edmonds Solutions ...
Full download : https://goo.gl/pGctpg Introductory Financial Accounting for Business 1st Edition Edmonds Solutions Manual
Recommended
Accounting question Assets Current - Long term Liabilities Curre.docx
Accounting question
Assets Current
=
Long term
Liabilities Current
+
Long term
Capital Stock
Retained
+Revenues
Stockholders Equity
+ Retained Earnings
Expenses
+Gains/
Losses Dividends
Cash Inventory Building
Accounts Payable
Unearned
Revenue Loan payable
Earnings from last
Cost of goods
sold Utilities Wages
$ 17,000
$
2,700
$ 46,000
$ 2,000
$ 900
$ 37,000
$ 20,000
$ 5,800
Balance from last accounting period
$ (5,000)
$ 50,000
$ 45,000
A
$
4,200
$ 4,200
Purchased $4,200 of inventory on credit
$ (950)
B
Paid 950 to employees for work during accounting period
$ 3,200
$
(1,400)
$ 3,200
$ (1,400)
C
D
$
(260)
Received bill for $260 for utilities
$ (50)
$ (50)
E
F
G
$ 14,200
$ 96,000
$ 6,460
$ 900
$ 20,000
$ 5,800
$ 3,200
$ (1,400) $
(260) $
(950) $
$ (50)
$
115,700
= H + $
26,340
Liabilities $ 115,700
Revenues COGS
$ 3,200
$ 1,400 (Not listed as negative since we always know expenses are subtracted) Beginning cash
$ 17,000
Gross Profit
I
Assets
Operating
Utilities
$ 260
Cash
L
Cash from sales
P
Other
$ 950
Inventory
$ 5,500
Payment to employees
$ (950)
Net Income
$ 590
Building
M
$ 2,250
Total
$ 115,700
Investing
Statement of Equity Capital Sto
Last Period $ 20,000
Retained Earnings Liabilities Cash paid for building
J Accounts Payable $ 6,460
Q
Sale of stock
Unearned Revenue
$ 900
Net Income
K
Loan Payable
$ 82,000
Financing
Dividends
$ (50)
Total
$ 89,360
End of period
$ 20,000 $ 6,340
Stockholders Equity
Dividends
$ (50)
Capital Stock
$ 20,000
$ (50)
Retained Earnings
N
Ending Cash
$ 14,200
Total Equity
$ 26,340
Liabilities and Equity
0
.
Introductory Financial Accounting for Business 1st Edition Edmonds Solutions ...
Full download : https://goo.gl/pGctpg Introductory Financial Accounting for Business 1st Edition Edmonds Solutions Manual
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
A Strategic Approach: GenAI in Education
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
How to Make a Field invisible in Odoo 17
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
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When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as below:
EmployeeDemo.java
import java.util.Scanner;
public class EmployeeDemo
{
static Scanner scan = new Scanner(System.in);
public static void main(String[] args)
{
Company clerk = new Company( );
Employee employee = new Employee();// one student
int count,dependent;
String fname,lname;
float hourly_rate,no_of_hours,l_tax,f_tax,s_tax;
System.out.println(\"Enter number of employees:\");
int numberOfEmployees = scan.nextInt();
for (count = 0; count < numberOfEmployees; count++)
{
System.out.println(\"Enter data for employee number \" + count);
System.out.println(\"First Name \");
fname = scan.next();
System.out.println(\"Last Name \");
lname = scan.next();
System.out.println(\"Number of dependents \");
dependent = scan.nextInt();
System.out.println(\"Hourly rate \");
hourly_rate = scan.nextFloat();
System.out.println(\"Number of hours worked \");
no_of_hours = scan.nextFloat();
System.out.println(\"Local tax withheld to date \");
l_tax = scan.nextFloat();
System.out.println(\"Federal tax withheld to date \");
f_tax = scan.nextFloat();
System.out.println(\"State tax withheld to date \");
s_tax = scan.nextFloat();
employee.readInput(fname,lname,dependent,hourly_rate,no_of_hours,l_tax,f_tax,s_tax);
employee.calculateData(count);
employee.writeOutput(count);
clerk.colectDataForCompanyReport(employee,count);
}
clerk.printDataForCompanyReport();
}
}
Employee.java
import java.util.ArrayList;
public class Employee {
private ArrayList fname,lname;
private ArrayList dependent;
private ArrayList
hourly_rate,no_of_hours,l_tax,f_tax,s_tax,g_wages,cf_tax,cl_tax,cs_tax,t_tax,ct_tax,net_pay;
public Employee(){
fname = new ArrayList();
lname = new ArrayList();
dependent = new ArrayList();
hourly_rate = new ArrayList();
no_of_hours = new ArrayList();
l_tax = new ArrayList();
f_tax = new ArrayList();
s_tax = new ArrayList();
g_wages = new ArrayList();
cl_tax = new ArrayList();
cf_tax = new ArrayList();
cs_tax = new ArrayList();
t_tax = new ArrayList();
ct_tax = new ArrayList();
net_pay = new ArrayList();
}
public ArrayList getFname() {
return fname;
}
public void setFname(ArrayList fname) {
this.fname = fname;
}
public ArrayList getLname() {
return lname;
}
public void setLname(ArrayList lname) {
this.lname = lname;
}
public ArrayList getDependent() {
return dependent;
}
public void setDependent(ArrayList dependent) {
this.dependent = dependent;
}
public ArrayList getHourly_rate() {
return hourly_rate;
}
public void setHourly_rate(ArrayList hourly_rate) {
this.hourly_rate = hourly_rate;
}
public ArrayList getNo_of_hours() {
return no_of_hours;
}
public void setNo_of_hours(ArrayList no_of_hours) {
this.no_of_hours = no_of_hours;
}
public ArrayList getL_tax() {
return l_tax;
}
public void setL_tax(ArrayList l_tax) {
this.l_tax = l_tax;
}
public ArrayList getF_tax() {
return f_tax;
}
public void setF_tax(ArrayList f_tax) {
this.f_tax = f_tax;
}
public ArrayList getS_tax() {
return s_tax;
}
public void setS_tax(ArrayList s_tax) {
this.s_tax = s_ta.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
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When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will alway.pdf
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
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there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post.pdf
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its e1 OMe attacks at 3-position by transfer of a.pdf
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H and F are identical, you just need to rotate H .pdf
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There are 37 classes in java.lang package as per Java SE7 The java.pdf
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The precations to be given to the workers areSolutionThe prec.pdf
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- 1. Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock + Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock + Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000 + - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 = 70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA (3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - = 17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + + 1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 = 70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000 Solution Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock + Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock + Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000 + - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 = 70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA (3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - = 17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + + 1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 = 70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000