Essay On Linear Function

Essay On Linear Function
Usually, translation involves only moving the graph around. To get started, let'sconsider one of the simpler types of functions that you have graphed;
namely, quadratic functions and their associated parabolas. If you have been doing your graphing by hand, you have probably started noticing some
relationships betweenthe equations and the graphs. This is always true: To move a function up, you add outside the function: f b are f moved up b units.
Moving the function down works the same way; f –b is f moved down b units. If you losetrack, think about the point on the graph where x = 0. The
first, flipping upside down, is found by takingthe negative of the original function; that is, the rule for this transformation is –f. To see how this ... Show
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Typical homework problems on this topic ask you tograph the transformation of a function, given the original function, or else askyou to figure out the
transformation, given the comparative graphs. Sometimes you will be given a point, or a graph with clearly plotted points, andtold to translate the
point(s) according to some rule. In other words, they won'tbe giving you a function, per se, to move; instead, you will be given points to move, and you
will have to know how to flip them around the axis systemyourself. Given the following graph of f, graph the transformation –f – 3. I have no formula
forf, so I cannot cheat; I have to do the transformation myself, point by point. Theway the original graph is drawn, there are four clearly plotted points
that I canuse to keep track of things. If I move the plotted points successfully, then I canfill in the rest of the graph once I am done. Now that I have
moved all the points, Ican graphs the transformation. Then pick a point to move, and trace out the sequence of steps with yourpencil tip, drawing in the
translated point once you reach its final location. Once you have moved all of the points, you can draw in the transformation. The other exercise type is
when you are given two graphs, one being theoriginal function and the other being the transformed function, and you are askedto figures out the
formula for the transformation.
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Derivative and Graph
CALCULATOR SECTION
1. For find at the point (3, 4) on the curve.
A. B. C. D. E.
2. Suppose silver is being extracted from a mine at a rate given by , A(t) is measured in tons of silver and t in years from the opening of the mine.
Which is an expression for the amount of silver extracted from the mine in the first 5 years of its opening?
A. B. C. D. E.
3. Joe Student 's calculus test grades (G) are changing at the rate of 2 points per month. Which is the expression that says this?
A. B. C. D. E.
4. If f is a continuous and differentiable function, then approximate the ... Show more content on Helpwriting.net ...
A. Points A and B B. Points A and D C. Points B and D D. Points B and C E. Points A and C
18.
The graph of is shown above, on the interval [ –5, 5] . Which is true?
A. The graph is continuous and differentiable. B. The graph is continuous but not differentiable. C. The graph is not continuous but is differentiable. D.
The graph is not continuous nor differentiable.
19. Graph in the plane above, over the window [–1, 8] X [–25, 25].
20. Give the x–interval(s) where the graph of g is increasing. GIVE A REASON for your answer.
21. Give the x–interval(s) where the graph of g is concave up. GIVE A REASON for your answer.
22. Give the x–coordinates of any critical points for the graph of g. For each tell if it is a relative maximum, a relative minimum or neither. EXPLAIN.
23. Give the x–coordinate of any points of inflection of the graph of g.
24. If is the velocity function for a particle moving along the x–axis, for time seconds, tell ...
A. when the particle changes direction. for .
B. for what intervals of time () the particle is moving to the left.
C. for what intervals of time

Distribution Of Minimum Spanning Trees
Distributed Veriﬁcation of Minimum Spanning Trees
Authors: Amos Korman, Shay Kutten
Problem Statement: A graph and a tree is given as input in a distributed manner and the algorithm is should be able to verifiy if the tree is a Minimum
Spanning Tree (MST).
Detailed Explanation of the Problem Statement
Definitions
Spanning tree: A spanning tree of an undirected graph is a subgraph which is a tree and includes all the vertices of G.
Minimum Spanning Tree (MST) : A spanning tree of a graph whose weight (sum of weight of its edges) is less than or equal to the weight of all other
spanning trees of the graph.
Verification of a Spanning Tree: A graph and a tree is given as input and the algorithm should check if the tree is an MST for the graph.
In distributed verification of Minimum Spanning Trees, the input is provided in a distributed manner which means that each node of the graph knows
which of its edges belong to the tree. A node does not have any knowledge of the edges which do not emanate from it. The verification algorithm
should label the vertices of the graph so that every node, given its own label and the labels of its neighbours only is able to detect if these edges are
MST edges or not and whether the input tree is an MST.
Motivation
The motivation for working on verification algorithms is that verification is easier than computation. In a distributed setting verification is even more
important because the tree is given in a distributed manner and computing such a

Analysis of Two Sets of Historical Data to Construct and...
ASSIGNMENT PART A EXECUTIVE SUMMARY The objective of this report is to analyze two sets of historical data and construct an appropriate
survival model to evaluate the behaviour of the two separate subjects. The process of modelling for the medflies included: 1. Preliminary data analysis
to find and plot the empirical hazard and survival functions from the raw data based on a study on mortality rates of medflies 2. Fitting and analyzing a
Gompertz survival model, and by using least squares to find the parameters 3. Considering the Weibull as an alternative model that would fit the
empirical data more appropriately 4. The optimal models chosen in steps two and three was analyzed against the empirical data on medflies in software
R for analysis and the reasons as to why the models don't entirely fit with the empirical data. The second set of data is based on a group of inmates
analyzed after release from Maryland State prisons in the early 1970s based on several covariates. The process of modelling for this set of data
included: 1. Looking at the Kaplan–Meier estimate of the survival function and the empirical hazard function without covariates 2. Considering the
arrest times for African Americans against other races by ignoring effects of other covariates and analyzing the difference. 3. Fitting a regression model
to the arrest time information with all covariates; the error distribution for the model is also looked at, along with which covariates were

Bouncy Ball Lab Report
In the Bouncy Ball Lab, my team conducted two experiment that looked at how rebound height was affected by different independent factors. In the
first experiment, we chose six different starting heights and measured the rebound height in order to calculate how bouncy our given ball was, also
called the rebound ratio. We then graphed our data and found an equation to model the relationship between starting height and rebound height. In the
second experiment, we allowed our bouncy ball to continue bouncing after an initial height of 200cm. Again, we graphed the rebound height as the
dependant variable on the y–axis, but our independent variable was the number of times the ball had bounced. we also found an equation to model this
relationship.

Sst4e Tif 07 Essay
Ch. 7 The Normal Probability Distribution 7.1 Properties of the Normal Distribution 1 Use the uniform probability distribution. MULTIPLE CHOICE.
Choose the one alternative that best completes the statement or answers the question. Provide an appropriate response. 1) High temperatures in a certain
city for the month of August follow a uniform distribution over the interval 64°F to 92°F. What is the probability that a randomly selected August day
has a high temperature that exceeded 69°F? A) 0.8214 B) 0.1786 C) 0.4423 D) 0.0357 2) High temperatures in a certain city for the month of August
follow a uniform distribution over the interval 73°F to 103°F. Find the high temperature which 90% of the August days exceed. A) 76°F B) 100°F C)
83°F ... Show more content on Helpwriting.net ...
You randomly sample 30 preschool children and find their weights to be as follows. 25 25 26 26.5 27 27 27.5 28 28 28.5 29 29 30 30 30.5 31 31 32
32.5 32.5 33 33 34 34.5 35 35 37 37 38 38 a) Draw a histogram to display the data. Is it reasonable to assume that the weights are normally distributed?
Why? b) Find the mean and standard deviation of your sample. c) Is there a high probability that the mean and standard deviation of your sample are
consistent with those found in previous studies? Explain your reasoning. Page 218 MULTIPLE CHOICE. Choose the one alternative that best
completes the statement or answers the question. 2) The graph of a normal curve is given. Use the graph to identify the value of μ and σ. 3 6 A) μ = 12,
σ = 3 9 12 15 18 B) μ = 3, σ = 12 21 C) μ = 12, σ = 9 D) μ = 9, σ = 12 3) The normal density curve is symmetric about A) Its mean B) The horizontal
axis C) An inflection point D) A point located one standard deviation from the mean 4) The highest point on the graph of the normal density curve is
located at A) its mean B) an inflection point C) μ + σ D) μ + 3σ 5) Approximately ____% of the area under the normal curve is between μ – 3σ and μ +
3σ. A) 99.7 B) 68 C) 95 D) 50 Determine whether the graph can represent a normal curve. If it cannot, explain why. 6) A) The graph cannot represent a
normal density function because it increases

Three Basic Trig Functions Of Trigonometry
SIX BASIC TRIG FUNCTIONS
Trigonometry, stemming from the greek words trigonon and metron , is the branch of mathematics in which sides and angles within in a triangle are
examined in relation to one another. A right triangle has six total functions used in correlation to its angles, represented by the greek letter theta (θ). The
primary operations are sine (sin), cosine (cos) and tangent (tan) which serve also as the reciprocal of cosecant (csc), secant (sec), and cotangent (cot) in
that order. All six have abbreviations shown in parenthesis. Sine is the trigonometric function that is equal to the ratio of the side opposite a given angle
(θ) to the hypotenuse. Cosine is the ratio of the side adjacent to θ to the hypotenuse. Tangent is the ratio of the opposite side from the given angle to the
adjacent side. These functions are used in order to calculate unknown angles or distances from some known and/or measured aspects in a geometric
figure.
BRIEF HISTORY Trigonometry began as a method born from necessity to model the motions of galactic objects in mathematical astronomy. In order
to predict their movements with geometric accuracy Hipparchus began the development of mathematical tools which would allow astronomers to
convert arc lengths to distance measurements. Many contribute Hipparchus as the father of trigonometry. He was the first to construct a table of values
of a trigonometric function and created the notion that all triangles as being inscribed into a circle

The Mathematics Of Blood Alcohol Concentration
The Mathematics of Blood Alcohol Concentration
As I approached my sixteenth birthday, I began to study for my G1 written test in order to receive my drivers' licence. While doing a practice test, I
came across a statistic that stated, "In the United States in 2013, it was estimated that 10 076 people were killed in crashes that involved one or more
drunk drivers and 290 000 people were injured in these accidents ". I had heard a variation of this statistic many times, however I didn't truly grasp the
magnitude of these numbers until I began to reflect on the effects of driving under the influence. As a potential new driver, I was concerned about the
use of alcohol while driving so I began to wonder how toxins, specifically alcohol, react within our bodies. I also wondered how, or even if, this
interaction could be represented through the use of mathematical analysis.
In my research I discovered for myself a field known as pharmacokinetics, which is a branch of pharmacology that deals with the interactions of drugs
in our bodies. In pharmacokinetics, the interaction of alcohol with the body can be visually represented using a concentration–time graph, where the
concentration can be graphed as a function with respect to time in hours. The concentration in this case refers to Blood Alcohol Concentration (BAC),
which is the amount of alcohol in 100 mL of blood with units, mg/100mL, or often expressed as a percent. BAC is a means by which doctors can
determine a person's

Gravity Lab
Gravity Lab The goal of the experiment was to identify the gravitational acceleration from the recorded distance(cm) vs time(sec) data of a fallen
object. The first step was to graph the distance–time graph from the data collected. Upon graphing the data, the best fit line was identified in order to
find the formula of the function. As the data is representative of a graphical parabola, a parabolic function was utilized to be the best fit trendline. The
function Positon=404.289cm/s^2(t^s) + 44.450cm/s(t) +4.876cm was identified. In the equation, 404.289cm/s^2(t) represents the slope of the parabolic
curve pertaining to the distance(cm) over time(sec) as the 4.876cm displays the y–intercept in which the function crosses the axis leading to the
resulting curve. From identifying the distance–time graph equation, the next step is to find the velocity of the set data. ... Show more content on
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However, in order to find a linear slope of a parabolic curve, the mathematical equation of distance/time^2 ( pertaining to the data as cm/s^2) is used to
produce the linearization of the distance–time graph. A linear distance–time graph is the equivalent of a velocity–time graph by identifying the slope of
the distance–time graph. Another best fit line (a linear trendline) was plotted within the newly charted velocity–time graph. The equation identified
through the trendline was Velocity=808.578cm/s^2 (t) +44.450 cm/s. The 44.450cm/s represents the point in which the linear data crosses the y–axis as
the y–intercept. Additionally, the 808.578cm/s^2 represents the slope of the velocity–time graph in which the acceleration can be

Ib Physics Ia
IB Physics Internal Assessment
Andy Tang
Research Question
In this internal assessment, I am given a cantilever to find the physical properties of it. I decide to investigate the relationship between the force I act on
one side of the cantilever and the maximum acceleration the tail can reach. This experiment will be also showing the elasticity of the cantilever. Since I
pull down one side of it and fixed the other side, when I cut the string, it will bounce up and down until all the internal energy is depleted.
Text books
Newton meter
Accelerometer
Equilibrium line
Materials 1) A piece of cantilever that is made by acrylic plastic (length:35.2cm±0.1; Width:4.0cm±0.1; thickness:0.2cm±0.1) 2) An accelerometer
(sensor; ... Show more content on Helpwriting.net ...
By considering the formula: Ep=kx2/2, when x (the displacement caused by deformation) cannot be changed any more, the potential energy will not be
changing. When there is no more energy added into the system, the acceleration will not change.
Raw Data Table Force (N±0.05) | Acceleration (ms^–2)(±0.2) | | Trial 1 | Trial 2 | Trial 3 | | max | min | max | min | max | min | 0.75 | 22.3 | –18.5 | 21.2 |
–15.3 | 25.7 | –26.1 | 1.00 | 40.6 | –36.3 | 36.9 | –42.5 | 35.6 | –35.2 | 1.25 | 48.7 | –43.4 | 46.6 | –37.2 | 40.7 | –39.3 | 1.50 | 52.7 | –55.6 | 52.0 | –41.7 | 49.1
| –45.9 | 1.75 | 55.3 | –52.7 | 57.3 | –53.0 | 50.2 | –48.3 | 2.00 | 64.7 | –57.5 | 66.8 | –55.0 | 65.6 | –56.1 | 2.25 | 69.8 | –59.7 | 67.3 | –61.2 | 65.3 | –63.2 |
2.50 | 78.0 | –63.8 | 68.0 | –63.8 | 64.3 | –62.8 | 2.75 | 74.7 | –63.8 | 83.8 | –63.8 | 83.7 | –63.2 | 3.00 | 83.8 | –63.8 | 83.1 | –63.8 | 83.6 | –63.8 |
Force uncertainty: The least count of the Newton meter that I used is 0.25N. Although the interspace of each scale is wide enough for me to determine,
I was not able to control the tension force which I act on the Newton meter. This created the uncertainty of the force measurement. By noticing the
fluctuation of the indicator, I estimate the uncertainty of the force is about 0.05N.
Acceleration uncertainty: The data of the acceleration were

Math Sl Fish Production
FISH PRODUCTION – MODELING The aim of this investigation is to consider commercial fishing in a particular country in two different
environments, that is from the sea and a fish farm (aquaculture). The following data provided below was taken form the UN Statistics Division
Common Database. The tables gives the total mass of fish caught in the sea, in thousands of tones (1 tone = 1000 kilograms). Year | 1980 | 1981 | 1982 |
1983 | 1984 | 1985 | 1986 | 1987 | 1988 | Total Mass | 426.8 | 470.2 | 503.4 | 557.3 | 564.7 | 575.4 | 579.8 | 624.7 | 669.9 | Year | 1989 | 1990 | 1991 | 1992
| 1993 | 1994 | 1995 | 1996 | 1997 | Total Mass | 450.5 | 379.0 | 356.9 | 447.5 | 548.8 | 589.8 | 634.0 | 527.8 | 459.1 | Year | ... Show more content on
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The principle axis is midway between the maximum and minimum, so d≈634.0+356.92≈495.45. So, the model is M≈138.75sin2π9x–c+495.45 for
some constant c. We can notice that the point A on the original graph, graph1, lies on the principles axis and so it is a point at which we are starting a
new period. Since A is at (1989,450.5), c = 1989. The model is therefore M≈138.75sin2π9x–1989+495.45 and we can superimpose it on the original
data as follows. Graph5. Sin model The graph shows what happens when we fit the original graph , Graph4. with its model graph. The slopes of the two
graphs are presented to be nearly equal at certain points. The model presents decreasing and increasing values. Points shown from year 1989 – 1991,
1995 – 1997, 1999 – 2000, 2002 – 2003, 2004 –2005 are decreasing, as for the rest of the years are increasing. The following table below presents the
total mass of fish that were raised form the fish farm, in thousands of tones. Year | 1980 | 1981 | 1982 | 1983 | 1984 | 1985 | 1986 | 1987 | 1988 | Total
Mass | 1.4 | 1.5 | 1.7 | 2.0 | 2.2 | 2.7 | 3.1 | 3.3 | 4.1 | Year | 1989 | 1990 | 1991 | 1992 | 1993 | 1994 | 1995 | 1996 | 1997 | Total Mass | 4.4 | 5.8 | 7.8 | 9.1 |
12.4 | 16.0 | 21.6 | 33.2 | 45.5 | Year | 1998 | 1999 | 2000 | 2001

Exponential, Or Cubic) Do You Believe Will Best Fit The Data?
Student Name: ____Chesey Colston ______ Date: _____12/3/2014_____ Class: Algebra 2 Explore Linear Models: Years of School Average Weekly
Paycheck Some high school 11 450 High school graduate 13 585 Some college 15 810 Bachelor's degree 17 1000 Master's degree 19 1250 Doctoral
degree 21 1600 1) Which type of function (linear, exponential, or cubic) do you believe will best fit the data? Support your choice. My choice would be
a Linear Function because it doesn't go through an intersection like an exponential function would, it also wouldn't be a cubic function because it is not
curved. It has all straight lines. 2) Find the rate of change between the data points of these intervals: (High school graduate) and (Some college) High ...
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Describe the pattern you see in them. 4) Use exponential regression (or find a constant ratio) to determine an equation for the data. 5) Graph the
equation you wrote in step four superimposed over the original data. Comment on how well or how poorly the equation fits the data. 6) If the rounds of
forwarding continued in the same pattern, predict the round that would be first to end up sending the link to more than 50,000 people. Explain how you
came up with this prediction. Explore Cubic Models: Record the volumes. Size of Corner Cut Volume of the Box (lwh) 1 100 2 3 4 5 Graph the table of
data. Use your graph to answer the questions that follow. 1) Which type of function (linear, exponential, or cubic) do you believe will best fit the data?
Support your choice. 2) Find the rate of change between the data points of these intervals: (Corner Cut 1) and (Corner Cut 2) (Corner Cut 2) and
(Corner Cut 3) (Corner Cut 3) and (Corner Cut 4) 3) What do the rate of change values you just calculated represent? Why are some positive and some
negative? 4) Use cubic regression to determine an equation for the data (or lwh where (12 – x) represents the sides and (x) represents the height of the
box). 5) Graph the equation you wrote in step four superimposed over the original data. Comment on how well or how

The Effects of Varying Horizontal G-Forces
Introduction This is a look into the effects of varying horizontal G–Forces that are exposed to us and the amount or limit a human can tolerate of the
horizontal G–Forces. Charts and graphs that will represent the data will lend to a more authentic and concrete conclusion. To demonstrate growth and
unknown variables, an equation will be crafted. Such variables will be labeled and shown on the visual representations. To aide in the analysis of the
information, calculations will be done with a graphing calculator as well as open–source software available here: HYPERLINK
"http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html"http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCa
– Any visual demonstrations will be applied to the paper via jpgs. Any calculations performed will follow a set and defined procedure detailed below.
Task 1 The first table of data illustrates the tolerance human beings have to horizontal G–force. The task is to define appropriate variables and
parameters and identify any contraints to the data. Time (Min) +Gx (g) 0.01 35 0.03 28 0.1 20 0.3 15 1 11 3 9 10 6 30 4.5 Variables X–Axis will be
labeled as +Gx in gees while the Y–Axis will be labeled as Time, specifically minutes. There is no constant variable here as both Time and +Gx
fluctuate in relation to each other. The analysis does demonstrate that as length of time increases the amount of +Gx gees tolerated decreases.
Parameters: In

Math 30 IB Standard Level Body Mass Index Portfolio...
This portfolio is an investigation into how the median Body Mass Index of a girl will change as she ages. Body Mass Index (BMI) is a comparison
between a person's height (in meters) and weight (in kilograms) in order to determine whether one is overweight or underweight based on their height.
The goal of this portfolio is to prove of disprove how BMI as a function of Age (years) for girls living in the USA in 2000 can be modeled using one or
more mathematical equations. This data can be used for parents wanting to predict the change in BMI for their daughters or to compare their daughter's
BMI with the median BMI in the USA.
The equation used to measure BMI is:
The chart below shows the median BMI for girls of different ages in the ... Show more content on Helpwriting.net ...
That can be fixed by adjusting the horizontal phase shift value of _c_ to 12.4 to compensate.
There is also a noticeable discrepancy between the function graph and the scatter plot in the domain {} and {}. A slight stretch about the y axis would
fit the curve closer to the data points in those areas, therefore the _b_ value should be changed from π/15 to π/14. The number π/14 was chosen because
reducing the denominator's value by 1 will increase the b value by a slight amount, and an increased b value will shorten period and compress the graph
about the y axis, resulting in the values within domain to be closer to that of the data points.
Making these changes, the revised formula for the sinusoidal function is as follows:
Using TI InterActive!™ to graph that function, overlaid with the original data, and restricting the graph of the function to the same domain and range as
the domain and range on the scatterplot, the graph is as follows:
The refined equation fits the data much more closely at the beginning, yet around the Age = 13 mark it starts to deviate again. Looking at this graph,
one can come to the conclusion that it will take more than one mathematical function to graph the entirety of the data.
If one were to relate the concept of human growth with the measurable

MTT Project 1 Graphs With Application
MTT Project 1 (Graphs with application) Name: Mohamed Alzbeidi ID: 1054072 Section: 1 Function: Quadratic Function Instructor: Jaya Kumar A.
Introduction: Quadratic is the function that is used for a squared degree. In this function its graph is called a parabola. The graph of all quadratic
function is called a parabola its shape is basically a U shape it might be transformed or reflected or inversed witch might change the shape in some
cases The simplest quadratic function is: y(x)=X^2 Furthermore, the general form to the quadratic function is y=〖ax〗^2+bx+c=0 In any case where a
quadratic function cannot be solved the quadratic formula is used x=(–b±√(b^2–4ac))/2a The Quadratic Inverse: y(x)=√x ... Show more content on
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The equation of the reflected graph is y=〖– (x)〗^2 Example: y(x)=〖–(2x–3)〗^2+1 C. Combination of all transformations with its inverse: Basic
Function: y=–1/2 (2x–4)^2+2 Inverse Function: y(x)=2±√(2–x)/√2 Full Graph including basic function its inverse and y = x D. Real life situation
Quadratic Function A ball shot can be made using the equation y=–0.〖0281x〗^2+2x+10 , Where x is distance traveled (in feet) and y is the height
(also in feet). How long was the throw? First we apply the quadratic formula x=(–2±√(2^2 )–4(–0.281×10))/(2(–0.0281)) x=75.9 ft x=–4.7 y=10 E.
Summary Although quadratic functions do not seem difficult but it is related to most fields in science and examples can be made by any shape or act
that might represent the form of a parabola. Including, there are more complex polynomials than the quadratic but it seems that this function is the best
introduction to functions and there graphs. Recourses https://www.desmos.com/

Math Sl Fish Production
FISH PRODUCTION –
MODELING
The aim of this investigation is to consider commercial fishing in a particular country in two different environments, that is from the sea and a fish farm
(aquaculture).
The following data provided below was taken form the UN Statistics Division Common Database. The tables gives the total mass of fish caught in the
sea, in thousands of tones (1 tone = 1000 kilograms). Year | 1980 | 1981 | 1982 | 1983 | 1984 | 1985 | 1986 | 1987 | 1988 | Total Mass | 426.8 | 470.2 |
503.4 | 557.3 | 564.7 | 575.4 | 579.8 | 624.7 | 669.9 |
Year | 1989 | 1990 | 1991 | 1992 | 1993 | 1994 | 1995 | 1996 | 1997 | Total Mass | 450.5 | 379.0 | 356.9 | 447.5 | 548.8 | 589.8 | 634.0 | 527.8 | 459.1 |
Year | 1998 | 1999 | ... Show more content on Helpwriting.net ...
Graph7. Model
The graph shows what happens when we fit the original graph , Graph6. with its model graph. The slopes of the two graphs are presented to be nearly
equal to each other, whereas at a certain places it presents variation in values. However it can clearly be seen that the function is constantly increasing.
By considering the two presented models, it can be seen that in Graph5. the possible trend will keep increasing and decreasing its values as the years go
by. The shown Graph7. shows the trends of the amount of fish caught will possibly keep on rising in the future as the years go by, however little
decreases way assure on the

How Does The Band Pass Digital Filter Design Using Kaiser...
5.6 Band Pass FIR Digital Filter Design using kaiser Window The band pass FIR digital filter has been analysed with hanning window by using FDA
tool in the MATLAB. The cut off frequency has been estimated by using nn tool. 5.6.1 Training using Feed Forward Back Propagation (FFBP) artificial
Neural Network Algorithm for kaiser Window Figure 5.11: trained network for kaiser window with FFBP Figure 5.12: performance plot for kaiser
window with FFBP In above figure 5.12, it shows the performance plot of a FFBP neural network. This plot is result of MLP training algorithm. Here
after 7 epochs the mean square error is almost 0. That means the network is trained. Figure 5.13: regression plot for kaiser window with FFBP Here
figure 5.13 ... Show more content on Helpwriting.net ...
Figure 5.16 shows an error graph between hamming window output obtained from the FDA tool of MATLAB and feed forward back propagation
algorithm output obtained from nn tool of MATLAB. Figure 5.16: Error graph between desired cut–off frequencies and obtained cut–off frequencies for
hamming window with FFBP Figure 5.17 shows an error graph between hamming window output obtained from the

The Low Form Credit Risk Model
Specification of the model.
In this dissertation the focus is on the reduced form credit risk model to calculate the prices of the default–free zero–coupon bonds. In order to use this
model the specification of the models' parameters should be done. More precisely, the hazard rate risk–neutral model, recovery rate and a default–free
term structure should be chosen.
Hazard process.
There are several most popular approaches for hazard process estimation.
First approach defines the hazard process as a stochastic process with help of Vasicek and CIR processes. Another approach that underlies the cross–
sectional estimation considers the hazard process to be either a stochastic or a constant. When the hazard rate is a stochastic process, there ... Show
First way is to estimate it is a parameter from a real market data and second way is to assume this rate as a constant. From the first point of view it
seems that the first method is more preferable than the second one, it is difficult and consuming in implementation.
The following graph shows a model obtained from the following security: a bond issued by Deutsche Bank that was taken from Bloomberg on the 23d
of July. The swap curve was used in the following graphs as a proxy for the default–free curve for a constant hazard rate model. The curves are built for
a constant recovery rates that vary from 10%–90% with a step of 10%. For each obtained value the hazard rate is estimated.
Graph 1. Graph one represents the fitted zero–coupon curve obtained from the Deutsche Bank bond from the bid quotes. The vertical axes is the zero–
coupon rate and the horizontal axes is time to maturity. The curve was calculated by Nelson–Siegel method in Matlab (see Appendix 1).
Graph 2. The second graph is function of 1 – recovery rate where recovery rate changes from 10% to 90%. The vertical axes values of the function one
minus recovery rate, meanwhile the horizontal axes shows the values of the recovery rate.
Graph 3. The third graph shows the hazard rate function that, as it was mentioned earlier, is a polynomial function of time to maturity and parameters
λ_i for i=1,...,n. The horizontal axes shows the recovery rate values, meanwhile the

Summary: Unit 2 Of College Algebra
After applying more of my critical thinking in solving some exercises while reading has been of a great effect to my learning process in unit 2 of
College Algebra. According to Stitz, C. & Zeager, J. (2011), During the second week of term 4, I could read and cover many topics but the text I found
difficult to read are firstly, Graphs of Polynomials that states where a0, a1, . . . , an are real numbers and n _ 1 is a natural number. According to 3.2
definition where we can now think of linear functions as degree 1 (or first degree') polynomial functions and quadratic functions as degree 2 (or second
degree') polynomial functions. The end behavior of a function is a way to describe what is happening to the function values (the y–values) as the x–
values approach the `ends' of the x–axis.9 That is, what happens to y as x becomes small without bound and, on the flip side, as x becomes large
without bound. While reading to understand this concept, I took up and practice this convention as stated in the text at this point and considered when
plotting it graphically, it looks a bit complex to my understanding. All ... Show more content on Helpwriting.net ...
The zeros of p are the solutions to x2 +1 = 0, or x2 = –1. The imaginary unit "i" satisfies the two following properties. Establishing that "i" does act as a
square root2 of –1, and property 2 establishes what we mean by the `principal square root' of a negative real number. After reading the textbook for
hours, I had no choice than to repeat the reading the passages twice because at the initial stage, I barely could understand every mathematical functions,
calculations, and graph of polynomial. I was able to read the text book twice in other to understand most part of the Graphs of polynomial, The Factor
Theorem and The Remainder Theorem, and the Complex Zeros and the Fundamental Theorem of

Finding A Bore Tide
Introduction:
Daylight hours are dependent on sunrise and sunset times for each day which are dependent on seasonal change. The number of daylight hours can be
represented by a periodic function. This periodic function can help Alaskan Council predict daylight hours for tourist travelling to watch their Bore
Tide. A Bore Tide is a tidal phenomenon in which the leading edge of the incoming tide forms a wave (or waves) of water that travels up a river or
narrow bay against the direction of the river or bay's current. Anchorage, Alaska is known for its famous Bore Tides. These bore tides occur at least
once a day during high and low tide. Yet, health warnings are applied to viewing bore tides during low tide. Tourists have died by getting ... Show more
content on Helpwriting.net ...
(Refer to Appendix 5 for the graph of the function:L=417 sin⁡
[2π/365 (t–81)]+744). As a regression analysis the function itself was used to find daylight
hours. The hours were then compared to the original data points. This comparison resulted in a percentage error being recorded. (Refer to Appendix 5
for the results of the function and percentage errors). The highest percentage error recorded was 7.35% on February 1st 2011. This error could be
because February has 29 days in a leap year but 2011 data was used. The error could also occur because only 24 data points were used, if more data
points were used a more precise graph would have been generated leaving less space for error.
Question 1e:
Simple deriving and calculus was used to verify that the equation L=417 sin⁡
[2π/365 (t–81)]+744 for when the longest and shortest day of the year
occur. The derivative of the function was started by using the chain rule(dy/dx=dy/du*du/dx). The derivative was found to be: dy/dx=2π/365 417
cos⁡
(2π/365 t–162π/365). dy/dx was made to equal 0 therefore the equation will end up looking like: 0=cos⁡
(2π/365 t–162π/365). When dealing with a
cos curve on a unit circle cos can only be 0 at 90 degrees (π/2) and 270 degrees (3π/2) therefore meaning that to find the longest and shortest days
(2π/365 t–162π/365) is made

Qrb501
WEEK ONE PROBLEMS
QRB501
McConnell & Brue Text
Chapter 7: Study Question 12
The following table shows nominal GDP and an appropriate price index for a group of selected years. Compute real GDP. Indicate in each calculation
whether you are inflating or deflating the nominal GDP data.
[pic]
Chapter 8: Study Question 2
Suppose an economy's real GDP is $30,000 in year 1 and $31,200 in year 2. What is the growth rate of its real GDP?
[(31,200 – 30,000) / 30,000] * 100 = 4.00%
Assume that population is 100 in year 1 and 102 in year 2. What is the growth rate of GDP per capita?
(30,000 / 100) = 300.00
(31,200 / 102) = 305.88
[(305.88 – 300.00) / 300.00)] * 100 = 1.96%
Chapter 8: Study ... Show more content on Helpwriting.net ...
The Average Total Cost graph is the sum of average fixed cost plus average variable cost. The shape of the graph is a hybrid of the average fixed cost
and average variable cost graphs. At any point on the X–axis, the plot for average total cost will equal the sum of average fixed cost plus average
variable cost.
The Marginal Cost graph is a function of change in total cost divided by change in quantity produced. Marginal cost is the added cost of producing one
additional unit of production, or the savings in not producing one additional unit. The graph decreases until the fourth unit of production, and then
increases rapidly, as marginal cost is tied to total cost and is thus subject to the law of diminishing returns.
...Continued on next page
The Marginal Cost graph intersects the Average Total Cost graph and the Average Variable Cost graphs at their minimum points. As long as the cost of
producing one additional unit remains less than average total cost, the average total cost continues to fall. When marginal cost finally exceeds average
total cost, average total cost begins to rise in response. The same effect applies to the relationship between marginal cost and average variable cost.
c) Explain how the location of each curve graphed in question 7b would be altered if (1) total fixed cost had been $100 rather than $60 and (2) total
variable cost had been $10

Blood Spatter Investigation Essay
Introduction: For my Mathematics Internal Assessment, I focused on how the diameter of a blood droplet was affected by the height in which they were
shot at. When I watch criminal shows, they always estimate a person's height by the way blood is spread out and I wondered if the diameter of a droplet
really did change with the height where they were shot at, and if it was an effective method of presuming the height where the victim was hit at the time
they were shot. This topic has always interested me as when I was younger, I wanted to be a forensic scientist and the way they solved crimes always
intrigued me. Specifically, the way they conducted tests at the crime scene such as blood spatter analysis. My aim is to find how related the height of
the bullet entry is with the diameter of a blood droplet,and by doing that I will have to conduct my own experiment as there is no data for what I want to
do. By the end I hope to ... Show more content on Helpwriting.net ...
This is because, I did not choose a droplet at random, but rather I would choose one that fit best with how the experiment was going. This was also
because many of the droplets that occurred were too small to get a result from and it would result in the same diameter for them in each different height
I tried. Graph 1.1 – Graph to show the list of points I obtained from my results From these results I plotted a graph, which I expected would give me a
quadratic equation, however the shape I got was not exactly a curve. As such, I approached it a different way and used piecewise function, which is a
function defined by multiple sub–functions, each sub–function applying to a certain interval of the main function's domain. To calculate a linear
equation for x values 10 to 90 cm and a quadratic equation from x values 90 to 190 cm, which I would then add onto my

Worksheet Analysis
Sketch a graph of the polynomial f(x) = (x–2)3Compute the results of the following operations involving polynomials: 4.(5k4+2k3+8)–(k2+4) 5.(x+2)
(x2 + 4x +2) 6.Rewrite the polynomial expression T = (–0.01897V + 25.41881 V2 – 0.42456 V3 + 0.04365 V4)/V Student does not recognize quadratic
function Student does not infer from graph intersections in creating equation How can you recognize a graph from each of the function families? Which
function family does this graph belong to? What is the general equation for a graph from this function family? How can you use points on the graph to
create your equation? 2.f(x) = (x)(x–1)3(x–2)(x–3)2Student does not use roots to create equation. Student does not use multiplicity of roots to create
equation. ... Show more content on Helpwriting.net ...
What clues does the way the graph interacts with the x–axis (intersects it, forms a tangent, or has a turning point on the x–axis) give for creating the
equation? 3.Student fails to create a cubic graph Student does not sketch correct intersection at (2,0) What information can be drawn from the exponent
in the equation? What point would the term (x–2) of a polynomial populate on a graph? What does the exponent reveal about the nature of the graph's
intersection with the

Mathematics and Calculations
Running Head: MATHEMATIC AND CALCULATIONS
1.
a) ix=x–1+2
Transformation: The graph is shifted one unit to the right
b) jx=x+3
Transformation: The graph is shifted two units to the left
c) hx=x+3
Transformation: The graph is shifted three units along the x– axis
d) gx= – x
Transformation: the graph is transformed at an angle of 1800
2. Since no real numbers can be a square root of a negative number, the domain of f consist of all real numbers x such that;
4x+12 0
Therefore determining the domain of f is the same as solving the inequality
Let
hx= 4x+12 0 hx= 4x+12
4x=12
x 3
D= [3, )
Therefore the domain of f is all real numbers in the closed interval of 3 and infinity Set the denominator to zero (0) x+12=0x=–12 The domain therefore
is all real numbers greater than or less than –12
D= [ , –12) In this case there are no denominators therefore there is no division by zero
There is also no radical therefore there is no square root of a negative
Therefore the domain will be all real numbers The domain will be all real numbers except 0
This is because 1/0 is undefined
[15, ) x–15 0 x 15
3. Vertical asymptotes
Steps
The function for the vertical asymptote is first written down. In normal cases it should be a rational function and it should have a variable x in its
denominator. Always the vertical asymptote occurs when the denominator of the rational function is nearing zero
The second step is to find the value of x which makes the denominator

The Neural Network Model
In the present chapter determining the radius for a given resonant frequency of centre feed circular microstrip antenna has been estimated using the
FFBP ANN
In the present chapter the radius for a given resonant frequency of a centre feed circular microstrip patch antenna has been analysed using two layer
neural network structures FFBP ANN model. The Levenberg – Marquardt training algorithm and the transfer function tansig have been used to
implement the neural network model. The simulated values for training and testing the neural network model are obtained by analysing the circular
microstrip patch antenna using CST Microwave Studio Software (CST–MWS). The results obtained using ANNs are compared with the simulation
findings and found ... Show more content on Helpwriting.net ...
Figure 3.1 shows the training performance graph that indicates the best validation performance and number of epochs required to achieve the minimum
mean square error level. The number of epochs required for training the aforesaid neural network to achieve mean square error (MSE) is 668. The
training time is 3 seconds and the training algorithm used in the analysis model is Levenberg – Marquardt training algorithm.
Figure 3.2 shows the training state of the FFBP ANN model, the training state condition is shown by 3 different graphs in the first graph gradient value
is shown at different epochs, in the next graph Mu which indicates the error values at different epochs are shown and the third figure shows the
validation check points at different epochs. All the three graphs are showing the values at epoch 674.
The network is tested for 10 patterns and the table 3.1 shows the comparison of results of CST and FFBP–ANN with 5 neurons for radius with the
variation of the resonant frequency of the circular patch microstrip antenna computing MSE function with constant substrate height and dielectric
constant.
The network is realized using FFBP architecture. In the model, developed for the analysis of radius there are 10

Simulation of Dynamic Responses of First Order and Second...
Objectives:
As part of the experiment requirements, we were required to simulate the dynamic response of a first order and a second order linear system with the
help of LabVIEW. One of our first objectives of this experiment was to observe the response of the first order system to the input step signal and then
relate it to the time constant of that specific first order system. The second objective of this experiment included observing the second order system to
the input step signal and then relating it to the damping ratio of the specific second order system. The third and most important objective of this
experiment was to use different functions of LabVIEW including loop execution control, LabVIEW formula node, LabVIEW graph, LabVIEW ...
Show more content on Helpwriting.net ...
A shift register was then used to store the y value for the next iteration (y(n–1)) in case of the first order system while a 2 stacked shift register, in case
of a second order system, was used to store the y values from previous iterations (y(n–1) and y(n–2)). A formula node was used in order to input the
formula required to program the algorithm for each of the first and second order systems respectively. After providing the required number inputs and
outputs (as per the requirement of each of the formula respectively), a waveform function was used to create the waveform data from the output data
and determine the time interval of the input waveform. After using an array to contain all the input and output waveforms, a graph indicator was finally
added to the VI to display the final graphical representation of the output data.
After saving, each of the VI were run separately set at different time constants (for the first order system) and different damping ratios and 100 Hz
undamped natural frequency (for the second order ratio).
Results:
After creating the VI for first order differential systems in LabVIEW, we ran the VI using five different time constant values (0.01, 0.03, 0.05, 0.07, 0.1)
and received the following graphs:
Figure : LabVIEW generated graph of amplitude against time for

Spring Break Project Case Study
Our first step in completing the Spring Break Project was choosing a car, and since the four of us will be traveling a long distance, we decided that a
luxury car would be the best option. Once we decided, we found the cost for renting a luxury car for each of the companies and created functions to
represent the total cost. Those functions are as follows: y = 0.18x + 308 for Hertz, y = 0.13x + 426 for Enterprise, y = 0.15x + 364 for Dollar, and y =
0.20x +326 for Avis. We created these formulas by using the cost per mile as the slope, or the number multiplied by x, and used the initial cost as the y–
intercept, which is the number added. When the formulas had been created, we went on to making our graphs and tables up to 3,000 miles. We used the
tables to analyze our data, and found that Hertz offers the best initial offer up to 2,000 miles. After 2,000 miles, Dollar becomes the best option, and at
3,250 we found that Enterprise becomes the best offer. We used our graph to double check this information, and found that after 3,250 miles, Enterprise
is the best option indefinitely. ... Show more content on Helpwriting.net ...
The three locations we chose were Myrtle Beach, New York City, and San Francisco. In order to find out how many miles a trip to each city would be,
we doubled the distance from Greensboro (where we would pick up the car) to the city to represent the round trip, and added 20 miles to that total in
case of detours or in–city travelling. This meant that a trip to Myrtle Beach would 412 miles, New York City would be 1,098, and San Francisco would
be 5,552 miles. To find the cost for each of these trips, we solved each function for the mileage of each city. Hertz had the best price for Myrtle Beach
and New York City, at $382.16 and $505.64, respectively. However, Enterprise was the best choice for San Francisco, only costing

Tide Modelling
IB Mathematics Standard Level Portfolio Assignment Task I
Tide Modeling
Kelvin Kwok
In this modeling assignment, I will develop a model function for the relationship between time of day and the height of the tide. I will first show the
data in a table form copied from the assignment sheet. Then I will use the data to construct a scatter graph of time against height, then I will develop a
function that models the behavior noted in the graph analytically, and describe any variables, parameters or constraints for the model. In the end I will
modify the same model using the regression feature of graphing software to develop a best–fit function for the data. This modeling task will allow me
to find out what is the best time that a good ... Show more content on Helpwriting.net ...
And for the value of C which is the horizontal translation, by trial and error method, I have found that by + π12 to the function which translate the
function to the left along the x–axis.
And D is the principal axis, as the min. value and max. value has already changed, so the new value for D would be 12.15+0.82=6.475
Hence we will get a modified function y=5.675sinx2+π12+6.475
Diagram3 Graph of the modified function y=5.675sinx2+π12+6.475 in method4
From diagram 3, we can see that the modified function has passed through 11 data points in total, which is 3 times more than the old function. So it is
obvious a better fit to the data points.
Method 5: Decide what time a good sailor should launch their boat based on the model in method 4
An outgoing tide is a receding tide , i.e. a tide that decreases from it's max height(crest) to its min. height(trough), from our observations on the graph in
method 4 , the max. height of the tide occurs at 2.6 hours after midnight and 15.2 hours after midnight which is 2:36am and 3:12pm respectively.
However, it's more sensible to launch a boat in day light rather than in the dark, therefore the best for a good sailor to launch a boat would be 3:12pm.
But since the function modeled in part 4 is not a perfit fit, therefore the perdiction of the best time to launch a boat is a theoretical guess.

Role Of Cosine In The Simpsons
In this project I was able to utilize my knowledge about functions in order to create an image that represent the cosine and sine graphs as well as other
trigonometric graphs. Moreover, this project was really amusing because I had the opportunity to draw an image that represent the given graphs. The
reason I choose to do this image was first based on the cartoonish character Bart of the famous animated comedy The Simpsons. After analyzing the
character, I change many of its features such as the mouth, nose, eyebrows, and other elements. Furthermore, I changed the eyebrows and nose and
convert them into cosine curves. Similarly, I changed the mouth, hair and the sleeves of the shirt of my character into sine curves. In order to find the
equation

Non-Function Piece-Wise Function Paper
For my "Non–function Piece–wise Function" project, I decided to use a miniature Christmas tree as my object. Right after tracing the object onto my
graph paper, I calculated the equation of each line segment. In order to find the equations of each line segment, I first had to find the slope of the lines.
To find the slope, I picked two obvious points from a line segment and plugged it into the slope equation. Finally, I plugged in the slope that I figured
out into the "point–slope form" equation along with one point of my choice, and finally got the equation. There was a particular error which I bumped
into during my analysis. At first, I had a plan to use a star as my object. But there was a problem. When I traced the

A Mathematical Model: An Idealization of a Real Problem
A mathematical model is an idealisation of a real problem. Mathematical models also allow predictions to be made in studies. These models are usually
expressed in functions. Graphs are then plotted from these functions and will be analysed. The mathematical model that will be studied in this
investigation is mainly the cubic function.
Cubic functions are equations that are expressed in the form of f(x)=ax3+bx2+cx+d where a≠0 and a,b,c and d are constants. There are usually two
stationary points and an inflection point in cubic functions. This inflection point can either be a stationary inflection point or a non–stationary inflection
point.
Cubic equations were known to the ancient Babylonians, Chinese, Greeks, Egyptians and Indians. Physicians and mathematicians in the past such as
Hippocrates , Diophantus , Menaechmus , Archimedes and many more have studied the cubic function.
The aim of this investigation is to investigate the relationship between the stationary points of a cubic polynomial and the point of inflection of cubic
functions .This investigation will also discuss the contexts of applying cubic models to the real life situations.
Several items were used in completing this investigation. A TI–84 plus calculator from Texas Instruments was used. A printer was also used in printing
the papers in this investigation
In this task, a real life situation is that the electricity used in a house is charged into an electricity bill. The electricity consumption in Australia

Isis Essential Standards Week 30 Essay
ESSENTIAL STANDARDS
ASSESSMENTS
By: Isis Gill–Reid
GRAPHING TRIGONOMETRIC
FUNCTIONS
Amplitude, Period, Phase Shift, Horizontal Shift of Sine and Cosine
DEFINITION
The trigonometric functions are functions of an angle. They relate the angles of a triangle to the lengths of its sides. Trigonometric functions are
important in the study of triangles and modeling periodic phenomena, among many other application. Amplitude is half the distance between the
minimum and maximum values of the range of a periodic function with a bounded range. A graph that repeats after a fixed interval, which is a period,
of the independent variable. Horizontal shift is obtained by determining the change being made to the x value. A phase shift represents the ... Show
If a sequence of values follows a pattern of adding a fixed amount from one term to the next, it is referred to as an arithmetic sequence.
Examples
Arithmetic
Sequence
Common Difference, d d add 3 to each term to arrive at the next term, or...the difference a2
– a1 is 3.
1, 4, 7, 10,
13, 16, ...
=3
15, 10, 5, 0,
–5, –10, ...
d=
–5
add –5 to each term to arrive at the next term, or...the difference a2
– a1 is –5. add–1/2 to each term to arrive at the next term, or....the difference a2 – a1 is –1/2.
REAL LIFE SITUATION
Arithmetic sequences and series are used every day by engineers, accountants, and builders.
GEOMETRIC SEQUENCES AND
SERIES
Geometric Sequence, Geometric Series
DEFINITION
If a sequence of values follows a pattern of multiplying a fixed amount times each term to arrive at the following term it is referred to as a geometric
sequence. The sum of the terms of a sequence is called a series.
EXAMPLE
Geometric Sequence
Common Ratio, r r 5, 10, 20, 40, ...
=2
multiply each term
by 2 to arrive
at the next
term or...divide a2

–11, 22, –44, 88, ...
by a1 to find the common ratio, 2.
r = –2
or...divide
multiply each term by –2 to arrive at the next term
.or...divide a2 by a1 to find the common ratio, –2. multiply each term by 2/3 to arrive at the next term a2 by a1 to find the common

Using Microsoft Excel And Microsoft Word
A quartic equation is a fourth–order polynomial equation of the form. Shortly after the discovery of a method to solve the cubic equation, Lodovico
Ferrari (1522–1565), a student of Cardano, found a way to solve the quartic equation. His solution is a testimony to both the power and the limitations
of elementary algebra. The objective of this project is to analyze a polynomial of degree four via various attributes using Microsoft Excel and Microsoft
Word. I was assigned a nuumber in class that resembles a fucntion provided on the list.
An end behavior on a graph basically talks about the tailends of the graph. You determine the end behavior by looking at which way the tailends are
pointing. The end behavior is the behavior of the graph ... Show more content on Helpwriting.net ...
Looking at my graph i can come to a conclusion that the left side of my graph is going upward so F(x) is approching positive infinity. The left side isnt
pointing upward or downward so i had to look at my equation to determine what f(x) is. Since the leading coefficient is negative the right side of the
graph is going down , so f(x) approches negative infinity.
Local extrema is basically all local maximums and minimums on a functions graph. Local extrema occurs at criticla points on the graph where the
derivative is zero or undefined. To find the exact number of a local extrema using your polynomial , first find the first derivative of f using the power
rule. Then you will set the derivative to zero and solve for x. The values you get are the critical points which is also your local extrema. To find the
local extrema in your calculator all you have to do is enter the equation into Y=. Then hit GRAPH and look for the max value first. To find the max
value just go to calculate and choose maximum. Then move your cursor to the left when they ask you for left bound and hit enter and it will tell you
that you locked the position and just repeat the bounds for the right side too. When it asks for guess just hit enter and the coordinates of he max value
will appear. I had atleast 4 local extrema.
A zero of a function is an input value that produces an output of zero and can also be referred to as, a root. An examples of this would be f(x)=

Decibel Portfolio Essay
The intensity I of a sound wave is measured in watts per metre squared ( ). The lowest intensity that the average human ear can detect, i.e. the threshold
of hearing, is denoted by , where . The loudness of sound, i.e. its intensity level , is measured in decibels (dB), where . From this function a specific
relationship between and can be drawn that holds true for any increase in intensity. By knowing the value of beta ( ), the value of can be found via
manipulation of the logarithmic function, and by knowing the value of beta can by found by just taking the log of and multiplying it by ten.
The intensity level of ordinary conversation is 65 dB. In order to find the intensity of normal conversation on must set beta to 65 dB and to . ... Show
The values denoted by an * are values that were inserted during the investigation for this project. The process to find the values of Intensity with a
given Intensity Level was already mentioned, but the process in order to find Intensity Level by knowing the Intensity of a sound was not. In order to
find intensity level beta (b) from the equation one just takes the logarithm of and multiplies it by ten. The finding of the intensity level of a quiet radio
by knowing its intensity will be the example to test the method.
After carrying out this process and the other to find all the missing values, a relationship between the increase of the values can be discerned. By
carefully analyzing the table above, it can is concluded that while Intensity Level increase ten units, Intensity increase 10 times. By using a graphing
utility

Basic Econ Essay
Chapter 2 MCQ's 1) According to the Law of Demand, the demand curve for a good will A) shift leftward when the price of the good increases. B) shift
rightward when the price of the good increases. C) slope downward. D) slope upward. Answer: C 2) An increase in the price of pork will lead to A) a
movement up along the demand curve. B) a movement down along the demand curve. C) a rightward shift of the demand curve. D) a leftward shift of
the demand curve. Answer: A 3) An increase in consumer incomes will lead to A) a rightward shift of the demand curve for plasma TVs. B) a
movement upward along the demand curve for plasma TVs. C) a rightward shift of the supply curve for plasma TVs. D) no change of the demand curve
for plasma TVs. Answer: ... Show more content on Helpwriting.net ...
B) no government regulations exist. C) demand curves are perfectly horizontal. D) suppliers will supply any amount that buyers wish to buy. Answer: A
19) Once an equilibrium is achieved, it can persist indefinitely because A) shocks that shift the demand curve or the supply curve cannot occur. B)
shocks to the demand curve are always exactly offset by shocks to the supply curve. C) the government never intervenes in markets at equilibrium. D)
in the absence of supply/demand shocks no one applies pressure to change the price. Answer: D 20) If price is initially above the equilibrium level, A)
the supply curve will shift rightward. B) the supply curve will shift leftward. C) excess supply exists. D) all firms can sell as much as they want.
Answer: C 21) An equilibrium in a market is described by A) a price only. B) a quantity only. C) the excess supply minus the excess demand. D) a price
and a quantity. Answer: D 3 22) The above figure shows a graph of the market for pizzas in a large town. At a price of $14, there will be A) no pizzas
supplied. B) equilibrium. C) excess supply. D) excess demand. Answer: C 23) The above figure shows a graph of the market for pizzas in a large town.
At a price of $5, there will be A) excess demand. B) excess supply. C) equilibrium. D) zero demand. Answer: A 24) The above figure shows a graph of
the market for pizzas in a large town. What are the equilibrium price and quantity? A) p = 8, Q = 60

Comparison Of Mean Square Error ( FFBP )
comparison of mean square error using feed forward back propagation (FFBP) and radial basis function(RBF) neural network algorithms are given in
table 5.2 for analysis of band pass FIR filter with hanning window.
Table 5.2 Comparison of mean square error using FFBP and RBF neural network algorithms used for cut off frequency calculation of band pass FIR
digital filter with hanning window
Test input
(Filter
Coefficient) hanning
Window (actual cut off
Frequency) Output of Artificial Neural Network
(calculated cut off frequency) Mean Square Error
(MSE)
FFBP RBF FFBP RBF h(n) fc1 fc2 fc1 fc2 fc1 fc2 fc1 fc2 fc1 fc2 h1(n) .155 .355 .15528 .35528 .155 .355 .0000000784 .0000000784 0 0 h2(n) .215
.415 .21459 .41459 .215 .415 ... Show more content on Helpwriting.net ...
Table 5.5 Comparison of mean square error using FFBP and RBF neural network algorithms used for cut off frequency calculation of band pass FIR
digital filter with kaiser window
Test input
(Filter
coefficient) Kaiser
Window (actual cut off
Frequency) Output of artificial neural network
(calculated cut off frequency) Mean Square Error FFBP RBF FFBP RBF h(n) fc1 fc2 fc1 fc2 fc1 fc2 fc1 fc2 fc1 fc2 h1(n) .155 .355 .15567 .35567 .155
.355 .0000004489 .0000004489 0 0 h2(n) .215 .415 .21418 .41418 .21498 .41498 .0000006724 .0000006724 .0000000004 .0000000004 h3(n) .275
.475 .27404 .47404 .27499 .47499 .0000009216 .0000009216 .0000000001 .0000000001 h4(n) .335 .535 .33475 .53475 .335 .535 .0000000625
.0000000625 0 0 h4(n) .395 .595 .39593 .59593 .395 .595 .0000008649 .0000008649 0 0 h5(n) .455 .655 .45541 .65541 .455 .655 .0000001681
.0000001681 0 0 h6(n) .515 .715 .5145 .7145 .515 .715 .00000025 00000025 0 0 h7(n) .575 .775 .57232 .77232 .575 .775 .0000071824 .0000071824 0
0 h8(n) .635 .835 .63531 .83531 .635 .835 .0000000961 .0000000961 0 0 h9(n) .695 .895 .69439 .89439 .695 .895 .0000003721 .0000003721 0 0
Table

Core Curriculum Writing Assignment: A Quadratic Function
Devon Sparrow Instructor: Ralph Best MATH–1332 17 November 2015 Core Curriculum Writing Assignment: Quadratic function This paper will
discuss all possible graphs of a quadratic function, how to know when you have found them all, and the roles of the intercepts and coefficients and how
they affect the graphing of a quadratic function (Core Curriculum math sample writing assignment). The form of a quadratic function is
f(x)=ax^2+bx+c (Quadratic Functions). The U shape formed by the graph is called a parabola (Quadratic Functions). A quadratic function can be
graphed to open either up or down (Stewart, Ingrid). The coefficient is "a" (Stewart, Ingrid). If the coefficient is negative the graph will open down
(Stewart, Ingrid). If it is positive the graph will open up (Stewart, Ingrid). If the graph opens up "a" is greater than 0 and if the graph opens down "a" is
less than 0. In a quadratic function there are no more than 3 intercepts. 2 x intercepts and 1 y intercept. There are not always 2 x intercepts but there is
always a y intercept (Stewart, Ingrid). Knowing where the intercepts are helps to determine exact ... Show more content on Helpwriting.net ...
Also mentioned was how to graph a quadratic function and information on the vertex and axis of symmetry. Works Cited "Quadratic Functions."
Quadratic Functions. N.p., n.d. Web. 17 Nov. 2015. http://dl.uncw.edu/digilib/mathematics/algebra/mat111hb/pandr/quadratic/quadratic.html#Content
"Core Curriculum Math Sample Writing Assignment". Handout. (Professor Ralph Best). Alvin Community College. Print. Stewart, Ingrid. "Quadratic
Functions." Quadratic Functions. N.p., n.d. Web. 17 Nov. 2015. http://sites.csn.edu/istewart/mathweb/math126/quad_func/quad.htm "Graphing
Quadratic Functions: Introduction." Graphing Quadratic Functions: Introduction. PurpleMath, n.d. Web. 17 Nov. 2015.

What Do Graphs Look Like?
Lesson Four
Comparing Offers 2–3 Days (adapted from Irvine Math Project/ HCPSS Secondary Mathematics Office (v2); adapted from: Stephen Leinwand
Accessible mathematics: 10 instructional shifts that raise student achievement).
Content Standards: 8.F.A.2 Compare properties of two functions each represented in a different way (algebraically, graphically, numerically in tables,
or by verbal descriptions.)
Learning Objectives: Students will be able to explain and compare two equations and what they mean in the context of the problem. Students will be
able to decide if it is a better business decision to take Mr. Jones' job offer.
Materials Needed:
Initial scenario and Mr. Jones's scenario
Multiple representations graphic organizer
Colored pencils
Graph paper
Chart paper
Markers
Computer
Anticipatory Set: Have students complete a think–pair–share review of their understanding of the ... Show more content on Helpwriting.net ...
Graphing Function Applet Activity – Using the given scenario, pairs will complete the graphing investigation on the computer applet
(http://cs.jsu.edu/~leathrum/Mathlets/grapher.html). Consider having the following questions on a sheet for students to answer as a pair: What do the
graphs look like? Have them draw a sketch of the graphs. Have students consider the realistic values for x and y. Have students find the y–intercept for
both functions.
b. Graphing Calculator Activity – Pairs will use the graphing calculators to graph the functions. Pairs will enter the equations into the calculator. What
do the graphs look like? Have them draw a sketch of the graphs. Have students write a conjecture based on what they have seen with the graphs of the
two functions. Teachers should help students adjust the window so the x–min and y–min are zero, since you cannot have negative values. Have students
consider the reasoning behind values being less than zero. Since x–max is the number of hours worked, have students think about realistic values.
Graphing

Consumer Behaviour of Purchasing Digital Camera
Consumer Behaviour of Purchasing Digital Camera
1.0 Introduction
In order to market the product into the market successfully, marketers need to have some marketing strategy to enter the desired market and make
profit. Market segmentation is the process of dividing a market into subsets of consumers with common needs or characteristics (Schiffman et al.,
2011). Understanding the market size and segmentation is valuable, but the keys to effective targeting is to know just how valuable specific consumer
groups are, and being able to quantify the impact of consumer trends ( Berry, 1999).
The purpose if this paper is to define the market segmentation for digital camera. Especially focus on Nikon digital camera which is the chosen product
in ... Show more content on Helpwriting.net ...
According to the consumer feedback survey conducted by Nikon in 2011, the consumers considered Nikon digital camera as user–friendly, affordable
price, well performance and good quality. The significant signal to explain this stage can be affordable price and good quality of the product.
2.1.2. Product benefits
After the product attributes it goes to the second stage which is product benefits. There are two consequences can discussed under the field of product
benefits, namely as functional consequences and psychosocial consequences.
The functional consequences is the tangible consequences of the product, it focus more on "what function is perform?'Also, it can be considered as an
external influence to the consumer. In this case the consequences may be user–friendly and excellence photographic performance.
The psychosocial consequence is a combination of psychological and social consequences. It emphasized more on 'How I feel?' and 'How people feel
about me?'which is more likely to be the internal influences to the consumers. Attraction and communication are significantly elements in this part. For
example, Nikon consumer may feel they catch people attention when they are using Nikon digital camera which is the psychological consequence. Also
the consumer may feel happy when they are using Nikon digital camera with others and create positiveexperience about the product, this may
considered as social consequence.
2.1.3 Personal values
The last

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