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Radical Equations
Radical equations are equations with the unknown x under
the radical.
Radical Equations
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
Radical Equations
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals.
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
b. οƒ–x – 3 = 4
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
b. οƒ–x – 3 = 4 square each side
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
b. οƒ–x – 3 = 4 square each side
(οƒ–x – 3)2 = 42
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
b. οƒ–x – 3 = 4 square each side
(οƒ–x – 3)2 = 42
x – 3 = 16
x = 19
Radical equations are equations with the unknown x under
the radical.
To solve radical equations, we use the following fact.
If L=R, then L2 = R2.
Radical Equations
To solve a radical equation, square each side of the equation
(repeatedly if necessary) to remove the radicals. Then solve
for x and check the answers.
Example A. Solve.
a. οƒ–x = 4 square each side
(οƒ–x)2 = 42
x = 16 It works.
b. οƒ–x – 3 = 4 square each side
(οƒ–x – 3)2 = 42
x – 3 = 16
x = 19 It works.
c. οƒ–2x + 1 = –3
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
For some problems, we have to square more than once to
eliminate all the radicals.
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
For some problems, we have to square more than once to
eliminate all the radicals. Recall the squaring formula that
(A Β± B)2 οƒ  A2 Β± 2AB + B2
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
Example B. Expand.
a. (οƒ–x + 4)2
For some problems, we have to square more than once to
eliminate all the radicals. Recall the squaring formula that
(A Β± B)2 οƒ  A2 Β± 2AB + B2
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
Example B. Expand.
a. (οƒ–x + 4)2
= (οƒ–x )2 + 2 * 4 οƒ–x + 42
For some problems, we have to square more than once to
eliminate all the radicals. Recall the squaring formula that
(A Β± B)2 οƒ  A2 Β± 2AB + B2
c. οƒ–2x + 1 = –3 square each side
(οƒ–2x + 1)2 = (–3)2
2x + 1 = 9
2x = 8
x = 4
However, x = 4 does not work. So there is no solution.
Radical Equations
Example B. Expand.
a. (οƒ–x + 4)2
= (οƒ–x )2 + 2 * 4 οƒ–x + 42
= x + 8οƒ–x + 16
For some problems, we have to square more than once to
eliminate all the radicals. Recall the squaring formula that
(A Β± B)2 οƒ  A2 Β± 2AB + B2
Radical Equations
b. (οƒ–2x + 1 – 3)2
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
4x = x2 – 2*3x + 9
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
4x = x2 – 2*3x + 9
0 = x2 – 10x + 9
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
4x = x2 – 2*3x + 9
0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1)
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
4x = x2 – 2*3x + 9
0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1)
x = 9 or x = 1
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
Radical Equations
b. (οƒ–2x + 1 – 3)2
= (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
= 2x + 1 – 6οƒ–2x + 1 + 9
= 2x + 10 – 6οƒ–2x+1
Example C. Solve for x.
a. οƒ–x + 4 = οƒ–5x + 4 square both sides
(οƒ–x + 4)2 = (οƒ–5x + 4 )2
x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical
8οƒ–x = 4x – 12 divide by 4
2οƒ–x = x – 3 square again
( 2οƒ–x)2 = (x – 3)2
4x = x2 – 2*3x + 9
0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1)
x = 9 or x = 1 Only 9 is good.
When squaring both sides of an equation to remove a radical,
make sure that the radical term is isolated to one side first.
b. οƒ–x + 1 – 3 = οƒ–x – 8
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
10 + 8 = 6οƒ–x + 1
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
10 + 8 = 6οƒ–x + 1
18 = 6οƒ–x + 1
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
10 + 8 = 6οƒ–x + 1
18 = 6οƒ–x + 1 div. by 6
3 = οƒ–x + 1
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
10 + 8 = 6οƒ–x + 1
18 = 6οƒ–x + 1 div. by 6
3 = οƒ–x + 1 square again
32 = (οƒ–x + 1)2
Radical Equations
b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides;
(οƒ–x + 1 – 3)2 = (οƒ–x – 8)2
x + 1 – 2*3οƒ–x + 1 + 32 = x – 8
x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical
10 + 8 = 6οƒ–x + 1
18 = 6οƒ–x + 1 div. by 6
3 = οƒ–x + 1 square again
32 = (οƒ–x + 1)2
9 = x + 1
8 = x This answer is good.
Radical Equations
Radical Equations
Exercise A. Isolate the radical then solve for x by squaring
both sides. Make sure to check your answers.
1. οƒ–x = 3 2. οƒ–x + 3 = 0 3. οƒ–x – 5 = 3
5. 2οƒ–x – 3 = 3
4. οƒ–x – 5 = 3
6. 2οƒ–x – 3 = 3 7. οƒ–2x – 3 = 3
8. οƒ–4x – 1 = 3 9. οƒ–4x – 1 = 3 10. οƒ–2x – 3 = – 3
11. 2οƒ–3x – 1 + 3 = 7 12. 4 – 3οƒ–3 – 2x = 1
13. οƒ–x2 – 8 – 1 = 0 14. οƒ–x2 – 8x – 3 = 0
Exercise B. Isolate one radical if needed, square. Then do it
again to solve for x. Make sure to check your answers.
15. οƒ–x – 2 = οƒ–x – 4 16. οƒ–x + 3 = οƒ–x + 1
17. 2οƒ–x – 1 = οƒ–x + 5 18. οƒ–4x + 1 – οƒ–x + 2 = 1
19. οƒ–x – 2 = οƒ–x + 3 – 1 20. οƒ–3x + 4 = οƒ–3 – x – 1
21. 2οƒ–x + 5 = οƒ–x + 4 22. οƒ–5 – 4x – οƒ–3 – x = 1
Radical Equations
25. Given that (x, 4) is the distance of 5 from the origin
(0, 0). Find x and draw the points.
26. Find y where the points (2, y) is the distance of 5 from
(–1 , –1). Draw the points.
23. Given that (x, 0) has the same distance to (0, 2) as to
the point (2, –2). Find x and draw.
24. Given that (0, y) has the same distance to (3, 0) as to
the point (2, 1). Find x and draw.
Exercise C. Use the distance formula D = βˆšΞ”x2 + Ξ” y2
to solve the following distance problems.

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4 radical equations

  • 2. Radical equations are equations with the unknown x under the radical. Radical Equations
  • 3. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. Radical Equations
  • 4. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations
  • 5. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals.
  • 6. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers.
  • 7. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4
  • 8. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side
  • 9. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42
  • 10. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16
  • 11. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works.
  • 12. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works. b. οƒ–x – 3 = 4
  • 13. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works. b. οƒ–x – 3 = 4 square each side
  • 14. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works. b. οƒ–x – 3 = 4 square each side (οƒ–x – 3)2 = 42
  • 15. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works. b. οƒ–x – 3 = 4 square each side (οƒ–x – 3)2 = 42 x – 3 = 16 x = 19
  • 16. Radical equations are equations with the unknown x under the radical. To solve radical equations, we use the following fact. If L=R, then L2 = R2. Radical Equations To solve a radical equation, square each side of the equation (repeatedly if necessary) to remove the radicals. Then solve for x and check the answers. Example A. Solve. a. οƒ–x = 4 square each side (οƒ–x)2 = 42 x = 16 It works. b. οƒ–x – 3 = 4 square each side (οƒ–x – 3)2 = 42 x – 3 = 16 x = 19 It works.
  • 17. c. οƒ–2x + 1 = –3 Radical Equations
  • 18. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 Radical Equations
  • 19. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 Radical Equations
  • 20. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 Radical Equations
  • 21. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 Radical Equations
  • 22. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations
  • 23. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations For some problems, we have to square more than once to eliminate all the radicals.
  • 24. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations For some problems, we have to square more than once to eliminate all the radicals. Recall the squaring formula that (A Β± B)2 οƒ  A2 Β± 2AB + B2
  • 25. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations Example B. Expand. a. (οƒ–x + 4)2 For some problems, we have to square more than once to eliminate all the radicals. Recall the squaring formula that (A Β± B)2 οƒ  A2 Β± 2AB + B2
  • 26. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations Example B. Expand. a. (οƒ–x + 4)2 = (οƒ–x )2 + 2 * 4 οƒ–x + 42 For some problems, we have to square more than once to eliminate all the radicals. Recall the squaring formula that (A Β± B)2 οƒ  A2 Β± 2AB + B2
  • 27. c. οƒ–2x + 1 = –3 square each side (οƒ–2x + 1)2 = (–3)2 2x + 1 = 9 2x = 8 x = 4 However, x = 4 does not work. So there is no solution. Radical Equations Example B. Expand. a. (οƒ–x + 4)2 = (οƒ–x )2 + 2 * 4 οƒ–x + 42 = x + 8οƒ–x + 16 For some problems, we have to square more than once to eliminate all the radicals. Recall the squaring formula that (A Β± B)2 οƒ  A2 Β± 2AB + B2
  • 29. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32
  • 30. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9
  • 31. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1
  • 32. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 33. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 34. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 35. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 36. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 37. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 38. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 39. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 40. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 41. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 4x = x2 – 2*3x + 9 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 42. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 4x = x2 – 2*3x + 9 0 = x2 – 10x + 9 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 43. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 4x = x2 – 2*3x + 9 0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1) When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 44. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 4x = x2 – 2*3x + 9 0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1) x = 9 or x = 1 When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 45. Radical Equations b. (οƒ–2x + 1 – 3)2 = (οƒ–2x + 1)2 – 2*3οƒ–2x + 1 + 32 = 2x + 1 – 6οƒ–2x + 1 + 9 = 2x + 10 – 6οƒ–2x+1 Example C. Solve for x. a. οƒ–x + 4 = οƒ–5x + 4 square both sides (οƒ–x + 4)2 = (οƒ–5x + 4 )2 x + 2*4 οƒ–x + 16 = 5x + 4 isolate the radical 8οƒ–x = 4x – 12 divide by 4 2οƒ–x = x – 3 square again ( 2οƒ–x)2 = (x – 3)2 4x = x2 – 2*3x + 9 0 = x2 – 10x + 9 οƒ 0 = (x – 9)(x – 1) x = 9 or x = 1 Only 9 is good. When squaring both sides of an equation to remove a radical, make sure that the radical term is isolated to one side first.
  • 46. b. οƒ–x + 1 – 3 = οƒ–x – 8 Radical Equations
  • 47. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 Radical Equations
  • 48. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 Radical Equations
  • 49. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 Radical Equations
  • 50. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical Radical Equations
  • 51. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical 10 + 8 = 6οƒ–x + 1 Radical Equations
  • 52. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical 10 + 8 = 6οƒ–x + 1 18 = 6οƒ–x + 1 Radical Equations
  • 53. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical 10 + 8 = 6οƒ–x + 1 18 = 6οƒ–x + 1 div. by 6 3 = οƒ–x + 1 Radical Equations
  • 54. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical 10 + 8 = 6οƒ–x + 1 18 = 6οƒ–x + 1 div. by 6 3 = οƒ–x + 1 square again 32 = (οƒ–x + 1)2 Radical Equations
  • 55. b. οƒ–x + 1 – 3 = οƒ–x – 8 square both sides; (οƒ–x + 1 – 3)2 = (οƒ–x – 8)2 x + 1 – 2*3οƒ–x + 1 + 32 = x – 8 x + 10 – 6οƒ–x + 1 = x – 8 isolate the radical 10 + 8 = 6οƒ–x + 1 18 = 6οƒ–x + 1 div. by 6 3 = οƒ–x + 1 square again 32 = (οƒ–x + 1)2 9 = x + 1 8 = x This answer is good. Radical Equations
  • 56. Radical Equations Exercise A. Isolate the radical then solve for x by squaring both sides. Make sure to check your answers. 1. οƒ–x = 3 2. οƒ–x + 3 = 0 3. οƒ–x – 5 = 3 5. 2οƒ–x – 3 = 3 4. οƒ–x – 5 = 3 6. 2οƒ–x – 3 = 3 7. οƒ–2x – 3 = 3 8. οƒ–4x – 1 = 3 9. οƒ–4x – 1 = 3 10. οƒ–2x – 3 = – 3 11. 2οƒ–3x – 1 + 3 = 7 12. 4 – 3οƒ–3 – 2x = 1 13. οƒ–x2 – 8 – 1 = 0 14. οƒ–x2 – 8x – 3 = 0 Exercise B. Isolate one radical if needed, square. Then do it again to solve for x. Make sure to check your answers. 15. οƒ–x – 2 = οƒ–x – 4 16. οƒ–x + 3 = οƒ–x + 1 17. 2οƒ–x – 1 = οƒ–x + 5 18. οƒ–4x + 1 – οƒ–x + 2 = 1 19. οƒ–x – 2 = οƒ–x + 3 – 1 20. οƒ–3x + 4 = οƒ–3 – x – 1 21. 2οƒ–x + 5 = οƒ–x + 4 22. οƒ–5 – 4x – οƒ–3 – x = 1
  • 57. Radical Equations 25. Given that (x, 4) is the distance of 5 from the origin (0, 0). Find x and draw the points. 26. Find y where the points (2, y) is the distance of 5 from (–1 , –1). Draw the points. 23. Given that (x, 0) has the same distance to (0, 2) as to the point (2, –2). Find x and draw. 24. Given that (0, y) has the same distance to (3, 0) as to the point (2, 1). Find x and draw. Exercise C. Use the distance formula D = βˆšΞ”x2 + Ξ” y2 to solve the following distance problems.

Editor's Notes

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