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1
The Inverse z-Transform
IIIB.ScMathematics
Transforms
Ms.S.Swathi Sundari, M.Sc.,M.Phil.,
2
z-transforms Table -1
3
z-transforms Table -2
4
The Inverse Z-Transform
• Formal inverse z-transform is based on a Cauchy integral
• Less formal ways sufficient most of the time
– Inspection method
– Partial fraction expansion
– Power series expansion
• Inspection Method
– Make use of known z-transform pairs such as
– Example: The inverse z-transform of
z  aan
unZ

1
1 az1
2
1 1
1  
1
n
xn 
2
 unz 
2

1 
Xz
z1
5
◆Find the inverse z-transform of:
◆Step 1: Divide both sides by z:
◆Step 2: Perform partial fraction:
◆Step 3: Multiply both sides by z:
◆Step 4: Obtain inverse z-transform of each term from table (#1 & #6):
The Inverse Z-Transform
6
• Apply partial fractional expansion
• First term exist only if M>N
– Br is obtained by long division
• Second term represents all first order poles
• Third term represents an order s pole
– There will be a similar term for every high-order pole
• Each term can be inverse transformed by inspection
k0
Inverse Z-Transform by Partial Fraction Expansion
• Assume that a given z-transform can be expressed as
M
akzk
bkzk
k 0
N
Xz
s
m1  m1
ik
MN
r
 r
r0 1 dz
Cm
k 1,ki 1  d z1
Ak
N
B z 

Xz
7
Inverse Z-Transform by Power Series Expansion
• The z-transform is power series


n
n
xnzXz
• In expanded form
Xz  x2z2
 x1z1
 x0 x1z1
 x2z2

• Z-transforms of this form can generally be inversed easily
• Especially useful for finite-length series
2
2
1 11
 z2

1
z  1 
1
z1
2 2
1  z 1  z 



 1 1  z
2
1
2
1
n 1    n  1 nn n 2x    

0
 2

1
 1
n  2

2
n  1
n  0
n  1
n  2
 1
xn 
1
8
Z-Transform Properties: Linearity
• Notation
8
– Note that the ROC of combined sequence may be larger than
either ROC
– This would happen if some pole/zero cancellation occurs
– Example:
• Both sequences are right-sided
• Both sequences have a pole z=a
• Both have a ROC defined as |z|>|a|
• In the combined sequence the pole at z=a cancels with a zero at z=a
• The combined ROC is the entire z plane except z=0
• We did make use of this property already, where?
ROC  RxxnZ
 Xz
ROC  Rx  R
1 x2
• Linearity
ax1n bx2nZ
 aX1z bX2 z
xn an
un- an
un - N
9
Find inverse z-transform – long division
◆Consider this example:
◆Perform long division:
◆Thus:
◆Therefore
10

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Inverse z-Transform Guide

  • 4. 4 The Inverse Z-Transform • Formal inverse z-transform is based on a Cauchy integral • Less formal ways sufficient most of the time – Inspection method – Partial fraction expansion – Power series expansion • Inspection Method – Make use of known z-transform pairs such as – Example: The inverse z-transform of z  aan unZ  1 1 az1 2 1 1 1   1 n xn  2  unz  2  1  Xz z1
  • 5. 5 ◆Find the inverse z-transform of: ◆Step 1: Divide both sides by z: ◆Step 2: Perform partial fraction: ◆Step 3: Multiply both sides by z: ◆Step 4: Obtain inverse z-transform of each term from table (#1 & #6): The Inverse Z-Transform
  • 6. 6 • Apply partial fractional expansion • First term exist only if M>N – Br is obtained by long division • Second term represents all first order poles • Third term represents an order s pole – There will be a similar term for every high-order pole • Each term can be inverse transformed by inspection k0 Inverse Z-Transform by Partial Fraction Expansion • Assume that a given z-transform can be expressed as M akzk bkzk k 0 N Xz s m1  m1 ik MN r  r r0 1 dz Cm k 1,ki 1  d z1 Ak N B z   Xz
  • 7. 7 Inverse Z-Transform by Power Series Expansion • The z-transform is power series   n n xnzXz • In expanded form Xz  x2z2  x1z1  x0 x1z1  x2z2  • Z-transforms of this form can generally be inversed easily • Especially useful for finite-length series 2 2 1 11  z2  1 z  1  1 z1 2 2 1  z 1  z      1 1  z 2 1 2 1 n 1    n  1 nn n 2x      0  2  1  1 n  2  2 n  1 n  0 n  1 n  2  1 xn  1
  • 8. 8 Z-Transform Properties: Linearity • Notation 8 – Note that the ROC of combined sequence may be larger than either ROC – This would happen if some pole/zero cancellation occurs – Example: • Both sequences are right-sided • Both sequences have a pole z=a • Both have a ROC defined as |z|>|a| • In the combined sequence the pole at z=a cancels with a zero at z=a • The combined ROC is the entire z plane except z=0 • We did make use of this property already, where? ROC  RxxnZ  Xz ROC  Rx  R 1 x2 • Linearity ax1n bx2nZ  aX1z bX2 z xn an un- an un - N
  • 9. 9 Find inverse z-transform – long division ◆Consider this example: ◆Perform long division: ◆Thus: ◆Therefore
  • 10. 10