4. 4
The Inverse Z-Transform
• Formal inverse z-transform is based on a Cauchy integral
• Less formal ways sufficient most of the time
– Inspection method
– Partial fraction expansion
– Power series expansion
• Inspection Method
– Make use of known z-transform pairs such as
– Example: The inverse z-transform of
z aan
unZ
1
1 az1
2
1 1
1
1
n
xn
2
unz
2
1
Xz
z1
5. 5
◆Find the inverse z-transform of:
◆Step 1: Divide both sides by z:
◆Step 2: Perform partial fraction:
◆Step 3: Multiply both sides by z:
◆Step 4: Obtain inverse z-transform of each term from table (#1 & #6):
The Inverse Z-Transform
6. 6
• Apply partial fractional expansion
• First term exist only if M>N
– Br is obtained by long division
• Second term represents all first order poles
• Third term represents an order s pole
– There will be a similar term for every high-order pole
• Each term can be inverse transformed by inspection
k0
Inverse Z-Transform by Partial Fraction Expansion
• Assume that a given z-transform can be expressed as
M
akzk
bkzk
k 0
N
Xz
s
m1 m1
ik
MN
r
r
r0 1 dz
Cm
k 1,ki 1 d z1
Ak
N
B z
Xz
7. 7
Inverse Z-Transform by Power Series Expansion
• The z-transform is power series
n
n
xnzXz
• In expanded form
Xz x2z2
x1z1
x0 x1z1
x2z2
• Z-transforms of this form can generally be inversed easily
• Especially useful for finite-length series
2
2
1 11
z2
1
z 1
1
z1
2 2
1 z 1 z
1 1 z
2
1
2
1
n 1 n 1 nn n 2x
0
2
1
1
n 2
2
n 1
n 0
n 1
n 2
1
xn
1
8. 8
Z-Transform Properties: Linearity
• Notation
8
– Note that the ROC of combined sequence may be larger than
either ROC
– This would happen if some pole/zero cancellation occurs
– Example:
• Both sequences are right-sided
• Both sequences have a pole z=a
• Both have a ROC defined as |z|>|a|
• In the combined sequence the pole at z=a cancels with a zero at z=a
• The combined ROC is the entire z plane except z=0
• We did make use of this property already, where?
ROC RxxnZ
Xz
ROC Rx R
1 x2
• Linearity
ax1n bx2nZ
aX1z bX2 z
xn an
un- an
un - N
9. 9
Find inverse z-transform – long division
◆Consider this example:
◆Perform long division:
◆Thus:
◆Therefore