The questions are here.. http://www.slideshare.net/MarwanShehata/electronics-project-questions

1. Marwan Shehata | LTSpice;Electronics | December 24, 2015
Electronics Project
Name: Marwan Shehata Mohamed Zeitoun
No: #157
Sec: #7

2. PAGE 1
Question #1 & #2
The circuit we’re going to use in this project
Question #3
The characteristics of the 1N5371B diode:
IZK=1 mA
IZM=79 mA
IZT=20 mA
Source: http://www.onsemi.com/pub_link/Collateral/1N5333B-D.PDF

3. PAGE 2
Question #4 A)
Changing RL to make IZ≈IZM ≈79 mA
1st Trial ⇊⇊
Putting R1= 3kΩ

4. PAGE 3
2nd Trial ⇊⇊
Putting R1= 2kΩ

5. PAGE 4
3rd Trial ⇊⇊
Putting R1= 1.9625kΩ
I’ve got a current flows throw the diode that approximately close to IZM ≈79 mA

6. PAGE 5
Question #4 B)
Put R1 < R1min , I assumed (R1 = 1000 Ω)<(R1min=1.9625 kΩ)
ID >IZM , and damage occurs to the diode

7. PAGE 6
Question #5 A)
Adjust R1=R1min=1.9625 kΩ & change RL until IZ≈ IZK≈ 1 mA
∴ RLmin ≈ 721.9 Ω ⇊⇊

8. PAGE 7
Question #5 B)
1st
: The voltage probe is at the terminal of the load resistance @RL =RLmin

9. PAGE 8
2nd
: The voltage probe is at the terminal of the load resistance 1000 Ω @RL >RLmin
Observation: Voltage increases on the load resistance

10. PAGE 9
Question #5 C)
Consider RL<RLmin , where RLmin ≈721.9 Ω
RL=500Ω & we will compare the voltage flow in RL with RL=RLmin and RL=500Ω
Observation: Voltage decreases on the load resistance

11. PAGE 10
Question #6
The diodes in the circuit are assembled to make a rectifier circuit
and the capacitor works to smoothen the current and make it close to a DC
The circuit without the capacitor
Wave form without the capacitor

12. PAGE 11
The effect of reducing and increasing of capacitor:
The capacitor is 10mF which is greater than the original one
The resulting current from increasing the capacitor

13. PAGE 12
The capacitor is 0.05mF which is less than the original one
The resulting current from increasing the capacitor

14. PAGE 13
Observation: The higher the capacitance the lesser the ripple, and vice versa …in other words; the voltage ripple is
inversely proportional to the capacitance.
Best Regards
Marwan Shehata