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A D PATEL INSTITUTE OF TECHNOLOGY
Created By,
Name : Lakhara Harshkumar Ashokbhai
Enrolment No. : 160010119035
Div. : 02
SUBJECT : Fluid Power Engineering
Topic : Force on plate when vane is moving in direction of jet
Impact of Jets :
The jet is a stream of liquid comes out from nozzle with a high velocity
under constant pressure. When the jet impinges on plates or vanes, its
momentum is changed and a hydrodynamic force is exerted. Vane is a
flat or curved plate fixed to the rim of the wheel.
1. Force exerted by the jet on a stationary plate
a) Plate is vertical to the jet
b) Plate is inclined to the jet
c) Plate is curved
2. Force exerted by the jet on a moving plate
a) Plate is vertical to the jet
b) Plate is inclined to the jet
c) Plate is curved
Impulse-Momentum Principle :
From Newton's 2nd Law :
F = m a = m (V1- V2) / t
 Impulse of a force is given by the change in momentum caused by the force
on the body.
Ft = mV1 – mV2 = Initial Momentum – Final Momentum
 Force exerted by jet on the plate in the direction of jet, F = m (V1 – V2) / t
= (Mass / Time) (Initial Velocity – Final Velocity)
= (ρQ) (V1 – V2) = (ρaV) (V1 – V2)
If Plate is moving at a velocity of ‘U’ m/s,
F = a(V-U)2
Force Exerted by jet on Vertical plate
Problems
A jet of water 50 mm diameter strikes a flat plate held normal to the
direction of jet. Estimate the force exerted and work done by the jet if
a. The plate is stationary
b. The plate is moving with a velocity of 1 m/s away from the jet along the line
of jet.
The discharge through the nozzle is 76 lps.
FN = a(V-U)2 sin 
Fx = FN sin
Fx = FN cos
Force Exerted by jet on Inclined plate
If Plate is moving at a velocity of ‘U’ m/s,
Problem
A jet of data 75 mm diameter has a velocity of 30 m/s. It strikes a flat plate inclined at 450 to the
axis of jet.
Find the force on the plate when.
a. The plate is stationary
b. The plate is moving with a velocity of 15 m/s along and away from the jet.
Also find power and efficiency in case (b)
Considering Relative Velocity,
If  < 900
Fx = aVr1 (Vr1 cos  + Vr2 cos )
Fx = aVr1 (VW1 + VW2)
OR
Force Exerted by jet on Curved plate
If  = 900
Considering Relative Velocity,
Fx = aVr1 (Vr1 cos – Vr2 cos)
Fx = aVr1 (VW1)
OR
Force Exerted by jet on Curved plate
If  > 900
Fx = aVr1 (Vr1 cos – Vr2 cos)
Fx = aVr1 (VW1 – VW2)
Considering Relative Velocity,
OR
Force Exerted by jet on Curved plate
Problems
1. A jet of water of diameter 75 mm strikes a curved plate at its center with a velocity of 25 m/s.
The curved plate is moving with a velocity of 10 m/s along the direction of jet. If the jet gets deflected through
1650 in the smooth vane, compute.
a) Force exerted by the jet.
b) Power of jet.
c) Efficiency of jet.
2. A jet of water impinges a curved plate with a velocity of 20 m/s making an angle of 200 with the direction
direction of motion of vane at inlet and leaves at 1300 to the direction of motion at outlet.
The vane is moving with a velocity of 10 m/s. Compute.
i) Vane angles, so that water enters and leaves without shock.
ii) Work done per unit mass flow rate

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Force on Plate when Vane is moving in direction of jet | Fluid Power Engineering

  • 1. A D PATEL INSTITUTE OF TECHNOLOGY Created By, Name : Lakhara Harshkumar Ashokbhai Enrolment No. : 160010119035 Div. : 02 SUBJECT : Fluid Power Engineering Topic : Force on plate when vane is moving in direction of jet
  • 2. Impact of Jets : The jet is a stream of liquid comes out from nozzle with a high velocity under constant pressure. When the jet impinges on plates or vanes, its momentum is changed and a hydrodynamic force is exerted. Vane is a flat or curved plate fixed to the rim of the wheel. 1. Force exerted by the jet on a stationary plate a) Plate is vertical to the jet b) Plate is inclined to the jet c) Plate is curved 2. Force exerted by the jet on a moving plate a) Plate is vertical to the jet b) Plate is inclined to the jet c) Plate is curved
  • 3. Impulse-Momentum Principle : From Newton's 2nd Law : F = m a = m (V1- V2) / t  Impulse of a force is given by the change in momentum caused by the force on the body. Ft = mV1 – mV2 = Initial Momentum – Final Momentum  Force exerted by jet on the plate in the direction of jet, F = m (V1 – V2) / t = (Mass / Time) (Initial Velocity – Final Velocity) = (ρQ) (V1 – V2) = (ρaV) (V1 – V2)
  • 4. If Plate is moving at a velocity of ‘U’ m/s, F = a(V-U)2 Force Exerted by jet on Vertical plate
  • 5. Problems A jet of water 50 mm diameter strikes a flat plate held normal to the direction of jet. Estimate the force exerted and work done by the jet if a. The plate is stationary b. The plate is moving with a velocity of 1 m/s away from the jet along the line of jet. The discharge through the nozzle is 76 lps.
  • 6. FN = a(V-U)2 sin  Fx = FN sin Fx = FN cos Force Exerted by jet on Inclined plate If Plate is moving at a velocity of ‘U’ m/s,
  • 7. Problem A jet of data 75 mm diameter has a velocity of 30 m/s. It strikes a flat plate inclined at 450 to the axis of jet. Find the force on the plate when. a. The plate is stationary b. The plate is moving with a velocity of 15 m/s along and away from the jet. Also find power and efficiency in case (b)
  • 8. Considering Relative Velocity, If  < 900 Fx = aVr1 (Vr1 cos  + Vr2 cos ) Fx = aVr1 (VW1 + VW2) OR Force Exerted by jet on Curved plate
  • 9. If  = 900 Considering Relative Velocity, Fx = aVr1 (Vr1 cos – Vr2 cos) Fx = aVr1 (VW1) OR Force Exerted by jet on Curved plate
  • 10. If  > 900 Fx = aVr1 (Vr1 cos – Vr2 cos) Fx = aVr1 (VW1 – VW2) Considering Relative Velocity, OR Force Exerted by jet on Curved plate
  • 11. Problems 1. A jet of water of diameter 75 mm strikes a curved plate at its center with a velocity of 25 m/s. The curved plate is moving with a velocity of 10 m/s along the direction of jet. If the jet gets deflected through 1650 in the smooth vane, compute. a) Force exerted by the jet. b) Power of jet. c) Efficiency of jet. 2. A jet of water impinges a curved plate with a velocity of 20 m/s making an angle of 200 with the direction direction of motion of vane at inlet and leaves at 1300 to the direction of motion at outlet. The vane is moving with a velocity of 10 m/s. Compute. i) Vane angles, so that water enters and leaves without shock. ii) Work done per unit mass flow rate