Planet Orbital Distance Equation

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Planet Orbital Distance Equation
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –27th
March 2021
Abstract
Planet Orbital Distance Equation
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
Where
d= A Planet Orbital Distance do= The Previous Planet Orbital Distance
Earth depends on Mercury
Mars depends on Venus
Pluto depends on Uranus
The Equation Concept Analysis
- Let's summarize the Equation Concept in following:
o The Equation tells that the solar planets are ordered by some geometrical
design and not as separated rigid bodies
o It tells, Each planet orbital circumference is created depending on its
previous planets orbital circumferences
o By that, the solar planets should be considered as one building, each planet
is a part of this same building.
o Or the Solar group works as a machine of Gears, each planet is a gear.
o Also, it tells, the solar planets move together one unified motion as a train
carriages.

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1- Introduction
- The equation is used simply with all planets … for example
- (1433.5 mkm)2
= 4 (778.6 mkm) (655 mkm)
- Where
- 1433.5 mkm = Saturn Orbital Distance
- 778.6 mkm = Jupiter Orbital Distance
- 655 mkm = Saturn Jupiter Distance
- This using shows how the equation is simple and useful,
- The equation works through dependency between a planet and its direct neighbor,
but because of Mars Migration, this rule has 3 exceptional, where Earth depends
on Mercury and Not Venus and Mars depends on Venus (and Not Earth) – also
Pluto depends on Uranus and not Neptune - for example
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 227.9 mkm = Mars Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 119.7 mkm = Venus Mars Distance
But
- Why does a planet orbital distance depend on its previous neighbor?
- The orbital distance analysis shows that, the solar planets are similar to different
stories in one house, each story is built on the other planets
- The data disproves the description that, The solar planets are rigid bodies revolve
around the sun. because the distances between these planets are defined based on
geometrical design and calculations
- That means, these distances are planned geometrically, and by that, the whole solar
system is designed geometrically and all distances are created based on each other.
- The paper analyzes the distances geometrical design to prove that, the solar system
is one geometrical design and building.

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2- Planet Orbital Distance Equation
2-1 The Equation Application
2-2 Jupiter Orbital Circumference Analysis
2-1 The Equation Application
- (108.2 mkm)2
= 4 (57.9 mkm) (50.3 mkm)
- Where
- 57.9 mkm = Mercury Orbital Distance
- 50.3 mkm = Mercury Venus Distance
- (149.6 mkm)2
= 4 (57.9 mkm) (91.7 mkm) (error 2.5%)
- Where
- 149.6 mkm = Earth Orbital Distance
- 57.9 mkm = Mercury Orbital Distance
- 91.7 mkm = Mercury Earth Distance
- (Earth depends on Mercury in place of its direct neighbor Venus)
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 119.7 mkm = Venus Mars Distance
- (Mars depends on Venus in place of its direct neighbor The Earth )
- (415 mkm)2
= 4 (227.9 mkm) (187.1 mkm)
- Where
- 415 mkm = Ceres Orbital Distance
- 187.1 mkm = Mars Ceres Distance

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- (778.6 mkm)2
= 4 (415 mkm) (363.6 mkm)
- Where
- 415 mkm = Ceres Orbital Distance
- 363.6 mkm = Ceres Jupiter Distance
- (1433.5 mkm)2
= 4 (778.6 mkm) (655 mkm)
- Where
- 655 mkm = Saturn Jupiter Distance
- (2872.5 mkm)2
= 4 (1433.5 mkm) (1439 mkm)
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 1439 mkm = Saturn Uranus Distance
- (4495.1 mkm)2
= 4 (2872.5 mkm) (1622.6 mkm) (error 4%)
- Where
- 4495.1 mkm = Neptune Orbital Distance
- 1622.6 mkm = Uranus Neptune Distance
- (5906 mkm)2
= 4 (2872.5 mkm) (3033.5 mkm)
- Where
- 5906 mkm = Pluto Orbital Distance
- 3033.5 mkm = Uranus Pluto Distance
- (Pluto depends on Uranus in place of its direct neighbor Neptune)

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The Discussion
- The data shows how the equation is so useful and working
- It defines each planet orbital distance depends on its direct neighbor
- The equation exceptions are 3
o Earth depends on Mercury (in place of Venus)
o Mars depends on Venus (in place of Earth)
o Pluto depends on Uranus (in place of Neptune)
o The error are 2 only (2.5 % and 4% with Earth and Neptune respectively)
- In next points we try to answer the question
- Why does each planet orbital distance depends on its neighbor?

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2-2 Jupiter Orbital Circumference Analysis
I-Data
4900 mkm = 360 mkm + 680 mkm + 940 mkm +1433 mkm +1433 mkm
Where
4900 mkm = Jupiter Orbital Circumference
360 mkm = Mercury Orbital Circumference
680 mkm = Venus Orbital Circumference
940 mkm = Earth Orbital Circumference
1433 mkm = Mars Orbital Circumference
II-Data Analysis
1st
Question
Why does Jupiter orbital circumference = the inner planets orbital circumferences
total?
2nd
Question
Why does the data use (Mars orbital circumference 1433 mkm) 2 times to be = Jupiter
orbital circumference?
Let's answer these questions in separated 2 points.

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2-2–1 The Outer Planet orbital Circumference Analysis
Why does Jupiter orbital circumference = the inner planets orbital circumferences
total?
Because
It's a general rule used for the outer planet orbital circumference – that means
(1)
Saturn orbital circumference = Jupiter orbital circumference + the 5 inner planets
orbital circumferences total
(2)
Uranus orbital circumference = Saturn orbital circumference + Jupiter orbital
circumference + the 5 inner planets orbital circumferences total
(3)
Pluto orbital circumference = Uranus orbital circumference + Saturn orbital
circumference + Jupiter orbital circumference + the 5 inner planets orbital
circumferences total
(4)
Neptune is exceptional for a reason, we should discuss later,
That explains the equation geometrical rule origin, because each planet orbital
circumference is a result of its previous planets orbital circumferences total and that
shows the source of Number (4) used in the equation – let's remember it
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
The number (4) is found because each planet orbital circumference = its previous
planets orbital circumferences total
Let's discuss that in detailed data in following

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Saturn Orbital Circumference
o The 5 inner planets orbital circumferences total (4846 mkm)+ Jupiter orbital
circumference (4900 mkm) = 9746 mkm
o Saturn orbital circumference = 9010 mkm
o The difference = 8%
o Spite of this difference, Can we consider, These 2 Values Are Equal?
o Yes, How??
o Because
o (720.7/778.6) = (671/720.7) = (629/671) = (9010/9746)
o 778.6 mkm = Jupiter orbital distance
o 720.7 mkm = Mercury Jupiter Distance
o 671 mkm = Venus Jupiter Distance
o 629 mkm = Earth Jupiter Distance
o Also
o 9010 mkm = Saturn orbital circumference
o 9746 mkm = all planets orbital circumferences total (before Saturn)
- As the data shows, the rate 1.0725 (or 1.08) is used frequently between 4 Jupiter
distances, So, it can be used with Saturn data also…
- Whatsoever the reason to use the rate (1.0725) with 4 Jupiter distances can be the
reason to use it between the distances total and Saturn orbital circumference.
- That means, while the inner planets orbital circumferences total (4846) + Jupiter
orbital circumference 4900 mkm = 9746 mkm
- But ..this value is considered to be = 9010 mkm
- So, These distances total be =9010 mkm = Saturn Orbital Circumference
- Based on that, we can say
- Saturn orbital circumference = the 5 inner planets orbital circumferences total +
Jupiter orbital circumference.

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Uranus Orbital Circumference 18040 mkm
- Based on this same rule
- Uranus orbital circumference should be equal = (the 5 inner planets + Jupiter +
Saturn) orbital circumferences total
- Indeed it's a fact
- 18020 mkm (Uranus orbital circumference) = 9010 mkm (Saturn orbital
circumference) + 9010 mkm (the 5 inner planets + Jupiter) orbital
- No error
Notice
- The 5 inner planets orbital circumferences total + Jupiter orbital circumference be
= 9746 mkm but used as 9010 mkm with Saturn and also by this same value (9010
mkm) is used with Uranus.
Pluto Orbital Circumference 37100 mkm
Suppose Neptune isn't found at all
Based on the used rule, What Pluto orbital circumference will be?
Pluto orbital circumference = all previous planets orbital circumferences total
i.e.
Pluto orbital circumference = Uranus orbital circumference + Saturn orbital
circumference + Jupiter orbital circumference + the 5 inner planets orbital
Pluto orbital circumference = 18040 mkm + 9010 mkm +9010 mkm = 36080 mkm
The error = 2.7%
A CONCLUSION
Planet Orbital Circumference = Its Previous Planets Orbital
Circumferences Total

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Neptune Orbital Circumference
- Why the rule can't explain Neptune orbital circumference 28255 mkm?
(We remember that, Bode Law also couldn’t predict Neptune orbital distance)
- Let's summarize the idea in following:
o Pluto was the Mercury Moon and has migrated with Mars Migration
o Neptune orbital distance was 5906 mkm = Pluto Current orbital distance
o Pluto has collided with Neptune and forced it to move more near to the sun
o Because of that, Neptune be at a distance =4495.1 mkm (That's why,
Neptune Pluto Distance = Pluto eccentricity distance=1433 mkm)
o But
o No orbit is designed in this point (4495.1 mkm) –i.e. – Neptune had no orbit
o Neptune had to seize 14% of Jupiter total energy to create its own orbital
circumference 28255 mkm!
- The previous story, can be considered as an imaginary story
- But
- The data shows that, the energy sent from Jupiter to Pluto and reflected to the inner
planets lost 14% which is accurately = Neptune orbital circumference
- Let's see this data in following
(1)
(Pluto orbital circumference – Jupiter orbital circumference) x 2π = 202320 mkm
(2)
(Neptune orbital circumference –Venus orbital circumference) x2π =2 x 86400 mkm
(3)
86400 mkm x 2 + 28255 mkm = 202320 mkm
(4)
Notice/ 202320 mkm = 1.16 mkm/s x 86400 seconds x 2 (error 1%)

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Planet Orbital Circumference Rule
The Planet Orbital Circumference= Its Previous Planets Orbital Circumferences
Total
- This rule is formed based on a mathematical series, let's remember it
- (0+1 =1), The number whose order 1 its value 1
- (1+2= 3), The number whose order 2 its value 3
- (1+2+3 = 6), The number whose order 3 its value 6
- (1+2+3+4 = 10), The number whose order 4 its value 10
- (1+2+…. 10= 55), The number whose order 17 its value 55
- I have tried to find the near numbers for the solar planets orbital distances starting
from Mercury (No. 10) to Pluto (No. 108)
- Almost these are the original distances before any changes in the solar system, the
day next Mars Migration,
- Where Earth orbital distance was 153 mkm
- I try to show that, there's a mathematical series controls the planet orbital
circumferences & distances, but the planets changed their distances during a period
of time as a result of their motions – for example- Earth original orbital distance
was 153 mkm but now became 149.6 mkm because Earth during 8211 years
moves toward the sun 3.4 mkm

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- Not all planets moves toward the sun, the original (supposed) distances show that
some geometrical mechanism is found to cause some planets to be more near and
others to be more far
- For example
(1)
- Earth and Mars moves toward the sun by equal distances (around 3 mkm) but
Venus and Mercury moves far from the sun by the same distance (around 3 mkm)
these distances aren't defined by any pure coincidences – we have here some
geometrical mechanism which causes these motions based on one another
(2)
- Jupiter moves more near to the sun with 1.4 mkm but Saturn moves far from the
sun with around 2.5 mkm
(3)
- Uranus, Neptune and Pluto all move far from the sun by a distance in range (20-30
mkm).

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2-2–2 Jupiter Orbital Circumference Analysis (Extending Discussion)
2nd
Question
Why does the data use (Mars orbital circumference 1433 mkm) 2 times to be =
Jupiter orbital circumference?
I-More Data
(1)
4900 mkm = 360 mkm + 680 mkm + 940 mkm +1433 mkm +1433 mkm
Where
4900 mkm = Jupiter Orbital Circumference
360 mkm = Mercury Orbital Circumference
680 mkm = Venus Orbital Circumference
940 mkm = Earth Orbital Circumference
1433 mkm = Mars Orbital Circumference
(2)
- Mercury moves during its day period a distance = 720.7 mkm = Mercury Jupiter
Distance (720.7 mkm)
- Venus Orbital circumference =680 mkm = Venus Jupiter distance (671 mkm error
1.3%)
- Earth Orbital circumference =940 mkm = Earth Jupiter distance (928 mkm error
1.3%) (where Earth and Jupiter should be at 2 different sides from the sun to create
this distance 928 mkm =778.6 mkm +149.6 mkm)
A hypothesis
- The orbital circumference 1433 mkm expresses The Earth Moon Orbital
Circumference – where Jupiter Data deals with the moon orbital circumference=
Mars orbital circumference and Not = Earth orbital circumference ! why?
- Let's try to answer in following

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The Discussion
- Let's summarize the idea in following
o The moon orbital circumference =2.550973 mkm
o The moon displacements total during 29.53 days = 2.59862 mkm
o The moon motion distance per a solar day = Earth motion distance per a
solar day = 2.573 mkm
o As we have discussed before, this distance (2.573 mkm) is effected by the
rate (1.0725) to be (2.4 mkm) and because of that the moon needs to do its
daily displacements (88000 km x 2) to cover the different distance –
Let's ask
- How the moon orbital circumference can be =1433 mkm and not 940 mkm?
o ((2.59862 mkm – 2.4 mkm)/2.4 mkm) x 5906 mkm = 489 mkm
o 940 mkm (arty orbital circumference) +489 mkm = 1433 mkm
o 5906 mkm = Pluto Orbital Distance
o That means
o The orbital circumference (2.4 mkm) express Earth Orbital Circumference
o And 2.59862 mkm expresses Mars Orbital Circumference 1433 mkm
o And by that, the moon orbital circumference be = 1433 mkm as a result of
the moon orbital geometrical structure.
o By that we can explain the data
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm (-1%)
Jupiter orbital circumference (4900 mkm) = the 4 inner planets orbital circumferences
total + the moon orbital circumference (which is considered to be 1433 mkm)
More Data
(a) (4900 mkm /0.3 mkm) = (1433 mkm /88000)
- The data tells
- Light known velocity (0.3mkm/s) travels a distance 4900 mkm (Jupiter orbital
distance) in 16333 seconds
- And in 16333 solar days, the moon total displacements be = 1433 mkm.

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(b) 1433 mkm = 2.5986 mkm x 550.7 mkm (Jupiter Mars Distance)
- The moon displacements total during 29.53 days = 2.598693 mkm
- Pluto motion distance during its day (153.3 h) = 2.593836 mkm
- But
- 88 x 2.598693 mkm = 228.684 mkm
- 88 x 2.593836 mkm = 228.2575 mkm
- The difference = -0.426 mkm
- 228.2572 + (-0.426 mkm) = 227.83 mkm (Mars orbital distance =227.9 mkm)
(c) 1433 mkm = 0.4136 mkm x 3475 km (The Moon Diameter)
- Where
o The moon displacements total during 29.53 days = 2.598693 mkm
o 2.598693 mkm = 2π x 0.4136 mkm
o That shows the distance 1433 mkm is defined basically based on the moon
displacements total and the moon diameter – means- it's a distance related to
the moon in essential form.
(d)
- 1433 mkm = 2.550973 mkm x 561.7 (1433 mkm x 2 = 2.55 x 1123)
- Where
o 2.550973 mkm = The Moon Apogee Orbital Circumference
o What's this value 561.7
o The moon displacements total during 561.7 years be = 18040 mkm (Uranus
orbital circumference).
o That shows Uranus effect on the moon motion through Venus effect.
o (561.7 = 24 x 23.4) BUT
(I)
18040 mkm x 2 = 1433 x 25.2
- Where 1433 mkm =Mars Orbital Circumference
- 25.2 deg = Mars Axial Tilt

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(II)
18040 mkm x 2 = 2.550973 mkm x 14144 (28255 mkm/2 = 14128)
(e)
- 88 x 2.550973 mkm (the moon apogee orbital circumference) = 224.5 mkm
- (Venus Orbital Period =224.7 days)
- The previous data tells us why Venus orbital period (number) is different from
Mars orbital distance (number) with 1.4%
- Because both are created based on the moon orbital circumferences
- (28255 mkm = Neptune orbital circumference)
(f)
- That explains why the moon apogee radius is rated to Venus data where
- 406000 km = 3475 km (the moon diameter) x 116.75 (Venus day period = 116.75 days)
(g)
- 243 days (Venus rotation period) /224.7 days (Venus orbital period) = (29.53 days
the moon day period /27.32 days the moon sidereal month).
Notice (1)
- The moon defines Mars orbital distance based on the moon distance to the Earth,
how can the moon do that? and Why does the moon do that? the moon may try to
connect Mars with Jupiter to provide the energy Mars lost by its migration, any
way this connection is done through Saturn-
- I want to say, some complex geometrical mechanism is found behind this data –
but more important that the moon connects Mars with Jupiter energy
Notice (2)
2870 mkm = 720.7 mkm +671 mkm +928 mkm +550.7 mkm
Where 2872.5 mkm = Uranus orbital distance
720.7 mkm = Jupiter Mercury Distance 671 mkm = Jupiter Venus Distance
550.7 mkm =Jupiter Mars Distance 928 mkm = Jupiter Earth Distance
(where Earth and Jupiter should be at 2 different sides of the sun)

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
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List of publications http://vixra.org/author/gerges_francis_tawdrous

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