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Variation Problems
● Variation problems determine a relationship function
between two variables.
● 2 Examples
○ Direct Variation (Relationship)
○ Inverse Variation (Divorce)
1
Direct Variation Problems
● Vary directly
● Vary as the square of
● Vary as the cube of
● Vary as the square root of
2
Inverse Variation Problems
● Vary inversely
● Vary inversely as the square of
● Vary inversely as the cube of
● Vary inversely as the square root of
3
Direct Variation Example
y varies directly as x; y = 36 when x = 4;
Solve for y when x = 6. Direct variation imply a y = kx relationship
Take initial statement: y = 36 when x = 4:
4k = 36 ← We use k for the constant of variation, y = kx
k = 9
This means our variation equation is y = 9x
The problem asks for y when x = 6
Y = 9(6) = 54
4
Inverse Variation Example
y varies inversely as x; y = 36 when x = 4;
Solve for y when x = 6. Inverse variation imply a y = k/x relationship
Take initial statement: y = 36 when x = 4:
k/4 = 36 ← We use k for the constant of variation, y = k/x
k = 144
This means our variation equation is x = 144/y
The problem asks for x when y = 6
x = 144/6 = 24
5
Direct Variation Squared Example
y varies directly as the square of x; y = 100 when x = 2;
Solve for y when x = 6. Direct variation imply a y = kx2 relationship
Take initial statement: y = 100 when x = 2:
22k = 100 ← We use k for the constant of variation, y = kx2
4K = 100 → k = 25
This means our variation equation is y = 25x2
The problem asks for y when x = 6
Y = 25(62) = 25(36) = 900
6

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Variation

  • 1. Variation Problems ● Variation problems determine a relationship function between two variables. ● 2 Examples ○ Direct Variation (Relationship) ○ Inverse Variation (Divorce) 1
  • 2. Direct Variation Problems ● Vary directly ● Vary as the square of ● Vary as the cube of ● Vary as the square root of 2
  • 3. Inverse Variation Problems ● Vary inversely ● Vary inversely as the square of ● Vary inversely as the cube of ● Vary inversely as the square root of 3
  • 4. Direct Variation Example y varies directly as x; y = 36 when x = 4; Solve for y when x = 6. Direct variation imply a y = kx relationship Take initial statement: y = 36 when x = 4: 4k = 36 ← We use k for the constant of variation, y = kx k = 9 This means our variation equation is y = 9x The problem asks for y when x = 6 Y = 9(6) = 54 4
  • 5. Inverse Variation Example y varies inversely as x; y = 36 when x = 4; Solve for y when x = 6. Inverse variation imply a y = k/x relationship Take initial statement: y = 36 when x = 4: k/4 = 36 ← We use k for the constant of variation, y = k/x k = 144 This means our variation equation is x = 144/y The problem asks for x when y = 6 x = 144/6 = 24 5
  • 6. Direct Variation Squared Example y varies directly as the square of x; y = 100 when x = 2; Solve for y when x = 6. Direct variation imply a y = kx2 relationship Take initial statement: y = 100 when x = 2: 22k = 100 ← We use k for the constant of variation, y = kx2 4K = 100 → k = 25 This means our variation equation is y = 25x2 The problem asks for y when x = 6 Y = 25(62) = 25(36) = 900 6