development of diagnostic enzyme assay to detect leuser virus
Inventory Control File II.pptx
1. Inventory Control
Dr. T. Anitha
Assistant Professor of Mathematics (SF)
V.V.Vanniaperumal College for Women
Virudhunagar
2. 1. Deterministic Inventory Problem with no
shortages
Case 1: The Fundamental Problem of EOQ
Case 2: Problem of EOQ with Several Production
Runs of Unequal Length
Case 3: Problem of EOQ with Finite Production
3. 2. Deterministic Inventory Problem with
shortages
Case 1: Problem of EOQ with Instantaneous
Production and Variable order Cycle Time
Case 2: Problem of EOQ with Instantaneous
Production and Fixed order Cycle
Case 3: Problem of EOQ with Finite Production
4. 1. Deterministic Inventory Problem with no
shortages
Demand is assumed to be fixed and completely pre-determined.
Case 1: The Fundamental Problem of EOQ
Objective: To determine an optimum order quantity(EOQ) such that the total
inventory cost is minimized.
Assumptions:
Demand is known and uniform
Shortages are not permitted.
Lead time is zero.
Production or supply of commodity is instantaneous.
5. Notation
D - Total number of units purchased/produced per time
Q - Lot size in each production run.
𝑪𝒐(or A) - Set-up cost (or ordering cost)
𝑪𝟏- Holding cost per unit.
𝑪- Unit cost
I- Inventory carrying cost
6. Assume that after each time t, the quantity Q is produced throughout the entire
period, say one year.
If 𝑛 is the total number of runs of the quantity produced during the year.
Then
1 = 𝑛𝑡 and 𝐷 = 𝑛𝑄 --------- (1)
7. Total inventory over the time period t days is the area of the first
triangle =
1
2
Qt.
The average inventory over the time period t days=
1
2
Qt
𝑡
=
1
2
Q
Annual Inventory holding cost 𝑓 𝑄 =
1
2
QC1
Annual costs associated with runs of size Q is 𝑔 𝑄 = 𝑛𝐶0 =
𝐷
𝑄
𝐶0 (by (1))
8. Since the minimum total cost occurs at the point where
the ordering cost equal to the total inventory carrying cost.
𝑓 𝑄 = 𝑔(𝑄)
1
2
𝑄𝐶1 =
𝐷
𝑄
𝐶0
𝑸𝒐
= 𝟐𝑫𝑪𝟎/𝑪𝟏
The above EOQ formula can also be expressed in terms of the
economic order value as
𝑸𝒐 = 𝟐𝑫𝑨/𝑪𝑰
9. Characteristics of Case 1.
1. Optimum number of order placed per year
𝑛0 =
𝐷
𝑄0 =
𝐷𝐶1
2𝐶0
2. Optimum length of time between order (or economic review period ERP)
𝑡0
=
𝑇
𝑛0 = 𝑇
2𝐶0
𝐷𝐶1
𝑇𝐸𝐶0 = Annual inventory carrying cost + Annual ordering cost
=
1
2
𝑄0𝐶1 +
𝐷
𝑄0
𝐶0
10.
11. Corollary 1
In the EOQ problem, if the set-up (ordering)
cost is 𝐶0 + 𝑏𝑄 instead of being fixed then there is no
change in the optimum order quantity produced due to
change in the set-up cost.
Proof:
The annual total cost is 𝑇𝐶 =
1
2
𝑄𝐶1 +
𝐷
𝑄
(𝐶0 + 𝑏𝑄)0
The optimum value of Q occur at
𝑑
𝑑𝑄
(𝑇𝐶) = 0
13. Case 2 : Problem of EOQ with Instantaneous Production and
Fixed order Cycle
All the assumption are same as in Case 1 except that the demand
is uniform and the production run differ in units.
Let 𝑡1, 𝑡2, … , 𝑡𝑛 denote the times of successive production runs
such that 𝑡1 + 𝑡2 + ⋯ + 𝑡𝑛 = 1 year.
14. The annual inventory holding cost is
𝑓 𝑄 =
1
2
𝑄𝑡1 𝐶1 +
1
2
𝑄𝑡2 𝐶1 + ⋯ +
1
2
𝑄𝑡𝑛 𝐶1
=
1
2
𝑄 𝑡1 + 𝑡2 + ⋯ + 𝑡𝑛 𝐶1
=
1
2
𝑄𝐶1
Set-up cost 𝑔 𝑄 =
𝐷
𝑄
𝐶0 Since 𝑛𝑄 = 𝐷
Total annual cost 𝑇𝐶 = 𝑓 𝑄 + 𝑔 𝑄 =
1
2
𝑄𝐶1 +
𝐷
𝑄
𝐶0
These cost are same as was obtained in Case 1, so the optimum
quantities are
𝑸𝒐 = 𝟐𝑫𝑪𝟎/𝑪𝟏
𝐓𝐂𝟎
= √𝟐𝑫𝑪𝟏𝑪𝟎.
15. Remark:
If the period is T instead of one year, then
the optimum order quantity becomes
𝑸𝒐 = 𝟐𝑫𝑪𝟎/𝑪𝟏𝑻
and the minimum total cost
𝐓𝐂𝟎
= 𝟐𝑫𝑪𝟏𝑪𝟎/T.
Thus the uniform rate of demand is replaced by
average rate of demand. ie., D is replaced by D/T.
16. Case 3: Problem of EOQ with Finite Production
All the assumption are same as in Case 1, except that of
instantaneous replenishment.
Assume that each production run of length t consists of two
parts, say 𝑡1 and 𝑡2 such that
(i) the inventory is building up at a constant rate or (k-r)
units, per unit of time during𝑡1, 𝑘 > 𝑟
(ii) there is no replenishment (or production) during time
𝑡2 and the inventory is decreasing at the
rate of r per unit of time.
The graphical representation of the situation is shown in Fig.
17.
18. Here, the total (order) quantity Q is produced over a period,
𝑡1, which is defined by the production rate 𝑘. Since the
inventory does not pile up in one shot but rather continuously
over a time period and is also consumed simultaneously, the
average inventory level would be determined not only by the
lot size Q, but also be affected by the production rate k and
depletion (demand) rate r.
To determine the average inventory:
Since 𝑡1 is the time required to produce Q at a rate k, we shall
have
𝑄 = 𝑘𝑡 or 𝑡1 =
𝑄
𝑘
19. During production period 𝑡1, inventory is increasing at the rate of k and
simultaneously decreasing the rate of r. Thus, inventory accumulates at the
rate of (k-r) units.
Therefore, the maximum inventory level shall be equal to
𝑡1(𝑘 − 𝑟).
Average inventory =
1
2
𝑡1 𝑘 − 𝑟 =
1
2
𝑄(1 −
𝑟
𝑘
). Since 𝑡1 =
𝑄
𝑘
The total annual holding cost is
𝑓 𝑄 = 𝐴𝑣𝑒𝑟𝑎𝑔𝑒 𝑖𝑛𝑣𝑒𝑛𝑡𝑜𝑟𝑦 × 𝐶1 =
1
2
𝑄𝐶1(1 −
𝑟
𝑘
)
Annual ordering cost
𝑔 𝑄 = 𝐶0 ×
𝐷
𝑄
where D is the total demand in a year.
20. Since the minimum total cost occurs at the point
where annual ordering cost and annual holding
cost are equal. So we must have
𝑓 𝑄 = 𝑔(𝑄)
This implies that
1
2
𝑄𝐶1 1 −
𝑟
𝑘
= 𝐶0 ×
𝐷
𝑄
Hence, the optimum value of Q is
𝑸𝟎 =
𝟐𝑫𝑪𝟎
𝑪𝟏(𝟏 −
𝒓
𝒌
)
=
𝟐𝑫𝑪𝟎
𝑪𝟏
𝒌
𝒌 − 𝒓
21. Characteristics of Case 3
1. Optimum number of production runs per year
𝒏𝟎 =
𝑫
𝑸𝟎
=
𝑫𝑪𝟏
𝟐𝑪𝟎
𝟏 −
𝒓
𝒌
2. Optimum length of each lot size production run
𝒕𝟏
𝟎
=
𝑸𝟎
𝒌
=
𝟐𝑫𝑪𝟎
𝑪𝟏𝒌(𝒌 − 𝒓)
3. Total minimum production inventory cost
𝑻𝑪𝟎 =
𝐶0𝐷
𝑄0
+
1
2
𝑄0 1 −
𝑟
𝑘
𝐶1
= 𝟐𝑫𝑪𝟎𝑪𝟏(𝟏 −
𝒓
𝒌
)