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Angle between 2 Lines
Preliminary Extension Mathematics

Date: Tuesday 10th May 2011
Angle between 2 lines
 y
                                   line l1 has gradient m1
         l2               l1       line l2 has gradient m2
                                   ∴ m1 = tan α and m2 = tan β
                  θ
              α       β
                               x
     0
Angle between 2 lines
 y
                                   line l1 has gradient m1
         l2               l1       line l2 has gradient m2
                                   ∴ m1 = tan α and m2 = tan β
                  θ
              α       β
                               x
                                    and α +θ =β (Why?)
     0
Angle between 2 lines
 y
                                 line l1 has gradient m1
         l2               l1     line l2 has gradient m2
                                 ∴ m1 = tan α and m2 = tan β
                  θ              and α +θ =β
              α       β
                               x (Exterior angle of V)
     0
Angle between 2 lines
 y
                                   So
         l2               l1       θ = β −α

                  θ
              α       β
                               x
     0
Angle between 2 lines
 y
                                   So
         l2               l1       θ = β −α
                                   ∴ tan θ = tan(β − α )
                  θ
              α       β
                               x
     0
Angle between 2 lines
 y
                                  So
         l2               l1      θ = β −α
                                 ∴ tan θ = tan(β − α )
                  θ                         tan β − tan α
                                         =
              α       β                    1 + tan β tan α
                               x
     0
                                  You will learn this formula later
Angle between 2 lines
 y
                                  So
         l2               l1      θ = β −α
                                 ∴ tan θ = tan(β − α )
                  θ                         tan β − tan α
                                         =
              α       β                    1 + tan β tan α
                               x
     0
                                            m1 − m2
                                         =
                                           1 + m1m2
                                             Why?
Angle between 2 lines
 y
                                  So
         l2               l1      θ = β −α
                                 ∴ tan θ = tan(β − α )
                  θ                         tan β − tan α
                                         =
              α       β                    1 + tan β tan α
                               x
     0
                                            m1 − m2
                                         =
                                           1 + m1m2
                                When tan θ is positive, θ is acute.
                                When tan θ is negative, θ is obtuse.
Angle between 2 lines
 y
                                      Thus for two lines of gradient
         l2                  l1               m1 and m2
                                  the acute angle between them is given by

                   θ                               m1 − m2
                                          tan θ =
              α          β
                                  x               1 + m1m2
     0


                  Note that m1m2 ≠ −1        what does this mean?
Angle between 2 lines
 y
                                         Thus for two lines of gradient
            l2                  l1               m1 and m2
                                     the acute angle between them is given by

                      θ                               m1 − m2
                                             tan θ =
                 α          β
                                     x               1 + m1m2
     0


                     Note that m1m2 ≠ −1
         the formula does not work for perpendicular lines
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3

                           m1 − m2
                   tan θ =
                           1 + m1m2
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3

                           m1 − m2
                   tan θ =
                           1 + m1m2
                           2+3
                 ∴ tan θ =
                           1− 6
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3

                           m1 − m2
                   tan θ =
                           1 + m1m2
                           2+3
                 ∴ tan θ =
                           1− 6
                 ∴ tan θ = −1
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3

                           m1 − m2
                   tan θ =
                           1 + m1m2
                           2+3
                 ∴ tan θ =
                           1− 6
                 ∴ tan θ = −1
                 ∴ tan θ = 1
Example 1
Find the acute angle between   y = 2x + 1   and   y = −3x − 2
(to nearest degree)
                ∴ m1 = 2 and m2 = −3

                           m1 − m2
                   tan θ =
                           1 + m1m2
                           2+3
                 ∴ tan θ =
                           1− 6
                 ∴ tan θ = −1
                 ∴ tan θ = 1          → θ = 45°
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
∴2y = 3x + 7
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
∴2y = 3x + 7
    3    7
∴y = x +
    2    2
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
∴2y = 3x + 7
      3  7
∴y = x +
      2  2
       3
∴ m1 =
       2
Example 2
Find the acute angle between   3x − 2y + 7 = 0    and
(to nearest degree)                                 2y + 4x − 3 = 0
∴2y = 3x + 7
                                    similarly   ∴2y = −4x + 3
      3  7
∴y = x +                                                     3
      2  2                                       ∴ y = −2x +
                                                             2
       3
∴ m1 =                                          ∴ m2 = −2
       2
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
applying the formula
                               m1 − m2
                       tan θ =                        3
                               1 + m1m2          m1 =     m2 = −2
                                                      2
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
applying the formula
                                m1 − m2
                        tan θ =                       3
                                1 + m1m2         m1 =     m2 = −2
                                                      2
                                  3
                                    +2
                       ∴ tan θ = 2
                                  1− 3
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
applying the formula
                                m1 − m2
                        tan θ =                       3
                                1 + m1m2         m1 =     m2 = −2
                                                      2
                                  3
                                    +2
                       ∴ tan θ = 2
                                  1− 3

                                 −7
                       ∴ tan θ =
                                 4
Example 2
Find the acute angle between   3x − 2y + 7 = 0   and
(to nearest degree)                               2y + 4x − 3 = 0
applying the formula
                                m1 − m2
                        tan θ =                       3
                                1 + m1m2         m1 =     m2 = −2
                                                      2
                                  3
                                    +2
                       ∴ tan θ = 2
                                  1− 3

                                 −7              7
                       ∴ tan θ =       ∴ tan θ =       → θ = 60°
                                 4               4
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3   and   y = −3x + 5
(to nearest degree)
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3    and   y = −3x + 5
(to nearest degree)

  y = −3x + 5   y
                            y= x+3



                θ

            α           β
                                     x
                    0
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3    and   y = −3x + 5
(to nearest degree)
                                          m1 = 1 → α = 45°
  y = −3x + 5   y
                            y= x+3



                θ

            α           β
                                     x
                    0
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3    and   y = −3x + 5
(to nearest degree)
                                          m1 = 1 → α = 45°
  y = −3x + 5   y
                            y= x+3        m2 = −3 → β = 108°


                θ

            α           β
                                     x
                    0
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3    and   y = −3x + 5
(to nearest degree)
                                          m1 = 1 → α = 45°
  y = −3x + 5   y
                            y= x+3        m2 = −3 → β = 108°
                                          But α +θ =β
                θ

            α           β
                                     x
                    0
Example 3 - by thinking and
drawing....
Find the acute angle between   y= x+3    and   y = −3x + 5
(to nearest degree)
                                          m1 = 1 → α = 45°
  y = −3x + 5   y
                            y= x+3        m2 = −3 → β = 108°
                                          But α +θ =β
                θ                         ∴θ = 63°
            α           β
                                     x
                    0

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Angle between 2 lines

  • 1. Angle between 2 Lines Preliminary Extension Mathematics Date: Tuesday 10th May 2011
  • 2. Angle between 2 lines y line l1 has gradient m1 l2 l1 line l2 has gradient m2 ∴ m1 = tan α and m2 = tan β θ α β x 0
  • 3. Angle between 2 lines y line l1 has gradient m1 l2 l1 line l2 has gradient m2 ∴ m1 = tan α and m2 = tan β θ α β x and α +θ =β (Why?) 0
  • 4. Angle between 2 lines y line l1 has gradient m1 l2 l1 line l2 has gradient m2 ∴ m1 = tan α and m2 = tan β θ and α +θ =β α β x (Exterior angle of V) 0
  • 5. Angle between 2 lines y So l2 l1 θ = β −α θ α β x 0
  • 6. Angle between 2 lines y So l2 l1 θ = β −α ∴ tan θ = tan(β − α ) θ α β x 0
  • 7. Angle between 2 lines y So l2 l1 θ = β −α ∴ tan θ = tan(β − α ) θ tan β − tan α = α β 1 + tan β tan α x 0 You will learn this formula later
  • 8. Angle between 2 lines y So l2 l1 θ = β −α ∴ tan θ = tan(β − α ) θ tan β − tan α = α β 1 + tan β tan α x 0 m1 − m2 = 1 + m1m2 Why?
  • 9. Angle between 2 lines y So l2 l1 θ = β −α ∴ tan θ = tan(β − α ) θ tan β − tan α = α β 1 + tan β tan α x 0 m1 − m2 = 1 + m1m2 When tan θ is positive, θ is acute. When tan θ is negative, θ is obtuse.
  • 10. Angle between 2 lines y Thus for two lines of gradient l2 l1 m1 and m2 the acute angle between them is given by θ m1 − m2 tan θ = α β x 1 + m1m2 0 Note that m1m2 ≠ −1 what does this mean?
  • 11. Angle between 2 lines y Thus for two lines of gradient l2 l1 m1 and m2 the acute angle between them is given by θ m1 − m2 tan θ = α β x 1 + m1m2 0 Note that m1m2 ≠ −1 the formula does not work for perpendicular lines
  • 12. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree)
  • 13. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3
  • 14. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3 m1 − m2 tan θ = 1 + m1m2
  • 15. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3 m1 − m2 tan θ = 1 + m1m2 2+3 ∴ tan θ = 1− 6
  • 16. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3 m1 − m2 tan θ = 1 + m1m2 2+3 ∴ tan θ = 1− 6 ∴ tan θ = −1
  • 17. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3 m1 − m2 tan θ = 1 + m1m2 2+3 ∴ tan θ = 1− 6 ∴ tan θ = −1 ∴ tan θ = 1
  • 18. Example 1 Find the acute angle between y = 2x + 1 and y = −3x − 2 (to nearest degree) ∴ m1 = 2 and m2 = −3 m1 − m2 tan θ = 1 + m1m2 2+3 ∴ tan θ = 1− 6 ∴ tan θ = −1 ∴ tan θ = 1 → θ = 45°
  • 19. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0
  • 20. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 ∴2y = 3x + 7
  • 21. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 ∴2y = 3x + 7 3 7 ∴y = x + 2 2
  • 22. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 ∴2y = 3x + 7 3 7 ∴y = x + 2 2 3 ∴ m1 = 2
  • 23. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 ∴2y = 3x + 7 similarly ∴2y = −4x + 3 3 7 ∴y = x + 3 2 2 ∴ y = −2x + 2 3 ∴ m1 = ∴ m2 = −2 2
  • 24. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 applying the formula m1 − m2 tan θ = 3 1 + m1m2 m1 = m2 = −2 2
  • 25. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 applying the formula m1 − m2 tan θ = 3 1 + m1m2 m1 = m2 = −2 2 3 +2 ∴ tan θ = 2 1− 3
  • 26. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 applying the formula m1 − m2 tan θ = 3 1 + m1m2 m1 = m2 = −2 2 3 +2 ∴ tan θ = 2 1− 3 −7 ∴ tan θ = 4
  • 27. Example 2 Find the acute angle between 3x − 2y + 7 = 0 and (to nearest degree) 2y + 4x − 3 = 0 applying the formula m1 − m2 tan θ = 3 1 + m1m2 m1 = m2 = −2 2 3 +2 ∴ tan θ = 2 1− 3 −7 7 ∴ tan θ = ∴ tan θ = → θ = 60° 4 4
  • 28. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree)
  • 29. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree) y = −3x + 5 y y= x+3 θ α β x 0
  • 30. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree) m1 = 1 → α = 45° y = −3x + 5 y y= x+3 θ α β x 0
  • 31. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree) m1 = 1 → α = 45° y = −3x + 5 y y= x+3 m2 = −3 → β = 108° θ α β x 0
  • 32. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree) m1 = 1 → α = 45° y = −3x + 5 y y= x+3 m2 = −3 → β = 108° But α +θ =β θ α β x 0
  • 33. Example 3 - by thinking and drawing.... Find the acute angle between y= x+3 and y = −3x + 5 (to nearest degree) m1 = 1 → α = 45° y = −3x + 5 y y= x+3 m2 = −3 → β = 108° But α +θ =β θ ∴θ = 63° α β x 0

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